Select xml node by attribute in php [duplicate] - php

Question

This question already has answers here:
SimpleXML: Selecting Elements Which Have A Certain Attribute Value
(2 answers)
Closed 2 years ago.
How do I find the node value by knowing the attribute value without traversing through every child and every attribute/value ?
$dom = new DOMDocument;
$dom->load('test.xml');
$rows = $dom->getElementsByTagName('row');
foreach ($rows as $row) {
$header = VALUE OF <field name="header">
$text = VALUE OF <field name="text">
}
XML:
<resultset>
<row>
<field name="item">2424</field>
<field name="header">blah blah 1</field>
<field name="text" xsi:nil="true" />
...
</row>
<row>
<field name="item">5321</field>
<field name="header">blah blah 2</field>
<field name="text">some text</field>
...
</row>
</resultset>

Answer 1

The simplest thing to do is use DOMXPath::querydocs
The following code finds all the <field> nodes within <row> nodes that have a name attribute equal to "header":
$dom = new DOMDocument;
$dom->loadXML($str); // where $str is a string containing your sample xml
$xpath = new DOMXPath($dom);
$query = "//row/field[#name='header']";
$elements = $xpath->query($query);
foreach ($elements as $field) {
echo $field->nodeValue, PHP_EOL;
}
Using the sample xml you provide, the above outputs:
blah blah 1
blah blah 2