Php image show issue - php

Question

I'm confused! Basically i've a form with 3 field ex: subject, image, message. So,
(1) If i upload image it's should be show image,
(2) if i don't upload image it's should be show just only subject and message no image box and
(3) if i don't upload image and if there are a youtube link in message box then it's should be show the vedio. **
Following is my php code, but i can't solved the number 3 point! **
<?php
if(empty($imgname))
{
echo '';
}
elseif(!empty($imgname))
{
echo "<span class='vedio'>";
echo '<img src="' . $upload_path . '/' . $imgname . '" width="195" height="130"
style=" background-color:f2f4f6;" />';
echo "</span>";
}
else
{
echo "<span class='vedio'>";
require_once("func.php");
if (preg_match('%(?:youtube\.com/(?:[^/]+/.+/|(?:v|e(?:mbed)?)/|.*[?&]v=)|youtu\.be/)
([^"&?/ ]{11})%i', $msg, $match))
{
// echo $video_id = $match[1];
}
echo #get_youtube_embed($video_id = $match[1]);
echo "</span>";
}
?>
Any Idea or Solution that would be better for me.
Shibbir.

Answer 1

You'll never get into your else statement because of your preceding if conditions. In ALL cases, $imgname will either be empty, or not empty.
To demonstrate further:
if (empty($imgname)) {
// ... First condition
} else if (!empty($imgname)) {
// ... Last possible condition
} else {
// Will never reach here because $imgname will
// fall into one of the two of the above conditionals.
}
It's difficult to add to your code without full context, but it seems you may want to include the following after the above code (not with):
if(!empty($msg) && preg_match('%(?:youtube\.com/(?:[^/]+/.+/|(?:v|e(?:mbed)?)/|.*[?&]v=)|youtu\.be/)
([^"&?/ ]{11})%i', $msg, $match)) {
require_once("func.php");
echo "<span class='vedio'>";
echo #get_youtube_embed($match[1]);
echo "</span>";
}