issues with stick forms in PHP - php

Question

i'm trying to make this form sticky but it's not doing. What i'm trying to do is that from a previous form, the user enters some parameters and the HTML table is generated to this page, while another form is displayed to edit the data in the table shown above it. But the values are not displaying in the form below.
Please help me
PLEASE FORGIVE MY FORMATING I TYPED ON A MOBILE. Thanks for you patience.
<?php session_start(); ?>
<?php require 'includes/dbconnect.php' ; ?>
<?php require 'includes/header.inc.php'; ?>
<?php
$matric_no = mysql_real_escape_string($_POST['matric_no']);
if ($_POST['matric_no'] == "")
{
echo"<div id=\"contentRight\">";
echo"<idv id=\"msg\">" ;
echo "You didn't enter a <span style=\"color:red\">Matric Number</span>";
echo"</div>";
echo"</div>";
exit();
}
$query = "SELECT matric_no
FROM students
WHERE matric_no = '$_POST[matric_no]'";
$result = mysql_query($query);
$duplicates = mysql_num_rows($result);
if ($duplicates < 1)
{
echo"<div id=\"contentRight\">";
echo"<idv id=\"msg\">" ;
echo "You dont have a record for <span style=\"color:red\">$matric_no</span>" ;
echo "</div>" ;
echo "</div>" ;
exit();
}
$result = mysql_query("SELECT matric_no, first_name, last_name, other_name
FROM students
WHERE matric_no = '".mysql_real_escape_string($_POST['matric_no'])."'") or die(mysql_error());
$number_cols = mysql_num_fields($result) ;
echo "<div id=\"contentRight\">" ;
echo "<span class=\"header\">";
echo "<p><b>Matric Number: ".mysql_real_escape_string($_POST['matric_no']) ."</b></p>";
echo "<table border = 1 , cellspacing = 0 , cellpadding = 2 bgcolor=lemonchiffon >\n";
echo "<tr align=center>\n";
for ($i=0; $i<$number_cols; $i++)
{
echo "<th>" . mysql_field_name($result, $i). "</th>\n";
}
echo "</tr>\n";
while ($row = mysql_fetch_row($result))
{
echo "<tr align=center>\n";
for ($i=0; $i<$number_cols; $i++)
{
echo "<td>";
if (!isset($row[$i]))
{echo "NULL";}
else
{echo $row[$i];}
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>";
echo"</span>" ;
echo"</div>";
?>
<br />
<?php
while($row = mysql_fetch_array($result)){
?>
<div id="contentRight">
<p>
Select the Score options you will like to update:
<form action="student_update2.php" method="post">
<ul>
<li>Matric Number: <input type="text" name="matric_no" value="<?php echo $row['matric_no'] ; ?>"> </li><br/><br/>
<li>First Name: <input type="text" name="first_name" value="<?php echo $row['firts_name'] ; ?>"> </li><br /><br/>
<li>Last Name: <input type="text" name="last_name" value="<?php echo $row['last_name'] ; ?>"> </li><br /><br />
<li>Other Names: <input type="text" name="other_name" value="<?php echo $row['other_name'] ; ?>"</li> <br /><br />
<input type="submit" name="submit" value="Update" />
<input type="hidden" name ="submitted" value="TRUE" />
<input name="Reset" type="reset" value="Reset" />
</ul>
</div>
</div>
</form>
<?php
}
require 'includes/footer.php'; ?>
formmatting cleaned a little

Answer 1

Try adding this:
$result = mysql_query("SELECT matric_no, first_name, last_name, other_name
FROM students
WHERE matric_no = '".mysql_real_escape_string($_POST['matric_no'])."'") or die(mysql_error());
Above this (approx line 99):
while ($row = mysql_fetch_array($result)){
?>
<div id="contentRight">
<p>Select the Score options you will like to update:</p>
I know you have this declared once already but since you've already use while to cycle through the recordset already it may need to be reset.