Results from an cURL request into a form - php

Question

As mentioned in my previous question I read about cURL and how to work with it. I got the request with the following API: api.openkvk.nl (it's in Dutch, sadly enough) working:
$get = $_POST['bedrijfsnaam'];
$get = str_replace(" ","%20",$get);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://api.openkvk.nl/php/SELECT%20*%20FROM%20kvk%20WHERE%20bedrijfsnaam%20=%20'$get'%20LIMIT%201;");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
print("<pre>"); print_r($result); print("</pre>");
$kvks = $result[0]["RESULT"]["ROWS"][0][2];
echo $kvks;
curl_close($ch);
and I got the results back in the following form:
array(array("RESULT"=>array("TYPES"=>array("bigint","varchar","int","int","varchar","varchar","varchar","varchar","varchar","varchar","bigint","varchar","decimal","decimal","date"),"HEADER"=>array("kvk","bedrijfsnaam","kvks","sub","adres","postcode","plaats","type","status","website","vestiging","rechtsvorm","lat_rad","lon_rad","anbi"),"ROWS"=>array(array("526937320000","Unicmedia","52693732","0","Terschellingstraat 12","1825ND","Alkmaar","Hoofdvestiging",NULL,NULL,"22611126",NULL,NULL,NULL,NULL)))))
What I want to do is the following:
Put this values from the database: kvks, adres, postcode and plaats in a form (so that I can edit them).
I don't know how to do this. Could you give me an explanation?
PS I'm new with API's so I don't understand everything yet.

Answer 1

Update:
Their API is returning it as a php string - change the part of your URL which says /php/ to /json/.
Then, make it so you have $result = json_decode(curl_exec($ch), true);
Now the array access should work.
To get the value of kvks, supposing the value you posted is the in $result, you'd use $kvks = $result[0]["RESULT"]["ROWS"][0][2].
(It looks like you're posting the result of a print_r - try encasing it in <pre> tags when you display it for a much more formatted result)
Since you have PHP getting the values, you could simply output an HTML form with them prefilled:
<form action="savedata.php" method="post">
<?php
echo "<input type='text' name='blah' value=\"" . htmlspecialchars($blah) ."\"><br>";
?>
Then, if $blah is asdf, this would output <input type='text' name='blah' value="asdf">.
When you submit it to your savedata.php method, you'd insert the modified values (now found through $_POST['blah']) into your database however you like.

Answer 2

From my experiments it seems this API is returning PHP code, this would have to be eval'd. eval is a very bad idea.
Can I suggest using the JSON method of the API instead, by replacing the /php/ with /json/
The API will then return a JSON string which you can decode into an object / array
You will also need to add curl_setop($ch, CURLOPT_RETURNTRANSFER,0); to your curl request
Here is some revised code
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://api.openkvk.nl/json/SELECT%20*%20FROM%20kvk%20WHERE%20bedrijfsnaam%20=%20'$get'%20LIMIT%201;");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
$result = curl_exec($ch);
curl_close($ch);
$apiResult = json_decode($result, true);
$apiResult will now contain an array with your result
A var_dump($apiResult) will give you
array
0 =>
array
'RESULT' =>
array
'TYPES' =>
array
...
'HEADER' =>
array
...
'ROWS' =>
array
...
Now that you have the array, you should easily be able to insert it into a DB.