MySQL highscore query [duplicate] - php

Question

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Closed 11 years ago.
Possible Duplicate:
mySQL “Rank in Highscore”-Query
I was just wondering if there is any effective way to gather the current rank of some id based on points.
My only idea was to grab whole points and then check every record if its more or less. Something like this.
Select * from whatever table
$x=0
while($row = mysql_fetch_array($result) {
if ($user == $row['user']) {
echo "$user is rank $x out of " . count($result);
break;
}
else {
$x++
}
}

Answer 1

You can use a variable, as shown here:
SET #rank=0;
SELECT user.*, #rank:=#rank+1 AS 'rank'
FROM user
ORDER BY score DESC

Answer 2

Do you mean like the "MAX" in mysql?
"SELECT max(score) as record FROM users";
This will retrieve a column with the highest score from the users table.

Answer 3

this can be done in mysql:
SELECT ui2.*,
(
SELECT COUNT(*)
FROM users ui
WHERE (ui.points, ui.id) >= (ui2.points, ui2.id)
) AS rank
FROM users ui2
WHERE id = #id

Answer 4

Yes you can use max() along with the group by clause to group the results based on certain criteria.
"SELECT max(score) as record FROM users_points group by user_id, game_id";

Answer 5

drop table if exists users;
create table users
(
id int unsigned not null auto_increment primary key,
score int unsigned not null default 0
)
engine=innodb;
insert into users (score) values (10),(30),(50),(30),(20),(45),(20);
select
#r:=#r+1 as rank,
u.id,
u.score
from
users u
inner join (select #r:=0) as r
order by
u.score desc;