I want to skip some records in a foreach loop.
For example, there are 68 records in the loop. How can I skip 20 records and start from record #21?
Five solutions come to mind:
Double addressing via array_keys
The problem with for loops is that the keys may be strings or not continues numbers therefore you must use "double addressing" (or "table lookup", call it whatever you want) and access the array via an array of it's keys.
// Initialize 25 items
$array = range( 1, 25, 1);
// You need to get array keys because it may be associative array
// Or it it will contain keys 0,1,2,5,6...
// If you have indexes staring from zero and continuous (eg. from db->fetch_all)
// you can just omit this
$keys = array_keys($array);
for( $i = 21; $i < 25; $i++){
echo $array[ $keys[ $i]] . "\n";
// echo $array[$i] . "\n"; // with continuous numeric keys
}
Skipping records with foreach
I don't believe that this is a good way to do this (except the case that you have LARGE arrays and slicing it or generating array of keys would use large amount of memory, which 68 is definitively not), but maybe it'll work: :)
$i = 0;
foreach( $array as $key => $item){
if( $i++ < 21){
continue;
}
echo $item . "\n";
}
Using array slice to get sub part or array
Just get piece of array and use it in normal foreach loop.
$sub = array_slice( $array, 21, null, true);
foreach( $sub as $key => $item){
echo $item . "\n";
}
Using next()
If you could set up internal array pointer to 21 (let's say in previous foreach loop with break inside, $array[21] doesn't work, I've checked :P) you could do this (won't work if data in array === false):
while( ($row = next( $array)) !== false){
echo $row;
}
btw: I like hakre's answer most.
Using ArrayIterator
Probably studying documentation is the best comment for this one.
// Initialize array iterator
$obj = new ArrayIterator( $array);
$obj->seek(21); // Set to right position
while( $obj->valid()){ // Whether we do have valid offset right now
echo $obj->current() . "\n";
$obj->next(); // Switch to next object
}
$i = 0;
foreach ($query)
{
if ($i++ < 20) continue;
/* php code to execute if record 21+ */
}
if want to skipped some index then make an array with skipped index and check by in_array function inside the foreach loop if match then it will be skip.
Example:
//you have an array like that
$data = array(
'1' => 'Hello world',
'2' => 'Hello world2',
'3' => 'Hello world3',
'4' => 'Hello world4',
'5' => 'Hello world5',// you want to skip this
'6' => 'Hello world6',// you want to skip this
'7' => 'Hello world7',
'8' => 'Hello world8',
'9' => 'Hello world8',
'10' => 'Hello world8',//you want to skip this
);
//Ok Now wi make an array which contain the index wich have to skipped
$skipped = array('5', '6', '10');
foreach($data as $key => $value){
if(in_array($key, $skipped)){
continue;
}
//do your stuf
}
You have not told what "records" actually is, so as I don't know, I assume there is a RecordIterator available (if not, it is likely that there is some other fitting iterator available):
$recordsIterator = new RecordIterator($records);
$limited = new LimitIterator($recordsIterator, 20);
foreach($limited as $record)
{
...
}
The answer here is to use foreach with a LimitIterator.
See as well: How to start a foreach loop at a specific index in PHP
I'm not sure why you would be using a foreach for this goal, and without your code it's hard to say whether this is the best approach. But, assuming there is a good reason to use it, here's the smallest version I can think of off the top of my head:
$count = 0;
foreach( $someArray as $index => $value ){
if( $count++ < 20 ){
continue;
}
// rest of foreach loop goes here
}
The continue causes the foreach to skip back to the beginning and move on to the next element in the array. It's extremely useful for disregarding parts of an array which you don't want to be processed in a foreach loop.
for($i = 20; $i <= 68; $i++){
//do stuff
}
This is better than a foreach loop because it only loops over the elements you want.
Ask if you have any questions
array.forEach(function(element,index){
if(index >= 21){
//Do Something
}
});
Element would be the current value of index.
Index increases with each turn through the loop.
IE 0,1,2,3,4,5;
array[index];
Related
I am trying to sort it in a repeating, sequential pattern of numerical order with the largest sets first.
Sample array:
$array = [1,1,1,2,3,2,3,4,5,4,4,4,5,1,2,2,3];
In the above array, I have the highest value of 5 which appears twice so the first two sets would 1,2,3,4,5 then it would revert to the second, highest value set etc.
Desired result:
[1,2,3,4,5,1,2,3,4,5,1,2,3,4,1,2,4]
I am pretty sure I can split the array into chunks of the integer values then cherrypick an item from each subarray sequentially until there are no remaining items, but I just feel that this is going to be poor for performance and I don't want to miss a simple trick that PHP can already handle.
Here's my attempt at a very manual loop using process, the idea is to simply sort the numbers into containers for array_unshifting. I'm sure this is terrible and I'd love someone to do this in five lines or less :)
$array = array(1,1,1,2,3,2,3,4,5,4,4,4,5,1,2,2,3);
sort($array);
// Build the container array
$numbers = array_fill_keys(array_unique($array),array());
// Assignment
foreach( $array as $number )
{
$numbers[ $number ][] = $number;
}
// Worker Loop
$output = array();
while( empty( $numbers ) === false )
{
foreach( $numbers as $outer => $inner )
{
$output[] = array_shift( $numbers[ $outer ] );
if( empty( $numbers[ $outer ] ) )
{
unset( $numbers[ $outer ] );
}
}
}
var_dump( $output );
I think I'd look at this not as a sorting problem, but alternating values from multiple lists, so rather than coming up with sets of distinct numbers I'd make sets of the same number.
Since there's no difference between one 1 and another, all you actually need is to count the number of times each appears. It turns out PHP can do this for you with aaray_count_values.
$sets = array_count_values ($input);
Then we can make sure the sets are in order by sorting by key:
ksort($sets);
Now, we iterate round our sets, counting down how many times we've output each number. Once we've "drained" a set, we remove it from the list, and once we have no sets left, we're all done:
$output = [];
while ( count($sets) > 0 ) {
foreach ( $sets as $number => $count ) {
$output[] = $number;
if ( --$sets[$number] == 0 ) {
unset($sets[$number]);
}
}
}
This algorithm could be adapted for cases where the values are actually distinct but can be put into sets, by having the value of each set be a list rather than a count. Instead of -- you'd use array_shift, and then check if the length of the set was zero.
You can use only linear logic to sort using php functions. Here is optimized way to fill data structures. It can be used for streams, generators or anything else you can iterate and compare.
$array = array(1,1,1,2,3,2,3,4,5,4,4,4,5,1,2,2,3);
sort($array);
$chunks = [];
$index = [];
foreach($array as $i){
if(!isset($index[$i])){
$index[$i]=0;
}
if(!isset($chunks[$index[$i]])){
$chunks[$index[$i]]=[$i];
} else {
$chunks[$index[$i]][] = $i;
}
$index[$i]++;
}
$result = call_user_func_array('array_merge', $chunks);
print_r($result);
<?php
$array = array(1,1,1,2,3,2,3,4,5,4,4,4,5,1,2,2,3);
sort($array);
while($array) {
$n = 0;
foreach($array as $k => $v) {
if($v>$n) {
$result[] = $n = $v;
unset($array[$k]);
}
}
}
echo implode(',', $result);
Output:
1,2,3,4,5,1,2,3,4,5,1,2,3,4,1,2,4
New, more elegant, more performant, more concise answer:
Create a sorting array where each number gets its own independent counter to increment. Then use array_multisort() to sort by this grouping array, then sort by values ascending.
Code: (Demo)
$encounters = [];
foreach ($array as $v) {
$encounters[] = $e[$v] = ($e[$v] ?? 0) + 1;
}
array_multisort($encounters, $array);
var_export($array);
Or with a functional style with no global variable declarations: (Demo)
array_multisort(
array_map(
function($v) {
static $e;
return $e[$v] = ($e[$v] ?? 0) + 1;
},
$array
),
$array
);
var_export($array);
Old answer:
My advice is functionally identical to #El''s snippet, but is implemented in a more concise/modern/attractive fashion.
After ensuring that the input array is sorted, make only one pass over the array and push each re-encountered value into its next row of values. The $counter variable indicates which row (in $grouped) the current value should be pushed into. When finished looping and grouping, $grouped will have unique values in each row. The final step is to merge/flatten the rows (preserving their order).
Code: (Demo)
$grouped = [];
$counter = [];
sort($array);
foreach ($array as $v) {
$counter[$v] = ($counter[$v] ?? -1) + 1;
$grouped[$counter[$v]][] = $v;
}
var_export(array_merge(...$grouped));
I have an array $scripts_stack = []; that holds arrays:
$array_item = array('script' => $file_parts, 'handle' => $file_name, 'src' => $url);
array_push($scripts_stack, $array_item);
<?php
for ($i = 0; $i < sizeof($scripts_stack); $i++) {
$child_array = $scripts_stack[$i];
if (is_array($child_array)) {
// Do things with $child_array,
// then remove the child array from $scripts_stack when done with (BELOW)
unset($scripts_stack[$i]);
}
}
echo "Array Size : " . (sizeof($scripts_stack)); // AT THE END
However, my attemts only remove half the elements. No matter what I try, it's only half the items that get removed. sizeof($scripts_stack) is always half the size of what it was at the start.
I'm expecting that it would be empty // AT THE END
Why is it that I only get half the elements in the array removed?
Thank you all in advance.
As mentioned in other answers, $i increments but the sizeof() the array shrinks. foreach() is probably the most flexible looping for arrays as it exposes the actual key (instead of hoping it starts at 0 and increments by 1) and the value:
foreach ($scripts_stack as $key => $child_array) {
if (is_array($child_array)) {
// Do things with $child_array,
// then remove the child array from $scripts_stack when done with (BELOW)
unset($scripts_stack[$key]);
}
}
Just FYI, the way you're doing it with for almost works. You just need to establish the count before the loop definition, rather than recounting in the continuation condition.
$count = sizeof($scripts_stack);
for ($i = 0; $i < $count; $i++) { // ...
Still, I think it would be better to just use a different type of loop as shown in the other answers. I'd personally go for foreach since it should always iterate every element even if some indexes aren't present. (With the way you're building the array, it looks like the indexes should always be sequential, though.)
Another possibility is to shift elements off of the array rather than explicitly unsetting them.
while ($child_array = array_shift($scripts_stack)) {
// Do things with $child_array,
}
This will definitely remove every element from the array, though. It looks like $child_array should always be an array, so the is_array($child_array) may not be necessary, but if there's more to it that we're not seeing here, and there are some non-array elements that you need to keep, then this won't work.
You advanced $i while the array is getting shrinked, but in the same time you jump over items in your array.
The first loop is where $i == 0, and then when you removed item 0 in your array, the item that was in the second place has moved to the first place, and your $i == (so you will not remove the item in the current first place, and so on.
What you can do is use while instead of for loop:
<?php
$i = 0;
while ($i < sizeof($scripts_stack)) {
$child_array = $scripts_stack[$i];
if (is_array($child_array)) {
// Do things with $child_array,
// then remove the child array from $scripts_stack when done with (BELOW)
unset($scripts_stack[$i]);
} else {
$i++;
}
}
echo "Array Size : " . (sizeof($scripts_stack)); // AT THE END
May be you can use this script.It's not tested.
foreach($array as $key => $value ) {
unset($array[$key]);
echo $value." element is deleted from your array</br>";
}
I hope , it will help you.
The problem root is in comparing $i with sizeof($scripts_stack). Every step further sizeof($scripts_stack) becomes lower (it calculates at every step) and $i becomes higher.
The workaround may look like this:
<?php
$scripts_stack = [];
$array_item = array('script' => 1, 'handle' => 2, 'src' => 3);
array_push($scripts_stack, $array_item);
array_push($scripts_stack, $array_item);
array_push($scripts_stack, $array_item);
array_push($scripts_stack, $array_item);
array_push($scripts_stack, $array_item);
while (sizeof($scripts_stack) > 0) {
$child_array = array_shift($scripts_stack);
if (is_array($child_array)) {
// Do things with $child_array,
// then remove the child array from $scripts_stack when done with (BELOW)
}
}
echo "Array Size : " . (sizeof($scripts_stack)); // AT THE END
https://3v4l.org/N2p3v
How may i know that - In php how many times the foreach loop will get run, before that loop get executed..In other words i want to know the count of that particular loop. I want to apply some different css depends upon the count.
Use the function count to get the amount of numbers in your array.
Example:
$array = array('test1', 'test2');
echo count($array); // Echos '2'
Or if you want to be an engineer for-sorts you can set up something like so:
$array = array('test1', 'test2');
$count = 0;
foreach ($array as $a) { $count++; }
And that can count it for you, and the $count variable will hold the count, hope this helped you.
Simply count() the array and use the output as a condition, like:
if (count($array) > 100) {
// This is an array with more than 100 items, go for plan A
$class = 'large';
} else {
// This is an array with less than 100 items, go for plan B
$class = 'small';
}
foreach ($array as $key => $value) {
echo sprintf('<div id="%s" class="%s">%s</div>', $key, $class, $value);
}
I was wondering if PHP has a gracefull method to find the first, last and/or nth row in a foreach loop.
I could do it using a counter as follows:
$i = 0;
$last = count($array)-1;
foreach ($array as $key => $row) {
if ($i == 0) {
// First row
}
if ($i == $last) {
// Last row
}
$i++;
}
But somehow this feels like a bit of a dirty fix. Any solutions or suggestions?
Edit
As suggested in the comments I moved the count($array) outside the loop.
foreach ($array as $key => $row) {
$index = array_search($key, array_keys($array));
if ($index == 0) {
// First row
}
if ($index == count($array) - 1) {
// Last row
}
}
In php we have current and end function to get first and last value of array.
<?php
$transport = array('foot', 'bike', 'car', 'plane');
echo $first = current($transport); // 'foot';
echo $end = end($transport); // 'plane';
?>
Modified :
Easy way without using current or end or foreach loop:
$last = count($transport) - 1;
echo "First : $transport[0]";
echo "</br>";
echo "Last : $transport[$last]";
Using Arrays
For the first element in an array you can simply seek $array[0];. Depending on the array cursor you can also use current($array);
For the middle of an array you can use a combination of array_search() and array_keys().
For the end of an array you can use end($array); noting that this aslso moves the array cursor to the last element as well (as opposed to simply returning the value).
Using Iterators
However ArrayIterator's may also work well in your case:
The first element is available at ArrayIterator::current(); once constructed. (If you're halfway through the iterator you'll need to reset().)
For the n'th or a middle element you can use an undocumented Iterator::seek($index); method.
For the last element you can use a combination of seek() and count().
For example:
$array = array('frank' => 'one',
'susan' => 'two',
'ahmed' => 'three');
$arrayobject = new ArrayObject($array);
$iterator = $arrayobject->getIterator();
// First:
echo $iterator->current() . PHP_EOL;
// n'th: (taken from the documentation)
if($iterator->valid()){
$iterator->seek(1); // expected: two, output: two
echo $iterator->current() . PHP_EOL; // two
}
// last:
$iterator->seek(count($iterator)-1);
echo $iterator->current() . PHP_EOL;
$arr = ["A", "B", "C", "D", "E"];
reset($arr);
// Get First Value From Array
echo current($arr);
// Get Last Value From Array
echo end($arr);
Visit below link for details of above used functions.
reset() : http://php.net/manual/en/function.reset.php
current() : http://php.net/manual/en/function.current.php
end() : http://php.net/manual/en/function.end.php
I want to replace all array values with 0 except work and home.
Input:
$array = ['work', 'homework', 'home', 'sky', 'door']
My coding attempt:
$a = str_replace("work", "0", $array);
Expected output:
['work', 0, 'home', 0, 0]
Also my input data is coming from a user submission and the amount of array elements may be very large.
A bit more elegant and shorter solution.
$aArray = array('work','home','sky','door');
foreach($aArray as &$sValue)
{
if ( $sValue!='work' && $sValue!='home' ) $sValue=0;
}
The & operator is a pointer to the particular original string in the array. (instead of a copy of that string)
You can that way assign a new value to the string in the array. The only thing you may not do is anything that may disturb the order in the array, like unset() or key manipulation.
The resulting array of the example above will be
$aArray = array('work','home', 0, 0)
A loop will perform a series of actions many times. So, for each element in your array, you would check if it is equal to the one you want to change and if it is, change it. Also be sure to put quote marks around your strings
//Setup the array of string
$asting = array('work','home','sky','door')
/**
Loop over the array of strings with a counter $i,
Continue doing this until it hits the last element in the array
which will be at count($asting)
*/
for($i = 0; $i < count($asting);$i++){
//Check if the value at the 'ith' element in the array is the one you want to change
//if it is, set the ith element to 0
if ($asting[$i] == 'work' || $asting[$i] == 'home')
$asting[$i] = 0;
}
Here is some suggested reading:
http://www.php.net/manual/en/language.types.array.php
http://www.php.net/manual/en/language.control-structures.php
But if you are struggling on stuff such as looping, you may want to read some introductory programming material. Which should help you really understand what's going on.
A bit other and much quicker way, but true, need a loop:
//Setup the array of string
$asting = array('bar', 'market', 'work', 'home', 'sky', 'door');
//Setup the array of replacings
$replace = array('home', 'work');
//Loop them through str_replace() replacing with 0 or any other value...
foreach ($replace as $val) $asting = str_replace($val, 0, $asting);
//See what results brings:
print_r ($asting);
Will output:
Array
(
[0] => bar
[1] => market
[2] => 0
[3] => 0
[4] => sky
[5] => door
)
An alternative using array_map:
$original = array('work','home','sky','door');
$mapped = array_map(function($i){
$exclude = array('work','home');
return in_array($i, $exclude) ? 0 : $i;
}, $original);
you may try array_walk function:
function zeros(&$value)
{
if ($value != 'home' && $value != 'work'){$value = 0;}
}
$asting = array('work','home','sky','door','march');
array_walk($asting, 'zeros');
print_r($asting);
You can also give array as a parameter 1 and 2 on str_replace...
Just a small point to the for loop. Many dont realize the second comparing task is done every new iteration. So if it was a case of big array or calculation you could optimize loop a bit by doing:
for ($i = 0, $c = count($asting); $i < $c; $i++) {...}
You may also want to see http://php.net/manual/en/function.array-replace.php for original problem unless the code really is final :)
Try This
$your_array = array('work','home','sky','door');
$rep = array('home', 'work');
foreach($rep as $key=>$val){
$key = array_search($val, $your_array);
$your_array[$key] = 0;
}
print_r($your_array);
There are a few techniques on this page that make zero iterated function calls -- which is good performance-wise. For best maintainability, I recommend separating your list of targeted string as a lookup array. By modifying the original array values by reference, you can swiftly replace whole strings and null coalesce non-targeted values to 0.
Code: (Demo)
$array = ['work', 'homework', 'home', 'sky', 'door'];
$keep = ['work', 'home'];
$lookup = array_combine($keep, $keep);
foreach ($array as &$v) {
$v = $lookup[$v] ?? 0;
}
var_export($array);
Output:
array (
0 => 'work',
1 => 0,
2 => 'home',
3 => 0,
4 => 0,
)
You can very easily, cleanly extend your list of targeted strings by merely extending $keep.
If you don't want a classic loop, you can use the same technique without modifying the original array. (Demo)
var_export(
array_map(fn($v) => $lookup[$v] ?? 0, $array)
);
this my final code
//Setup the array of string
$asting = array('work','home','sky','door','march');
/**
Loop over the array of strings with a counter $i,
Continue doing this until it hits the last element in the array
which will be at count($asting)
*/
for($i = 0; $i < count($asting); $i++) {
//Check if the value at the 'ith' element in the array is the one you want to change
//if it is, set the ith element to 0
if ($asting[$i] == 'work') {
$asting[$i] = 20;
} elseif($asting[$i] == 'home'){
$asting[$i] = 30;
}else{
$asting[$i] = 0;
}
echo $asting[$i]."<br><br>";
$total += $asting[$i];
}
echo $total;