passing and acting upon multiple json encoded strings - php

Question

function logsig() {
var username = $("#username").val();
var password = $("#password").val();
var dataString = '&username=' + username + '&password=' + password;
if(username=='' || password=='') {
$('#success').fadeOut(400).hide();
$('#error').fadeOut(400).show();
} else {
$.ajax({
type: "POST",
dataType: "JSON",
url: "<?=base_url()?>index.php/home/logsig",
data: dataString,
json: {session_state: true},
success: function(data) {
if(data.session_state == true) {
window.location = "<?=base_url()?>";
} else if(data.session_state == false) {
$("#login_failure").fadeIn(400);
}
}
});
}
}
How can I pass multiple json encoded values to my form above. What I'm doing is if user logs in, 'session_state' is passed, and if user has a 'pending' account, 'pending' is passed. Both json values have an expression to be executed.
public function logsig() {
header('Content-type:application/json');
$postedEmail = $this->input->post('username');
$password = $this->input->post('password');
$hashedPass = $this->encrypt->sha1($password);
$query = $this->db->query("SELECT * FROM users WHERE username = '{$postedEmail}' AND password = '{$password}'");
if ($query->num_rows() > 0) { // if user is already registered and is logging in, execute the following sql/php commands.
$row = $query->row();
if ($row->status == "pending") {
echo json_encode(array('pending' => true));
} else {
echo json_encode(array('pending' => false));
}
//$this->session->set_userdata('userid', $idgen);
//$this->session->set_userdata('email', $postedEmail);
$this->session->set_userdata('logged', "1"); // 1 means user is logged in.
echo json_encode(array('session_state' => true));
} else {
echo json_encode(array('session_state' => false)); // false sends to jquery that member isn't registered
}
}

Answer 1

You should collect all your data and at the end output it as the single JSON string. For example:
$output= array();
if ($query->num_rows() > 0) {
$row = $query->row();
// Status flag
$output['pending'] = $row->status == "pending";
$this->session->set_userdata('logged', "1"); // 1 means user is logged in.
// Session state
$output['session_state'] = true;
}
else {
$output['session_state'] = false;
}
header('Content-type: application/json');
die(json_encode($output));
Or in this case even better (optimized true-branch):
$row = $query->row();
$this->session->set_userdata('logged', "1"); // 1 means user is logged in.
// Session state
$output = array(
'pending' = $row->status == "pending",
'session_state' = false
);