PHP if statement with checkbox error - php

Question

Sorry for the dumb question, though I'm a little new to PHP.
I've tried a lot of other ways to do this, but simply couldn't get this to work... Actually I want it to make it that I can have different functions attached to each checkbox that when a user selects a checkbox or another, and clicks the submit button, it triggers the specific functions. But I cannot get the checkboxes to work. It either works with only one selected, or if I check the 1st one then the 4th one, it outputs the 4th's code.
Any other ways of doing this?
Here is my attempt:
1.php
<form method="POST" action="2.php">
<input type="checkbox" name="test[]" value="test1" />test1<br />
<input type="checkbox" name="test[]" value="test2" />test2<br />
<input type="submit" name="submit" value="submit" />
</form>
2.php
$val = $_POST['test'];
if(isset($val)==true){
for($i = 0 ; $i<count($val) ; $i++){
if($val=='test1'){
echo $val;
die();
}elseif($val=='test2'){
echo $val;
die();
}else{
echo "fail";
die();
}
}
}else{
return false;
}
Thank you.

Answer 1

Try:
$vals = $_POST['test'];
$valsCount = count($vals);
if ($valsCount > 0) {
foreach ($vals as $val) {
switch ($val) {
case 'test1':
echo $val;
break;
case 'test2':
echo $val;
break;
default:
echo 'Fail';
break;
}
}
}

Answer 2

As another option, if you're looking to call functions based on the value of the checkbox, you could do something like this ...
I've compressed it all into one file for simplicity, but this is the general idea ...
<form method="post" action="<?php echo $_SREVER['PHP_SELF']; ?>">
<input type="checkbox" name="boxes[]" value="box1">Box 1</input><br />
<input type="checkbox" name="boxes[]" value="box2">Box 2</input><br />
<input type="checkbox" name="boxes[]" value="box3">Box 3</input><br />
<input type="checkbox" name="boxes[]" value="box4">Box 4</input><br />
<input type="checkbox" name="boxes[]" value="box5">Box 5</input><br />
<input type="submit" value="Go!" />
</form>
<?php
class boxProcessor
{
public function box1()
{
echo "<p>You've found box 1.</p>";
}
public function box2()
{
echo "<p>You've found box 2.</p>";
}
public function box3()
{
echo "<p>You've found box 3.</p>";
}
public function box4()
{
echo "<p>You've found box 4.</p>";
}
public function box5()
{
echo "<p>You've found box 5.</p>";
}
}
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$boxes = $_POST['boxes'];
if(empty($boxes)){
echo "<p>Nothing to do ...</p>";
} else {
$proc = new boxProcessor();
foreach($boxes as $box){
$proc->$box();
}
}
}
?>

Answer 3

You're pretty close with your code as is, you just have to take into account array indexes.
for ($i = 0, $length = count($val); $i < $length; $i++)
{
// add [$i] to $val to access an index of $val
if ($val[$i] == 'test1')

Answer 4

Try changing the names from test1[] to test1 in 1.php and also check a typo on line 7- 2.php.
Hope this helps.

Answer 5

There are a couple of issues that probably don't have anything to do with the real problem:
1) You talk about "1st" and "4th" checkboxes ... but your code only shows two checkboxes
2) Your example misspells "tes2" (so PHP won't/can't find it)
3) You should probably get rid of all the "die()" clauses
SUGGESTION:
Check out this link:
http://www.html-form-guide.com/php-form/php-form-checkbox.html