splitting name and id - php

I have a string
"JonSmith02-11-1955"
I use
preg_split to get JonSmith (reg='[0-9-]') then do it again ('[a-zA-Z]\ ') to get his birthdate.
Is there any better way to get them both in one split ?

/(?<=[a-z])(?=\d)/i
works in this case. It matches a position preceded by a letter and followed by a digit. Read about lookbehinds and -aheads for more information.
This won't work if the name can contain digits.
DEMO

What about ^(.*)(\d{2})\-(\d{2})\-(\d{4})$?
It will parse your string into four parts: JonSmith, 02, 11 and 1955.

Try /(\w*)(\d{2}-\d{2}-\d{4})/ as your regex - someone else can probably do that more efficiently. This will give you two capturing groups, so
$array = preg_match_all('/(\w*)(\d{2}-\d{2}-\d{4})/', "JonSmith02-11-1955");
print_r($array);
/*
Array
(
[0] => Array
(
[0] => JonSmith02-11-1955
)
[1] => Array
(
[0] => JonSmith
)
[2] => Array
(
[0] => 02-11-1955
)
)
*/

^([a-zA-z]*)([0-9]*)\-(.+)*$
For this example :
JonSmith02-11-1955
Give :
JonSmith
02
11-1955

preg_match('/([a-z]+)([0-9-]+)/i', 'JonSmith02-11-1955', $matches);
echo "Name is $matches[1]<br>\n";
echo "Birth date is $matches[2]<br>\n";
See it working

Related

How to get a particular string using preg_replace?

i want to get a particular value from string in php. Following is the string
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_replace('/(.*)\[(.*)\](.*)\[(.*)\](.*)/', '$2', $str);
i want to get value of data01. i mean [1,2].
How can i achieve this using preg_replace?
How can solve this ?
preg_replace() is the wrong tool, I have used preg_match_all() in case you need that other item later and trimmed down your regex to capture the part of the string you are looking for.
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_match_all('/\[([0-9,]+)\]/',$string,$match);
print_r($match);
/*
print_r($match) output:
Array
(
[0] => Array
(
[0] => [1,2]
[1] => [2,3]
)
[1] => Array
(
[0] => 1,2
[1] => 2,3
)
)
*/
echo "Your match: " . $match[1][0];
?>
This enables you to have the captured characters or the matched pattern , so you can have [1,2] or just 1,2
preg_replace is used to replace by regular expression!
I think you want to use preg_match_all() to get each data attribute from the string.
The regex you want is:
$string = 'users://data01=[1,2]/data02=[2,3]/*';
preg_match_all('#data[0-9]{2}=(\[[0-9,]+\])#',$string,$matches);
print_r($matches);
Array
(
[0] => Array
(
[0] => data01=[1,2]
[1] => data02=[2,3]
)
[1] => Array
(
[0] => [1,2]
[1] => [2,3]
)
)
I have tested this as working.
preg_replace is for replacing stuff. preg_match is for extracting stuff.
So you want:
preg_match('/(.*?)\[(.*?)\](.*?)\[(.*?)\](.*)/', $str, $match);
var_dump($match);
See what you get, and work from there.

PHP - What regex code do I need to match this boundary sequence?

I have the following text string:
-asc100-17-asc100-17A-asc100-17BPH-asc100-17ASL
What regex code do I need to extract the values so that they appear in the matches array like this:
-asc100-17
-asc100-17A
-asc100-17BPH
-asc100-17ASL
Thanks in advance!
You may try this:
$str = "-asc100-17-asc100-17A-asc100-17BPH-asc100-17ASL";
preg_match_all('/-asc\d+-[0-9a-zA-Z]+/', $str, $matches);
// Print Result
print_r($matches);
Output:
Array
(
[0] => Array
(
[0] => -asc100-17
[1] => -asc100-17A
[2] => -asc100-17BPH
[3] => -asc100-17ASL
)
)
Based on the very limited information in your question, this works:
-asc100-17[A-Z]*
Debuggex Demo
If you want to capture the post -asc100- code, then use
-asc100-(17[A-Z]*)
Which places 17[the letters] into capture group one.
Might use preg_split with a lookahead as well for your scenario:
print_r(preg_split('/(?=-asc)/', $str, -1, PREG_SPLIT_NO_EMPTY));
Are you trying to break the string in an array? Then why regex is required? This function can handle what you want:
$arr = explode('-asc', '-asc100-17-asc100-17A-asc100-17BPH-asc100-17ASL');
foreach ($arr as $value) {
if(!empty($value)){
$final[] = '-asc'.$value;
}
}
print_r($final);
Output array : Array ( [0] => -asc100-17 [1] => -asc100-17A [2] => -asc100-17BPH [3] => -asc100-17ASL )

split regular expression php

I have a string like that :
0d(Hi)i(Hello)4d(who)i(where)540d(begin)i(began)
And i want to make it an array with that.
I try first to add separator, in order to use the php function explode.
;0,d(Hi),i(Hello);4,d(who),i(where);540,d(begin),i(began)
It works but the problem is I want to minimize the separator to save disk space.
Therefore i want to know by using preg_split, regular expression, if it's possible to have a huge array like that without using separator :
Array ( [0] => Array ( [0] => 0 [1] => d(hi) [2] => i(Hello) )
[1] => Array ( [0] => 4 [1] => d(who) [2] => i(where) )
[2] => Array ( [0] => 540 [1] => d(begin) [2] => i(began) )
)
I try some code & regex, but I saw that the value in the regular expression was not present in the final result (like explode function, in the final array we do not have the delimitor.)
More over, i have some difficulties to build the regex. Here is the one that I made :
$modif = preg_split("/[0-9]+(d(.+))?(i(.+))?/", $data);
I must precise that d() and i() can not be present (but at least one)
Thanks
If you do
preg_match_all('/(\d+)(d\([^()]*\))?(i\([^()]*\))?/', $subject, $result, PREG_SET_ORDER);
on your original string, then you'll get an array where
$result[$i][0]
contains the ith match (i. e. $result[0][0] would be 0d(Hi)i(Hello)) and where
$result[$i][$c]
contains the cth capturing group of the ith match (i. e. $result[0][1] is 0, $result[0][2] is d(Hi) and $result[0][2] is i(Hello)).
Is that what you wanted?

Regular Expression with wordpress shortcodes

I'm trying to find all shortcodes within a string which looks like this:
 [a_col] One
 [/a_col]
outside
[b_col]
Two
[/b_col] [c_col] Three [/c_col]
I need the content (eg "Three") and the letter from the col (a, b or c)
Here's the expression I'm using
preg_match_all('#\[(a|b|c)_col\](.*)\[\/\1_col\]#m', $string, $hits);
but $hits contains only the last one.
The content can have any character even "[" or "]"
EDIT:
I would like to get "outside" as well which can be any string (except these cols). How can I handle that or should I parse this in a second step?
This will capture anything in the content, as well as attributes, and will allow any characters in the content.
<?php
$input = '[a_col some="thing"] One[/a_col]
[b_col] Two [/b_col]
[c_col] [Three] [/c_col] ';
preg_match_all('#\[(a|b|c)_col([^\[]*)\](.*?)\[\/\1_col\]#msi', $input, $matches);
print_r($matches);
?>
EDIT:
You may want to then trim the matches, since it appears there may be some whitespace. Alternatively, you can use regex for removing the whitespace in the content:
preg_match_all('#\[(a|b|c)_col([^\[]*)\]\s*(.*?)\s*\[\/\1_col\]#msi', $input, $matches);
OUTPUT:
Array
(
[0] => Array
(
[0] => [a_col some="thing"] One[/a_col]
[1] => [b_col] Two [/b_col]
[2] => [c_col] [Three] [/c_col]
)
[1] => Array
(
[0] => a
[1] => b
[2] => c
)
[2] => Array
(
[0] => some="thing"
[1] =>
[2] =>
)
[3] => Array
(
[0] => One
[1] => Two
[2] => [Three]
)
)
It might also be helpful to use this for capturing the attribute names and values stored in $matches[2]. Consider $atts to be the first element in $matches[2]. Of course, would iterate over the array of attributes and perform this on each.
preg_match_all('#([^="\'\s]+)[\t ]*=[\t ]*("|\')(.*?)\2#', $atts, $att_matches);
This gives an array where the names are stored in $att_matches[1] and their corresponding values are stored in $att_matches[3].
use ((.|\n)*) instead of (.*) to capture multiple lines...
<?php
$string = "
[a_col] One
[/a_col]
[b_col]
Two
[/b_col] [c_col] Three [/c_col]";
preg_match_all('#\[(a|b|c)_col\]((.|\n)*)\[\/\1_col\]#m', $string, $hits);
echo "<textarea style='width:90%;height:90%;'>";
print_r($hits);
echo "</textarea>";
?>
I don't have an environment I can test with here but you could use a look behind and look ahead assertion and a back reference to match tags around the content. Something like this.
(?<=\[(\w)\]).*(?=\[\/\1\])

Print out certain text from string with preg_match

I want to get a certain string from an .torrent name but I'm only getting this from it:
array
0 => string 'e' (length=1)
What have I done wrong? This is the preg_match I use:
preg_match('/[S(0-9)E(0-9)]/i', 'True.Blood.S04E12.SWESUB.PDTV.XviD-DSMEDiA', $matches);
Thanks in advance.
Remove the square brackets and put them around the numbers and add + (meaning 1 or more) after them. This way you get the entire S##E## string, plus the numbers separately:
preg_match('/S([0-9]+)E([0-9]+)/i', 'True.Blood.S04E12.SWESUB.PDTV.XviD-DSMEDiA', $matches);
print_r($matches);
/* output:
Array
(
[0] => S04E12
[1] => 04
[2] => 12
)
*/
You could also replace [0-9] with \d
I would recommend using:
preg_match('/S[0-9]{1,2}E[0-9]{1,2}/i', 'True.Blood.S04E12.SWESUB.PDTV.XviD-DSMEDiA', $matches);
It gets out this:
array(1) { [0]=> string(6) "S04E12" }
The following regex will return the appropriate string.
/* Pattern: /\d{2}E\d{2}/ */
preg_match_all('/\d{2}E \d{2}/', '{{your data}}', $arr, PREG_PATTERN_ORDER);
/*Result*/
Array
(
[0] => Array
(
[0] => 04E12
)
)

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