I have this string
$url = offer?offer_id={{offer_category_id}}&item{{offer_title}}
Is there a way how I can create a php array with the text inside the {{ }} thus resulting an array similar to
$array[0] = 'offer_category_id'
$array[1] = 'offer_title'
This is what I have but its not working as wanted
preg_match("/{{([^\"]*)\}}/", $url , $cols);
This code will give your values:
$str = 'offer?offer_id={{offer_category_id}}&item{{offer_title}}';
if ( preg_match_all('~{\s*{([^}]*)}~i', $str, $m) )
print_r ( $m[1] );
OUTPUT:
Array
(
[0] => offer_category_id
[1] => offer_title
)
Use preg_match_all:
preg_match_all("/{{([^\"}]+)\}}/", $url , $cols);
i think it should be (you might need to play with the flag to get the desired order):
preg_match_all("/{{([^}]+)\}}/", $url , $cols, PREG_SET_ORDER);
Related
Example:
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d\d\d\d-\d\d-\d\d)|i', $string, $arr_result);
print_r($arr_result);
Returns:
Array
(
[0] => 2010-07-18
[date] => 2010-07-18
[1] => 2010-07-18
)
But I want it to be:
Array
(
[date] => 2010-07-18
)
In PHP's PDO object there is an option that is filtering results from database by removing these duplicate numbered values : PDO::FETCH_ASSOC. But I haven't seen similar modifier for the PCRE functions in PHP yet.
How to return only named groups with preg_match or preg_match_all?
This is currently (PHP7) not possible.
You will always get a mixed type array, containing numeric and named keys.
Lets quote the PHP manual (http://php.net/manual/en/regexp.reference.subpatterns.php):
This subpattern will then be indexed in the matches array by its
normal numeric position and also by name.
To solve the problem the following code snippets might help:
1. filter the array by using an is_string check on the array key (for PHP5.6+)
$array_filtered = array_filter($array, "is_string", ARRAY_FILTER_USE_KEY);
2. foreach over the elements and unset if array key is_int() (all PHP versions)
/**
* #param array $array
* #return array
*/
function dropNumericKeys(array $array)
{
foreach ($array as $key => $value) {
if (is_int($key)) {
unset($array[$key]);
}
}
return $array;
}
Its a simple PHP function named dropNumericKeys(). Its for the post-processing of an matches array after a preg_match*() run using named groups for matching. The functions accepts an $array. It iterates the array and removes/unsets all keys with integer type, leaving keys with string type untouched. Finally, the function returns the array with "now" only named keys.
Note: The function is for PHP downward compatiblity. It works on all versions. The array_filter solution relies on the constant ARRAY_FILTER_USE_KEY, which is only available on PHP5.6+. See http://php.net/manual/de/array.constants.php#constant.array-filter-use-key
preg_match does not have any flag or option that it only returns named matches (yet). So what you want is not directly possible. However you can remove all items with non-fitting keys from your matches array and then you get what you're looking for:
$matches = array_intersect_key($matches, array_flip(array('name', 'likes')));
I do not think you can make preg_* do it, but you can do it with a simple loop. But I don't see why those elements pose a problem.
It also possible to unset all numeric indexes before return:
foreach (range(0, floor(count($arr_result) / 2)) as $index) {
unset($arr_result[$index]);
}
Similar to the answer that hakre posted above, I use this snippet to get just the named parameters:
$subject = "This is some text written on 2010-07-18.";
$pattern = '|(?<date>\d\d\d\d-\d\d-\d\d)|i';
preg_match_all($pattern, $subject, $matches, PREG_SET_ORDER);
echo '<pre>Before Diff: ', print_r($matches, 1), '</pre>';
$matches = array_diff_key($matches[0], range(0, count($matches[0])));
echo '<pre>After Diff: ', print_r($matches, 1), '</pre>';
...which produces this:
Before Array
(
[0] => Array
(
[0] => 2010-07-18
[date] => 2010-07-18
[1] => 2010-07-18
)
)
After Array
(
[date] => 2010-07-18
)
I read in your post that these are possible overloads of future memory etc ...
In this case, why no't can be solved with an unset():
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d{4}-\d{2}-\d{2})|i', $string, $arr_result);
$date = array("date" => $arr_result['date']);
unset($arr_result, $string);//delete array and string preg_match origen
print_r($date);
//or create a new:
// $arr_result = $date;
//print_r($arr_result);
You could use T-Regx and go with group() or namedGroups() which only returns named capturing groups.
<?php
$subject = "This is some text written on 2010-07-18.";
pattern('(?<date>\d\d\d\d-\d\d-\d\d)', 'i')->match($subject)->first(function ($match) {
$date = $match->get('date');
// 2010-07-18
$groups = $match->namedGroups();
// [
// 'date' => '2010-07-18'
// ]
});
I use some of introduced codes and this is the final code works on php 5.6+:
$re = '/\d+\r\n(?<start>[\d\0:]+),\d+\s--\>\s(?<end>[\d\0:]+),.*\r\nHOME.*\r\nGPS\((?<x>[\d\.]+),(?<y>[\d\.]+),(?<d>[\d\.]+)\)\sBAROMETER\:(?<h>[\d\.]+)/';
$str= file_get_contents($srtFile);
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
echo '<pre>';
$filtered=array_map(function ($d){
return $array_filtered = array_filter($d, "is_string", ARRAY_FILTER_USE_KEY);
},$matches);
var_dump($filtered);
if you are interested what it does it read position data from a str file that DJI drones generate while recording video.
Try this:
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d\d\d\d-\d\d-\d\d)|i',$string,$arr_result);
echo $arr_result['date'];
I want to extract matched parts of strings --digital part from an array
array("HK00003.Day","HK00005.Day").
<?php
$arr=array("HK00003.Day","HK00005.Day");
$result= array();
foreach ($arr as $item){
preg_match('/[0-9]+/',$item,$match);
array_push($result,$match[0]);
}
It can get the result :00003 00005,it seems tedious,preg_grep seems simple but the result is not what i want .
preg_grep('/[0-9]+/',$arr);
The output is "HK00003.Day","HK00005.Day", not 00003 00005,
is there more simple way to get the job done?
You can use preg_filter (which already uses preg_replace and does not require additional callback functions) to replace the each entry in the array with the number inside:
<?php
$arr = array("HK00003.Day","HK00005.Day");
$matches = preg_filter('/^.*?([0-9]+).*/', '$1',$arr);
print_r($matches);
?>
Output of a sample program:
Array
(
[0] => 00003
[1] => 00005
)
This should work for you:
(Here I just get rid off every character in your array which isn't a number with preg_replace())
<?php
$arr = ["HK00003.Day", "HK00005.Day"];
$result = preg_replace("/[^0-9]/", "", $arr);
print_r($result);
?>
output:
Array ( [0] => 00003 [1] => 00005 )
Your code is fine, not tedious at all. If you want a one-liner you can try something like this (remove everything that's not a digit):
array_push($result, preg_replace("~[^0-9]~", "", $item));
preg_grep return array entries that match the pattern！ Therefore, it returns an array of entry rather than the matching string
try below:
preg_match_all('/[0-9]+/',implode('-',$arr),$result);
I use coordinates for shops and manually add the coordinates as lang and long to database. Sometimes by mistake, approving the coordinate.
Let me exlain by an example.
For example;
Lang is 33.4534543543 .But by mistake sometimes i push keyboard and it becomes like,
33.4534543543<
or
33.4534543543,
or
,(space)33.4534543543<
How can I get only the 33.4534543543?
preg_match_all
To find matches from a string containing multiple matches, you would use preg_match_all:
$strings = "33.4534543543<
33.4534543543,
, 33.4534543543<";
$pattern = "!(\d+\.\d+)!";
preg_match_all($pattern,$strings,$matches);
print_r($matches[0]);
Output
Array
(
[0] => 33.4534543543
[1] => 33.4534543543
[2] => 33.4534543543
)
preg_match
To find the match from a single string you could use preg_match.
$string = "33.4534543543<";
$pattern = "!(\d+\.\d+)!";
if(preg_match($pattern,$string,$match)){
print($match[0]);
}
Output
33.4534543543
preg_replace
To replace anything that is not what you want in your existing string you would use preg_replace:
$string = preg_replace('![^\d.]!','',$string);
An example:
$strings = "33.4534543543<
33.4534543543,
, 33.4534543543<";
$strings_exp = explode("\n",$strings);
$output = '';
foreach($strings_exp as $string){
$output.= "String '$string' becomes ";
$new_string = preg_replace('![^0-9.]!','',$string);
$output.= "'$new_string'\n";
}
echo $output;
output
String '33.4534543543<' becomes '33.4534543543'
String '33.4534543543,' becomes '33.4534543543'
String ', 33.4534543543<' becomes '33.4534543543'
Sound like you want to do a preg_match: http://phpfiddle.org/main/code/z6q-a1d
$old_vals = array(
'33.4534543543<',
'33.4534543543,',
', 33.4534543543<'
);
$new_vals = array();
foreach ($old_vals as $val) {
preg_match('(\d*\.?\d+)',$val, $match);
array_push($new_vals, $match[0]);
}
print_r($new_vals);
Output
Array (
[0] => 33.4534543543,
[1] => 33.4534543543,
[2] => 33.4534543543
)
I'm beginner in php and I have string like this:
$test = http://localhost/biochem/wp-content/uploads//godzilla-article2.jpghttp://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg
And I want to split string to array like this:
Array(
[0] => http://localhost/biochem/wp-content/uploads//godzilla-article2.jpg
[1] => http://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg
)
What should I do?
$test = 'http://localhost/biochem/wp-content/uploads//godzilla-article2.jpghttp://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg';
$testurls = explode('http://',$test);
foreach ($testurls as $testurl) {
if (strlen($testurl)) // because the first item in the array is an empty string
$urls[] = 'http://'. $testurl;
}
print_r($urls);
You asked for a regex solution, so here you go...
$test = "http://localhost/biochem/wp-content/uploads//godzilla-article2.jpghttp://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg";
preg_match_all('/(http:\/\/.+?\.jpg)/',$test,$matches);
print_r($matches[0]);
The expression looks for parts of the string the start with http:// and end with .jpg, with anything in between. This splits your string exactly as requested.
output:
Array
(
[0] => http://localhost/biochem/wp-content/uploads//godzilla-article2.jpg
[1] => http://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg
)
you can split them if they are always like this vith substr() function reference: http://php.net/manual/en/function.substr.php but if they are dynamic in lenght. you need to get a ; or any other sign that is not likely to be used there before 2nd "http://" and then use explode function reference: http://php.net/manual/en/function.explode.php
$string = "http://something.com/;http://something2.com"; $a = explode(";",$string);
Try the following:
<?php
$temp = explode('http://', $test);
foreach($temp as $url) {
$urls[] = 'http://' . $url;
}
print_r($urls);
?>
$test = 'http://localhost/biochem/wp-content/uploads//godzilla-article2.jpghttp://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jp';
array_slice(
array_map(
function($item) { return "http://" . $item;},
explode("http://", $test)),
1);
For answering this question by regular expression I think you want something like this:
$test = "http://localhost/biochem/wp-content/uploads//godzilla-article2.jpghttp://localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg";
$keywords = preg_split("/.http:\/\//",$test);
print_r($keywords);
It returns exactly something you need:
Array
(
[0] => http://localhost/biochem/wp-content/uploads//godzilla-article2.jp
[1] => localhost/biochem/wp-content/uploads/life-goes-on-wpcf_300x111.jpg
)
Example:
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d\d\d\d-\d\d-\d\d)|i', $string, $arr_result);
print_r($arr_result);
Returns:
Array
(
[0] => 2010-07-18
[date] => 2010-07-18
[1] => 2010-07-18
)
But I want it to be:
Array
(
[date] => 2010-07-18
)
In PHP's PDO object there is an option that is filtering results from database by removing these duplicate numbered values : PDO::FETCH_ASSOC. But I haven't seen similar modifier for the PCRE functions in PHP yet.
How to return only named groups with preg_match or preg_match_all?
This is currently (PHP7) not possible.
You will always get a mixed type array, containing numeric and named keys.
Lets quote the PHP manual (http://php.net/manual/en/regexp.reference.subpatterns.php):
This subpattern will then be indexed in the matches array by its
normal numeric position and also by name.
To solve the problem the following code snippets might help:
1. filter the array by using an is_string check on the array key (for PHP5.6+)
$array_filtered = array_filter($array, "is_string", ARRAY_FILTER_USE_KEY);
2. foreach over the elements and unset if array key is_int() (all PHP versions)
/**
* #param array $array
* #return array
*/
function dropNumericKeys(array $array)
{
foreach ($array as $key => $value) {
if (is_int($key)) {
unset($array[$key]);
}
}
return $array;
}
Its a simple PHP function named dropNumericKeys(). Its for the post-processing of an matches array after a preg_match*() run using named groups for matching. The functions accepts an $array. It iterates the array and removes/unsets all keys with integer type, leaving keys with string type untouched. Finally, the function returns the array with "now" only named keys.
Note: The function is for PHP downward compatiblity. It works on all versions. The array_filter solution relies on the constant ARRAY_FILTER_USE_KEY, which is only available on PHP5.6+. See http://php.net/manual/de/array.constants.php#constant.array-filter-use-key
preg_match does not have any flag or option that it only returns named matches (yet). So what you want is not directly possible. However you can remove all items with non-fitting keys from your matches array and then you get what you're looking for:
$matches = array_intersect_key($matches, array_flip(array('name', 'likes')));
I do not think you can make preg_* do it, but you can do it with a simple loop. But I don't see why those elements pose a problem.
It also possible to unset all numeric indexes before return:
foreach (range(0, floor(count($arr_result) / 2)) as $index) {
unset($arr_result[$index]);
}
Similar to the answer that hakre posted above, I use this snippet to get just the named parameters:
$subject = "This is some text written on 2010-07-18.";
$pattern = '|(?<date>\d\d\d\d-\d\d-\d\d)|i';
preg_match_all($pattern, $subject, $matches, PREG_SET_ORDER);
echo '<pre>Before Diff: ', print_r($matches, 1), '</pre>';
$matches = array_diff_key($matches[0], range(0, count($matches[0])));
echo '<pre>After Diff: ', print_r($matches, 1), '</pre>';
...which produces this:
Before Array
(
[0] => Array
(
[0] => 2010-07-18
[date] => 2010-07-18
[1] => 2010-07-18
)
)
After Array
(
[date] => 2010-07-18
)
I read in your post that these are possible overloads of future memory etc ...
In this case, why no't can be solved with an unset():
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d{4}-\d{2}-\d{2})|i', $string, $arr_result);
$date = array("date" => $arr_result['date']);
unset($arr_result, $string);//delete array and string preg_match origen
print_r($date);
//or create a new:
// $arr_result = $date;
//print_r($arr_result);
You could use T-Regx and go with group() or namedGroups() which only returns named capturing groups.
<?php
$subject = "This is some text written on 2010-07-18.";
pattern('(?<date>\d\d\d\d-\d\d-\d\d)', 'i')->match($subject)->first(function ($match) {
$date = $match->get('date');
// 2010-07-18
$groups = $match->namedGroups();
// [
// 'date' => '2010-07-18'
// ]
});
I use some of introduced codes and this is the final code works on php 5.6+:
$re = '/\d+\r\n(?<start>[\d\0:]+),\d+\s--\>\s(?<end>[\d\0:]+),.*\r\nHOME.*\r\nGPS\((?<x>[\d\.]+),(?<y>[\d\.]+),(?<d>[\d\.]+)\)\sBAROMETER\:(?<h>[\d\.]+)/';
$str= file_get_contents($srtFile);
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
echo '<pre>';
$filtered=array_map(function ($d){
return $array_filtered = array_filter($d, "is_string", ARRAY_FILTER_USE_KEY);
},$matches);
var_dump($filtered);
if you are interested what it does it read position data from a str file that DJI drones generate while recording video.
Try this:
$string = "This is some text written on 2010-07-18.";
preg_match('|(?<date>\d\d\d\d-\d\d-\d\d)|i',$string,$arr_result);
echo $arr_result['date'];