Display image along with other data in a table - php

Question

I know it's not the greatest technique, but coming from Foxpro and Dbase background, some habits just don't die. I am absolutely fresh in PHP and trying to re-create learning curve of my earlier programming experience.
I have drilled GOOGLE for the issue and tried to come up with the script, only issue is sometimes I came up with garbles, sometime empty screen, sometimes only IMAGE.
The scenario is If I am able to create this simple script, I will probably understand how to handle images issue.
I have a database in my MYSQL called crm. In the database I have a table called mast_cust with fields f_name, l_name and pic (BLOB)
I already have some records in them.
What I understood was:
Images and Data (Textual) cannot be printed together
You have to have two scripts , one gathering the image and the other gathering data
The one which gathers data , calls the one which collects images and prints it.
What I want is, to see data in tabular format
First Name | Last Name | Image
These are my two scripts, which is the one which prints garble
Script 1 : Main PHP file - list.php
Script 2 : Image Storing Script: pix.php
list.php
<?php
$errmsg = "";
if (! #mysql_connect("localhost","root","Admin"))
{
$errmsg = "Cannot connect to database";
}
#mysql_select_db("crm");
$strSQL = "select f_name,l_name,pic from mast_cust";
$rsPix = mysql_query($strSQL);
$numRows = mysql_numrows($rsPix);
$i = 0;
while($i < $numRows){
?>
<img src="pix.php?pixID=<?php echo mysql_result($rsPix,$i,"pic"); ?>"/>
<?php
$i++;
}
?>
Script 2 pix.php
<?php
$errmsg = "";
if (! #mysql_connect("localhost","root","Admin"))
{
$errmsg = "Cannot connect to database";
}
#mysql_select_db("crm");
if (IsSet($_GET['pixID'])){
$gotten = #mysql_query("select pic from pix where cust_id = ".$_GET['pixID']);
header("Content-type: image/jpeg");
while ($row = mysql_fetch_array($gotten))
{
print $row['pic'];
}
mysql_free_result($gotten);
}
?>
Any help resolving this issue is highly appreciated.
Thanks and Regards

Answer 1

It seems like you're storing the jpeg image as a blob in mysql.
1.) You can only send one pic at a time. So no need for a for loop.
2.) If so, you'll need to format the output of the data for the pic, so that a browser can read it.
I would recommend against this approach. You should avoid using a relational database for storing images. Try storing the jpegs on a regular filesystem or a file server (like S3), and store the url to it in the database.
If obfuscating the image url isn't enough, try the following approach:
Echo/print a jpg-image with php, for safety?
It uses:
http://php.net/manual/en/function.readfile.php