php pass auto incremnt id in next page - php

I have a form where I insert a record and the ID (Primary key is Auto increment).
How I can show the ID in the next page after submit. I tried to echo mysql_insert_id(); in next page but didnt work:
<?php echo "Your refrence number is = ". mysql_insert_id(); ?>

Friend, Let's see your issue this way. You have two pages A, and B. You insert data to the database in page A and get the last insert id with mysql_insert_id(); Now the issue is you want to use this in page B. I can propose you 4 ways. but I will explain you session base way since I think it is the best solution for you.
POST
GET
Cookie
Session
Ok In your page A top of your page you write session_start(); remember it should be the first line. Once you get the last insert ID in page a you create a session variable.
$_SESSION["lastID"] = mysql_insert_id();
And in page B also you initiate the session as you did in page A. Then you can simply get the last ID using.
$lastID = $_SESSION["lastID"];
Hope you understand.

Use PHP Session variable. Put mysql_insert_id() in session after insert and access on next page.
$_SESSION["yourID"] = mysql_insert_id();
and access it on next page.

You should get the last insert id in the the page where you insert the record, and then pass the the id to the next page (by url parameter).

Related

Automatically edit a php table

I have a coins table in phpMyAdmin and I need it to be automatically updated when a user completes a purchase via PayPal. The way it is setup is that PayPal will automatically redirect them to a link I choose.
So, how can I run a script that takes the parameters from the URL and adds a new record to the table?
Thank you for all your help.
So that link would need to be a page called something like payment_success.php
On that page you would need to have a script that looks like this:
<?php
include 'credentials.php'; /*this is a file that will contain your database connection info
Then here you will establish the connection and enter the data into the desired table*/
$var1 = 'some information collected from paypal that you want to update';
$id = 'some identifiable information about your user that can connect them to the correct row in your table';
I won't hold your hand through all this but the SQL query you would need would be:
UPDATE table_name SET column_1 = '$var1' WHERE ID = '$id'
Set the confirmation PayPal link to increment the number of coins value in the MySQL table for the particular user....!!!
I hope that will work out..... If I could get a idea of your table or some more info, I could give you a clear idea about that.

Codeigniter get id on same form

I have this problem,on the same form,i want to get the id from saved value.
i already make some example on JS Fiddle
JS Fiddle :
https://jsfiddle.net/8a79wch7/
Detailed Process :
1.Input Value on Form 1-3.
2.Save Value to database and get the auto incremented ID
3.Click Next,and use the ID from previous saved value (this is the question i want to ask).
Any Tips for doing this ?
This will give you the last insert ID
$this->db->insert_id();
Just redirect the user with correct URL by getting the LAST_INSERT_ID
redirect('controller/method/LAST_INSERT_ID', 'refresh');
The URL might Look something like this
http://example.com/controller/method/1

mysql - Query to display record just added

I have two pages. One is a form that I use to simply input data that will be sent to my database and the second page that actually takes the data inputted into the form and sends it to the database and is supposed to display the information that I've just added.
Everything works fine, however I'm struggling with the query slightly. What I need it to do is display all the information for the last data inputted to the database.
The query I currently have just displays the data with the highest ID:
$sql = "SELECT * FROM Results ORDER BY ID DESC LIMIT 1";
So as an example I would be left with the following information after completing my form:
Success! Data being saved:
ID = 900 Amount = 206 Date = 2016-12-26
This is obviously just showing the data with the highest ID, but since the ID and all the data fluctuates, I need it to just show the data that has just been inputted.
I came accross this: Query to select newly added records only. But I don't believe this soultion to be viable as the database is external and I don't want to be creating new tables.
I was thinking that it might be possible to assign a hidden value to each newly added record via the query. e.g. New 1, New 2, New 3 etc. Then printing the latest record for New. However, I couldn't find anything on how to do this.
Any help would be greatly appreciated!
You must use this method to have very correct value:
Input form must send to another file that do inserting (we call it here insert.php)
insert.php must insert the data after validation and after that you can fetch the last ID number from database. Depending on the method you are working with it can be different. for example if you are using PDO you can get it by PDO::lastInsertId
after getting the ID you need to forward it to the viewing or editing page. for example view.php?id=LastInsertId. This forward have some reasons:
Codes can be cleaner.
We prevent refresh and resend inserting. for example if you do inserting inside view.php and user hit F5 to refresh the page, The insertion happening again.
This is the whole idea. you can use this method for only one page:
page.php?do=new
page.php?do=insert
forward to the page.php?do=view&id=lastInsertID
why you trying to get just inputted data from database? you can do it using HTTP POST/GET method easily.just send data as parameters and show them in second page.
If you already have the data you are inserting, you don't need to run a query to get it back from the database again, you could just ensure that the query was successful and display the data directly. Anyways:
You can get the insert ID from the last insert using the MySQLi object. For example:
$sql = "<your insert statement>"
$conn->query($sql);
$last_id = $conn->insert_id; //Id of the row you just inserted
$sql = "SELECT * FROM Results WHERE id=$last_id";
This is assuming you do the insert in the same page that you display the result.

Count the number of times post has been viewed

I am working on a project where only title of posts are shown on main page and on clicking the title, full post is loaded on another page posts.php code for this is:
<?php echo $row['title']; ?>
Now to count post views I have a column hits in my posts table ,initially value of hits is set to 0 and whenever a post is opened value of hits is increased by 1, for this my code is in posts.php
$id = $_GET['postId'];
$sql = "UPDATE posts SET hits = hits + 1 WHERE post_id = $id";
But this is not a good practice for tracking post views as views increase whenever page is refreshed. I want a clean system to track post views where, for every distinct user or visitor views increase by one irrespective of fact how many times the same user/visitor views same post (as in stackoverflow). Like tracking them by their IP address or something else, just an idea (how these guys do it) or how the stuff works would be enough to let me start my work.
You cannot solve your problem so simply. Your problem is counting unique users who view a page (with, perhaps a time component). You have several problems, as described in the comments. The first is determining what you are counting. For a prototype, IP address is good as anything else for getting started. However, it has many short-comings, and you will need to think hard about identifying a "visitor".
There is a way to solve your problem in SQL, sort of efficiently. But, it requires an additional table at the level of post/visitor. It will have one row per combination, and then you will need to count from there. To quickly get the unique counts, you then need an insert trigger on that table.
Here is a sketch of the code:
create unique index unq_postvisitors_post_visitor on postvisitors(postid, visitorid);
insert into PostVisitors (postid, visitorid)
select $postid, $visitorid
on duplicate key update set counter = counter + 1;
delimiter $$
create trigger trig_PostVisitors
after insert on PostVisitors
begin
update posts
set numvisitors = numvisitors + 1
where posts.post_id = new.post_id;
end;$$
delimiter ;
Simplest way I use to solve this problem is through cookies.
Whenever your page is opened, you check if there's set cookie_name cookie through isset($_COOKIE[$cookie_name]).
If isset returns false, you set a cookie through setcookie(cookie_name, value, expire);, maybe setting expire time to 24h (you have to set it in seconds, so 24h is 84600). Also, you trigger your counting systems with a +1 to your visitor counter.
If isset returns true, do nothing.
PHP Cookies Refs
Try this It'll Work
$refreshed = $_SERVER['HTTP_CACHE_CONTROL'];
if ($refreshed == 'max-age=0'){
$sql = "UPDATE posts SET hits = hits + 1 WHERE post_id = $id";
}
Try this script on the page $_SERVER['HTTP_CACHE_CONTROL'] get place when page is refreshed

SQL/PHP: Calling unique ID

I have made a form page with some radio buttons, text/textarea inputs and a total amount (price) at the end.
It is working/possible to input this into a table in MYSQL with a unique ID (AUTO INCREMENT at 100000).
Here is the situation:
When I submit my page i would like to automatically navigate to another page that still holds the "UNIQUE ID" and the "TOTAL AMOUNT (price)" so I could use it there to put it into another variable that i have to use for the redirection to the payment website.
I thought just to read the last entry in my database but what if 2 people are paying at the same time (no option!).
My unique ID is made into the database itself maybe that is my problem?
Is there somebody who could help me and provide me a walktrough?
Ex. My code:
if(isset($_POST['verzenden'])) {
$firstname = htmlentities ($_POST['firstname']);
$name = htmlentities ($_POST['name']);
$con= mysqli_connect("sqladres","username","password","databasename");
$query = 'INSERT INTO `inputorder`
(`contact_firstname`, `contact_name`)
VALUES ("'.$firstname.'","'.$name.'")';
Now I think I have to use $_SESSION to generate a session ID and also to write the amount (price) into this session and take it to the action page. But I've never used it before and really dont know how to use it in a good safe way!
see similar question to get last insert id:
How do I get the last inserted ID of a MySQL table in PHP?
To redirect with your variables you can use get method as:
header("Location:yourwebsite.com/payment.php?uniqe_id=". $uniqe_id . "&total=" . $total);

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