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using php include in jquery
(2 answers)
Closed 9 years ago.
My problem is that I need to include a PHP file inside a DIV when a button is pressed without the page reloading.
There is even more explanation in the 'Jsfiddle' file.
Below is an included Jsfiddle document.
http://jsfiddle.net/jjygp/5/
Thanks for your time. I am more than happy to provide any information upon request.
See here for your updated jsfiddle
You had marked the change button with a name of Change but were trying to select it with an id of change. Also, you had not told jsfiddle to include jQuery.
Try the following:
<button name="Change" id="Change">Change Div</button>
You are specifying a click function on an id, but no id is set on the button.
You can try with load() function in jquery
http://api.jquery.com/load/
PHP is a server-side script language, which will be executed before a JavaScript script did.
Therefore, you cannot use .load() to execute a PHP code, however, you may try .ajax() to create an AJAX request to the server which can implement the PHP code.
Please see http://api.jquery.com/jQuery.ajax/ if you have trouble on using .ajax().
Note: in .ajax() method, there is a setting called beforeSend, which "can be used to modify the jqXHR (in jQuery 1.4.x, XMLHTTPRequest) object before it is sent". Hope this method helps you in any way.
Then, your JavaScript code will be like this:
$(document).ready(function(){
$("#Change").click(function(){
//doing AJAX request
$.ajax({
url:"include/start10.php",
beforeSend:function(){
$('#myDiv').fadeOut('slow');
},
success:function(data){
// do something with the return data if you have
// the return data could be a plain-text, or HTML, or JSON, or JSONP, depends on your needs, if you do ha
$('#myDiv').fadeIn('slow');
}
});
});
});
You cannot include PHP file with AJAX, but instead the response of the AJAX server-side script, which is the PHP (which has the same effect).
Loading...
The JS file (code):
function ajaxalizeDiv()
{
$.ajax({
type: "get",
url: "/path/to/the/php/you/want/to/include",
data: {
// Anything in json format you may want to include
id: myvarwithid, // descriptive example
action: "read" // descriptive example
},
dataType: "json",
success: onAjax
});
}
function onAjax(res)
{
if(!res || !res.text)
return;
$("#mydiv").html(res.text);
}
And here goes the PHP file:
<?php
$id = (int) #$_GET['id']; // same as in data part of ajax query request
$action = #$_GET['action']; // same as in data part of ajax query request
$text = 'click me';
// Note this is short example you may want to echo instead of die
// You may use not JSON, but raw text. However, JSON is more human-friendy (readable)
// and easy to maintain.
// Note also the array keys are used in the onAjax function form res (response).
die(json_encode(array('text' => $text /* and anything else you want */)));
?>
Related
I've recently changed my searching page to a searchable datatable page due to my employer's request for easier data management. The problem is that it is taking too long to load.
I'm wondering it there is a way to only load like a portion of the table and finish loading the page first. Then finish off loading the rest of the table after that, e.g. while the user actually attempt to search for the data.
This was requested because the user might want to navigate to other parts of the page instead of using the datatable.
Extra info : The page is in .php and the data is loaded using php do-while loop. Maybe we can do a workaround using php functions?
Using the AJAX method recommended in the comments, the following is similar to how you could handle the page-load. You would need the jQuery library for the below.
Initial page
<script type="text/javascript">
// when the page is done loading,
// let's send a call to load more data
$(document).ready(function(){
myFunction();
});
// function to handle AJAX request to gather data
function myFunction(){
$.ajax({
type: "POST",
url: "./linkToMyPHP.php?loadData=1",
success: function(data){
// handle the data using the "data" variable
}
});
}
</script>
AJAX Page
<?php
if(isset($_GET["loadData"])){
// call query here and echo information
}
It may be recommended, to actually use a PHP function called json_encode() to echo back the information from your AJAX page in JSON form. This would allow you to transmit an array of information, instead of raw data. You would then need to update your AJAX request function similar to below.
$.ajax({
type: "POST",
url: "./linkToMyPHP.php?loadData=1",
dataType: "json",
success: function(data){
$("#myDivToChange").html(data);
}
});
You can read up on JSON at this highly rated question.
I know this has been covered a few times, but I'm completely a noob when it comes to javascript so I have no idea what I'm doing. I am running a javascript that sends variables to a php file and that info is ajaxed into the current page using innerhtml. Here is that part of the code...
function givingHistory(dyear,did)
{
var divname="giving" + dyear;
$.ajax({
url: 'finance/givinghistory.php',
type: 'POST',
data: {
year: dyear,
id: did
},
success: function(givedata) {
document.getElementById(divname).innerHTML = givedata;
}
});
}
</script>
In the givedata function response from the php file there is a call to another javascript function that is already loaded in my common .js file (so both javascript functions are loaded when the page loads). How do I get the onClick that is added via innerhtml to work? Inside the php file, I check to see if id = a php session variable. If it does it spits out the text that includes the onClick.
If you use a specific id/class/identifier when the page loads in the $('*') function then the action will only bind to that. To get the action bind to anything ever try using $(document).on('click', **selector**, function() {});.
Previously there was bind/live that bound to elements as and when but on is the function now.
Also why are you mixing the $.ajax (jQuery) with document.getElementById(divname).innerHTML (regular javascript)? If you are already using jQuery you could just use $('#'+divname).html(blahbahblah);
i am trying to get a button on my page which will eventually be a delete button to work. However because it is a <li> element and not your average submit button with a form etc... i have to use ajax to send all the variables to be processed, at the moment i just want them to be in a state where they can be processed, but at the moment my script doesn't seem to return any value like i want it to and output them.
Hopefully from the code below you will see what i mean, all i need it to do at the moment is just select all the values from the checkboxes which are cehcked and send it to the mail_trash.php, and then just send it back and output the array, just so i can see it is selecting the proper values etc... The actual delete php code is already written and working, this is just to check the Ajax.
Here is the javascript and ajax
<script>
$("document").ready(function (){
$("li.trash").click(function(e){
var db = $(':checkbox:checked').map(function(i,n) {
return $(n).val();
}).get(); //get converts it to an array
if(db.length == 0) {
db = "none";
}
$.ajax({
type: "GET",
url: "mail_trash.php",
data: {'db[]':db },
dataType: "json",
statusCode: {
200: function (response) {
$("#mail_header_name").html(response.mess_id);
}
}
});
});
});
</script>
And here is the script for the mail_trash.php
<?php
include 'connect_to_mysql.php';
$mess_id = $_GET["db"];
echo json_encode($mess_id);
?>
And just to check things the button
<li><a class="trash" href=""> </a></li>
Thank you so much for your help, this has been bugging me for the last couple of hours.
It's not li.trash. It's a.trash because trash is a class of the a element. As such the first three lines of the js should be:
<script>
$("document").ready(function (){
$("a.trash").click(function(e){
and then so on with the rest of you code. I haven't checked the rest of your code necessarily, although I am pretty iffy about $(':checkbox:checked') as I don't think that's correct jquery.... To start off, I'd suggest fixing the first selector I mentioned, checking the second with jquery docs and then jshinting/jslinting your code. (Javascript only)
I don't know if its a typo in the question itself or the issue with your script but name of th e parameter while passing is "db" but on the server side you are expecting "mess_id"
I have a page with multiple forms that do the same thing, acting as a like button for each post in the page, and right next to it the number of likes inside a div named "likes".$id, so I can identify where to write the likes count after the ajax call. I was trying to use jQuery ajax function, but I couldn't set what div to write the results of the function.
$.ajax({
type:'POST',
url: 'likepost.php',
data:$('#like').serialize(),
success: function(response) {
$('#like').find('#likediv').html(response);
}
});
And how would I access the data on likepost.php? I am terrible with javascript, so I hope someone could help me and explain how the jQuery function really works, because I've been copying and pasting it without really knowing what I was doing.
Would this work?
$(function () {
$("#likebutton").click(function () {
var id = $('input[name=id]'); // this is me trying to get a form value
$.ajax({
type: "POST",
url: "likepost.php",
data: $("#like"+id).serialize(), // the form is called like+id e.g. like12
success: function(data){
$("#likes"+id).html(data); // write results to e.g. <div id='likes12'>
}
});
});
});
I put this in the code but when the button is clicked, the usual post refreshing page is done. Why is that?
Making a mini-form, serializing it, and POSTing it seems like a lot of heavy lifting when all you really want to do is send the ID to the likepost.php script.
Why not just retrieve the ID and post it to the script?
First let's break down your function:Type is the type of the request we're making, you specified POST here. This means in your PHP file you'll access the data we're sending using $_POST. Next up is URL which is just the url of where you're sending the data, your php file in this case.
After that is data, that is the data we're sending to the url (likepost.php). You're serializing whatever has a ID of "like" and sending it to the php file. Finally success is a function to run once the request is successful, we get a response back from the PHP and use it in the function to output the response.
As for the multiple forms I'd recommend doing something like:
http://www.kavoir.com/2009/01/php-checkbox-array-in-form-handling-multiple-checkbox-values-in-an-array.html
Here's documentation on the stuff we talked about, if you're every confused about jquery just break it down and search each part.
http://api.jquery.com/serialize/
http://api.jquery.com/jQuery.ajax/
you can try :
function submitform(id) {
var jqxhr = $.post('./likepost.php',$("#"+id).serialize(), function(data) {
$("#"+id).find('#likediv').html(data);
}, "json")
return false;
}
in form:
<form method="post" id="likeForm" onsubmit="return submitform(this.id);">
<input..... />
<input type="submit" value="Submit" />
</form>
in likepost.php add first line:
if ($_SERVER['HTTP_X_REQUESTED_WITH'] != "XMLHttpRequest") {
header("location: " . $_SERVER['HTTP_REFERER']);
exit();
}
you can see more : http://api.jquery.com/serialize/
working for me.
Is it possible to get an element id into a PHP variable?
Let's say I have a number of element with IDs:
<span id="1" class="myElement"></span>
<span id="2" class="myElement"></span>
How do I get this into a PHP variable in order to submit a query. I suppose I would have to resubmit the page, which is OK. I would like to use POST. Can I do something like:
<script language="JavaScript">
$(document).ready(function(){
$(".myElement").click(function() {
$.post("'.$_SERVER['REQUEST_URI'].'", { id: $(this).attr("id") });
});
});
</script>
I need to pass $(this).attr('id') into $newID in order to run
SELECT * from t1 WHERE id = $newID
jQuery is a very powerful tool and I would like to figure out a way to combine its power with server-side code.
Thanks.
This is like your question: ajax post with jQuery
If you want this all in one file (posting to active file) here is what you would need in general:
<?php
// Place this at the top of your file
if (isset($_POST['id'])) {
$newID = $_POST['id']; // You need to sanitize this before using in a query
// Perform some db queries, etc here
// Format a desired response (text, html, etc)
$response = 'Format a response here';
// This will return your formatted response to the $.post() call in jQuery
return print_r($response);
}
?>
<script type='text/javascript'>
$(document).ready(function() {
$('.myElement').click(function() {
$.post(location.href, { id: $(this).attr('id') }, function(response) {
// Inserts your chosen response into the page in 'response-content' DIV
$('#response-content').html(response); // Can also use .text(), .append(), etc
});
});
});
</script>
<span id="1" class="myElement"></span>
<span id="2" class="myElement"></span>
<div id='response-content'></div>
From here you can customize the queries and response and what you would like to do with the response.
You have two "good" choices in my mind.
The first is to initiate a post request every time the ordering changes. You might be changing the ordering using jQuery UI sortable. Most libraries that support dragging and dropping also allow you to put an event callback on the drop simply within the initialization function.
In this even callback, you'd initiate the $.post as you have written it in your code (although I would urge you to look up the actual documentation on the matter to make sure you're POSTing to the correct location).
The second strategy is to piggyback on a form submission action. If you're using the jQuery Form Plugin to handle your form submissions, they allow you to indicate a before serialize callback where you can simply add into your form a field that specifies the ordering of the elements.
In both cases, you'd need to write your own function that actually serializes the element IDs. Something like the following would do just fine (totally untested; may contain syntax errors):
var order = [];
$('span.myElement').each(function(){
// N.B., "this" here is a DOM element, not a jQuery container
order.push(this.id);
});
return order.join(',');
You're quite right, something along those lines would work. Here's an example:
(btw, using $.post or $.get doesn't resubmit the page but sends an AJAX request that can call a callback function once the server returns, which is pretty neat)
<script language="JavaScript">
$(document).ready(function(){
$(".myElement").click(function() {
$.post(document.location, { id: $(this).attr("id") },
function (data) {
// say data will be some new HTML the server sends our way
// update some component on the page with contents representing the element with that new id
$('div#someContentSpace').html(data);
});
});
});
</script>
Your approach looks perfectly fine to me, but jQuery does not have a $_SERVER variable like PHP does. The url you would want to provide would be window.location (I believe an empty string will also work, or you can just specify the url on your own). You seem to be sending the ID just fine, though, so this will work.
If you want the page to react to this change, you can add a callback function to $.post(). You can do a variety of things.
$.post(window.location, {id: this.id}, function (data) {
//one
location.reload();
//two
$("#responsedata").html(data);
//three
$("#responsedata").load("affected_page.php #output");
});
I think number 2 is the most elegent. It does not require a page reload. Have your server side php script echo whatever data you want back (json, html, whatever), and it will be put in data above for jQuery to handle however you wish.
By the way, on the server side running the query, don't forget to sanitize the $id and put it in quotes. You don't want someone SQL Injecting you.