I am using a single page submission form to create and also edit a record. It creates the record fine and will populate the form and update it if I define the record id myself.
It will not update if I try and pull in the $_GET value.
Here is what I have:
if(isset($_GET['id'])) {
$id = $_GET['id'];
$guests = Guest::find_by_id($id);
}
$message = "";
if(isset($_POST['submit'])) {
$guest = new Guest();
if (isset($_GET['id'])) {
$guest->id = $id;
}
$guest->name = $_POST['guest_name'];
$guest->info = $_POST['guest_info'];
$guest->image_path = $_POST['guest_image_path'];
$guest->sc_player = $_POST['guest_sc_player'];
if($guest->update()) {
$message = "Uploaded successfully.";
} else {
$message = join("<br />", $guest->errors);
}
}
It works if I replace the second if statement with $guest->id = "14"
Where is your ID I can't see it anywhere, where is it set?
Related
I am creating a updating form page. it shows no error but there is no updation in my database.
I already check whole the database row names but that doesnt help.
that code is a little bit long but please help.
<?php
if (isset($_POST['update'])) {
$update_id = $_GET['edit_form'];
$bill = $_POST['b_no'];
$naam = $_POST['name'];
$mobile_no = $_POST['mobile'];
$addres = $_POST['add'];
$detail = $_POST['p_detail'];
$p_img_name = $_FILES['p_img']['name'];
$p_img_type = $_FILES['p_img']['type'];
$p_img_size = $_FILES['p_img']['size'];
$p_img_tmp = $_FILES['p_img']['tmp_name'];
$prc = $_POST['price'];
$deposite = $_POST['d_amt'];
$remaning = $_POST['r_amt'];
$b_img_name = $_FILES['b_img']['name'];
$b_img_type = $_FILES['b_img']['type'];
$b_img_size = $_FILES['b_img']['size'];
$b_img_tmp = $_FILES['b_img']['tmp_name'];
$p_date = date('y-m-d');
move_uploaded_file($p_img_tmp, "images/Product/$p_img_name");
move_uploaded_file($b_img_tmp, "images/Bill/$b_img_name");
$update_query = "UPDATE new_entry SET bill_no='$bill', name='$naam',
mobile_no='$mobile_no', address='$addres', product_detail='detail',
product_image='$p_img_name', price='$prc', deposite_amt='deposite',
remaining='$remaning', bill_image='$b_img_name',Product_date='$p_date'
WHERE s_no='$update_id' ";
if(mysqli_query($conn, $update_query)) {
echo "<script> alert('Entry Updated Successfully') </script>";
echo "<script> window.open('view_entry.php','_self') </script>";
} else {
echo "cant Update Entry.." .mysqli_error($conn);
}
}
?>
final.php
Here I am trying to get the data from the url using GET method and trying to insert into the database. I was able to insert the data for first few rows after that the data is not inserted. Can anyone help me regarding this?
when I try to run the url: www.myii.com/app/final.php?name=123&glucose=3232...
the data is not inserting.
<?php
include("query_connect.php");
$name = $_GET['name'];
$glucose = $_GET['glucose'];
$temp = $_GET['temp'];
$battery = $_GET['battery'];
$tgs_a = $_GET['tgs_a'];
$tgs_g = $_GET['tgs_g'];
$heartrate = $_GET['heartrate'];
$spo2 = $_GET['spo2'];
$rr = $_GET['rr'];
$hb = $_GET['hb'];
$ina22 = $_GET['ina22'];
$accucheck = $_GET['accucheck'];
$isactive = $_GET['isactive'];
$address = $_GET['address'];
$deviceno = $_GET['deviceno'];
$sql_insert = "insert into query (name,glucose,temp,battery,tgs_a,tgs_g,heartrate,spo2,rr,hb,ina22,accucheck,isactive,address,deviceno) values ('$name','$glucose','$temp',$battery','$tgs_a','$tgs_g','$heartrate','$spo2','$rr','$hb','$ina22','$accucheck','$isactive','$address','$deviceno')";
mysqli_query($sql_insert);
if($sql_insert)
{
echo "Saving succeed";
//echo $date_time;
}
else{
echo "Error occured";
}
?>
Query_connect.php
This is my database config php file.
<?php
$user = "m33root";
$password = "me3i434";
$host = "localhost";
$connection = mysqli_connect($host,$user,$password);
$select = mysqli_select_db('miiyy',$connection);
if($connection)
{
echo "connection succesfull<br>";
}
else {
echo "Error";
}
?>
Make sure that all columns can contain NULL so that not filled fields will stay NULL instead of throwing an error.
Try below to see mysql error:
mysql_query($sql_insert);
echo mysql_error()
Try these
In SQL
Change the table name of query to some other name. Because "query" is reserved in SQL
In code
if (!mysqli_query($con,$sql_insert ))
{
echo("Error description: " . mysqli_error($con));
}
else
{
echo "Success";
}
Use mysqli_error() function
I'm currently creating the account management system of my website and I decided to add a feature that enables me to declare weather a specific account is active or inactive. The data is retrieved from my mysql table.
$query = mysqli_query($DBConnect,"SELECT * from REG");
echo "<table class = 'table' style = 'width:90%;text-align:center'>";
while($getData = mysqli_fetch_assoc($query))
{
$username = $getData['uname'];
$fname = $getData['fname'];
$mname = $getData['mname'];
$lname = $getData['lname'];
$bday = $getData['bday'];
$email = $getData['email'];
$contact = $getData['contact'];
$gender = $getData['gender'];
if($getData['userlevel'] == 1)
{
$userlevel = "user";
}
else
{
$userlevel = "admin";
}
if($getData['status'] == 1)
{
$status = "active";
}
else
{
$status = "disabled";
}
echo "<tr>";
echo "<td>$username</td><td>$fname</td><td>$mname</td><td>$lname</td><td>$bday</td><td>$email</td><td>$contact</td><td>$gender</td><td>$userlevel</td><td>
<a href ='..\status.php' >$status </a></td></tr>";
}
echo "</table>";
This is the content of status.php
session_start();
$DBConnect = mysqli_connect("localhost", "root","","kenginakalbo")
or die ("Unable to connect".mysqli_error());
$query = mysqli_query($DBConnect,"SELECT * from REG where id = '$_SESSION[id]'");
while($getData = mysqli_fetch_assoc($query))
{
$status = $getData['status'];
echo "'$_SESSION[id]'";
}
if($status == 1)
{
$query = mysqli_query($DBConnect, "UPDATE REG SET status = 0 where id = '$_SESSION[id]'");
}
else if ($status == 0)
{
$query = mysqli_query($DBConnect, "UPDATE REG SET status = 1 where id = '$_SESSION[id]'");
}
header("Location: admin/login.php");
What I need to do is get the ID of the row clicked and declare it in my session so that it can be used in the "status.php" file. But in this code, the last id in the table is the one that is declared into the session because of the loop. How do I get the value of the id of the row that is clicked? (is there sort of like onClick function in php? Thank you.
pass id parameter,
status.php?id=$id;
in status.php
$id = $_GET['id'];
Change:
echo "<td>$username</td><td>$fname</td><td>$mname</td><td>$lname</td><td>$bday</td><td>$email</td><td>$contact</td><td>$gender</td><td>$userlevel</td><td>
<a href ='..\status.php' >$status </a></td></tr>";
to:
echo "<td>$username</td><td>$fname</td><td>$mname</td><td>$lname</td><td>$bday</td><td>$email</td><td>$contact</td><td>$gender</td><td>$userlevel</td><td>
<a href ='..\status.php{$getData['id']}' >$status </a></td></tr>";
And in your status.php change $_SESSION['id'] to $_GET['id']. But make sure to first prevent SQL injection either through mysql_real_escape_string($_GET['id']) or through PDO.
There is no onclick function in PHP but you can create a form with a button on each row that holds the value of the row that it is in. Have that form simply do a post or a get request back to the status.php. Adding it to the session might be a bad idea.
Instead of a button you can also create a link modify your loop so that there is a property called $rowid and increment it within your loop.
Perhaps, what you really want is to use a GET superglobal here. You can switch
for
Then, you use $_GET["userid"] instead of $_SESSION[id] on the status.php page.
Also, you dont need a while for the status page. You should check the number of results, if it was 1 it means the user exists, and then you just do a $getData = mysqli_fetch_assoc($query) without the while
I have a two forms from one form. I can sucessfully store the data to database.when that form submitted user will directed to the second form. I am passing variable $uniqueid in the url from first form to second form. But, when I tried stored the data of the second form into the database that relevant to the same user its not stored.
I want to store mobile number of the user from second page.databse column also mobile number.
This is my code
<?php
include_once 'dbconnect.php';
$a = $_GET['uniquekey'];
if(isset($_POST['btn-signup']))
{
$mobilenumber = $_POST['mobilenumber'];
$xxx = mysql_query("SELECT * FROM who WHERE uniquekey = '$a'")or die(mysql_error());
$yyy = mysql_fetch_row($xxx);
if(mysql_num_rows($xxx) > 0) {
$aaa = mysql_query("INSERT INTO who(mobilenumber) VALUES('$mobilenumber')");
}
else{
echo 'wrong';
}
}
?>
$xxx = mysql_query("SELECT * FROM who WHERE uniquekey = '$a'")or die(mysql_error());
$yyy = mysql_fetch_row($xxx);
if(mysql_num_rows($xxx) > 0) {
$aaa = mysql_query("UPDATE who setmobilenumber='$mobilenumber' where uniquekey = '$a' ");
}
else{
echo 'wrong';
}
Here you can use update query for update user mobile number.
include_once 'dbconnect.php';
$a = $_GET['uniquekey'];
if(isset($_POST['btn-signup']))
{
$mobilenumber = $_POST['mobilenumber'];
$xxx = mysql_query("SELECT * FROM who WHERE uniquekey = '$a'")or die(mysql_error());
$yyy = mysql_fetch_row($xxx);
if($yy>0)
{
$update="update who set mobilenumber=$mobilenumber where uniquekey='$a'";
$query=mysql_query($update);
}
else
{
echo "wrong";
}
}
table name - user_table
i try to save and update value from single Save button.
but I can not understand how to merge save and update code in 'if else' using certain condition.
Below is my save code :
<?php
require_once('includes/config.php');
$errors = array();
$Admin = new admins;
if(isset($_POST['save']))
{
$errors = $Admin->validate_cms_user_table();
if(!count($errors))
{
$table = $Admin->user_table;
$fields_func = array ('password' =>"md5('{$_POST['password']}')");
unset ($_POST['password']);
if($Admin->save_advance($table,$_POST,$fields_func))
{
$_SESSION['message'] = "User Created Successfully";
header("Location:user_master.php");
exit;
}
}
}
?>
Update code
if($Admin->save($Admin->user_table,$_POST,"id=".$_GET['id']))
{
$_SESSION['message'] = "Updated Successfully";
header("Location: user_master.php");
exit;
}
Update Condition
if(!isset($_GET['catid']))
{
//Then Save Code
}
Else
{
//Update Code
}