require_once to global scope within a function - php

It seems that if require_once is called within function, the included file doesn't extend the global variable scope. How to require_once a file to global scope from within a function?
What I'm trying to do is some dynamic module loader:
function projects_init()
{
...
foreach ($projects as $p) {
require_once($p['PHPFile']);
$init_func = $p['init'];
if ($init_func)
$init_func();
}
}
If it is not possible to use require_once that way, what is the simplest solution for this? (Please no heavy frameworks.)
EDIT: it should also work for PHP 5.2.

To summarize all the information:
functions are not an issue, they will be global anyway this way
for global variables, there are 2 options:
declare them as global in the included file
declare them as global in that function (projects_init() in my case)

The above answer is right, you can use global to get what you need.
In the included file just declare the variables global at the beginning of the file, this way the code will run in the function scope but it will change the global variables(yes, you have to be careful and declare everything you need to change as global but it should work), example:
function a() {
require_once("a.php");
}
a();
echo $globalVariable;
and in the a.php file:
global $globalVariable;
$globalVariable="text";

Functions are not an issue (ref):
All functions and classes in PHP have the global scope - they can be called outside a function even if they were defined inside and vice versa.
About global variables: As in an existing question regarding the scope of require and the like, the scope is defined where the use is. If you need something else, there are numerous answers (my take) that show how to deal with global variables, most making use of get_defined_vars.

You can use global to put a variable in the global scope.
http://php.net/manual/en/language.variables.scope.php

Related

Can global variables be created with the keyword global and through a superglobal variable within a function in PHP?

I have heard using global variables is not good, however I am just trying to understand how the PHP language works. I am a beginner in the coding world.
Why can global variables be created within functions? Whether it is through the use of the global keyword or through a superglobal variable. I thought these two actions were used to access global variables in a function. I thought the only way you can create a global variable is to create it outside a function; in the global scope. I have looked at many different websites including w3schools.com and php.net
This is just some simple code I created to try and understand the way global variables work with functions:
<?php
function sample1() {
global $a;
echo $a = "this ";
}
sample1();
function sample2() {
echo $GLOBALS['$b'] = "is ";
}
sample2();
function sample3() {
global $c;
$c = "an ";
}
sample3();
echo $c;
function sample4() {
$GLOBALS['$d'] = "example ";
}
sample4();
echo $GLOBALS['$d'];
?>
This is the result of the code:
this is an example
All of the code works, but I don't understand how I created a global variable on any of these blocks of code? The global variables were not created outside of the functions. How can they be created inside of a function? What am I missing? Any response is appreciated - If possible, please keep the answer simple - I would like to discuss this further in the comment section, because I'm sure I will have follow up questions - Thank you
Variables can be created in the global scope in the two ways you just did - there's nothing saying that a function can't create (or change) a variable in the global scope - WHEN you explicitly ask for it through $GLOBALS or the global keyword.
The issue is that your belief "I thought the only way you can create a global variable is to create it outside a function; in the global scope." is not an exact statement. When you're using $GLOBALS and global, you're referring to the global scope. You're introducing a reference to the global scope inside your function.
With global you're in effect linking the local reference to the global reference, while with $GLOBALS you're explicitly referencing the global scope (which internally inside PHP can be introduced to the local scope in the same way).
In that case you're explicitly saying "I want this variable to be available in the global scope, make it so!" and PHP does what you're asking it to. This behaviour differ between languages, but as you've discovered for PHP, it's allowed.
It's not something I would recommend using in any way - it makes your code very hard to follow and argue around, so consider it an esoteric detail.

Defining a global variable, and including functions that require it?

I have six functions that require a global variable. In an attempt to reduce redundancy, I wrote a new function that is triggered rather than triggering all six. This one function has a global $var that is required by the other functions.
So, it looks like this
function one_function_for_the_rest() {
global $importantVar;
functionOne();
functionTwo();
functionThree();
}
but the global variable is not being seen by the called functions. Am I doing this incorrectly, or is this a limitation I was not aware of?
You're not doing it correctly as the variable is defined when on_function_for... is called. An easier way for this would be just to have $importantVar; at the start of the code.
Or wrap your functions inside a class and put the variable inside the class.
e: so basically do : function myFunc($important) { stuff } and when calling the function do myFunc($importantVar)
example :
$asd = "lol";
class myclass {
public function lol($asd) {
echo $asd;
}
}
$obj = new myclass;
$obj->lol($asd);
You're not doing it correctly. Each function either needs to use the global scope identifier, like global $importantVar;, or have $importantVar passed as a parameter. Otherwise, the other functions don't have $importantVar in their respective scopes.
Simply calling a function from within one_function_for_the_rest does not tell that other function anything about global variables or variables used in one_function_for_the_rest. In technical terms, your function calls do not bring $importantVar into the respective scopes of functionOne, functionTwo, or functionThree.
PHP does not have the same scoping rules as most other languages have. That is the downside to not having to declare variables with var as in JavaScript or other similar constructs.
Basically in PHP, every function used is only available in that function. There are three exceptions:
The global keyword
The $this variable inside objects. This one is also "magic" as it's also available inside anonymous functions defined inside a class.
When declaring an anonymous functions you can bind variables to it using use.

PHP set global variable as handle for class

For some reason, when defining:
function __construct() {
if(!isset($_GLOBALS["className"])) {
$_GLOBALS["className"] = new className;
}
return true;
}
$_GLOBALS["className"]->classMethod();
PHP for some reason states that $_GLOBALS["className"] is undefined.
Oh, and the same also occurs even if I set the global value to something else, from within that class. I can test the value of the global through the construct or some other method, but not outside - it seems that the global is lost outside the class for some reason.
Is there a way to retain the global after declaring it from within an external class?
Any help is sincerely appreciated!
You want to use $GLOBALS and not $_GLOBALS:
http://php.net/manual/en/reserved.variables.globals.php
$_GLOBALS will just be available in your function scope.

Using require/require_once() in a functions file

my functions.php file is just a placeholder for many different functions. I have another file settings.php that I use to store different settings. Some of the functions in functions.php will need to access some of the variables in settings.php, so I tried:
require("settings.php")
on top of the functions.php file, but that does not seem to give my functions access to the variable in settings.php. I need to put require("settings.php") in every function separately.
Is there a way I can declare the variables in settings.php to be accessible globally to all functions defined in functions.php?
Thank you,
You need to modify your functions in functions.php to use global variables defined in settings.php.
Inside settings.php;
$var1 = "something";
$var2 = "something else";
By using the global keyword:
function funcName() {
global $var1;
global $var2;
// Rest of the function...
}
Or more preferably, using the $GLOBALS[] superglobal array. Any variables declared at global scope, like I assume your settings.php vars are, will be included as array keys in $GLOBALS[]. It's a little better for readability than using the global keyword inside each function.
function funcName() {
$y = $GLOBALS['var1'];
$x = $GLOBALS['var2'];
// Etc...
}
Although you've set these variables in your settings.php file, when you try to reference them in your functions it won't work. This is because variables in functions a locally scoped to the function.
To access these global variables you need to use the global keyword to bring your global variables into scope.
For example:
// Declared in settings.php
$x = 1234;
// One of your functions
function MyFunc()
{
global $x;
DoSomething($x);
}
You need to do this for every function where $x is accessed.
For more information see:
Variable scope - php.net docs
I do not know the details of your issue, but you may wish to use require_once() within each function. This seems to be better idea than using some global variables.
You're thinking global variables.
However that's not the best way to go.
Can you perhaps create a class?
class SomeClass
{
private $settings;
function __construct()
{
require_once($settings);
$this->settings = $variable(s) from settings file
}
function some_function()
{
print($this->settings['something']);
}
}

PHP variable scope with nested include returned by function

Thanks in advance for any help. :)
Ok, here's my problem.
Simplified version of the code:
global space with include file
include file where $var is defined and function is called that returns an include statement
include file returned by function and where $var is no longer accessible
Why is $var no longer accessible?
I suspect it has to do with the function or maybe I am missing something else.
The function is like so:
function blah() {
return include_once 'filename.php';
}
Works as designed. Think of the code as if the includes weren't there: You're inside a function, which has its own scope. Global variables are not accessible there.
Your options:
Pass the variable as a reference to blah(&$variable)
Import the variable from global space using global $varname
If you're on PHP 5.3, use the new closure feature
Use a fancy OOP construct like Static classes, Singletons or Dependency Injection (probably overkill)

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