Removing unnecessary nested index in array (generated by Cake PHP) - php

Question

The following question can either be solved by probably changing my use of the find method in Cake PHP OR using some PHP function. I would prefer to solve it using Cake but it doesn't matter too much. I have any array like this:
Array
(
[0] => Array
(
[Model] => Array
(
[id] => 14
[foo] => bar
)
)
[1] => Array
(
[Model] => Array
(
[id] => 15
[foo] => something
)
) .............
I just want to remove the Model index and just use the numeric one. The following function generated this array:
$arr = $this->Model->find('all', array('contain' => false ) );
I probably need to change the 'contain' part of the call. Basically, in addition to the data that appears under each Model index, I also have a second and third model and the contain = false just restricts Cake from getting data from the current model (Model).

Answer 1

If I understand your question correctly, I think CakePHP's Set::combine function will help http://book.cakephp.org/2.0/en/core-utility-libraries/set.html#Set::combine :
$result = Set::combine($your_array, '{n}.Model.id', '{n}.Model.data');
This will result in:
Array
(
[14] => Array
(
[foo] => bar
)
[15] => Array
(
[foo] => something
)
)

Answer 2

you have to write your own piece of code to modify your array , here is a function that will do what you want (you can improve it)
function reformArray($array,$modelName)
{
foreach($arr as $key => $value)
{
$newArr[] = $arr[$key][$modelName];
}
return $newArr;
}
you have to pass your array and the Model Name to this function and will return you the result

Answer 3

$a = array(
array(
'User' => array(
'id' => 2,
'group_id' => 1,
'Data' => array(
'user' => 'mariano.iglesias',
'name' => 'Mariano Iglesias'
)
)
),
array(
'User' => array(
'id' => 14,
'group_id' => 2,
'Data' => array(
'user' => 'phpnut',
'name' => 'Larry E. Masters'
)
)
),
array(
'User' => array(
'id' => 25,
'group_id' => 1,
'Data' => array(
'user' => 'gwoo',
'name' => 'The Gwoo'
)
)
)
);
RUN THIS TO REMOVE THE MODEL NAME USER
Set::extract($a, '{n}.User');
WILL RETURN THIS
$a = array(
array(
'id' => 2,
'group_id' => 1,
'Data' => array(
'user' => 'mariano.iglesias',
'name' => 'Mariano Iglesias'
)
),
array(
'id' => 14,
'group_id' => 2,
'Data' => array(
'user' => 'phpnut',
'name' => 'Larry E. Masters'
)
),
array(
'id' => 25,
'group_id' => 1,
'Data' => array(
'user' => 'gwoo',
'name' => 'The Gwoo'
)
)
);

Answer 4

In CakePHP 2:
$data = $this->Model->find('all');
$data = Set::extract('/Model/.', $data );
You can achieve this result by foreach also
foreach ($data as $k => &$t) {
$t = $t['Model']
}

Answer 5

It will be much easier with Object. Change the Array with Object.
Actually I had faced the same problem with nested array And I found the solution with Set::map($array);
If you don't want the model_name as nested array, You can prefer this solution.
$data = array(
array(
"IndexedPage" => array(
"id" => 1,
"url" => 'http://blah.com/',
'hash' => '68a9f053b19526d08e36c6a9ad150737933816a5',
'get_vars' => '',
'redirect' => '',
'created' => "1195055503",
'updated' => "1195055503",
)
),
array(
"IndexedPage" => array(
"id" => 2,
"url" => 'http://blah.com/',
'hash' => '68a9f053b19526d08e36c6a9ad150737933816a5',
'get_vars' => '',
'redirect' => '',
'created' => "1195055503",
'updated' => "1195055503",
),
)
);
$mapped = Set::map($data);
/* $mapped now looks like: */
Array
(
[0] => stdClass Object
(
[_name_] => IndexedPage
[id] => 1
[url] => http://blah.com/
[hash] => 68a9f053b19526d08e36c6a9ad150737933816a5
[get_vars] =>
[redirect] =>
[created] => 1195055503
[updated] => 1195055503
)
[1] => stdClass Object
(
[_name_] => IndexedPage
[id] => 2
[url] => http://blah.com/
[hash] => 68a9f053b19526d08e36c6a9ad150737933816a5
[get_vars] =>
[redirect] =>
[created] => 1195055503
[updated] => 1195055503
)
)

Answer 6

you may do this :
$tmp = $this->Model->find('all', array('contain' => false ) );
$arr = $tmp['ModelName'];