Display MySQL Database as an array - php

I have a MySQL database full of user information, like their username, password, email, etc.
I want a PHP script that allows me to pull JUST their username and display it like so:
"username1","username2","username3"
Literally exactly like that, the quotes and all.
EDIT: Sorry for not supplying enough information.
The table is named "users" the field I want to pull off it is "username" I can get it to pull and display all the information, my only problem is imploding it.

OK dude, read the comments
<?php // open a php tag
$dbc = mysql_connect("host", "username", "password"); // connect to database
mysql_select_db("db_name", $dbc) // select the database
$sql = "SELECT `username` FROM `users_table`"; // select only the username field from the table "users_table"
$result = mysql_query($sql); // process the query
$username_array = array(); // start an array
while($row = mysql_fetch_array($result)){ // cycle through each record returned
$username_array[] = "\"".$row['username']."\""; // get the username field and add to the array above with surrounding quotes
}
$username_string = implode(",", $username_array); // implode the array to "stick together" all the usernames with a comma inbetween each
echo $username_string; // output the string to the display
?>

I've seen all the other answers, however have you considered using PDO instead of mysql_query functions? It's a much nicer way to work with the database.
Here's what you want to achieve in a few lines of code (using lamba functions):
$dbh = new PDO("mysql:host=localhost;dbname=test", "yourusername", "yourpassword");
$results = $dbh->prepare("SELECT u.username FROM users u");
$results->execute();
$results = $results->fetchAll();
echo implode(", ", array_map(function(&$r) { return $r['username']; }, $results));
Output: Jamie, Bob, Chris
Nice and clean. Also, you should check if you have any results that have been returned and if the query was successful.
Just another approach.
EDIT: I've just realised you're a beginner so my answer may be a bit too advanced. However, i'll leave it for others to see as a solution, and perhaps you might look into using PDO an lamba functions when you learn a bit more. Best of luck.

Let's assume that you have a 'mydb' database and 'users' table in it.
SQL needed:
USE mydb;
SELECT username from users;
Short version:
Wrap it in PHP calls to mysql PHP library
Get result as an array then implode it with comma symbol.
Long version:
First we need to connect to database:
$db = mysql_connect('DATABASE_HOST', 'USER', 'PASSWORD');
if (!$db) {
die('Not connected : ' . mysql_error());
}
$db_selected = mysql_select_db('mydb', $db);
if (!$db_selected) {
die ('Can\'t use mydb: ' . mysql_error());
}
Remember to always check the return values of functions.
Then we query the database:
$result = mysql_query('select username from users', $db);
...and fetch results in flat array (we need only usernames):
while ($row = mysql_fetch_array($result, MYSQLI_ASSOC))
{
$data[] = $row['login'];
}
Then we format the returned data according to your specs:
$string_result = '"'. implode('", "', $data) . '"';
You can do with $string_result anything you want, just close the database connection immediately after use:
mysql_close($db);
Good luck with learning PHP, BTW. ;)

You could using PHP's implode, but it's probably easier just do it in SQL assuming that the list won't be too long:
SELECT GROUP_CONCAT(CONCAT('"', username, '"')) AS usernames
FROM your_table

Related

mysql vs mysqli config file and queries

I need start using the mysqli extension but I'm finding all kinds of conflicting info depending on how all the info is that I'm trying to use.
For example, my header connects to a 'config.php' file that currently looks like this:
<?php
$hostname_em = "localhost";
$database_em = "test";
$username_em = "user";
$password_em = "pass";
$em = mysql_pconnect($hostname_em, $username_em, $password_em) or trigger_error(mysql_error(),E_USER_ERROR);
?>
But when I go to php.net I see that I should be using this but after updating everything I get no database.
<?php
$mysqli = new mysqli("localhost", "user", "password", "database");
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
echo $mysqli->host_info . "\n";
$mysqli = new mysqli("127.0.0.1", "user", "password", "database", 3306);
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
echo $mysqli->host_info . "\n";
?>
I also went through and added an "i" to the following code in my site and again no luck:
mysql_select_db($database_em, $em);
$query_getReview =
"SELECT
reviews.title,
reviews.cover_art,
reviews.blog_entry,
reviews.rating,
reviews.published,
reviews.updated,
artists.artists_name,
contributors.contributors_name,
contributors.contributors_photo,
contributors.contributors_popup,
categories_name
FROM
reviews
JOIN artists ON artists.id = reviews.artistid
JOIN contributors ON contributors.id = reviews.contributorid
JOIN categories ON categories.id = reviews.categoryid
ORDER BY reviews.updated DESC LIMIT 3";
$getReview = mysql_query($query_getReview, $em) or die(mysql_error());
$row_getReview = mysql_fetch_assoc($getReview);
$totalRows_getReview = mysql_num_rows($getReview);
And here's the only place on my display page that even mentions mysql so far:
<?php } while ($row_getReview = mysql_fetch_assoc($getReview)); ?>
I did see something at oracle that another stackoverflow answer pointed someone to that updates this stuff automagically, but I have so little code at this point it seems like overkill.
Adding an i to any mysql function won't make it a valid mysqli function. Even if such function exists, maybe the parameteres are different. Take a look here http://php.net/manual/en/book.mysqli.php and take some time to check mysqli functions. Maybe try some examples to become familiar with the way things work. I also reccomend you to choose either object oriented code, either procedural. Don't mix them.
I just made the switch to mysqli lately, took me a few hours to wrap my head around it. It works well for me, hope it will help you out a bit.
Here the function to connect to the BD:
function sql_conn(){
$sql_host = "localhost";
$sql_user = "test";
$sql_pass = "pass";
$sql_name = "test";
$sql_conn = new mysqli($sql_host, $sql_user, $sql_pass, $sql_name);
if ($sql_conn->connect_errno) error_log ("Failed to connect to MySQL: (" . $sql_conn->connect_errno . ") " . $sql_conn->connect_error);
return $sql_conn;
}
This will return a Mysqli Object that you can use to make you request afterward. You can put it in your config.php and include it or add it at the top of your file, whatever works the best for you.
Once you have this object, you can use it to make your query against the object like so: (in this case, if an error came up it will be outputted in the error_log. I like having it there, you can echo it instead.
//Use the above function to create the mysqli object.
var $mysqli = sql_conn();
//Create the query string (truncated for the example)
var $query = "SELECT reviews.titl ... ... ted DESC LIMIT 3";
//Launch the query on the mysqli object using the query() method
if(!($results = $mysqli->query($query))){
//It it fails, log the error
error_log(mysqli_error($mysqli));
}else{
//Manipulate your data.
//here it depends on what you retunr, a single value, row or a list of rows.
//Example for a set of rows
while ($record = $results->fetch_object()){
array_push($array, $record);
}
}
//Just to show, this will output the array:
print_r($array);
//Close the connection:
$mysqli->close();
So basically, in mysqli, you create an object and use the method to work your way out.
Hope this helps. Once you figured it out, you will most likely enjoy mysqli more that mysql. I did anyway.
PS: Please note that this was copy/pasted from existing, working code. Might have some typo, and might forgot to change a var somewhere, but it's to give you an idea of how mysqli works. Hope this helps.

Basic MySQL help? - submitting data

I've been getting better at PHP - but I have NO idea what I'm doing when it comes to MySQL.
I have a code
<IMG>
I need to grab the "for", "affi" and "reff" and input them into a database
//Start the DB Call
$mysqli = mysqli_init();
//Log in to the DB
if (!$mysqli) {
die('mysqli_init failed');
}
if (!$mysqli->options(MYSQLI_INIT_COMMAND, 'SET AUTOCOMMIT = 0')) {
die('Setting MYSQLI_INIT_COMMAND failed');
}
if (!$mysqli->options(MYSQLI_OPT_CONNECT_TIMEOUT, 5)) {
die('Setting MYSQLI_OPT_CONNECT_TIMEOUT failed');
}
if (!$mysqli->real_connect('localhost', 'USERNAME', 'PASSWORD', 'DATABASE')) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
That's what I'm using to create a connection. It works. I've also got a table created, call it "table", with rows for "for", "affi", and "reff".
So my question is... someone gets directed to http://www.example.com/test.php?for=abcde&affi=12345&reff=foo
Now that I've got a DB connection open - how do I SEND that data to the DB before redirecting them to their destination site? They click - pass across this page - get redirected to destination.
BONUS KARMA - I also need a separate PHP file that I can create that PULLS from that data base. If you could point me at some instructions or show me a simple "how to pull this rows values from this table" I would be greatly appreciative :)
If I understand correctly, you'll want to use $_GET to get the URL parameters.
Then you want to run an insert query on the db with the values you got, which should be something like:
INSERT INTO table VALUES(x, y, z)
Then you need to change the page using a location header.
For the bonus question you just need the code you have now with a select query like:
SELECT * FROM table WHERE 1;
and then fetch the query results.
If this does not answer your questions please provide some clarifications.
Mysqli is the deprecated function and now PDO is recommended to connect to database. You could do following.
<?php
$conn = new PDO('dblib:host=your_hostname;dbname=your_db;charset=UTF-8', $user, $pass);
$sql = "SELECT * FROM users WHERE username = '$username'";
$result = $conn->query($sql);
?>
Read more here.

Mysql Query, comparing values and assigning to PHP variables

I have done a fair bit of research into what i want to do, although i haven't found anything. I am not too sure if i am looking for the right thing :( I am also a little bit new to PHP and MySQL syntax, so please be kind.
I wish to perform the following in this order:
Connect to a database (DONE)
Query for a specific string (I think im done)
From here is gets a bit fuzzy :(
If a match is found for the variable, copy the whole row (I need other variables).
Assign the values from the SQL query to a PHP variables.
From there i will be right to carry on.
I have established the connection to the database with the following:
function connect() {
$dbname = 'database';
$dbuser = 'username';
$dbpass = 'password';
$dbhost = 'localhost';
mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
}
And then calling the function connect();
I then wish to query the database for a particular value, for the sake of this argument i will use a static value. This is what i have:
mysql_select_db(DATABASENAME) or die( "Unable to select database");
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE 'VAULE'";
$result=mysql_query($query);
From here i am not too sure how to compare the query result to see if it is a match (something along the lines of mysql rows?).
If there is a match, then i would like to obtain the entire row, and assign each value to a php variable.
I am not asking for you to do it for me, simply i kick in the right direction should be fine!
Hope it explains it enough :)
Thanks for your kind guidance
Ok. You will want to keep the connection to the mysql database somewhere. A common use is $conn.
So you would have
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
Then, either from the URL or Post, or just some variables you have sitting in your php file, you can query the database by putting the variables in the query itself. Also, here you can use $conn so that you have one place to connect to the database, in an include for example, and you won't have to make all of the connection string in each place you need to connect to the DB.
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%" . $varToCompare . "%'";
$result=mysql_query($query,$conn);
Above you are using a like. You may want to just look at doing .. Where column=$var.
Then you can use php to spin through the results into an array (for queries where would get multiple rows).
Where the hell you learned how to use MySQL in PHP ? The mysql_* functions are more then 10 years old and not maintained anymore. Community has already begun to work on deprecating them.
You should be using PDO or MySQLi for that.
// connection to database
$db = new PDO('mysql:host=localhost;dbname=datadump_pwmgr;charset=UTF-8',
'datadump_pwmgr',
'kzddim05xrgl');
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
// setting up prepared statement for the query
$statement = $db->prepare('SELECT * FROM table WHERE column LIKE :value');
$statement->bindParam(':value', $some_variable, PDO::PARAM_STR, 127);
// executing query and fetching first result
if ( $statement->execute())
{
$data = $statement->fetch(PDO::FETCH_OBJ);
var_dump( $data );
}
This should give you something like what you needed. Though, I would recommend to try this tutorial. And learning more about prepared statements could be useful too.
Also , if you are working with objects, then it is possible to create a single DB connection object , and pass it to multiple other classes to use it:
$pdo = new PDO('sqlite::memory:');
$a = new Foo( $pdo );
$b = new Bar( $pdo, 'something');
This way you pass both objects the same database connection, and you do not need to reinitialize it.
I think you're looking for something like this:
$count = mysql_num_rows($result);
//if there is more then 1 record retrieved from the database
if($count > 0)
{
//Do what ever you want to do here, which I think you want to be
while ($row = mysql_fetch_assoc($result))
{
echo $row["Columnname1"];
echo $row["Columnname2"];
echo $row["Columnname3"];
}
}
else
{
echo "There are no matches for this specific value";
}
You can get the queried data by rows as an associated array using mysql_fetch_array():
$row = 0;
$data = mysql_query("SELECT name1,name2 FROM ....");
while(($result = mysql_fetch_array($data)) !== false)
{
echo "row = $row, name1 = " . $result["name1"] . ", name2 = " . $result["name2"];
$row ++;
}
... or as an objects using mysql_fetch_object():
$row = 0;
$data = mysql_query("SELECT name1,name2 FROM ....");
while(($result = mysql_fetch_object($data)) !== false)
{
echo "row = $row, name1 = $result->name1, name2 = $result->name2";
$row ++;
}
I'm not too sure of what you want, but I can see one probable bug here: you're using LIKE in a way which means =: in order to have LIKE to behave like a like, you need some joker chars :
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE 'VAULE'" // This will return all rows where column='VAUL'
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE%'" // This will return all rows where column='%VAUL%' // This will return any row containing 'VAUL' in column
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE'" // This will return all rows where column='%VAUL' // this will return all rows ending by VAUL. I guess you get it now :)
An to retrieve the actual results:
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE%'";
$result=mysql_query($query);
while (false !== ($row = mysql_fetch_assoc($result))) {
//here $row is an array containing all the data from your mysql row
}
Try to write the database connection in another page no need to use function and include that page in where ever you need.
ex: require_once 'dbConnect.php';
dbConnect.php consists:
<?php
$dbname = 'datadump_pwmgr';
$dbuser = 'datadump_pwmgr';
$dbpass = 'kzddim05xrgl';
$dbhost = 'localhost';
mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
?>

INSERT IGNORE In mySQL

I wonder whether someone can help me please.
I'm trying to put together a PHP script that takes data from an xml file and places the data in a mySQL data. I've been working on this for a few days and I'm still can't seem to get this right.
This is the code that I've managed to put together:
<?
$objDOM = new DOMDocument();
$objDOM->load("xmlfile.xml");
$Details = $objDOM->getElementsByTagName("Details");
foreach( $Details as $value )
{
$listentry = $value->getElementsByTagName("listentry");
$listentrys = $listentry->item(0)->nodeValue;
$sitetype = $value->getElementsByTagName("sitetype");
$sitetypes = $sitetype->item(0)->nodeValue;
$sitedescription = $value->getElementsByTagName("sitedescription");
$sitedescriptions = $sitedescription->item(0)->nodeValue;
$siteosgb36lat = $value->getElementsByTagName("siteosgb36lat");
$siteosgb36lats = $siteosgb36lat->item(0)->nodeValue;
$siteosgb36lon = $value->getElementsByTagName("siteosgb36lon");
$siteosgb36lons = $siteosgb36lon->item(0)->nodeValue;
//echo "$listentrys :: $sitetypes :: $sitedescriptions :: $siteosgb36lats :: $siteosgb36lons <br>";
}
require("phpfile.php");
//Opens a connection to a MySQL server
$connection = mysql_connect ("hostname", $username, $password);
if (!$connection) {
die('Not connected : ' . mysql_error());
}
// Set the active MySQL database
$db_selected = mysql_select_db($database, $connection);
if (!$db_selected) {
die ('Can\'t use db : ' . mysql_error());
}
mysql_query("INSERT IGNORE INTO scheduledsites (listentry, sitetype, sitedescription, siteosgb36lat, siteosgb36lon) VALUES('$listentrys','$sitetypes','$sitedescriptions','$siteosgb36lats','$siteosgb36lons') ")
or die(mysql_error());
echo "Data Inserted!";
?>
I can pull the data from the xml file, but it's the part of the script that sends the data to my database table that I'm having trouble with.
The script runs but only the last record is saved to the database.
I can parse the fields from the xml file without any problems and the check I'm trying to put in place is, if there is a 'listentry' number in the new data that is matched to one already in the table then I don't want that record to be added to the table, i.e. ignore it.
I just wondered whether someone could perhaps take a look at this please and let me know where I'm going wrong.
Many thanks
You are only calling mysql_query once. So it will only insert one row.
The sql needs to be inside the loop.

Basic SQL output question

this is probably the most basic question in the world, but I cannot figure it out.
I would like to simply display a users First name, and Email adress from my table. I have tried using a loop, but that was entirely worthless considering I am only selecting one row. I know this is a menial question but I could not find/remember how to do it. Thank you!
$db = mysql_connect("server","un", "pw");
mysql_select_db("db", $db);
$sql = "SELECT FirstName, EmailAddress"
. " FROM Student"
. " WHERE StudentID = '$student' ";
$result = mysql_query($sql, $db);
$num = mysql_num_rows($result);
$userinfo = mysql_result($result,$userinfo);
$student is a session variable. I want to echo the First name and email address somewhere in the page, but I cannot believe how much pain thats causing me. Thanks again!
mysql_fetch_assoc() turns a result row into an array.
$result = mysql_query($sql, $db);
$user = mysql_fetch_assoc($result);
echo $user['FirstName'];
echo $user['EmailAddress'];
It looks like you spelled address wrong, so it probably doesn't match your real column name. More importantly, your code appears vulnerable to SQL injection. You really need to use prepared statements (see How to create a secure mysql prepared statement in php?) or escaping.
To fetch a row, you must use one of the mysql_fetch functions (e.g. mysql_ fetch_ array, mysql_ fetch_ object, etc.)

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