Order By Year with Date field Mysql/PHP - php

Question

I am having trouble with getting my year to echo properly.
Example: I have 2 news articles one with a year of 2011 and the other 2012. They are splitting into the correctly "year" div. But when it comes to rendering out the year, it works. But 2011 and 2012 are stacked above each other. Something like this.
2012
2011
5.1.12 My news article
Where 2011 year is suppose to go
5.1.11 My news article
Here is my code.
<?
$startYear = 2010;
$endYear = 2012;
for($y = $endYear; $y > $startYear -1; $y--) { ?>
<?
$news = query("SELECT * FROM news_entries
WHERE title > ''
AND published = 1
AND date >= '" . mktime(0,0,0,0,0,$y) . "'
AND date < '" . mktime(0,0,0,0,0,$y+1) . "'
ORDER BY date DESC");
?>
The rest of the query.
<? if($news['total']>0) { ?>
<h3><? echo $y; ?></h3>
<table cellpadding="0" cellspacing="0" border="0">
<tr>
<th class="first" width="125">Date</th>
<th>News Headline</th>
<th width="140"> </th>
</tr>
<? do { ?>
<tr>
<td><span><? echo date("F d, Y",$news['data']['date']); ?></span></td>
<td><? echo $news['data']['headline']; ?></td>
<td>Learn More</td>
</tr>
<? } while($news['data'] = mysql_fetch_assoc($news['object'])); ?>
<? }} ?>
<tr>
<td colspan="2" class="last"></td>
<td class="last"> Back to Top</td>
</tr>
</table>

Answer 1

I agree with Kato's comment. Typically, you get all of the results and iterate over them, printing a new header when the data changes.
Here's how this type of thing is usually handled (pseudocode):
$sql = "SELECT * FROM news_enteries ORDER BY date DESC";
// Prepare statement
$stmt = $pdo->prepare($sql);
// Bind variables
...
// Execute query
$stmt->execute() or die();
$year_header = "";
while ($row = $stmt->fetch()) {
$year = date("Y", strtotime($row['date']));
// Do we need a new year header?
if ($year_header <> $year) {
$year_header = $year;
// Print year header
echo $year_header;
}
// Process rest of the row
...
}