MySQL live Query - php

Question

I wonder if someone can help i am trying to incorporate a live search into my website, I have found a tutorial and the appearance side of things is now working, could someone please tell me how i can edit the follow PHP to pull information from only one table.
Table - movies
Fields to echo for each result - Movie, description, Image
At the moment it is pulling information from 2 tables successfully one displays the content of the search the other provides information for category dividers, What i need is to remove the category aspect and pull information from the a single table.
Apologies my PHP knowledge is very limited, hope this best describes the problem.
<p id="searchresults">
<?php
// PHP5 Implementation - uses MySQLi.
// mysqli('localhost', 'yourUsername', 'yourPassword', 'yourDatabase');
$db = new mysqli('localhost', 'yourUsername', 'yourPassword', 'yourDatabase');
if(!$db) {
// Show error if we cannot connect.
echo 'ERROR: Could not connect to the database.';
} else {
// Is there a posted query string?
if(isset($_POST['queryString'])) {
$queryString = $db->real_escape_string($_POST['queryString']);
// Is the string length greater than 0?
if(strlen($queryString) >0) {
$query = $db->query("SELECT * FROM search s INNER JOIN categories c ON s.cat_id = c.cid WHERE name LIKE '%" . $queryString . "%' ORDER BY cat_id LIMIT 8");
if($query) {
// While there are results loop through them - fetching an Object.
// Store the category id
$catid = 0;
while ($result = $query ->fetch_object()) {
if($result->cat_id != $catid) { // check if the category changed
echo '<span class="category">'.$result->cat_name.'</span>';
$catid = $result->cat_id;
}
echo '<a href="'.$result->url.'">';
echo '<img src="search_images/'.$result->img.'" alt="" />';
$name = $result->name;
if(strlen($name) > 35) {
$name = substr($name, 0, 35) . "...";
}
echo '<span class="searchheading">'.$name.'</span>';
$description = $result->desc;
if(strlen($description) > 80) {
$description = substr($description, 0, 80) . "...";
}
echo '<span>'.$description.'</span></a>';
}
echo '<span class="seperator">Nothing interesting here? Try the sitemap.</span><br class="break" />';
} else {
echo 'ERROR: There was a problem with the query.';
}
} else {
// Dont do anything.
} // There is a queryString.
} else {
echo 'There should be no direct access to this script!';
}
}
?>
</p>

Answer 1

Replace
SELECT * FROM search s INNER JOIN categories c ON s.cat_id = c.cid WHERE name LIKE '%" . $queryString . "%' ORDER BY cat_id LIMIT 8
with
SELECT * FROM movies WHERE movie LIKE '%" . $queryString . "%' ORDER BY movie LIMIT 8
would be a good start.
Can you carry on from there?
Aside - you wrote 'Movie' for the field name in your description above - I've used a lower case 'M' so you may need to change it.
[edit] In reply to comment #1:
Let's start off simple - replace if ($query) { ... } with
if ($query) {
while ($result = $query ->fetch_object()) { // this line loops through all the results
echo '<img src="search_images/'.$result->image.' />'; // check capital I on 'image'
echo '<strong>'.$result->movie.'</strong>';
echo $result->description.'<br />';
}
}
Basically, you just put $result->myFieldName inside of the while loop to get the data out you want.
Hopefully that should be enough get you going =]

Answer 2

I guess:
<p id="searchresults">
<?php
// PHP5 Implementation - uses MySQLi.
// mysqli('localhost', 'yourUsername', 'yourPassword', 'yourDatabase');
$db = new mysqli('localhost', 'yourUsername', 'yourPassword', 'yourDatabase');
if(!$db) {
// Show error if we cannot connect.
echo 'ERROR: Could not connect to the database.';
} else {
// Is there a posted query string?
if(isset($_POST['queryString'])) {
$queryString = $db->real_escape_string($_POST['queryString']);
// Is the string length greater than 0?
if(strlen($queryString) >0) {
$query = $db->query("SELECT * FROM movies WHERE Movie LIKE '%" . $queryString . "%' ORDER BY Movie LIMIT 8");
if($query) {
// While there are results loop through them - fetching an Object.
while ($result = $query ->fetch_object()) {
echo '<a href="'.$result->url.'">';
echo '<img src="search_images/'.$result->img.'" alt="" />';
$name = $result->movie;
if(strlen($name) > 35) {
$name = substr($name, 0, 35) . "...";
}
echo '<span class="searchheading">'.$name.'</span>';
$description = $result->description;
if(strlen($description) > 80) {
$description = substr($description, 0, 80) . "...";
}
echo '<span>'.$description.'</span></a>';
}
echo '<span class="seperator">Nothing interesting here? Try the sitemap.</span><br class="break" />';
} else {
echo 'ERROR: There was a problem with the query.';
}
} else {
// Dont do anything.
} // There is a queryString.
} else {
echo 'There should be no direct access to this script!';
}
}
?>
</p>