Fixtures PHP algorithm - php

Struggling with this tournament fixtures algorithm.
The code is working perfectly but I need help inserting the data to mysql
I cant seem to access the $varables..
any tweaking by a php pro greatly appreciated ...
$teamnames = "Arsenal|Tottenham|Leeds|Man United|Liverpool";
# XXX check for int
print show_fixtures(isset($_GET['teams']) ? nums(intval($_GET['teams'])) : explode("|", trim($teamnames)));
function nums($n) {
$ns = array();
for ($i = 1; $i <= $n; $i++) {
$ns[] = $i;
}
return $ns;
}
function show_fixtures($names) {
$teams = sizeof($names);
print "<p>Fixtures for $teams teams.</p>";
// If odd number of teams add a "ghost".
$ghost = false;
if ($teams % 2 == 1) {
$teams++;
$ghost = true;
}
// Generate the fixtures using the cyclic algorithm.
$totalRounds = $teams - 1;
$matchesPerRound = $teams / 2;
$rounds = array();
for ($i = 0; $i < $totalRounds; $i++) {
$rounds[$i] = array();
}
for ($round = 0; $round < $totalRounds; $round++) {
for ($match = 0; $match < $matchesPerRound; $match++) {
$home = ($round + $match) % ($teams - 1);
$away = ($teams - 1 - $match + $round) % ($teams - 1);
// Last team stays in the same place while the others
// rotate around it.
if ($match == 0) {
$away = $teams - 1;
}
$rounds[$round][$match] = team_name($home + 1, $names)
. " v " . team_name($away + 1, $names);
}
}
// Interleave so that home and away games are fairly evenly dispersed.
$interleaved = array();
for ($i = 0; $i < $totalRounds; $i++) {
$interleaved[$i] = array();
}
$evn = 0;
$odd = ($teams / 2);
for ($i = 0; $i < sizeof($rounds); $i++) {
if ($i % 2 == 0) {
$interleaved[$i] = $rounds[$evn++];
} else {
$interleaved[$i] = $rounds[$odd++];
}
}
$rounds = $interleaved;
// Last team can't be away for every game so flip them
// to home on odd rounds.
for ($round = 0; $round < sizeof($rounds); $round++) {
if ($round % 2 == 1) {
$rounds[$round][0] = flip($rounds[$round][0]);
}
}
// Display the fixtures
for ($i = 0; $i < sizeof($rounds); $i++) {
print "<hr><p>Round " . ($i + 1) . "</p>\n";
foreach ($rounds[$i] as $r) {
print $r . "<br />";
}
print "<br />";
}
print "<hr>Second half is mirror of first half";
$round_counter = sizeof($rounds) + 1;
for ($i = sizeof($rounds) - 1; $i >= 0; $i--) {
print "<hr><p>Round " . $round_counter . "</p>\n";
$round_counter += 1;
foreach ($rounds[$i] as $r) {
print flip($r) . "<br />";
}
print "<br />";
}
print "<br />";
if ($ghost) {
print "Matches against team " . $teams . " are byes.";
}
}
function flip($match) {
$components = split(' v ', $match);
return "$components[1]" . " v " . "$components[0]";
}
function team_name($num, $names) {
$i = $num - 1;
if (sizeof($names) > $i && strlen(trim($names[$i])) > 0) {
return trim($names[$i]);
} else {
return "BYE";
}
}

I'm not entirely sure what you're hung up on (you should really be more specific in your questions, as specified by the FAQ), but I suspect it is a matter of scope.
When you set a variable within a function, that variable is only accessible within that function. For example:
function do_something() {
$a = 'something!';
}
do_something();
echo $a;
This should result in PHP notice telling you that PHP doesn't know what $a is in the scope that it is trying to echo. Now, if I modify this script...
$a = '';
function do_something() {
global $a; // Lets PHP know we want to use $a from the global scope
$a = 'something!';
}
do_something();
echo $a;
This will work and output "something!", because $a is being "defined" in the scope outside of the function.
You can read more about variable scope in the PHP documentation: http://php.net/manual/en/language.variables.scope.php
Now, something else you need to pay attention to is outputting user data. In your script, you take data straight from $_GET and print it out to the page. Why is this bad? Someone could inject some nice JavaScript into your page (or anything they wanted) and steal users' sessions. You should be using htmlspecialchars() any time you need to output a variable. Even if it is just a team name, you never know when some team will stick a ; or < or > or some other reserved character in there.
Finally, I strongly recommend not mixing your logic with your computation. Let your program figure everything out, and then loop through the data for your output. You should be able to save the entire data for this type of problem in a nice associative array, or some crafty object you come up with.

Related

Why can't I use a function to simplify my "for loops"

I build a webpage to crack simple MD5 hash of a four digit pin for fun. The method I used was basically try all combination and check against the MD5 value the user has entered. Below is the PHP code I created to accomplish the goal.
Debug Output:
<?php
$answer = "PIN not found";
if (isset($_GET['md5'])) {
$txt = 'abcdefjhig';
$time_pre = microtime(TRUE);
$value = $_GET['md5'];
$show = 15;
for ($i = 0; $i <= 9; $i++) {
$first = $i;
for ($j = 0; $j <= 9; $j++) {
$second = $j;
for ($k = 0; $k <= 9; $k++) {
$third = $k;
for ($x = 0; $x <= 9; $x++) {
$fourth = $x;
$whole = $first . $second . $third . $fourth;
$check = hash('md5', $whole);
if ($check == $value) {
$answer = $whole;
echo "The pin is $answer";
}
if ($show > 0) {
print"$check $whole \n";
$show = $show - 1;
}
}
}
}
}
echo "\n";
$time_post = microtime(TRUE);
print "Elapsed time:";
print $time_post - $time_pre;
}
?>
Notice that in the middle there are four very similar for loops,I tried to simplify this by using functions, but it just returns one four digit number which is 9999 instead of all of them.
Below is the function I created:
function construct($input){
for($i=0; $i<=9, $i++){
$input=$i;
}
return $input
}
Then I tried to call this function for four times to form all of the four digit numbers but it just gives me 9999. Can anybody help? Thanks a lot.
Try this:
for ($i=0; $i<=9999 ; $i++) {
$whole = sprintf('%04d', $i);
$check=hash('md5', $whole);
if($check==$value){
$answer=$whole;
echo "The pin is $answer";
break; //remove this if you do not want to break the loop here
}
if ($show>0) {
print"$check $whole \n";
$show=$show-1;
}
}
You're using numbers from 0 to 9999, so why just loop through those numbers? You can add zero's by using str_pad() like so:
for ($i = 0; $i <= 9999; $i++) {
$whole = str_pad($i, 4, '0', STR_PAD_LEFT);
}
Also I'd like to mention that you really should think about better formatting of your code, especially indentation

PHP: Getting random combinations to specified input

I am trying to display possibilities for additions of specific numbers but have not been getting the right results.
<?php
$num3 = 20;
$set = null;
$balance = $num3;
$dig = mt_rand(1,5);
for($i = $balance; $i > 0; $i -= $dig ){
echo $dig.'<br>';
if($i < 1){
$set .= $i;
$balance = 0;
}
else{
$set .= $dig.'+';
$dig = mt_rand(1,5);
}
}
echo $set.'='.$num3;
?>
Here are some of the outputs:
2+5+1+4+5+3+=20
1+4+3+5+3+=20
3+1+1+2+3+4+4+1+3+=20
Appreciate any pointers. Thank in advance...
Ok, even though the requirement isn't completely clear, here's an approach:
(edit: demonstrating prevention of endless loop)
$max_loops = 1000;
$balance = 20;
$found = [];
while($balance > 0 && $max_loops-- > 0) {
$r = mt_rand(1, 5);
if ($balance - $r >= 0) {
$found[] = $r;
$balance -= $r;
}
}
echo implode(' + ', $found) . ' = '.array_sum($found);
Note: This code has a small risk of getting caught in an endless loop... though it's doubtful that it'll ever happen :)
Edit: Now the loop contains a hard-limit of 1000 iterations, after which the loop will end for sure...
To provoke an endless loop, set $balance = 7 and modify mt_rand(4, 5).
You can use a recursive function for this:
function randomAddends($target, $maxAddend = 5, $sum = 0, $addends = [])
{
// Return the array of addends when the target is reached
if ($target <= $sum) {
return $addends;
}
// generate a new random addend and add it to the array
$randomAddend = mt_rand(1, min($maxAddend, $target - $sum));
$addends[] = $randomAddend;
// make the recursive call with the new sum
return randomAddends($target, $maxAddend, $sum + $randomAddend, $addends);
}

I'm new to PHP and I created a For loop and would like to know if anyone knows how to re-write it to a while loop?

This is the code I have. It currently works as is, However I'm experimenting with loops and want to see it can be done with a while loop and how it would be done. With this code I can take 2 input numbers and display them, then point out all odds, add all evens, and add all the squares of the odds.
define ("B","<br/>");
$firstNum = $_POST["firstNum"];
$secondNum = $_POST["secondNum"];
if ($firstNum < $secondNum)
{
$firstNum = true;
}
elseif ($firstNum >= $secondNum)
{
$firstNum = "You didn't listen, dumb dumb!".'<br/>GO BACK';
}
echo "First Number: ".$firstNum."<br/>"."Second Number: ".$secondNum;
echo B;
echo B;
$numbers = array();
$numbers = range($firstNum, $secondNum);
$length = count($numbers);
$odds = array();
$sumSqOdds = 0;
$sumEven = 0;
$j = 0;
for ($x = 0; $x < $length; $x++)
{
if (($numbers[$x] % 2) == 1)
{
$odds[$j] = $numbers[$x];
$sumSqOdds = $sumSqOdds + pow ($numbers[$x], 2);
$j++;
}
else
{
$sumEven = $sumEven + $numbers[$x];
}
}
$x = 0;
$y = 0;
printf("The odd numbers between your integers are: ");
for ($x = 0; $x < $j; $x++)
{
echo $odds[$x];
echo ' ';
$y++;
if (($y % 10) == 0)
{
echo B;
}
}
echo B;
echo B;
printf("The sum of all even numbers between your integers is: ".$sumEven);
echo B;
echo B;
printf("The sum of the square of the odd numbers between your integers is: ".$sumSqOdds);
Here is my while loop but it seems to be infinite...
$numW = array ();
$numW = range ($firstNum, $secondNum);
$lengthW = count ($numW);
$oddsW = array ();
$sumSqOddsW = 0;
$sumEvenW = 0;
$j = 0;
$x = 0;
while ($x < $lengthW)
{
if (($numW[$x] % 2) == 1)
{
$oddsW[$j] = $numW[$x];
$sumSqOddsW = $sumSqOddsW + pow ($numW[$x], 2);
$x++;
$j++;
}
else
{
$sumEvenW = $sumEvenW + $numW[$x];
}
}
$x = 0;
$y = 0;
printf ("The odd numbers between your integers are: ");
while ($x < $j)
{
$x++;
echo $oddsW[$x];
echo "nbsp;";
$y++;
if (($y % 10) == 0)
{
echo B;
}
}
Equivalent loops:
for ($i = 0; $i < 10; $i++) {
echo $i;
}
$i = 0;
while ($i < 10) {
echo $i;
$i++;
}
For a loop to ever finish it has to change one of the two evaluating variables. So either $x, or $lengthW would have to change during iteration. You made an if statment, in the first case you define that X increases by 1, but in the else case you do not change any variable that then has an effect on either $x, or $lengthW
Nor is there any check that sees if the else state has been reached and to catch that by either changing $x or $lengthW in a later iteration.
As such there's an infinite loop as soon as you reach the else case.
The if statement uses the same $x value as the last iteration checking the same position of the $numW, as such nothing has changed since the last iteration and you'll hit the else again, and again, and so on.
while ($x < $lengthW)
{
if (($numW[$x] % 2) == 1)
{
$oddsW[$j] = $numW[$x];
$sumSqOddsW = $sumSqOddsW + pow ($numW[$x], 2);
$x++; //$x is increased by one, and as such, the loop will progress.
// remove this $x++ if you place it outside the if else statement.
$j++;
}
else // reached when ($numW[$x] %2) != 1
{
$sumEvenW = $sumEvenW + $numW[$x];
// No changes to $x or $lengthW as such you'll hit the else again
// this could be solved by either adding $x++; here.
}
// or by adding $x++; here
// (if you do add it here, remove it in the if case above,
// or you risk increasing it by 2 every iteration
}

How to return array in php?

How to return array in php ? Actually I want to return whole value of $x[] insted of last index of $x[]. Please help me...
<?php
function top() {
require './php/connection.php';
$sql = "SELECT * FROM tbl_add";
$query = mysqli_query($connect, $sql);
$n = 0;
while ($result = mysqli_fetch_assoc($query)) {
$a[$n] = $result['add_id'];
$n = $n + 1;
}
$n = $n - 1;
for ($j = 0; $j < $n; $j++) {
for ($i = 0; $i < $n - 1 - $j; $i++) {
if ($a[$i] > $a[$i + 1]) {
$tmp = $a[$i];
$a[$i] = $a[$i + 1];
$a[$i + 1] = $tmp;
}
}
}
for ($i = 0; $i <= $n; $i++) {
echo $a[$i] . '<br>';
}
$j = 1;
for ($i = 0; $i <= 5; $i++) {
$r = $a[$i];
$sql = "SELECT * FROM tbl_add WHERE add_id='$r'";
$query = mysqli_query($connect, $sql);
$result = mysqli_fetch_assoc($query);
if ($result) {
$x[] = $result['mail'];
return $x[];
}
}
}
?>
return $x[]; is invalid syntax.
In expression $x[] = $result['mail'];, $x[] doesn't mean "the last element of $x". It is just a courtesy of PHP that spares the programmer of writing $x[count($x)]1 instead.
Returning an array is as easy as return $x; (given $x is an array).
Btw, there is no place in your code where $x is initialized as array. You just add values to some variable that doesn't exist, using the array syntax. PHP helps you and creates an array first and stores it in the $x variable but this practice is strongly discouraged. You should add $x = array(); somewhere before you use $x for the first time (outside the loop, of course). For example, you can put it before the line for ($i = 0; $i <= 5; $i++) {.
`
1 This statement is not entirely correct. However, if the values are added to the array using only the $x[] = ... syntax (as it happens in the posted code) then it is correct.
You have to return $x
Then when you call this function $data = top();
Now you get return data of function top to variable name data
// the code below will return $x as it is, independent of what it is. Array, integer, string etc..
Return $x;
// if you need to return two values use:
Return array($x, $y);
// again bit variables are returned as they are.
To call the function and get the values/array use:
$array = top();
Var_dump($array); //should be $x from your function

warning occuring in php word occurence

I have written the following code to count the number of string occurrences in a given file.
PHP
<?php
$p = fopen("g.txt", "r");
$q = fread($p, filesize("g.txt"));
$t = explode(" ", $q);
$m = explode(" ", $q);
$i = 0;
$j = 0;
$r = 0;
$count = 0;
$c = count($t);
$d = array();
echo "count of".
"<br/>";
for ($i = 0; $i < $c; $i++) {
for ($j = $i; $j < $c; $j++) {
if ($t[$i] == $t[$j]) {
$count = $count + 1;
}
}
for ($r = $i + 1; $r < $c; $r++) {
if ($t[$i] == $t[$r])
unset($t[$r]);
}
echo $t[$i].
"=".$count.
"<br/>";
$count = 0;
}
?>
I am getting a notice of undefined offset on line numbers 17 and 24, though my output is coming out to be correct. Can you please help me in rectifying the above problem?
The problem is that you are deleting items from the array $t. You saved the count in $c, but the actual count will change by your last inner loop.
Even if you replace $c by count($t) everywhere, it will go wrong, because the last loop should be in reverse order, otherwise you skip items. For instance if you have the list 'a', 'b', 'c'. then when you delete 'b' and increment $r, you will not check 'c' at all.
So, if I fix those things, your code becomes as below. Although I didn't really check it for other issues. Frankly, I don't really get what is should do. ;-)
<?php
$p=fopen("g.txt","r");
$q=fread($p,filesize("g.txt"));
$t=explode(" ",$q);
$m=explode(" ",$q);
$i=0;
$j=0;
$r=0;
$count=0;
$d=array();
echo "count of"."<br/>";
for($i=0; $i<count($t); $i++)
{
for($j=$i; $j<count($t); $j++)
{
if($t[$i]==$t[$j])
{
$count=$count+1;
}
}
for($r=count($t) - 1; $r > $i; $r--)
{
if($t[$i]==$t[$r])
unset($t[$r]);
}
echo $t[$i]."=".$count."<br/>";
$count=0;
}
?>
In conclusion, you should do more tests. If the outcome of this script was okay, then it was by accident.

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