Mongodb query from php - can't getting it working - php

Trying to do a simple mongodb query that drives me mad.... I have the following table/db:
[_id] => MongoId Object (
[$id] => 4f22efa1ef9dec8495b374bc
)
[h1] => a
[h2] => b
[h3] => c
[_id] => MongoId Object (
[$id] => 4f22efa1ef9dec8495b374bd
)
[h1] => d
[h2] => e
[h3] => f
Using the mongo tool command line and typing:
db.things.find({$or: [{'h1' : 'a'},{'h1': 'd'}]})
I get:
{ "_id" : ObjectId("4f22efa1ef9dec8495b374bc"), "h1" : "a", "h2" : "b", "h3" : "c" }
{ "_id" : ObjectId("4f22efa1ef9dec8495b374bd"), "h1" : "d", "h2" : "e", "h3" : "f" }
Which is fine. However trying doing the same from PHP, I get nothing ??:
$m = new Mongo();
$db = $m->selectDB('testdb');
$collection = new MongoCollection($db, 'things');
$query = array( '$or' => array( array('h1' => 'a')),
array('h1' => 'd'));
$cursor = $collection->find($query);
I do not see what I am doing wrong, but I have tried anything (or I think so) for 3 days now and it will not work. If I do queries using '>=' '<=' '<>' '<' '>' it works fine but using '=' as in this case it does not.
Thanks for your effort !

You're better off using $in for your given example, i.e.:
$collection->find(array('h1' => array('$in' => array('a', 'd'))));
As to why your query doesn't work - you're not using $or correctly (or infact, at all). This is the query you've put in the question reformatted:
$query = array(
'$or' => array(
array('h1' => 'a')
),
array('h1' => 'd')
);
Whereas you would need:
$query = array(
'$or' => array(
array('h1' => 'a'),
array('h1' => 'd')
)
);
If you have a look in the mongodb error log most likely it says something about that illegal loose top-level array in the conditions.

Related

PHP MongoDB find with multiple "AND" conditions?

After hours of experimentations and readings, I cannot find a solution to this problem:
I want to do a MongoDB->find($query) with multiple AND conditions.
For instance, say I want id = 5 and a < 6 and a > 2 and b > 10 and b < 20
I was expecting $query to be:
$query = array("id" => 5,
"a" => array('$gt' => 2,
'$lt' => 6),
"b" => array('$gt' => 10,
'$lt' => 20))
But this returns empty results with my DB
I tried various syntaxes such as:
$query = array("id" => 5,
array( "a" => array('$gt' => 2,
'$lt' => 6),
"b" => array('$gt' => 10,
'$lt' => 20)))
But this fails too.
Also tried with "$AND" variants, no luck.
Is it possible to "mix" several AND conditions in PHP-MongoDB find() requests?
I've just tested this using MongoDB PHP driver v1.6.11 (PHP-5.5.9). The test data are as below
db.collection.insert({id:5, a:4, b:15})
db.collection.insert({id:9, a:4, b:15})
db.collection.insert({id:5, a:4, b:20})
Using PHP code snippet:
$condition = array(
'$and' => array(
array(
"id" => 5,
"a" => array('$gt' => 2, '$lt' => 6),
"b" => array('$gt' => 10, '$lt' => 20)
)
)
);
$docs = $coll->find($condition);
foreach( $docs as $o=> $doc) {
echo json_encode($doc);
}
The above returns only the first document sample. This indicates that $and should work as expected. I've also tested without $and, i.e. :
$condition = array(
"id" => 5,
"a" => array('$gt' => 2, '$lt' => 6),
"b" => array('$gt' => 10, '$lt' => 20)
);
Which also works the same. Try checking your dataset, whether there is a document matching your criteria.
This issue is closed: bad value types in the DB (string instead of float/double). Works as expected when updating to correct types in DB.

Complex statement in MongoDB AND & OR conditions

Continuing on my project, I need to translate some SQL statements to mongoDB
My SQL Statement is:
Delete from 'table' where proc_id = $xxx and (day_id < $day OR day_id > $anotherDay)
Now my condition array is this:
$condicion = array(
'proc_id' => $xxx,
'$or' => array(
'day_id' => array(
'$lt' => $day,
'$gt' => $anotherDay
)
)
);
The function made for delete in mongo collections returns cannot delete...
Some help please?
Each "day_id" would be in it's own $or argument:
$query = array(
'proc_id' = > $xxx,
'$or' => array(
array( 'day_id' => array ( '$lt' => $day ) ),
array( 'day_id' => array ( '$gt' => $anotherDay ) ),
)
)
That is how $or conditions work as a "list" of possible expressions.
The JSON syntax is clearer to visualise:
{
"proc_id": $xxx,
"$or": [
{ "day_id": { "$lt": $day } },
{ "day_id": { "$gt": $anotherDay }}
]
}
Since there is a very clear distinction between a "list" and an "object" definition. $or conditions are "lists" of "objects", and that means you list the full condition just as if it were a query in itself. Since this is not called within an $elemMatch.
And of course the "DELETE" part is the .remove() method:
$collection->remove($query)
There are general examples and resources in the core documentation SQL to MongoDB Mapping Chart, where if the examples there do not immediately help, the linked articles and presentations should.

mongodb: update nested document by an array?

I have a deeply nested PHP array which I saved as a document in Mongo and ended up with this structure:
{
"_id" : "...",
"categ1" : {
"aaa" : 112.6736,
"bbb" : 83.9137,
"ccc" : 80.3322,
.....
},
"categ2" : {
"xxx" : 1,
"yyy" : 22,
"zzz" : 7,
"subcateg" : {
"sub1" : 1,
"sub2" : 22
}
}
}
Now, I have another array with a similar structure and I would like to increase the values of the record, by the values of the modifier array:
$modifier=array(
'categ1' => array(
'aaa' => 3,
'bbb' => -1,
'mmm' => 11
),
'categ2' => array(
'yyy' => -2,
'subcateg' => array(
'sub1' => -1
)
)
);
How can I increase the values inside the document by the values of the $modifier all at once, in a single query, and without loading the entire document ?
I've looked around the web but couldn't find any info on this.
Also, i'm pretty newbie at Mongo. Thanks
You can get your $modifier array to look like this:
$modifier = array(
'categ1.aaa' => 3,
'categ1.bbb' => -1,
'categ1.mmm' => 11,
'categ2.yyy' => -2,
'categ2.subcateg.sub1' => -1
)
Link for how to get that.
Then you should be able to simply use:
$col->update(
array("_id" => "..."),
array('$inc' => $modifier),
array("upsert" => true)
);

cakephp OR condition

Originaly posted on cakephp Q&A but i'll put it up here in hope of getting some answers.
I have a bunch of companies that has a status of 0 as default but sometimes get a higher status. Now i want to use the high status if exists but revert to 0 if not. i have tried a bunch of different approaches but i always get either only the ones with status 0 or the ones with the status i want, never giving me status if exists and 0 if not.
Gives me only the status i specify, not giving me the ones with status 0:
'Company' => array (
'conditions' => array (
'OR' => array(
'Company.status' => 0,
'Company.status' => $status,
)
)
)
Gives me only status of 0:
'Company' => array (
'conditions' => array (
'OR' => array(
'Company.status' => $status,
'Company.status' => 0
)
)
)
Status definition and retrieving data in code:
function getCountry($id = null, $status = null) {
// Bunch of code for retrieving country with $id and all it's companies etc, all with status 0.
$status_less_companies = $this->Country->find...
if ($status) {
$status_companies = $this->Country->find('first', array(
'conditions' => array(
'Country.id' => $id
),
'contain' => array(
'Product' => array (
'Company' => array (
'conditions' => array (
'OR' => array(
'Company.status' => $status,
'Company.status' => 0
)
)
)
)
)
)
}
// Mergin $status_less_companies and $status_companies and returning data to flex application.
}
I changed the name for the models for this question just to make more sense, people are generaly frighten away when i tell them i work with cakephp for my flex application. I guess the logic to this question doesn't make sense but trust me that it makes sense in my application.
Thanks!
Try
'Company' => array (
'conditions' => array (
'OR' => array(
array('Company.status' => 0),
array('Company.status' => $status),
)
)
)
In the cookbook it says to wrap the or conditions in arrays if they are pertaining to the same field
http://book.cakephp.org/2.0/en/models/retrieving-your-data.html#complex-find-conditions
I'm not sure to have understood what results you expect. If you want to retrieve all records having status = 0, plus let's say the one having status = 3, you could use an 'IN' instead of an 'OR'.
In Cake, you would write it like this:
$status = 3;
$conditions = array('Company.status' => array(0, $status));
You can also fetch record by using following method:
put values in an array
e.g. $arr=array(1,2);
$res = $this->Model->find('all', array(
'conditions' =>array('Model.filedname'=>$arr),
'model.id' => 'desc'
));
I hope you will find answer.
$this->loadModel('Color');
$colors = $this->Color->find('all', [
'conditions' => [
'Color.is_blocked' => 0,
'Color.is_deleted' => 0,
'OR' => [
[
'Color.isAdmin' => $user_data['id'],
],
[
'Color.isAdmin' => 0,
]
],
]
]);

Find Records in Mongo DB with PHP where ID != X

is it possible to find all records in an collection where the MongoID is not in
an provided array?
Something like this (?):
$search = array(
'_id' => array('$ne' => $ids)
'readby' => array('$ne' => $userId) // works
);
Iam using PHP with the Mongo Extension.
Use $nin instead of $ne with arrays. Something like:
$search = array(
'_id' => array('$nin' => $ids),
'readby' => array('$ne' => $userId)
);
should do what you want.

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