When converting a MongoCursor to PHP I use this script. Which was presented here
StackOverflowSO
using the upper method, the structure is same but _id is whereas using the lower script which yields the below included result.
Unfortunately, this results in the actual object being embedded into an array with the _id from Mongo. Like this :
`4eefa79d76d6fd8b50000007 = {
"_id" = {
"$id" = 4eefa79d76d6fd8b50000007;
};
longText = "Error Description";
nCode = dee29fd7e15ce4ab2d3f7dfa7c5d8fc44b27501ad00908771128c920ef276154;
nStatus = Process;
nText = "E12345";
nVType = Type1;
pId = {
"$id" = 4eefa79676d6fd8b50000003;
};
pushDate = "2011-12-20+06%3A07%3A41";
updateFlag = 1;
};`
Since I am passing this object to another service for processing the _id is not known.
How can I convince the PHP Driver to parse the object properly?
Basically what I did was this.
return json_encode(iterator_to_array($cursor));
But this created the aforementioned object which is not what I needed.
I solved it in this way.
$i=0;
foreach($cursor as $item){
$return[$i] = array(
'_id'=>$item['_id'],
'nCode'=>$item['nCode'],
'pId'=>$item['pId'],
'nText'=>$item['nText'],
'longText'=>$item['longText'],
'nStatus'=>$item['nStatus'],
'nVType'=>$item['nVType'],
'pushDate'=>$item['pushDate'],
'updateFlag'=>$item['updateFlag'],
'counter' => $i
);
$i++;
}
return json_encode($return);
If you result is big in order to save RAM you could try this more efficient method:
function outIterator($iterator, $resultName='results')
{
// Efficient MongoCursor Iterator to JSON
// instead of encoding the whole result array to json
// process each item individually
// in order to save memory by not copying the data multiple times
//Start Json Output
header('Content-Type: application/json');
echo '{' . $resultName . ': ['
//Output each item as json if there are results in the iterator
if ($iterator->hasNext()){
foreach ($iterator as $item)
{
echo json_encode ($fixeditem);
if ($iterator->hasNext()) echo ', ';
}
}
//end Json output
echo ']}';
}
$results = $db->collection->find();
outIterator($results);
Related
I'm trying to GET a JSON format back when I POST a specific ID to my database. As I get more than one result I have multiple rows, which I want to get back. I do get different arrays back, but it is not a valid JSON Format. Instead of
[{...},{...},{...}]
it comes back as
{...}{...}{...}
Therefore the [...] are missing and the arrays are not separated by commas.
My code is down below. The function "getUserBookingsKl" is defined in a different php.
//get user bookings
public function getUserBookingsKl($id) {
//sql command
$sql = "SELECT * FROM `***` WHERE `hf_id`=$id AND `alloc_to`>DATE(NOW()) AND NOT `confirmation`=0000-00-00 ORDER BY `alloc_from`";
//assign result we got from $sql to $result var
$result = $this->conn->query($sql);
// at least one result
if ($result !=null && (mysqli_num_rows($result) >= 1 ))
{
while ($row = $result->fetch_array())
{
$returArray[] = $row;
}
}
return $returArray;
}
...
...
foreach($userdb as $dataset)
{
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
echo json_encode($returnArray);
# return;
}
// Close connection after registration
$access->disconnect();
It looks like you're sequentially emitting the values, not pushing into an array. You need to make an array, push into it, then call json_encode on the resulting structure:
$final = [ ];
foreach ($userdb as $dataset)
{
$returnArray = [ ];
$returnArray["group"] = $dataset["kf_id"];
$returnArray["from"] = $dataset["alloc_from"];
$returnArray["to"] = $dataset["alloc_to"];
$final[] = $returnArray;
}
echo json_encode($final);
Note that it's important here to not use the same variable inside the loop each time through or you're just pushing the same array in multiple times.
I need looped php data in an html template so I know it has something to do with JSON however not a JSON expert and cannot find much help in searching the web.
$uniqueFranchise_id = array_unique($franchise_id);
$dataArr = '[
{
"name": "Dylan",
"page_link": "https://mypage.com/"
}
]';
foreach($uniqueFranchise_id as $franchise)
{
$sqlFranchise = "select * from franchise where franchise_id = $franchise";
$resultFranchise = $conn->query($sqlFranchise);
if($resultFranchise->num_rows > 0)
{
while($rowFranchise = $resultFranchise->fetch_assoc())
{
$dataArr = json_decode($data, TRUE);
$dataArr[] = "['name'=>'".$rowFranchise['name']."', 'page_link'=>'".$rowFranchise['page_link']."']";
//$json = json_encode($dataArr);
}
}
}
$json = json_encode($dataArr);
print_r($dataArr);
But it only appends one row. In fact it deleteds that data that's already in my dataArr and just adds one row from my loop? Maybe I'm approaching this situation completely wrong?
You set your $dataArr inside the while-loop. So each time the loop is runs, it will be overwritten. Also, it makes more sense and it's much more clear when you handle it as an array (or object) and afterwards convert it to JSON.
$dataArr = array(array('name' => 'Dylan', 'page_link' => 'https://mypage.com/'));
foreach($uniqueFranchise_id as $franchise)
{
$sqlFranchise = "select * from franchise where franchise_id = $franchise";
$resultFranchise = $conn->query($sqlFranchise);
if($resultFranchise->num_rows > 0)
{
while($rowFranchise = $resultFranchise->fetch_assoc())
{
$dataArr[] = array('name' => $rowFranchise['name'], 'page_link' => $rowFranchise['page_link']);
}
}
}
$json = json_encode($dataArr);
echo $json;
You shouldn't be building the string up by yourself, you should build the data and then JSON encode the result (comments in code)...
$dataArr = '[
{
"name": "Dylan",
"page_link": "https://mypage.com/"
}
]';
// decode existing JSON to start array
$dataArr = json_decode($data, TRUE);
foreach($uniqueFranchise_id as $franchise)
{
// Read just the data you need from the table
$sqlFranchise = "select name, page_link from franchise where franchise_id = $franchise";
$resultFranchise = $conn->query($sqlFranchise);
if($resultFranchise->num_rows > 0)
{
// Read all of the rows into an array
$newData = $resultFranchise->fetch_all(MYSQLI_ASSOC);
// Add in existing data
$dataArr = array_merge($dataArr, $newData);
}
}
// Now encode the list of elements into 1 string
echo json_encode($dataArr);
You should also look into prepared statements if this data is not trusted to stop SQL injection.
I am working on parsing HTML and get multidimensional output array as json.
I am parsing html like I want but I couldn't create JSON array.
The example output of foreach loop:
PS: every json object has different string value.
0:"blahblah"
1:"blahblah"
2:"blahblah"
3:"blahblah"
4:" " // only space
5:"blahblah"
6:"blahblah"
7:"blahblah"
8:"blahblah"
9:" " // only space
...
I want create json array like this:
$output = array();
$html = str_get_html($ret);
$lessons["lesson"] =array();
foreach($html->find('table//tbody//tr') as $element) {
$temp = strip_tags($element->innertext);
array_push($lessons['lesson'], $temp); // the objects (I wrote as 'blahblah' every object but I getting different values always)
if($temp == " ") // if there is only space push array the output and create new array
{
array_push($output , $lessons["lesson"]);
unset($lessons);
$lessons["lesson"] = array();
}
}
echo (json_encode($output ,JSON_UNESCAPED_UNICODE)); // $output show nothing
Thanks in advice.
If your issue is getting all the blah into the array then the below will get you there. I am not following the code too well but attempt to explain my thoughts in comments.
$json = ["blahblah"
,"blahblah"
,"blahblah"
,"blahblah"
," "
,"blahblah"
,"blahblah"
,"blahblah"
,"blahblah"
," "];
$lessons["lesson"] = []; // I think this is the array you are using
$tmp = []; // Something tmp to hold things
foreach($json as $elm){ //Loop what I assume $html->find('table//tbody//tr') is returning
if($elm != ' '){//Wait for a ' ' and add to tmp
$tmp[] = $elm;
} else {
$lessons["lesson"][] = $tmp; // This array is done so keep it and restart
$tmp = [];
}
}
I need to edit some data in a JSON file, and I'm looking to do so in PHP. My JSON file looks like this:
[
{
"field1":"data1-1",
"field2":"data1-2"
},
{
"field1":"data2-1",
"field2":"data2-2"
}
]
What I've done so far is $data = json_decode(file_get_contents(foo.json)) but I have no idea how to navigate this array. If for example I want to find the data from the first field of the second object, what's the PHP syntax to do so? Also, are there other ways I should know about for parsing JSON data into a PHP friendly format?
This JSON contains 2 arrays with 2 objects each, you can access like this:
$arr = json_decode(file_get_contents(foo.json));
// first array
echo $arr[0]->field1;
echo $arr[0]->field2;
// second array
echo $arr[1]->field1;
echo $arr[1]->field2;
if you convert this to an array and avoid objects you can then access like this:
$arr = json_decode(file_get_contents(foo.json), true);
// first array
echo $arr[0]['field1'];
echo $arr[0]['field2'];
// second array
echo $arr[1]['field1'];
echo $arr[1]['field2'];
$data = json_decode(file_get_contents(foo.json));
foreach($data as $k => &$obj) {
$obj->field1 = 'new-data1-1';
$obj->field2 = 'new-data1-2';
}
Please use this code to navigate through your json format. This code is dynamic and can navigate for any number of objects you have in your result.
<?php
$json ='[
{
"field1":"data1-1",
"field2":"data1-2"
},
{
"field1":"data2-1",
"field2":"data2-2"
}
]';
if($encoded=json_decode($json,true))
{
echo 'encoded';
// loop through the json values
foreach($encoded as $key=>$value)
{
echo'<br>object index: '.$key.'<br>';
foreach($value as $bKey=>$bValue)
{
echo '<br> '.$bValue.' = '.$bValue;
}
}
// get a perticular item
echo '<br>object[0][field1]: '.$encoded[0]['field1'];
}
else
{
echo'error on syntax';
}
?>
Which will have following output
encoded
object index: 0
data1-1 = data1-1
data1-2 = data1-2
object index: 1
data2-1 = data2-1
data2-2 = data2-2
object[0][field1]: data1-1
I load a php/json file. This is my json file:
echo '{';
echo '"position":[';
while($inhoud = mysql_fetch_array($result))
{
echo '{';
echo '"lat":"'.$inhoud['lat'].'",';
echo '"long":"'.$inhoud['long'].'",';
echo '}';
}
echo ']}';
This works. I want to load it in my javascript and do it like this:
$.getJSON('req/position.php', function(data) {
$.each(data, function(key, val) {
newLatLng = key;
});
});
but this doesn't work. It loads the file but i don't get this data. What should i do?
Thanks,
I think you have some syntax errors in the JSON output.
When you output "long" data, you append a comma , at the end, but you should not, because "long" is the last key of the object.
You print out an object in a while cycle. These objects are part of an array. So, except for the last one, you have to append a comma , after the closing }.
And, if I can ask, why you are not using the json_encode() PHP function, instead of build all the JSON string manually? With it, you build all the data as normal PHP array, and then encode (translate) it in JSON. You will avoid all these annoying syntax stuffs.
Just try it:
$data = array();
$data['position'] = array();
while($inhoud = mysql_fetch_array($result))
{
$data['position'][] = array(
"lat" => $inhoud['lat'],
"long" => $inhoud['long']
);
}
echo json_encode($data);
You have your co-ordinates defined in the array named position. You need to iterate through that. The Array contains objects with the properties lat and long. If you want to use the values, you should try something like:
$.getJSON('req/position.php'), function(data){
$.each(data.position, function(index, value){
var newLatLng = { latitude: value.lat, longitude: value.long };
});
});
Return proper header in PHP script
header('Content-type: application/json');
And it should work.
Also use json_encode to encode PHP values into valid JSON.
Constructing JSON in php through strings works but is primitive. Start constructing an array and use json_encode().
$arr = array();
while($inhoud = mysql_fetch_array($result)){
$temp = array();
$temp['lat'] = $inhoud['lat'];
$temp['long'] = $inhoud['long'];
$arr[] = $temp;
}
echo json_encode($arr);
If all that you select in your mysql query is 'lat' and 'long' you could also just place $inhoud into $arr inside your while loop like so.
while($inhoud = mysql_fetch_array($result)){
$arr[] = $inhoud;
}
If you do this just make sure you only select columns in your mysql query that you would want to output in JSON.
$.getJSON('req/position.php', function(data) {
var obj = JSON.parse(data);
// At this point, obj is an object with your JSON data.
});
Source: MDN