This is the first time I have came in contact with JSON, and I literally have no idea how to parse it with PHP. I know that functions to decode JSON exist in PHP, but I am unsure how to retrieve specific values defined in the JSON. Here's the JSON for my app:
http://itunes.apple.com/search?term=enoda&entity=software
I require a few values to be retrieved, including the App Icon (artworkUrl100), Price (price) and Version (version).
The things I am having issues with is putting the URL of the App Icon into an actual HTML image tag, and simply retrieving the values defined in the JSON for the Price and Version.
Any help/solutions to this would be fantastic.
Thanks,
Jack
Yeah, i have something similar, for my App review website, here is a bit code:
$context = stream_context_create(array('http' => array('header'=>'Connection: close')));
$content = file_get_contents("http://ax.phobos.apple.com.edgesuite.net/WebObjects/MZStoreServices.woa/wa/wsLookup?id=$appid&country=de");
$content = json_decode($content);
$array = $content->results["0"];
$version = $array->version;
$artistname = $array->artistName;
$artistid = $array->artistId;
Thats what I used to get Information from the AppStore, maybe you can change the link and some names and it would work for you.
Related
I am trying to use a weather API for a project and I am trying to build a simple weather app that will check the forecast and display it. The code looks like this:
$url = "http://api.openweathermap.org/data/2.5/weather?zip=30553&appid={APIKEY}";
$data = file_get_contents($url);
$decodeJSON = json_decode($data);
$testvar = "weather[0]->main";
echo $decodeJSON->$testvar;
and ideally I would like to be able to change $testvar to point at different variables returned by the API and as of right now I know it can't be done by combining "$decodeJSON->" and "$testvar", but is there anyway to achieve something close to what I have above that basically just assembles the two?
Appreciate all the help in advance and any feedback on the code is greatly appreciated!
I just started playing D&D, and I'm working on a project for my group to help us play the game a littler easier. We all created Characters on D&D Beyond. They don't have an official API, but apparently, if you type in "your-character-sheet/json" - you can get some JSON output about your character.
I attempted to grab this data in php as I normally would
<?php
$request = "https://www.dndbeyond.com/profile/PixiiBomb/characters/9150025/json";
$url = file_get_contents($request);
$json = json_decode($url, true);
echo $json["character"]["id"];
?>
This should echo out: "9150025" - but I actually see nothing. It's totally blank. So I tried to echo $url, and this is what I see.
Which of course, it not what I should be seeing (because that is formatting from their website, minus the stylesheets)
I went back to the JSON view and manually saved the data as pixii.json This time using the following:
$request = "uploads/dndbeyond_sheets/pixii.json"; // Saved to my harddrive
$url = file_get_contents($request);
$json = json_decode($url, true);
echo $json["character"]["id"];
THIS WORKS if I manually save the file. But that would mean that every time we level up, I would have to manually save all of our JSON data, and run some code to read it and update it.
Is there something else I can try to allow me to use this URL instead of having to manually save the page?
Ideally, I would like to have all of my code written , and then when we level up, I press a button and grab the new data from the site (which I don't need help with, that's not part of the question). Instead of manually visiting each website, saving the data, and then parsing it.
I'm trying to build a little script that would let me do this:
http://example.com/appicons.php?id=284417350
and then display this in plain text
http://a3.mzstatic.com/us/r1000/005/Purple/2c/a0/b7/mzl.msucaqmg.png
This is the API query to get that information (artworkUrl512):
http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/wa/wsLookup?id=284417350
Any help and example code would be much appreciated!
I am not sure why you have jQuery in your tags, unless you want to make the request dynamically without a page refresh. However you can do this simply in PHP using the following example:
$request = array (
"app_id" => #$_GET["id"]
);
// parse the requests.
if (empty($request["app_id"])) {
// redirects back / displays error
}
else {
$app_uri = "http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/wa/wsLookup?id=" . $request["app_id"];
$data = file_get_contents ($app_uri);
$json = json_decode (trim($data));
print($json->results[0]->artworkUrl100);
}
$request = file_get_contents($itms_url);
$json = json_decode(trim($request));
echo $json[0]->artworkUrl512;
should work in PHP. Unless of course there is more than one hit to the search. A solution using jQuery is probably not very much more difficult.
In Short, I am pulling the feed from my blogger using the Zend API in PHP. I need to get the URL that will link to that post in blogger. What is the order of functions I need to call to get that URL.
Right now I am pulling the data using:
$query = new Zend_Gdata_Query('http://www.blogger.com/feeds/MYID/posts/default');
$query->setParam('max-results', "1");
$feed = $gdClient->getFeed($query);
$newestPost = $feed->entry[0];
I can not for the life of me figure out where I have to go from here to get the URL. I can successfully get the Post title using: $newestPost->getTitle() and I can get the body by using $newestPost->getContent()->getText(). I have tried a lot of function calls, even ones in the documentation and most of them error out. I have printed out the entire object to look through it and I can find the data I want (so I know it is there) but the object is too complex to be able to just look at and see what I have to do to get to that data.
If anyone can help me or at least point me to a good explanation of how that Object is organized and how to get to each sub object within it, that would be greatly appreciated.
EDIT: Never mind I figured it out.
You are almost there, really all you need to do is once you have your feed entry is access the link element inside. I like pretty URLs so I went with the alternate rather than the self entry in the atom feed.
$link = $entry->link[4]->href;
where $entry is the entry that you are setting from the feed.
The solution is:
$query = new Zend_Gdata_Query('http://www.blogger.com/feeds/MyID/posts/default');
$query->setParam('max-results', "1");
$feed = $gdClient->getFeed($query);
$newestPost = $feed->entry[0];
$body = $newestPost->getContent()->getText();
$body now contains the post contents of the latest post (or entry[0]) from the feed. This is just the contents of the body of the post, not the title or any other data or formatting.
I'm using curl to retrieve information from wikipedia. So far I've been successful in retrieving basic text information but I really would want to retrieve it in HTML.
Here is my code:
$s = curl_init();
$url = 'http://boss.yahooapis.com/ysearch/web/v1/site:en.wikipedia.org+'.$article_name.'?appid=myID';
curl_setopt($s,CURLOPT_URL, $url);
curl_setopt($s,CURLOPT_HEADER,false);
curl_setopt($s,CURLOPT_RETURNTRANSFER,1);
$rs = curl_exec($s);
$rs = Zend_Json::decode($rs);
$rs = ($rs['ysearchresponse']['resultset_web']);
$rs = array_shift($rs);
$article= str_replace('http://en.wikipedia.org/wiki/', '', $rs['url']);
$url = 'http://en.wikipedia.org/w/api.php?';
$url.='format=json';
$url.=sprintf('&action=query&titles=%s&rvprop=content&prop=revisions&redirects=1', $article);
curl_setopt($s,CURLOPT_URL, $url);
curl_setopt($s,CURLOPT_HEADER,false);
curl_setopt($s,CURLOPT_RETURNTRANSFER,1);
$rs = curl_exec($s);
//curl_close( $s );
$rs = Zend_Json::decode($rs);
$rs = array_pop(array_pop(array_pop($rs)));
$rs = array_shift($rs['revisions']);
$articleText = $rs['*'];
However the text retrieved this way isnt well enough to be displayed :( its all in this kind of format
'''Aix-les-Bains''' is a [[Communes of
France|commune]] in the [[Savoie]]
[[Departments of France|department]]
in the [[Rhône-Alpes]] [[regions of
France|region]] in southeastern
[[France]].
It lies near the [[Lac du Bourget]],
{{convert|9|km|mi|abbr=on}} by rail
north of [[Chambéry]].
==History== ''Aix'' derives from [[Latin]] ''Aquae'' (literally,
"waters"; ''cf'' [[Aix-la-Chapelle]]
(Aachen) or [[Aix-en-Provence]]), and
Aix was a bath during the [[Roman
Empire]], even before it was renamed
''Aquae Gratianae'' to commemorate the
[[Emperor Gratian]], who was
assassinated not far away, in
[[Lyon]], in [[383]]. Numerous Roman
remains survive. [[Image:IMG 0109 Lake
Promenade.jpg|thumb|left|Lac du
Bourget Promenade]]
How do I get the HTML of the wikipedia article?
UPDATE: Thanks but I'm kinda new to this here and right now I'm trying to run an xpath query [albeit for the first time] and can't seem to get any results. I actually need to know a couple of things here.
How do I request just a part of an article?
How do I get the HTML of the article requested.
I went through this url on data mining from wikipedia - it put an idea to make a second request to wikipedia api with the retrieved wikipedia text as parameters and that would retrieve the html - although it hasn't seemed to work so far :( - I don't want to just grab the whole article as a mess of html and dump it. Basically my application what it does is that you have some locations and cities pin pointed on the map - you click on the city marker and it would request via ajax details of the city to be shown in an adjacent div. This information I wish to get from wikipedia dynamically. I'll worry about about dealing with articles that don't exist for a particular city later on just need to make sure its working at this point.
Does anyone know of a nice working example that does what I'm looking for i.e. read and parse through selected portions of a wikipedia article.
According to the url provided - it says I should post the wikitext to the wikipedia api location for it to return parsed html. The issue is that if I post the information I get no response and instead an error that I'm denied access - however if I try to include the wikitext as GET it parses with no issue. But it fails of course when I have waaaaay too much text to parse.
Is this a problem with the wikipedia api? Because I've been hacking at it for two days now with no luck at all :(
The simplest solution would probably be to grab the page itself (e.g. http://en.wikipedia.org/wiki/Combination ) and then extract the content of <div id="content">, potentially with an xpath query.
There is a PEAR Wiki Filter that I have used and it does a very decent job.
Text Wiki
Phil
Try looking at the printable version of the desired Wikipedia article in question.
In other words, change this line of your source code:
$url.=sprintf('&action=query&titles=%s&rvprop=content&prop=revisions&redirects=1', $article);
to something like:
$url.=sprintf('&action=query&titles=%s&printable=yes&redirects=1', $article);
Disclaimer: Have not tested, and this is just a guess at how your API might work.
As far as I understand it, the Wikipedia software converts the Wiki markup into HTML when the page is requested. So using your current method, you'll need to deal with the results.
A good place to start is the Mediawiki API. You can also use http://pear.php.net/package/Text_Wiki to format the results retrieved via cURL.