I have a reference table album_content which has: album_id, content_id, and sort_key. I set it up as an entity with #ManyToOne relations:
/**
* #ManyToOne(targetEntity="Album")
* #JoinColumns({
* #JoinColumn(name="album_id", referencedColumnName="id")
* })
*/
private $albumId;
/**
* #ManyToOne(targetEntity="Content")
* #JoinColumns({
* #JoinColumn(name="content_id", referencedColumnName="id")
* })
*/
private $contentId;
/**
* #Column(name="sort_key", type="integer", nullable=false)
*/
private $sortKey;
Right now Doctrine is complaining No identifier/primary key specified. What's the correct annotation to reference these without adding an extra ID column?
First, you probably shouldn't be naming things $contentId or $albumId, but instead just call them $content and $album.
That said, the quick solution is to add #Id annotations to both of your associations.
The manual goes into further detail about using composite keys in Doctrine 2.
Related
I'm using Doctrine2 inside Symfony and I have the following setup:
An Item class:
/**
* Class Item
*
* #ORM\Table()
* #ORM\Entity(repositoryClass="OneShortly\CommonBundle\Entity\ItemRepository")
*/
class Item
{
/**
* #ORM\ManyToOne(targetEntity="Category")
* #ORM\JoinColumn(name="primaryCategory", referencedColumnName="foreignId")
*/
private $primaryCategory;
}
And a Category class:
/**
* Category
*
* #ORM\Table()
* #ORM\Entity(repositoryClass="OneShortly\CommonBundle\Entity\CategoryRepository")
*/
class Category
{
/**
* #var integer
*
* #ORM\Column(name="foreignId", type="integer", unique=true)
*/
private $foreignId;
}
Now when I do this:
$item = new Item();
$item->setPrimaryCategory($category);
$this->em->persist($item);
$this->em->flush();
I get this error:
[Symfony\Component\Debug\Exception\ContextErrorException] Notice:
Undefined index: foreignId in
home/www/project/vendor/doctrine/orm/lib/Doctrine/ORM/Persisters/BasicEntityPersister.php
line 692
Now, I've been looking at this from all angles and still cannot see what is wrong with this code. Can you help?
After some more digging I figured out myself by using doctrine:schema:validate:
[Mapping] FAIL - The entity-class
'Acme\CommonBundle\Entity\Item' mapping is invalid:
* The referenced column name 'foreignId' has to be a primary key column on the target entity class
'Acme\CommonBundle\Entity\Category'.
[Database] FAIL - The database schema is not in sync with the current
mapping file.
So, I changed the foreign key from foreignId to id (which happens to be the primary key) and it works. I could, of course, just use foreignId as a primary key, but I realized actually I don't need that.
Take a look at http://symfony.com/doc/current/book/doctrine.html#relationship-mapping-metadata.
You should rather have:
/**
* Class Item
*
* #ORM\Table()
* #ORM\Entity(repositoryClass="OneShortly\CommonBundle\Entity\ItemRepository")
*/
class Item
{
/**
* #ORM\ManyToOne(targetEntity="Category", inversedBy="items")
* #ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
private $primaryCategory;
}
and:
/**
* Category
*
* #ORM\Table()
* #ORM\Entity(repositoryClass="OneShortly\CommonBundle\Entity\CategoryRepository")
*/
class Category
{
/**
* #ORM\OneToMany(targetEntity="Item", mappedBy="primaryCategory")
*/
private $items;
}
Forget ID in ORM.
Class Comment
/**
* #var \Caerus\AppBundle\Entity\Users
*
* #ORM\ManyToOne(targetEntity="User" , inversedBy="comment")
*
* #ORM\JoinColumn(name="user_id", referencedColumnName="user_id")
*
*/
protected $user;
Class User
/**
* #var mixed
*
* #ORM\OneToMany(targetEntity="Comment", mappedBy="user")
*/
protected $comment;
Basically quite simple. I need the comments class to have a user_id field which is a direct copy of the original user_id field from the users class.
The error is as following:
[Doctrine\ORM\ORMException] ManyToOne Column name id referenced for relation from Comment towards User does not exist
Why exactly is it still saying doesn't exist and how do I solve that ?
Referenced Column name should be the "id" property of the User class.
/**
* #var \Caerus\AppBundle\Entity\Users
*
* #ORM\ManyToOne(targetEntity="User" , inversedBy="comment")
* #ORM\JoinColumn(name="user_id", referencedColumnName="id")
*
*/
protected $user;
P.S.
I would also name the OneToMany property "comments" as it holds many Comment objects.
"#var \Caerus\AppBundle\Entity\Users" should be ...\User as your class is called User
Running php bin/console doctrine:schema:validate will give you more insight into which entity classes and columns are involved in the error condition.
Also you can use this code:
/**
* #var \Caerus\AppBundle\Entity\Users
*
* #ORM\ManyToOne(targetEntity="User" , inversedBy="comment")
*
* #ORM\JoinColumn(nullable=true , referencedColumnName="variable_id_of_comment")
*/
protected $user;
I have the following property in my User entity to track followers and following. Basically a user can follow other user as well. I have a join column called app_user_follow_user, however I also wanted to add a timestamp of whenever someone follows another user, when did it happen. How can I specify a created timestamp via this ORM?
/**
* #ORM\ManyToMany(targetEntity="User", mappedBy="following")
*/
protected $followers;
/**
* #ORM\ManyToMany(targetEntity="User", inversedBy="followers")
* #ORM\JoinTable(name="app_user_follow_user",
* joinColumns={#ORM\JoinColumn(name="user_id", referencedColumnName="id")},
* inverseJoinColumns={#ORM\JoinColumn(name="follow_user_id", referencedColumnName="id")}
* )
*/
protected $following;
Doctrine ManyToMany relationships are used when your join table has two columns. If you need to add another column you have to convert the relationship to OneToMany on both sides and ManyToOne on the joined entity.
This is entirely untested but it will hopefully give you the gist.
User Entity
/**
* #ORM\OneToMany(targetEntity="AppUserFollowUser", mappedBy="appUser")
*/
protected $followers;
/**
* #ORM\OneToMany(targetEntity="AppUserFollowUser", mappedBy="followUser")
*/
protected $following;
AppUserFollowUser Entity
/**
* #ORM\Table(name = "app_user_follow_user")
*/
class AppUserFollowUser
{
/**
* #ORM\Id
* #ORM\ManyToOne(targetEntity="User", inversedBy="followers")
* #ORM\JoinColumns({
* #ORM\JoinColumn(name="user_id", referencedColumnName="id")
* })
*/
private $appUser;
/**
* #ORM\Id
* #ORM\ManyToOne(targetEntity="User", inversedBy="following")
* #ORM\JoinColumns({
* #ORM\JoinColumn(name="follow_user_id", referencedColumnName="id")
* })
*/
private $followUser;
/**
* #ORM\Column(name="created_date", type="datetime", nullable=false)
*/
private $createdDate;
}
I think that you will have to create a link entity manually (entiy1 onetomany linkEntity manytoone entity2.
Because, the usual link entity are automated and should be as simple and (data less) as possible, so doctrine can take all the controle over it,
imagine you need to get the timestamp, how can you do it on an (none hard coded) entity, you will need a getter, and the annotations are not supposed to contains code.
I am trying to construct an object with two composite foreign keys pointing out to the same object, but they seem to have the same data, like doing the join only on one column, product_id.
class PostpaidProduct extends Product {
/**
* #ManyToOne(targetEntity="Bundle", fetch="EAGER", cascade={"persist"})
* #JoinColumn(name="bundle_voice_id", referencedColumnName="id")
*/
private $bundleVoice;
/**
* #ManyToOne(targetEntity="Bundle", fetch="EAGER", cascade={"persist"})
* #JoinColumn(name="bundle_data_id", referencedColumnName="id")
*/
private $bundleData;
/**
* #OneToMany(targetEntity="BundlePromo", mappedBy="product", fetch="EAGER", cascade={"persist"})
* #JoinColumns({
* #JoinColumn(name="id", referencedColumnName="product_id"),
* #JoinColumn(name="bundle_voice_id", referencedColumnName="bundle_id")
* })
*/
private $bundleVoicePromos;
/**
* #OneToMany(targetEntity="BundlePromo", mappedBy="product", fetch="EAGER", cascade={"persist"})
* #JoinColumns({
* #JoinColumn(name="id", referencedColumnName="product_id"),
* #JoinColumn(name="bundle_data_id", referencedColumnName="bundle_id")
* })
*/
private $bundleDataPromos;
}
What would be wrong with my mapping?
Is it possible to have composite foreign keys but without being primary keys?
I have talked to one of the developers of Doctrine and he said that the #JoinColumns field in #OneToMany relationships is ignored. The alternative would be having just one foreign key and to use matching criterias in an entity method, filtering for the entries needed based on the other key. Another solution would be having repository methods specific for getting these values.
Also, in OneToMany relationships eager fetching does not work, so it does separate queries for all children. So if you have a product with multiple prices, when fetching a product it will do separate queries for fetching the prices.
I'm trying to create a UniqueEntity with 2 fields (both are ManyToOne fields).
The code is as follow:
/*
* #ORM\Table()
* #ORM\Entity
* #ORM\HasLifecycleCallbacks()
* #UniqueEntity(fields={"user", "connect"})
*/
class UserConnect
{
/**
* #var integer $id
*
* #ORM\Column(name="id", type="integer")
* #ORM\Id
* #ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* #var boolean $isLeader
*
* #ORM\Column(name="isLeader", type="boolean")
*/
private $isLeader;
/**
* #var date $joinedDate
*
* #ORM\Column(name="joinedDate", type="date")
*/
private $joinedDate;
/**
* #ORM\ManyToOne(targetEntity="User", inversedBy="userConnects")
*
*/
private $user;
/**
* #ORM\ManyToOne(targetEntity="Connect", inversedBy="userConnects")
*
*/
private $connect;
The goal is to ensure that I've got only one Entity that link a USER with a CONNECT.
Should I write something else in my #UniqueEntity declaration?
I understand you want to get an error only when both user and connect fields for one record are duplicated in other record in the database.
The #UniqueEntity annotation is rightly declared for your purpose (multiple column index) but only will be triggered in the form validation and doesn't affects the DDBB schema.
If you want to add the same check at database level you should use the #UniqueConstraint annotation in the Table() declaration and give a name to the new index. Something like:
/*
* #ORM\Table(uniqueConstraints={#ORM\UniqueConstraint(name="IDX_USER_CONNECT", columns={"user_id", "connect_id"})})
* #ORM\Entity
* #ORM\HasLifecycleCallbacks()
* #UniqueEntity(fields={"user", "connect"})
*/
class UserConnect
{
In the other hand, if you declare #ORM\Column(unique=true) in each attribute you will get a very different behavior, it won't be a multiple column index but you will have two independent unique columns, if you enter twice the same user_id you will get an error independently of the connect_id value, and the same will happens if you enter twice the same connect_id value.
This works:
/**
* State
*
* #ORM\Table(
* name="general.states",
* uniqueConstraints={
* #ORM\UniqueConstraint(name="states_country_name_code_key", columns={"idcountry", "name","code"}),
* })
* #ORM\Entity(repositoryClass="Fluency\Bundle\GeneralBundle\Entity\Repository\StateRepository")
*/
class State
{.......
Taken from an entity on my system. This way affects Database schema. See where i put #\ORM\UniqueConstraint annotation. Sorry #estopero... next time i must read first the other answers.
you should add the unique declaration in your attributes annotations too.
/**
* #ORM\ManyToOne(targetEntity="User", inversedBy="userConnects")
* #ORM\Column(unique=true)
*/
private $user;
/**
* #ORM\ManyToOne(targetEntity="Connect", inversedBy="userConnects")
* #ORM\Column(unique=true)
*/
private $connect;
See this symfony doc and this StackOverflow answer.