PHP dynamic navigation menu active styling - php

Question

I want to create a dynamic menu in PHP and based on what page they are on the menu will have different styling. I have this but it's not how I want it to be :(
This is the array I have, containing info from the database
Array(
[Home] => Array
(
[url] => Home
[name] => Home
[is_home] => 1
)
[About] => Array
(
[url] => About
[name] => About
[is_home] => 0
)
[Contact] => Array
(
[url] => Contact.php
[name] => Contact
[is_home] => 0
)
)
This is what I currently have,
if(isset($_GET["p"])) {
if(in_array($page_name, $navigation[$page_name])) {
$navigation[$page_name]["name"] = "<span>{$navigation[$page_name]["name"]}</span>";
}
}
foreach ($navigation as $nav) {
echo "<li>{$nav["name"]}</li>";
}
This is how the page_name variable looks
$page_name = current(explode(".", ucfirst(strtolower($_GET["p"]))));
As you can see this inserts the span tags in the navigation menu name so this works but that's not how I want it to be. I want to add class="active" the the list item that is the current page. I just don't know how to do it
I hope you understand what I mean and sorry for any messy indentation that occurred when pasting the code in here.
//Edit
The fetch and array code
$mysql->query("SELECT `page_name`, `is_home` FROM `pages` ORDER BY `order` ASC");
$navigation_items = array();
while ($mysql->fetch($row)){
$navigation_items[] = array(
"url" => $row["page_name"],
"name" => current(explode(".", $row["page_name"])),
"is_home" => $row["is_home"]
);
}
return $navigation_items;

Answer 1

First of all the array you provided is reformatted which means you changed the indexes into page names which isn't necessary.
This is how you can achieve what you want:
<?php
$menu = $Db->fetchAll("SELECT * FROM `menu`"); //or whatever method you're using to get data from the database.
$current = null;
if(isset($_GET['p'])) {
$current = current(explode(".", ucfirst(strtolower($_GET["p"]))));
}
$navigation = '';
for($i=0;$i<count($menu);$i++) {
$url = ucfirst(strtolower($menu[$i]['url']));
if($current == $url)
$class = ' class="active"';
else
$class = '';
$name = '<span'.$class.'>'.$menu[$i]['name'].'</span>';
$navigation .= "<li><a href='{$url}'>{$name}</a></li>";
}
?>