Rather noobish question but I have tried searching and just cannot find a solution. My problem is I have a table called Off, which stores all of the staffs holidays. However before a staff member may have that day off it has to be authorised. I have a query which gets all of the unauthorised holidays and I display them in a html table. The problem is that I need 2 radio buttons per record. one for authorise and one for deny. The radio buttons are displayed but when going through the records only one of the radio buttons is selectable. Is it possible to use radio buttons in this way?
<?php
$path = $_SERVER['DOCUMENT_ROOT'];
$path .= "/Apollo/dbc.php";
include_once($path);
$rs_results = mysql_query("SELECT * FROM off WHERE IsItAuthorised='0' and isitsick='0' ORDER BY DayOff");
?>
<html>
<head>
<title>Administration Main Page</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<?php
$limit = count($OffID);
if (isset($_POST['submit'])) {
//Assign each array to a variable
$id = $_POST['OffID'];
$answer = $_POST['radio'];
$limit = count($OffID);
$values = array(); // initialize an empty array to hold the values
for($k=0;$k<$limit;$k++){
$msg[] = "$limit New KPI's Added";
$query = "UPDATE Off SET IsItAuthorised = '{$answer[$k]}' WHERE OffID = '{$OffID[$k]}'";
}
$Event = "INSERT INTO events (UserName, Event ) VALUES ('$_SESSION[user_name]', 'Entered New KPI' )";
if (!mysql_query($query,$link)){
die('Error: ' . mysql_error());
} else {
mysql_query($Event);
echo "<div class=\"msg\">" . $msg[0] . "</div>";
}
}
?>
</head>
<body>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="14%" valign="top"><?php
?>
</td>
<td width="74%" valign="top" style="padding: 10px;">
<p><?php
if(!empty($msg)) {
echo $msg[0];
}
?></p>
<p>
<?php
$cond = '';
$sql = "select * from off ";
$rs_total = mysql_query($sql) or die(mysql_error());
$total = mysql_num_rows($rs_total);
?>
<p>
<form name "searchform" action="/Apollo/Admin/HolidayRequests" method="post">
<table width="100%" border="0" align="center" cellpadding="2" cellspacing="0">
<tr class="mytables">
<td width="4%"><font color="white"><strong>ID</font></strong></td>
<td width="4%"> <font color="white"><strong>Staff Member</font></strong></td>
<td width="10%"><font color="white"><strong>Day Off</font></strong></div></td>
<td width="10%"><font color="white"><strong>Is It Authorized</font></strong></div></td>
<td width="15%"> </td>
</tr>
<tr>
<td> </td>
<td width="10%"> </td>
<td width="17%"><div align="center"></div></td>
<td> </td>
</tr>
<?php while ($rrows = mysql_fetch_array($rs_results)) {?>
<tr>
<td><input type="" name="id[]" id="id[]" size="4" value="<?php echo $rrows['OffID'];?>" /></td>
<td><?php echo $rrows['StaffMember']; ?></td>
<td><?php echo date('d/m/Y', strtotime($rrows['DayOff']));?></div></td>
<td> <span id="approve<?php echo $rrows['id']; ?>">
<?php if(!$rrows['IsItAuthorised']) { echo "Pending"; } else {echo "Authorized"; }?>
</span> </td>
<td>
<input type="radio" name="radio[0]" id="radio[0]" value="1" />Approve
<input type="radio" name="radio[1]" id="radio[1]" value="0" />Deny
</td>
</tr>
<?php } ?>
</table>
<input name="submit" type="submit" id="submit" value="Submit">
</form>
</p>
<?php
?>
<p> </p>
<p> </p>
<p> </p>
<p> </p></td>
<td width="12%"> </td>
</tr>
</table>
</body>
</html>
Your problem is to do with your use of the "name" attribute - this attribute is used in a special way on radio buttons.
When you click on a radio button, all the other radio buttons with the same name are deselected - in your case, you will have half of the radio buttons on the page in one group and half in another, which would probably explain why you can only select one. I'd imagine you can actually select two at the same time, if you click on the right radio buttons.
To fix this you'd need to have some kind of count for the while loop, ie:
$resultNumber = 0;
while ($rrows = mysql_fetch_array($rs_results)) {
Then you'd need to use this number in the name (and also id) of the radio buttons -
<input type="radio" name="radio<?php echo $resultNumber; ?>" id="radio<?php echo $resultNumber; ?>" value="1" />
Then simply increment the $resultNumber at the end of each iteration -
<?php
$resultNumber++;
}
?>
Alternatively, you could use the primary key of the row from the database table you're querying to distinguish groups, but not knowing the table structure I couldn't give sample code for that.
Further reading on radio buttons (also a source for the name attribute problem) :
http://www.echoecho.com/htmlforms10.htm
Instead of radio buttons, I used checkboxes, which I looped through. Each checkbox set a value to a different column. Should have been obvious to me to begin with.
Related
I am new to PHP(loving it already)
I have a form that looks up a table that sends 'golf hole' info back and allows a golfer to input their score of the hole. Problem I have is that I can present the first hole by looking up the hole_detail table but then cant figure out how loop through the table for hole 2, 3.....18 when the form is submitted. I have searched stackoverflow but cant find anything that specific about it. I have tried an if statement, if (isset($_POST['Submit'])) to try increment the $hole_id. Am I completely going about it the wrong way? Thanks in advance.
<?php
include ('../scripts/dbconfig.php');
# get the most recent course name:
$get_course_name = mysql_query("SELECT course_name FROM comp ORDER BY PID DESC LIMIT 1");
$show_course_name = mysql_fetch_array($get_course_name);
if (isset($_POST['Submit'])) {
$hole_id =1;
else {
$hole_id = $hole_id + 1;
}
}
# get the hole yardage and SI from most recent selected golf course:
$get_course_detail = mysql_query("SELECT * FROM `course_detail` WHERE course_name = '". $show_course_name['course_name'] . "'");
$show_course_detail = mysql_fetch_array($get_course_detail);
$get_hole_detail = mysql_query("SELECT * FROM `course_detail`,`phoenix_hole` WHERE Course_ID = 6 AND hole_id = $hole_id");
$show_hole_detail = mysql_fetch_array($get_hole_detail);
?>
</head>
<body>
<table width="300" cellspacing="0" cellpadding="0">
<tr>
<td width="40"><?php echo $show_course_name['course_name'];?></td>
</tr>
<tr>
<td width="20">HOLE <?php echo $show_hole_detail['hole_id']?></td>
<td width="5"> PAR <?php echo $show_hole_detail['hole_par'];?></td>
</tr>
<tr>
<td width="20">Yards</td>
<td width="20">S.I</td>
</tr>
<tr>
<td bgcolor="yellow"><?php echo $show_hole_detail['yellow_yards'];?></td>
<td><?php echo $show_hole_detail['hole_si'];?></td>
</tr>
<tr>
<td border="1px" bgcolor="white"><?php echo $show_hole_detail['white_yards'];?></td>
<td><?php echo $show_hole_detail['hole_si'];?></td>
</tr>
<tr>
<td bgcolor="red"><?php echo $show_hole_detail['red_yards'];?></td>
<td><?php echo $show_hole_detail['hole_si'];?></td>
</tr>
</table>
</p>
<form id="game_form" name="game_form" method="post" action="game_form.php">
<table width="300" border="0" align="left" cellpadding="2" cellspacing="0">
<tr>
<td><b>Hole Shots</b></td>
<td><input name="hole_shots" type="text" class="textfield" id="hole_shots" maxlength="2" size="3" ></td>
<td><b>Putts</b></td>
<td><input name="putts" type="text" class="textfield" id="putts" maxlength="2" size="3"></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="Submit" value="Next Hole" align="center" /></td>
</tr>
</table>
</form>
</body>
</html>
Or you can use a hidden field that keeps the hole number and you can increment it from php.
$hole_id, in this scenario, will always be 1, because when a user clicks the Submit button, $_POST['Submit'] will always have a value. What you should do instead is have $_POST['Submit'] contain the value of $hole + 1. PHP is not going to "remember" what $hole_id was last time around; it's up to you to remind it. As soon as a request is sent to the browser--unless you're using sessions--PHP forgets everything about that request (HTTP is "stateless").
<?php
if (isset($_POST['Submit'])) {
$hole_id = (int)$_POST['Submit'];
} else {
$hole_id = 1;
}
# other code here
?>
You are on hole #<?php echo $hole_id; ?>.
<form>
<!-- form stuff here -->
<button type="submit" name="Submit" value="<?php echo $hole_id + 1; ?>">Next hole</button>
</form>
I have a table called "project_name" in my database called "encrypt_decrypt". The table contains only 1 column called "name" which contains different values of name (ex : p1, p2, p3...). I have to retrieve this values(p1,p2,p3..) from my database and display it on a registration form with each value displaying one below the other having a checkbox with it so that user can select any of the name while registering! How do i do this in php ???
Thanks in advance!
<html>
<body>
<form name="reg" action="code_exec2.php" onsubmit="return validateForm()" method="post">
<table width="274" border="0" align="center" cellpadding="2" cellspacing="0">
<tr>
<td><div align="right" style="white-space:nowrap" >Please select the project:</td>
</tr>
<tr>
<td><div align="right"><input type="checkbox" name="project[]" ></div></td>
<td><?php
session_start();
include('connection2.php');
$row=mysql_query("select * from project_name");
$array= array();
$output = mysql_fetch_assoc($row);
while($output){
$array[] = $output;
}
print_r($array);
?></td>
</tr>
<tr>
<td><div align="right"><input type="checkbox" name="Select all"
value="select all" onclick="toggle(this)"></div></td>
<td>Select all</td>
</tr>
<tr>
<td><div align="right"></div></td>
<td><input name="submit" type="submit" value="Submit" /></td>
</tr>
</table>
</form>
</body>
Try this.
$result=mysql_query("select * from project_name");
$checkboxes=array();
while($r=mysql_fetch_assoc($result)){
$checkboxes[]='<input type="checkbox" name="names[]" value="'.$r['name'].'">'.$r['name'].'<br />';
}
Then echo below wherever you want the checkboxes to appear.
echo implode("\n",$checkboxes);
Assuming, that your connection to db is correct, you need to change the way you display results:
<?php
session_start();
include('connection2.php');
$row=mysql_query("select * from project_name");
$array= array();
while($output = mysql_fetch_assoc($row)){
//now you have row with name, and you need to display each name with new tr:
?>
<tr>
<td><div align="right"><input type="checkbox" name="project[]" value="<?php echo $output['name'] ?>"></div></td>
<td><?php echo $output['name'] ?></td>
</tr>
<?php } // closing while loop
?>
Note that I added value to checkbox - if you want to do something with checked project, you have to know which one it was.
And remember taht mysql_ functions are depreated! You should use PDO or mysqli_ instead
i tried this and i got: any ways thanks for all your help :)
<?php
include('connection.php');
$r=mysql_query("select distinct name from project_name");
$ProdArray=array();
while ($row = mysql_fetch_object($r)) {
array_push($ProdArray,$row->name);
}
foreach($ProdArray as $p) {
echo "<tr>";
echo "<td><div align='right'>";
echo "<input type='checkbox' name='project[]' value=" .$p. " />";
echo "</div></td>";
echo "<td>$p</td>";
echo "</tr>";
}
?>
I want to delete multiple rows from my MYSQL database table. I have created this file to select various links and delete them using checkboxes.
This doesn't seem to delete any row. My data is populated in the table. I guess the problem is with my PHP code. Please check the below code and guide me to get out from this...
<html>
<head>
<title>Links Page</title>
</head>
<body>
<h2>Choose and delete selected links.</h2>
<?php
$dbc = mysqli_connect('localhost','root','admin','sample') or die('Error connecting to MySQL server');
$query = "select * from links ORDER BY link_id";
$result = mysqli_query($dbc,$query) or die('Error querying database');
$count=mysqli_num_rows($result);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<form name="form1" method="post" action="">
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td bgcolor="#FFFFFF"> </td>
<td colspan="3" bgcolor="#FFFFFF">
<strong>Delete multiple links</strong>
</td>
</tr>
<tr>
<td align="center" bgcolor="#FFFFFF">#</td>
<td align="center" bgcolor="#FFFFFF">
<strong>Link ID</strong>
</td>
<td align="center" bgcolor="#FFFFFF">
<strong>Link Name</strong>
</td>
<td align="center" bgcolor="#FFFFFF">
<strong>Link URL</strong>
</td>
</tr>
<?php
while ($row=mysqli_fetch_array($result)) {
?>
<tr>
<td align="center" bgcolor="#FFFFFF">
<input name="checkbox" type="checkbox" value="
<?php echo $row['link_id']; ?>">
</td>
<td bgcolor="#FFFFFF"> <?php echo $row['link_id']; ?> </td>
<td bgcolor="#FFFFFF"> <?php echo $row['link_name']; ?> </td>
<td bgcolor="#FFFFFF"> <?php echo $row['link_url']; ?> </td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center" bgcolor="#FFFFFF">
<input name="delete" type="submit" value="Delete">
</td>
</tr>
</table>
</form>
</td>
</tr>
</table>
<?php
// Check if delete button active, start this
if(isset($_POST['delete']))
{
$checkbox = $_POST['checkbox'];
for($i=0; $i<count($checkbox); $i++) {
$del_id = $checkbox[$i];
$sql = "DELETE FROM links WHERE link_id='$del_id'";
$result = mysqli_query($sql);
}
// if successful redirect to delete_multiple.php
if($result){
echo '<meta http-equiv="refresh" content="0;URL=view_links.php">';
}
}
mysqli_close($dbc);
?>
</body>
</html>
You should treat it as an array like this,
<input name="checkbox[]" type="checkbox" value="<?php echo $row['link_id']; ?>">
Then only, you can take its count and loop it for deletion.
You also need to pass the database connection to the query.
$result = mysqli_query($dbc, $sql);
Yours did not include it:
$result = mysqli_query($sql);
Use array notation like name="checkbox[]" in your input element. This will give you $_POST['checkbox'] as array. In the query you can utilize it as
$sql = "DELETE FROM links WHERE link_id in ";
$sql.= "('".implode("','",array_values($_POST['checkbox']))."')";
Thats one single query to delete them all.
Note: You need to escape the values passed in $_POST['checkbox'] with mysql_real_escape_string or similar to prevent SQL Injection.
<?php $sql = "SELECT * FROM guest_book";
$res = mysql_query($sql);
if (mysql_num_rows($res)) {
$query = mysql_query("SELECT * FROM guest_book ORDER BY id");
$i=1;
while($row = mysql_fetch_assoc($query)){
?>
<input type="checkbox" name="checkboxstatus[<?php echo $i; ?>]" value="<?php echo $row['id']; ?>" />
<?php $i++; }} ?>
<input type="submit" value="Delete" name="Delete" />
if($_REQUEST['Delete'] != '')
{
if(!empty($_REQUEST['checkboxstatus'])) {
$checked_values = $_REQUEST['checkboxstatus'];
foreach($checked_values as $val) {
$sqldel = "DELETE from guest_book WHERE id = '$val'";
mysql_query($sqldel);
}
}
}
Delete Multiple checkbox using PHP Code
<input type="checkbox" name="chkbox[] value=".$row[0]."/>
<input type="submit" name="delete" value="delete"/>
<?php
if(isset($_POST['delete']))
{
$cnt=array();
$cnt=count($_POST['chkbox']);
for($i=0;$i<$cnt;$i++)
{
$del_id=$_POST['chkbox'][$i];
$query="delete from $tablename where Id=".$del_id;
mysql_query($query);
}
}
Something that sometimes crops up you may/maynot be aware of
Won't always be picked up by by $_POST['delete'] when using IE. Firefox and chrome should work fine though. I use a seperate isntead which solves the problem for IE
As for your not deleting in your code above you appear to be echoing out 2x sets of check boxes both pulling the same data? Is this just a copy + paste mistake or is this actually how your code is?
If its how your code is that'll be the problem as the user could be ticking one checkbox array item but the other one will be unchecked so the php code for delete is getting confused. Either rename the 2nd check box or delete that block of html surely you don't need to display the same list twice ?
$deleted = $_POST['checkbox'];
$sql = "DELETE FROM $tbl_name WHERE id IN (".implode(",", $deleted ) . ")";
hey guys im having trouble with an array. all i need is for the query to update 2 columns on the table based on the records id
The table has a column called OffID and it looks for any record that has not yet been authorised. to mark it authorised the user will select a check box for either authorise or deny and then press the submit button. however at the moment i have 9 records which show in the table each with there own unique id but when submit is selected it will only update one. any help in showing where ive gone wrong would be grateful and cheers in advance :)
ok i edited the code but it is only now setting the first record. so if there are 8 records and i choose accept for the first record and deny for the second record both the accept and deny are set to the first record in the database my new code is below
<?php
$path = $_SERVER['DOCUMENT_ROOT'];
$path .= "/Apollo/dbc.php";
include_once($path);
$rs_results = mysql_query("SELECT * FROM off WHERE IsItAuthorised='0' and isitsick='0' ORDER BY DayOff");
?>
<html>
<head>
<title>Administration Main Page</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<?php
if (isset($_POST['submit'])) {
//Assign each array to a variable
$id = $_POST['id'];
$approve = $_POST['approve'];
$deny = $_POST['deny'];
$limit = count($rs_results);
$values = array(); // initialize an empty array to hold the values
for($k=0;$k<$limit;$k++){
$msg[] = "$limit New KPI's Added";
$query = "UPDATE off SET Authorised = '$approve[$k]', Deny = '$deny[$k]' WHERE OffID = '$id[$k]'";
}
$Event = "INSERT INTO events (UserName, Event ) VALUES ('$_SESSION[user_name]', 'Entered New KPI' )";
echo $query;
if (!mysql_query($query,$link)){
die('Error: ' . mysql_error());
} else {
mysql_query($Event);
echo "<div class=\"msg\">" . $msg[0] . "</div>";
}
}
?>
</head>
<body>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="14%" valign="top"><?php
?>
</td>
<td width="74%" valign="top" style="padding: 10px;">
<p><?php
if(!empty($msg)) {
echo $msg[0];
}
?></p>
<p>
<?php
$cond = '';
$sql = "select * from off ";
$rs_total = mysql_query($sql) or die(mysql_error());
$total = mysql_num_rows($rs_total);
?>
<p>
<form name "searchform" action="/Apollo/Admin/HolidayRequests.php" method="post">
<table width="100%" border="0" align="center" cellpadding="2" cellspacing="0">
<tr class="mytables">
<td width="4%"><font color="white"><strong>ID</font></strong></td>
<td width="4%"> <font color="white"><strong>Staff Member</font></strong></td>
<td width="10%"><font color="white"><strong>Day Off</font></strong></div></td>
<td width="10%"><font color="white"><strong>Is It Authorized</font></strong></div></td>
<td width="15%"> </td>
</tr>
<tr>
<td> </td>
<td width="10%"> </td>
<td width="17%"><div align="center"></div></td>
<td> </td>
</tr>
<?php while ($rrows = mysql_fetch_array($rs_results)) {?>
<tr>
<td><input name="id[]" id="id[]" size="4" value="<?php echo $rrows['OffID'];?>" /></td>
<td><?php echo $rrows['StaffMember']; ?></td>
<td><?php echo date('d/m/Y', strtotime($rrows['DayOff']));?></div></td>
<td> <span id="approve<?php echo $rrows['id']; ?>">
<?php if(!$rrows['IsItAuthorised']) { echo "Pending"; } else {echo "Authorized"; }?>
</span> </td>
<td>
<input type="checkbox" name="approve[]" id="approve[]" value="1"> Approve
<input type="checkbox" name="deny[]" id="deny[]" value="1"> Deny
</td>
</tr>
<?php } ?>
</table>
<input name="submit" type="submit" id="submit" value="Submit">
</form>
</p>
<?php
?>
<p> </p>
<p> </p>
<p> </p>
<p> </p></td>
<td width="12%"> </td>
</tr>
</table>
</body>
</html>
isn't it because your $id etc isn't passes an array:
$id = $_POST['id'];
$approve = $_POST['approve'];
$deny = $_POST['deny'];
You're using $_POST['id'] but nowhere in your <form/> do I see any <input name="id[]"/> which could provide the data
I'm trying to get the emails corresponding to the checkbox using the following codes. But, I'm not getting the correct checked emails in the new variable. Can anyone please check ??
<?php
include("connection.php");
$username=$_SESSION['username'];
$query=mysql_query("SELECT * FROM contacts WHERE username='$username'");
$num=mysql_num_rows($query);
$info=mysql_fetch_array($query);
$i=0;
$msg='';
?>
<table width="672" border="0">
<?php
$i=0;
while($info)
{
?>
<form action="compose.php" method="post">
<tr style="font-size:14px;">
<td width="21" bgcolor="#f2f2f2"> <input type="checkbox" name="add" onSelect="<?php $msg=$msg.$info['email'].", ";?>"/> </td>
<td width="229" bgcolor="#f2f2f2"> <?php echo $info['email']; ?> </td>
<td width="408" bgcolor="#f2f2f2"> <?php echo $info['name']; ?> </td>
</tr>
<?php
$info=mysql_fetch_array($query);
$i++;
}
$_SESSION['contacts']=$msg;
?>
<tr><td></td><td></td><td><br />
<input class="new-button" type="submit" value="Insert & Compose" name="submit" /></td>
</tr>
</form>
</table>
To get any value back for checkboxes they must have a value=. In your case you probably would want the value to be the according email address.
One problem with your code is using onSelect= instead of value=, and second you didn't print the actual value into the page. Rewrite it to:
<td width="21" bgcolor="#f2f2f2">
<input type="checkbox" name="add"
value="<?php print $info['email']; ?>"/> </td>
If you need the $msg variable to do something, assemble it after the output.
<input type="checkbox" name="add" value="<?php echo $msg.$info['email'];?>"/>
checkbox does not have onSelect event probobly you got value in mind and in PHP code you should echo and what .", " is for?