$date = new DateTime("11:00");
$date->format('Y-m-d H:i W');
this create new datetime which is now with hour 11:00:
2011-12-22 11:00 51
how can i make it with W - weekend?
i would like create new date with hour 11:00 and week 20. (now is 51)
How can i make it?
$date = new DateTime("11:00");
$date->format('W H:i');
the format method accepts the same format identifier as the date function. The W return the week number.
Related
how can i convert a time stamp to Monday corresponding with that week?
example:
1473750000 (Tue, 13 Sep 2016 07:00:00 GMT)
// coding magic
1473638400 (Mon, 12 Sep 2016 00:00:00 GMT )
To convert timestamps, you can use a PHP Function gmdate(). I already use this on some of my projects/sites.
$timestamp = strtotime("+1 hour"); //Uk Time
echo gmdate("H:i", $timestamp); //Hour:Minutes
For the other parts of gmdate(), check the PHP Manual.
I also add my solution to the problem, using DateInterval.
function getLastMonday($timestamp){
// Initialize DateTime object
$date = new DateTime();
$date->setTimestamp($timestamp);
// Calculate num of days to substract and create date interval
$dayOfWeek = $date->format("w");
$interval = new DateInterval("P".(($dayOfWeek+6)%7).'D');
$interval->invert = 1;
// Substract the Date interval
$date->add($interval);
return $date;
}
I've found an answer using the documentation provided in the answers:
$date = date('Y-m-d',strtotime('this monday this week',1473750000));
If I send a DAY and TIME (not DATE) to the DateTime API like this :
$tz = new \DateTimeZone("UTC");
$now = new \DateTime("now", $tz);
$then = \DateTime::createFromFormat('l g A', 'Thursday 8 PM', $tz);
And it is currently Saturday 26th March, $then, when echoed as follows :
echo $then->format('l jS, F');
Will return :
Thursday 31st, March
How do I make it return the date of the Thursday in the CURRENT week that has just passed :
Thursday 24th March
Not the next Thursday?
DateTime::__construct() and strtotime() uses a lot of rules to guess what you mean when you specify an incomplete or relative date. Most of the times thy guess right but some of the rules are very similar and the final result is not the one expected by the programmer.
DateTime::createFromFormat() is limited, it cannot understand all the formats from the list.
You try to parse a relative date format. When only the day name is specified, it is interpreted as the next occurrence of the specified day of the week (see the dayname entry under the Day-based Notations table in the documentation.)
You can get the date you want by using Thursday this week instead. DateTime::createFromFormat() doesn't understand relative dates that contain references to the week but DateTime::__construct() does.
Try this:
$then = new \DateTime('Thursday this week 8 PM', $tz);
Could always call the 'sub' method on it, subtracting 7 days.
$tz = new \DateTimeZone("UTC");
$now = new \DateTime("now", $tz);
$then = \DateTime::createFromFormat('l g A', 'Thursday 8 PM', $tz);
$then->sub(new DateInterval('P7D'));
echo $then->format('l jS, F');
I can get the for example 19 March of specific date with this code:
$date = strtotime(" 19 March", $current_time);
For example if I gave the unix timestamp of 1st of January of 2010 as an input, It gave me 19 March of 2010. But also if I gave the unix timestamp of 20 March of 2010,I still get 19 March 2010. What I want is to get the next 19 March which in this case, It would be 19 March of 2011.
How can I do that?
Using PHP DateTime this can be achieved as follows:
// New DateTime object
$date = new DateTime('2010-03-19');
// Add a year
$date->add(new DateInterval('P1Y'));
// Output timestamp
echo $date->getTimestamp();
You can do something like as
$get = "19 March";
$given_date = "01 January 2010";
$date_month = date('d F',strtotime($given_date));
$year = date('Y',strtotime($given_date));
if(strtotime($given_date) - strtotime($date_month) < 0){
echo date('l,d F Y',strtotime("$get $year"));
}else{
echo date('l,d F Y',strtotime("$get ".($year+1)));
}
You should first get year from specified date. Then after you can create 19 march date with year and use strtotime() to get timestamp.
//add format according to your current_time variable format
$date = DateTime::createFromFormat("Y-m-d", $current_time);
echo $date->format("Y");
$fixed_date = strtotime($date->format("Y")."-03-19");
You can specify how many days or week you want to add or subtract from a day, as well as set the time with these functions
$nextUpdate = new DateTime("+5 day 1:00 pm");
echo $nextUpdate->getTimestamp();
$nextWeek = new DateTime("+1 week 9:00 am");
echo $nextWeek->getTimestamp();
I am taking in a parameter that is a date in PST timezone which will be in the format of "YYYY-MM-DD" (e.g. "2011-08-15"). This parameter is optional. I have 2 questions that I've been struggling with.
I need to calculate the start and end datetime in UTC for this date.
So if the inputted date is 2011-08-15, I want to get the start and end datetimes:
2011-08-15 07:00:00
2011-08-15 06:59:59
(These are essentially the beginning and end of day)
Second, is to handle the case when the date is not passed in. I want to default to the current PST date them and start from there. So if the current datetime is 2011-08-01 10:00:00, I want to get the same start and end datetimes similar to the first scenario except it's based on the inputted date.
2011-08-01 07:00:00
2011-08-01 06:59:59
I've been pulling my hair out dealing with date and datetime conversions. I'm sure I'm missing something super straightforward.
Parse the date and assume PST timezone:
$date = new DateTime("2011-08-15", new DateTimeZone("PST"));
Change the timezone to UTC: (this does the all conversions for you)
$date->setTimeZone(new DateTimeZone("UTC"));
Calculate start and end. Start is our $date and end is $date + 1 day
$start = $date;
$end = clone $date;
$end->modify("+1 day"); // now $end is $start + 1 day
Print start/end:
printf("start: %s, end: %s\n", $start->format('Y-m-d H:i:s'), $end->format('Y-m-d Hi:s'));
// this prints start: 2011-08-15 07:00:00, end: 2011-08-16 07:00:00
For the last part of your questions, you can easily compare two dates:
if ($date > new DateTime()) { // if $date is after now
// do something
}
So you could do something like that:
if ($date > new DateTime()) {
$date->setTimeZone(new DateTimeZone("UTC"));
}
If you don't much like the OO syntax you could also use the function aliases:
$date = date_create(...);
date_format($date, ...);
date_modify($date, ...);
// ...
Use setTimezone function
Working example (I'm not in PST timezone, so I have to set it explicitly)
$date_input = "20011-09-15";
//$date_input = null; //That will emulate no-input case
date_default_timezone_set("America/Los_Angeles"); //if you are in PST, you don't need this line
$date_start = new DateTime($date_input);
$date_end = new DateTime($date_input);
$date_end->modify("+1 day");
/*$date_start->setTimezone(new DateTimeZone("America/Los_Angeles"));
$date_end->setTimezone(new DateTimeZone("America/Los_Angeles"));*/
//end of date is equal to start of the next day.
//But, if you need something like 2011-08-11 23:59:59 add $date_end->modify('-1 second')
$date_start->setTime(0,0,0);
$date_end->setTime(0,0,0);
echo "Date Start PST:".$date_start->format("Y-m-d H:i:s")."<br/>";
echo "Date End PST:".$date_end->format("Y-m-d H:i:s")."<br/>";
//UTC is equal to London time. Almost :)
$date_start->setTimezone(new DateTimeZone ('Europe/London'));
$date_end->setTimezone(new DateTimeZone ('Europe/London'));
echo "Date Start UTC:".$date_start->format("Y-m-d H:i:s")."<br/>";
echo "Date End UTC:".$date_end->format("Y-m-d H:i:s")."<br/>";
I have a PHP DateTime variable.
How can I reduce or subtract 12hours and 30 minutes from this date in at PHP runtime?
Subtract 12 Hours and 30 minutes from a DateTime in PHP:
$date = new DateTime();
$tosub = new DateInterval('PT12H30M');
$date->sub($tosub);
The P stands for Period. The T stands for Timespan.
See DateTime, DateTime::sub, and DateInterval in the PHP manual. You'll have to set the DateTime to the appropriate date and time, of course.
Try with:
$date = new DateTime('Sat, 30 Apr 2011 05:00:00 -0400');
echo $date->format('Y-m-d H:i:s') . "\n";
$date->sub(new DateInterval('PT12H30M'));
echo $date->format('Y-m-d H:i:s') . "\n";
//Result
2011-04-30 05:00:00
2011-04-29 16:30:00
Try strtotime() function:
$source_timestamp=strtotime("Sat, 30 Apr 2011 05:00:00 -0400");
$new_timestamp=strtotime("-12 hour 30 minute", $source_timestamp);
print date('r', $new_timestamp);
Maybe it will be useful for some cases
$date = new DateTime();
$date->modify('-12 hours -30 minutes');
echo $date->format('H:i:s');
try using this instead
//set timezone
date_default_timezone_set('GMT');
//set an date and time to work with
$start = '2014-06-01 14:00:00';
//display the converted time
echo date('Y-m-d H:i',strtotime('+1 hour +20 minutes',strtotime($start)));
If you are not so familiar with the spec of DateInterval like PT12H30M you can proceed with more human readable way using DateInterval::createFromDateString as follows :
$date = new DateTime();
$interval = DateInterval::createFromDateString('12 hour 30 minute');
$date->sub($interval);
Or with direct interval in sub function like below :
$date = new DateTime();
$date->sub(DateInterval::createFromDateString('12 hour 30 minute'));
Store it in a DateTime object and then use the DateTime::sub method to subtract the timespan.
I used in one line, for 12 hours only, and just as an hour display
$date = new DateTime(); $date->modify('-12 hours'); echo $date->format('H')-0;
I used the -0 since sometimes it put a 0 in front of the digit unless I done that, strange.
Here is detailed description of date function,
Using simply strtotime
echo date("Y-m-d H:i:s",strtotime("-12 hour -30 minutes"));
Using DateTime class
$date = new DateTime("-12 hour -30 minutes");
echo $date->format("Y-m-d H:i:s");