i know this question was probably asked 1 million times, but for the 1.000.001 time :)
i need to call a php function from JavaScript. And i am having a bit of an argument on if ajax will do it.
i don't want to send any data just a ajax call that will call and run that function.
here is what i have so far:
$.post('functions/test.php', function() {
console.log("Hooray, it worked!");
});
is this gonna run the test.php ?
thanks
It definitely runs the test.php, to check it you may do sth. on succes
$.ajax({
type: "POST",
url: "ajax/test.php",
success: function(data) {
alert(data);
}
});
But what's the purpose of sending if no data is send?
Most likely, yes. I can't guarantee it because I don't do jQuery.
This, however, will definitely run it no problems (except versions of IE so old you shouldn't care about them):
var a = new XMLHttpRequest();
a.open("GET","functions/test.php");
a.onreadystatechange = function() {
if( a.readyState == 4) {
if( a.status == 200) {
console.log("Hooray, it worked!");
// optionally, do stuff with a.responseText here
// a.responseText is the content the PHP file outputs, if any
}
else alert("HTTP error "+a.status+" "+a.statusText);
}
}
a.send();
Yes the test.php script will run, and you can grab the output from the test.php script like this (if you want to):
$.post('functions/test.php', function(data) {
//the `data` variable now stores the server response (whatever you output in `test.php`)
console.log("Hooray, it worked!");
});
In JQuery you can do:
$.post('functions/test.php', function(data) {
alert(data);
});
Whatever is returned in test.php will be put into the variable "data"
So you can do any php functions you need to in test.php and send the output back.
I always use
jQuery.ajax("url.php");
Related
I try to pass this value to my php code, but I do not know how to do it. post method does not work. (I do not know why).
<script>
var val = localStorage.getItem('sumalist');
$.ajax({
type: "POST",
url: "index.php",
data: {value: val},
success: function () {
console.log(val);
}
});
</script>
and in my php code, value is not set.
if (isset($_POST["value"])) {
echo "Yes, value is set";
$value = $_POST["value"];
}else{
echo "N0, value is not set";
}
PS: My php code is in the same file in js code.
Check if this works
<?php
if(!empty($_POST)) {
$value = (isset($_POST["value"])) ? $_POST["value"] : NULL;
$return = ($value != NULL) ? "Yes, value is: ".$value : "N0, value is not set";
echo $return;
exit;
}
?>
<script src="//code.jquery.com/jquery-3.3.1.js"></script>
<script>
var val = 'value sent';
$.ajax({
type: "POST",
url: "index.php",
data: {value: val},
success: function (ret) {
console.log(ret);
}
});
</script>
Open console for result
Please use console if you're using chrome then open console and try debugging,
And first you run that ajax function in jquery ready function like this
$(document).ready(function (){ $.ajax( replaced for ajax function ) }
If you want to use the response in callback success function, use this:
success: function (ret) {
console.log(ret); //Prints 'Yes, value is set' in browser console
}
In your browser you have Developer Tools - press F12 to open, go to Network tab (FireFox, Chrome, IE - all the same), then reload your page and you will see the line for your AJAX call (if it is performed on load, or trigger your call if this is not the case), select it and right hand you'll see a extra frame where you can see all the details of your request, including request params, headers, response headers, the actual response and many other.
That's the best solution to check your AJAX request without asking uncompleted questions and seeking for the answers in case someone can assemble your full case in his mind.
Believe me - this is the best solution for you and not only for this case!
Of course your JS should be performed when DOM is ready so you have to wrap it in
${function() {
// your code here
});
in case you want to be executed on load.
I am very new to PHP and Javascript.
Now I am running a PHP Script by using but it redirect to another page.
the code is
<a name='update_status' target='_top'
href='updateRCstatus.php?rxdtime=".$time."&txid=".$txid."&balance=".$balance."&ref=".$ref."'>Update</a>
How do I execute this code without redirecting to another page and get a popup of success and fail alert message.
My script code is -
<?PHP
$rxdtime=$_GET["rxdtime"];
$txid=$_GET["txid"];
$balance=$_GET["balance"];
$ref=$_GET["ref"];
-------- SQL Query --------
?>
Thanks in advance.
You will need to use AJAX to do this. Here is a simple example:
HTML
Just a simple link, like you have in the question. However I'm going to modify the structure a bit to keep it a bit cleaner:
<a id='update_status' href='updateRCstatus.php' data-rxdtime='$time' data-txid='$txid' data-balance='$balance' data-ref='$ref'>Update</a>
I'm assuming here that this code is a double-quoted string with interpolated variables.
JavaScript
Since you tagged jQuery... I'll use jQuery :)
The browser will listen for a click event on the link and perform an AJAX request to the appropriate URL. When the server sends back data, the success function will be triggered. Read more about .ajax() in the jQuery documentation.
As you can see, I'm using .data() to get the GET parameters.
$(document).ready(function() {
$('#update_status').click(function(e) {
e.preventDefault(); // prevents the default behaviour of following the link
$.ajax({
type: 'GET',
url: $(this).attr('href'),
data: {
rxdtime: $(this).data('rxdtime'),
txid: $(this).data('txid'),
balance: $(this).data('balance'),
ref: $(this).data('ref')
},
dataType: 'text',
success: function(data) {
// do whatever here
if(data === 'success') {
alert('Updated succeeded');
} else {
alert(data); // perhaps an error message?
}
}
});
});
});
PHP
Looks like you know what you're doing here. The important thing is to output the appropriate data type.
<?php
$rxdtime=$_GET["rxdtime"];
$txid=$_GET["txid"];
$balance=$_GET["balance"];
$ref=$_GET["ref"];
header('Content-Type: text/plain; charset=utf-8');
// -------- SQL Query -------
// your logic here will vary
try {
// ...
echo 'success';
} catch(PDOException $e) {
echo $e->getMessage();
}
Instead of <a href>, use ajax to pass the values to your php and get the result back-
$.post('updateRCstatus/test.html', { 'rxdtime': <?php ecdho $time ?>, OTHER_PARAMS },
function(data) {
alert(data);
});
I'm trying to test an ajax call on post by doing the following just for testing purposes, but for some reason the call is never successful. I've been searching around and there isn't much that I could find that would explain why this isn't working.
$.ajax({
type: "POST",
url: "file.php",
success: function(data) {
if(data == 'true'){
alert("success!");
}
},
error: function(data) {
alert("Error!");
}});
file.php contains the following:
<?php
return true;
?>
Can someone please point me in the right direction. I realize that this may seem simple but I am stumped. Thank.
return true will make the script exit. You need:
echo 'true';
Firstly check your paths. Is file.php residing in the same folder as the file that your javascript is contained in?
If your path is incorrect, you will get a 404 error printed to your javascript console if you are using chrome.
Also you should change your php to:
<?php
echo 'true';
Once your path is correct and your php is amended you should be good to go.
Have you tried by accessing to the file directly and see if it outputs something?
return true shouldn't be use in that case (or any other, it's better to use exit or die), everything get by a AJAX call is hypertext generated by server side, you should use (as they pointed you before echo 'true';)
You could also try a traditional AJAX call XMLHttpRequest (without JQuery) if problem persists, and then check if there is any problem between the request and server..
EDIT: also, do not check by comparison, just make an alert to 'data' to see what it gets.
In addition to the echo 'true' suggestion, you can also try to alert the actual data that's returned to ajax. That way you can see if you have the proper value/type for your if statement.
success: function(data) {
alert(data);
}
try this, the new ajax syntax
$.ajax({ type: "POST", url: "file.php" }).done(function(resp){
alert(resp);
});
Here is correct way:
$.ajax({
type : "POST",
url : "file.php",
success : function (data) {
/* first thing, check your response length. If you are matching string
if you are using echo 'true'; then it will return 6 length,
Because '' or "" also considering as response. Always use trim function
before using string match.
*/
alert(data.length);
// trim white space from response
if ($.trim(data) == 'true') {
// now it's working :)
alert("success!");
}
},
error : function (data) {
alert("Error!");
}
});
PHP Code:
<?php
echo 'true';
// Not return true, Because ajax return visible things.
// if you will try to echo true; then it will convert client side as '1'
// then you have to match data == 1
?>
I am writing a javascript which will post hostname of the site to a php page and get back response from it, but I don't know how to assign the hostname to adrs in url and not sure that code is correct or not.And this needs to done across server
javascript:
function ursl()
{
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=',
success: function (response)
if (response)=='yes';
{
alert("yes");
}
});
}
track.php
$url=$_GET['adrs'];
$sql="SELECT * FROM website_ad where site='$url'";
$res=mysqli_query($link,$sql);
if(mysqli_num_rows($res)==0)
{
echo"no";
}
else
{
echo"yes";
}
Your ajax function should be written thusly:
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=' + window.location.hostname,
success: function (response) {
if (response === 'yes') {
$.getScript('http://example.com/en/pop.js', function () {
// do anything that relies on this new script loading
});
}
}
});
window.location.hostname will give you the host name. You are passing it to the ajax url by concatenating it. Alternatively, as katana314 points out, you could pass the data in a separate parameter. Your ajax call would then look like this:
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=',
data: {adrs: window.location.hostname},
success: function (response) {
if (response === 'yes') {
$.getScript('http://example.com/en/pop.js', function () {
// do anything that relies on this new script loading
});
}
}
});
I'm not sure what you intend response to be, but this code assumes it is a string and will match true if the string is 'yes'. If response is meant to be something else, you need to set your test accordingly.
$.getScript() will load your external script, but since it's asynchronous you'll have to put any code that is dependent on that in the callback.
In this type of GET request, the variable simply comes after the equals sign in the URL. The most basic way is to write this:
url: 'http://example.com/en/member/track.php?adrs=' + valueToAdd,
Alternatively, JQuery has a more intuitive way of including it.
$.ajax({
url: 'http://example.com/en/member/track.php',
data: { adrs: valueToAdd }
// the rest of the parameters as you had them.
Also note that you can't put a script tag inside a script. You will need some other way to run the Javascript function mentioned; for instance, wrap its contents in a function, load that function first (with a script tag earlier in the HTML), and then call it on success.
And for the final puzzle piece, you can retrieve the current host with window.location.host
You'll need to change this line to look like so:
url: 'http://example.com/en/member/track.php?adrs='+encodeURIComponent(document.URL)
The full success function should look like so:
success: function (response){
if (response==="yes"){
//do your thing here
}
}
That should solve it...
I am very new to ajax and jquery, but I came across a code on the web which I am manipulating to suit my needs.
The only problem is that I want to be able to respond to the ajax from PHP.
This ajax POSTS to a php page (email.php).
How can I make the email.php reply back if the message is sent or if message-limit is exceeded (I limit the nr of messages sent per each user)?
In other words, I want ajax to take a 1 or 0 from the php code, and for example:
if(response==1){ alert("message sent"); } else { alert("Limit exceeded"); }
Here is the last part of the code: (If you need the full code just let me know)
var data_string = $('form#ajax_form').serialize();
$.ajax({
type: "POST",
url: "email.php",
data: data_string,
success: function() {
$('form#ajax_form').slideUp('slow').before('');
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}//end success function
}) //end ajax call
return false;
})
Thanks
The success function of an $.ajax call receives a parameter, usually called data though that's up to you, containing the response, so:
success: function(data) {
// Use the data
}
(It also receives a couple of other parameters if you want them; more in the docs.)
The data parameter's type will vary depending on the content type of the response your PHP page sends. If it sends HTML, data will be a string containing the HTML markup; if your page sends JSON, the data parameter will be the decoded JSON object; if it's XML, data will be an XML document instance.
You can use 1 or 0 if you like (if you do, I'd probably set the content type to "text/plain"), so:
success: function(data) {
if (data === "1") {
// success
}
else if (data === "0") {
// failure
}
else {
// App error, expected "0" or "1"
}
}
...but when I'm responding to Ajax requests, nine times out of ten I send JSON back (so I set the Content-Type header to application/json), because then if I'm using a library like jQuery that understands JSON, I'll get back a nice orderly object that's easy to work with. I'm not a PHP guy, but I believe you'd set the content type via setContentType and use json_encode to encode the data to send back.
In your case, I'd probably reply with:
{"success": "true"}
or
{"success": "false", "errMessage": "You reached the limit."}
so that the server-side code can dictate what error message I show the user. Then your success function would look like this:
success: function(data) {
var msg;
if (typeof data !== "object") {
// Strange, we should have gotten back an object
msg = "Application error";
}
else if (!data.success) {
// `success` is false or missing, grab the error message
// or a fallback if it's missing
msg = data.errMessage || "Request failed, no error given";
}
if (msg) {
// Show the message -- you can use `alert` or whatever
}
}
You must pass an argument to your "success" function.
success: function(data)
{
if(data == '1')
{
$('form#ajax_form').slideUp('slow').before('');
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}
}
And in your php file, you should just echo the response you need
if(mail())
{
echo '1';
}
else
{
echo '0';
}
Anything you echo or return in the php file will be sent back to you jquery post. You should check out this page http://api.jquery.com/jQuery.post/ and think about using JSON formatted variables to return so like if you had this in your email script:
echo '{ "reposonse": "1" }';
This pass a variable called response with a value of 1 back to you jquery script. You could then use an if statement how you described.
just have email.php echo a 0 or 1, and then grab the data in the success event of the ajax object as follows...
$.ajax({
url: 'email.php',
success: function(data) {
if (data=="1"){
...
}else{
...
}
}
});
what you do is, you let your ajax file (email.php) print a 1 if successful and a 0 if not (or whatever else you want)
Then, in your success function, you do something like this:
function(data) {
$('form#ajax_form').slideUp('slow').before('');
if(data==1){ alert("message sent"); } else { alert("Limit exceeded"); }
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}
So you capture the response in the data var of the function. If you a bigger variety in your output, you can set you dataType to "json" and have your php file print a json_encoded string so that you can access your different variables in your response via for example data.success etc.
PHP can only return to AJAX calls, by its output. An AJAX call to a PHP page is essentially the same as a browser requesting for the page.
If your PHP file was something like,
<?php
echo "1";
?>
You would receive the "1" in your JavaScript success callback,
that is,
success: function(data) {
// here data is "1"
}
As an added note, usually AJAX responses are usually done in JSON format. Therefore, you should format your PHP replies in JSON notation.