I'm trying to write a page that allows users to type a post and, when submitted, opens a new page with the post on it. This means that the post must be inputted in a database first before it can be retrieved on another page. This is similar to when someone asks a question on stackoverflow. the question appears on a new page and the page is given a unique id, except i would like this unique id to be in a get variable.
HTML of current page (ask.php):
<form method=POST' action='ask.php?q<php echo $id ?>'>
<input type='text' id='post'>
<input type='submit' value='submit' name='submit'>
PHP:
$post=$_POST['post'];
//then run query to input data into database
}
$result=mysql_query("SELECT * FROM questions WHERE user='$user' AND time='$time'");
while ($row = mysql_fetch_assoc($result)){
$id=$row['id'];
}
ask_action.php:
<?php header("Location: http://localhost/biology/question.php?q=$id"); ?>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
</head>
<body>
<?php
include '../connect.php';
if (isset($_POST['questionSubmit'])){
$question=mysql_real_escape_string($_POST['question']);
$detail=mysql_real_escape_string($_POST['detail']);
$date=date("d M Y");
$time=time();
$user=$_SESSION['id'];
$put=mysql_query("INSERT INTO questions VALUES ('','$question','$detail','$date','$time','$user','biology','0')");
$id=mysql_insert_id();
}
?>
</body>
</html>
If you don't want the "ask" page to be on the same page that you view the post, you can split this in to three pages.
Page 1:
The page with the form where people writes their post and submits. Page 2 will be in the action part of the form.
Page 2:
The page that retrieves the POST data. Here you'll verify all the information and submit it to the database. You then retrieve the insert id and redirect the user to the page where you want to display the results. You use the id from the insert query in the redirecting.
Page 3:
Where the users see the submitted information.
I notice that you've tried this approached somehow, but you've got a few mistakes that needs correcting. First of all your ask.php page needs improvement.
You're missing one apostrophe ( ' ) before the POST in method, and your action needs correcting. Remember that the form action is supposed to go to the page that verifies and handles the data from the form. In this case it would be the *ask_action.php* page. Therefore the ask.php page should be like this:
<form method='POST' action='ask_action.php'>
<input type='text' name='question' />
<input type='text' name='detail' />
<input type='submit'> value='submit' name='submit' />
</form>
*ask_action.php* will handle the data, verify it and redirect to the page that views it. There is no need for html on the page that verifies it.
<?php
include('../connect.php'); // your database connection etc.
if(isset($_POST['submit'])) { // only react if the submit button is pressed
$question = mysql_real_escape_string($_POST['question']);
$detail = mysql_real_escape_string($_POST['detail']);
$date = date("d M Y");
$time = time();
$user = $_SESSION['id'];
mysql_query("INSERT INTO questions VALUES('', '$question', '$date', '$time', '$user', 'biology', 0)");
$id = mysql_insert_id();
header("Location: view_page.php?id=$id");
} else {
echo "Nothing submitted.";
}
?>
Then you'd have a third page where you display the data that you get from the database. If you notice the header function that I've used, it's redirecting the user to view_page.php. This is where you'll display the data by the id number that is supplied. To get the id number you simply use $id = $_GET['id'];.
I also noticed that you're using both time() and date("d M y"). That is not necessary. If you read about time on php.net you'll see that the time function generates the current unix timestamp. You can use that to output a date in the way that you want to. For instance: if you'd like to display both the date and time that the question was submitted you can use this date("d M y H:i", $time) where $time is the time-column in your database table.
This can all be combined in one single page, but I kept them separated so it's easier for you to see the difference.
The first problem here is in your opening form tag. It should read:
<form method='post' action='ask.php?q=<?php echo $id ?>'>
or
<form method='post' action='ask.php?q=<?= $id ?>'>
Your input tag should read:
<input type='text' name='post' id='post' />
I think the functionality you're looking for is provided by mysql_insert_id, as long as your id column is auto-incremented. If you're not auto-incrementing your id column, could you provide more info about your db table?
You have a few problems here. First and foremost you NEED to synthesize your incoming code with something like mysql_escape_string($_POST). You also need to name your text field, currently you're trying to pull it based on ID and that won't work
Change: <input type='text' id='post'> into <input type='text' name='post' id='post'>
Your order is backwards as well. Without using AJAX the best way to do this is to load your posts & id's using PHP at the top of the page, then have the actual writing to the database happen on the resulting page.
On your "submit" page, you need to have the PHP code do the insert into the database then retrieve the ID of that new post using mysql_insert_id. Then that page could redirect the user to the appropriate page using the just-retrieved ID as a GET parameter (using the header function)
Related
First of all I'll be sincere, I'm a student and I've been asked to do a task that seems impossible to me. I don't like asking questions because generally speaking I've always been able to fix my coding issues just by searching and learning, but this is the first time I've ever been on this possition.
I need to create a php file that contains a form with two inputs that the user fills. Once he clicks submit the website will show on top of it the two values. Till here I haven't had an issue, but here's the problem, the next time the user sends another submission, instead of clearing the last 2 values and showing 2 new ones, now there needs to be 4 values showing.
I know this is possible to do through JSON, the use of sessions, Ajax, hidden inputs or using another file (this last one is what I would decide to use if I could), but the teacher says we gotta do it on the same html file without the use of any of the methods listed earlier. He says it can be done through an Array that stores the data, but as I'll show in my example, when I do that the moment the user clicks submit the array values are erased and created from zero. I know the most logical thing to do is asking him, but I've already done that 4 times and he literally refuses to help me, so I really don't know what to do, other than asking here. I should point out that the answer has to be server side, because the subject is "Server-Side Programming".
Thank you for your help and sorry beforehand because I'm sure this will end up being a stupid question that can be easily answered.
For the sake of simplicity I erased everything that has to do with formatting. This is the code:
<?php
if (isset($_POST['activity']) && isset($_POST['time'])){
$agenda = array();
$activity = $_POST['activity'];
$time = $_POST['time'];
$text = $activity." ".$time;
array_push($agenda, $text);
foreach ($agenda as $arrayData){
print implode('", "', $agenda);
}
}
?>
<html>
<head>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="POST">
<label for="Activity">Activity</label><br>
<input name= "activity" type="text"><br><br>
<label for="Time">Time</label><br>
<input name= "time" type="time"><br><br>
<input type="submit">
</form>
</body>
</html>
Your question was not very clear to be honest but I might have gotten something going for you.
<?php
$formaction = $_SERVER['PHP_SELF'];
if (isset($_POST['activity']) && isset($_POST['time'])){
$agenda = array();
//if the parameter was passed in the action url
if(isset($_GET['agenda'])) {
$agenda = explode(", ", $_GET['agenda']);
}
//set activity time
$text = $_POST['activity']." ".$_POST['time'];
//push into existing array the new values
array_push($agenda, $text);
//print everything
print implode(", ", $agenda);
//update the form action variable
$formaction = $_SERVER['PHP_SELF'] . "?agenda=" . implode(", ", $agenda);
}
?>
<html>
<head>
</head>
<body>
<form action="<?php echo $formaction; ?>" method="POST">
<label for="Activity">Activity</label><br>
<input name= "activity" type="text"><br><br>
<label for="Time">Time</label><br>
<input name= "time" type="time"><br><br>
<input type="submit">
</form>
</body>
</html>
SUMMARY
Since you cant save the posted values into SESSION vars or HIDDEN input, the next best thing would be to append the previous results of the posted form into the form's action url.
When the form is posted, we verify if the query string agenda exists, if it does we explode it into an array called $agenda. We then concatenate the $_POST['activity'] and $_POST['time'] values and push it to the $agenda array. We then PRINT the array $agenda and update the $formaction variable to contain the new values that were added to the array.
In the HTML section we then set the <form action="" to be <form action="<?php echo $formaction; ?>
I am creating a script and I came across a problem. I am having to use $_POST and $_GET on the same page, which I don't think makes sense.
I get the value for user id using the GET method from another page through a link and I have to input data from a form into the database in the current page.
CODE SNIPPET 1 : (GET METHOD on page page.php)
echo "<td align=center width=90px height=10px><strong><a href='sessions.php?id=".$userid."' style=text-decoration:none><font color='red' size='5pt'>$i</font></a></strong></td>";
CODE SNIPPET 2 : (POST METHOD on sessions.php going to same page sessions.php)
if($_SERVER["REQUEST_METHOD"]=="GET"){
$id=$_GET["id"];
if($_SERVER["REQUEST_METHOD"]=="POST")
$suggestions=$_POST["suggest"];
Can I get the userid from the url and the POST the values from the form in the same page?
If not, is there a way I can do this better?
You can use one hidden input field in your form in session.php and store $_GET['id'] in value attribute of that input field and it will be pass with your form submit to session.php <input type="hidden" name="id" value="<?php echo $_GET['id']">
you can get the value from GET by adding the following code in sesssion.php
$id="";
if (isset($_GET['id'])) {
$id=$_GET['id'];
}else{
$id="";
}
then in the form located at session.php place a input field like following
<input type="hidden" value="<?php echo $_GET['id']" name="suggest">
then add the following code in the same page
if($_SERVER["REQUEST_METHOD"]=="POST"){
if($id){
$suggestions=$_POST["suggest"];
// run your sql query for insert.
}
}
I got a code here that if I refreshed the page it automaticaly save the data....can anyone help me that it will only save if the submit button is clicked.
current code:
<?php
ob_start();
?>
<html>
<head>
<title>test</title>
</head>
<body>
<?php
include('include/connect.php');
$query = mysql_query("SELECT DISTINCT count(batchcode) as batchcode1 FROM batchcodes");
while( $rows = mysql_fetch_array($query)) {
$code=$rows['batchcode1'];
}
if(isset($_POST['save'])){
$var = $code+1;
$sql = mysql_query("INSERT INTO batchcodes(batchcode) VALUES (". $var .")");
}
?>
<form method="post" action="index.php" >
<input type="text" value="batch<?php echo $var; ?>" />
<input type="submit" name="save">
</form>
</body>
</html>
The code you show is from your "handling" page. That page handles the post, it checks if there was a parameter "save" and if so, it saves.
If the user refreshes that page, he visits the page again, sending again a "save" parameter, so the INSERT is done twice.
To avoid this, you should use the POST-REDIRECT-GET model, where your handling page gets the data, saves it, and then redirects the user to a "GET" page (no post, no insert) that just shows the data. If the user then hits refresh, he only refreshes the "GET" page.
Offcourse, a user can always keep using the BACK button to go to the actual insert page. His browser will warn him "you are resubmitting form data...", but if he chooses to, he can. If you really want to handle this, you can work with session keys: have an extra field "submitID" on your form, and on INSERT, first check if that ID was already "used". You'll need an extra table/column "submitID" somewhere to ensure a form can only be submitted once.
The problem is the form is getting submitted again, you can make header redirect to this same page,
header("location: index.php) after updating your database and this will solve your issue.
Create one button in html
<input type="submit" name="submit"/>
In php Code, you can write like
<?php
if(isset($_POST['submit']))
{
//place your total code here
}
?>
As soon as the form is submitted once it has got the $_POST-Array in the site request. When you reload the page after the first submit, it will always send the data again.
You got multiple possibilities to resolve this problem:
1)
Reload the page after the execution of the PHP code. To do so put the PHP code at the top of the page (before writing anything in HTML) and reload the page after the execution of the query:
if(isset($_POST["save"])) {
/* MySQL Query */
$back = $_SERVER['HTTP_REFERER'] ; // the site who called this site
header("Location: $back") ; // Link back to this site
}
2)
Personally I prefer to execute my PHP scripts with an Ajax call, which would look as follows in jQuery.
function ajaxCall()
{
$.ajax({
type: "POST",
url: "handler.php",
data: {save: 1, textfield: $("#textfield").val()}
}) ;
}
Don't forget, that the forms action isn't the redirect to another site anymore, it is the call to this function ajaxCall. If you want more fields to submit, have a look at the serialize-function. The handler.php-file contains only your php-Code:
<?php
ob_start();
include('include/connect.php');
$query = mysql_query("SELECT DISTINCT count(batchcode) as batchcode1 FROM batchcodes");
while( $rows = mysql_fetch_array($query)) {
$code=$rows['batchcode1'];
}
if(isset($_POST['save'])){
$var = $code+1;
$sql = mysql_query("INSERT INTO batchcodes(batchcode) VALUES (". $var .")");
}
exit(0) ;
?>
In the ajax function you could also handle what happens when the call is successful (e.g. redirect). Have a look at the $.ajax-reference of jQuery. If you want you could also use ajax without jQuery.
3)
You could also make your page in action similiar to the handler.php in the second possibility.
<form action="handler.php" method="POST"></form>
In this case you had to replace the exit-statement with the $back and header-call in possibility 1 (similar to the response of Konerak).
I am trying to create a multi steps form where user will fill the form on page1.php and by submitting can go to page2.php to the next 'form'. What would be the easiest way?
Here is my code:
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
?>
<form id="pdf" method="post">
New project name:<input type="text" name="pr_name" placeholder="new project name..."><br/>
New project end date:<input id="datepicker" type="text" name="pr_end" placeholder="yyyy-mm-dd..."><br/>
<textarea class="ckeditor" name="pagecontent" id="pagecontent"></textarea>
<?php
if ($_POST["pr_name"]!="")
{
// data collection
$prname = $_POST["pr_name"];
$prend = $_POST["pr_end"];
$prmenu = "pdf";
$prcontent = $_POST["pagecontent"];
//SQL INSERT with error checking for test
$stmt = $pdo->prepare("INSERT INTO projects (prname, enddate, sel, content) VALUES(?,?,?,?)");
if (!$stmt) echo "\nPDO::errorInfo():\n";
$stmt->execute(array($prname,$prend, $prmenu, $prcontent));
}
// somehow I need to check this
if (data inserted ok) {
header("Location: pr-pdf2.php");
}
}
$sbmt_caption = "continue ->";
?>
<input id="submitButton" name="submit_name" type="submit" value="<?php echo $sbmt_caption?>"/>
</form>
I have changed following Marc advise, but I don't know how to check if the SQL INSERT was OK.
Could give someone give me some hint on this?
thanks in advance
Andras
the solution as I could not answer to my question (timed out:):
Here is my final code, can be a little bit simple but it works and there are possibilities to check and upgrade later. Thanks to everyone especially Marc.
<form id="pdf" method="post" action="pr-pdf1.php">
New project name:<input type="text" name="pr_name" placeholder="new project name..."><br/>
Email subject:<input type="text" name="pr_subject" placeholder="must be filled..."><br/>
New project end date:<input id="datepicker" type="text" name="pr_end" placeholder="yyyy-mm-dd..."><br/>
<textarea class="ckeditor" name="pagecontent" id="pagecontent"></textarea>
<?php
include_once "ckeditor/ckeditor.php";
$CKEditor = new CKEditor();
$CKEditor->basePath = 'ckeditor/';
// Set global configuration (will be used by all instances of CKEditor).
$CKEditor->config['width'] = 600;
// Change default textarea attributes
$CKEditor->textareaAttributes = array(“cols” => 80, “rows” => 10);
$CKEditor->replace("pagecontent");
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
// data collection
$prname = $_POST["pr_name"];
$prsubject = $_POST["pr_subject"];
$prend = $_POST["pr_end"];
$prmenu = "pdf";
$prcontent = $_POST["pagecontent"];
//SQL INSERT with error checking for test
$stmt = $pdo->prepare("INSERT INTO projects (prname, subject, enddate, sel, content) VALUES(?,?,?,?,?)");
// error checking
if (!$stmt) echo "\nPDO::errorInfo():\n";
// SQL command check...
if ($stmt->execute(array($prname, $prsubject, $prend, $prmenu, $prcontent))){
header("Location: pr-pdf2.php");
}
else{
echo"Try again because of the SQL INSERT failing...";
};
}
$sbmt_caption = "continue ->";
?>
<input id="submitButton" name="submit_name" type="submit" value="<?php echo $sbmt_caption?>"/>
</form>
Add the attribute action with the url you'd like to go to. In this case it'd be
<form id="pdf" method="post" action="page2.php">
EDIT: i missed you saying this method doesn't work. What part of it doesn't work?
You should keep the action to the same script, so the POST action is still performed and then redirect with header("Location: page2.php"); when the processing is done.
A basic structure like this will do it:
form1.php:
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
... process form data here ...
if (form data ok) {
... insert into database ...
}
if (data inserted ok) {
header("Location: form2.php");
}
}
?>
... display page #1 form here ...
And then the same basic structure for each subsequent page. Always submit the form back to the page it came from, and redirect to the next page if everything's ok.
You're probably better off separating the php code from the form. Put the php code in a file called submit.php, set the form action equal to submit.php, and then add the line header('Location: whateverurl.com'); to your code.
The easiest way is to post it to form2.php by giving the form the attribute action="page2.php". But there's a risk in that. It means that form2 must parse the posted data of form1. Also, if the data is wrong (verification) form1 must be shown instead of form2. This will make your code over complicated and creates dependencies between the two forms.
So the better solution (and quite easy as well) is to implement the post-redirect-get pattern.
You post to form1, verify all data and store it. If the data is ok, you redirect to form2. If the data is wrong, you just show form1 again.
Redirecting is done by a header:
// Officially you'll need a full url in this header, but relative paths
// are accepted by all browsers.
header('Location: form2.php');
Save already posted fields in hidden input fields, but don't forget to validate them every time user submits another step of the form as the user may change hidden inputs in source code.
<input type="hidden" name"some_name" value="submitted_value"/>
There are several ways handling the submitted data while jumping between steps.
You will find your reasons for /against writing data to session, database, whatever... after each step or not.
I did following approach:
The form includes always a complete set of input elements, but on page #1 the step-2-elements are hidden ... and other way round.
I built a 6-step-wizard this way. One large template, some JS /Ajax for validating input, additional hidden inputs that hold current step-ID and PHP deciding, which fields to show or hide.
The benfit in my opinion: Data can easily be saved completely, as soon as input is alright and complete. No garbage handling, if users abort after step 1.
I would store it all in a session array (or sub array)
a really rough example where I'm saving all the form names to an array (to be checked later of course):
<?
foreach($_POST as $k => $v){
$session['register'][$k]=$v;}
?>
I've got the following php code printing out the contents of a SQL table.
$query="select * from TABLE";
$rt=mysql_query($query);
echo mysql_error();
mysql_close();
?>
<i>Name, Message, Type, Lat, Lng, File </i><br/><br/>
<?php
while($nt=mysql_fetch_array($rt)){
if($nt[name] != null){
echo "$nt[id] $nt[name] $nt[message] $nt[type] $nt[lat] $nt[lng] $nt[file]";
}
}
?>
How would I implement a button so for each "row" if the button is clicked on that row it'll submit the information of that row to another php file?
I want it looking something like...
details details2 details3 BUTTON
details4 details5 details6 BUTTON
details7 details8 details9 BUTTON
details10 details11 details12 BUTTON
Where if BUTTON was hit on row 1 details1,2,3 would be sent to a php file, on row 2 detals 4,5,6 would be sent etc. How would I do this?
Thanks.
it's going to be something like that, depending on the data you need to send:
while($nt = mysql_fetch_array($rt)) {
if($nt[name] != null){
echo "$nt[id] $nt[name] $nt[message] $nt[type] $nt[lat] $nt[lng] $nt[file] ".'send request<br/>';
}
}
You can either use GET method and send a query string to the second php page and receive the variables there, like
next.php?variable1=value1&variable2=value2&...
or use POST method by making a hidden form for each row and assign a hidden field for each variable you want to send.
<form method="post" action"next.php">
<input type="hidden" name="variable1" value="value1" />
<input type="hidden" name="variable2" value="value2" />
.
.
.
</form>
or instead of sending all the values, just send the row ID (if any) using any of these two methods and run another query in next.php to get the information you need from database.
Instead of submitting the entire data, just send the ID and fetch the results from the database in the other script. If you want to have an input button, you can do
<form action="/other-script.php" method="GET">
<?php printf('<input type="submit" name="id" value="%s" />', $nt["id"]); ?>
</form>
but you could also just add a link, e.g.
printf('Submit ID', $nt["id"]);
If you really want to send the entire row values over again, you have to make them into form inputs. In that case, I'd send them via POST though.