SQL: get all column records with same id - php

Question

I'm quite new to sql and I'm having trouble writing this
i have a table like this
id name
1 A
2 B
3 C
1 D
1 E
1 F
...
I want a query that will return to me the names of the ID i give it... say if i ask for 1, i want it to return A D E F
i tried this in PHP:
$result3 = mysql_query("SELECT name FROM table WHERE id='1'", $link);
$pfilearray=array();
$pfilearray=mysql_fetch_assoc($result3);
print_r($pfilearray);
but this gives me only the first name found with id 1, what am i missing?

Answer 1

You should iterate the whole result set using while() and mysql_fetch_assoc(). example:
while(($rs=mysql_fetch_assoc($result3))!=null)
{
$pfilearray[]=$rs['name'];
}
print_r($pfilearray);

Answer 2

You can use this code and verify you could able to retieve
while($row = mysql_fetch_array($result3))
{
echo $row['name'];
echo "<br>";
}

Answer 3

Loop through your result set using mysql_fetch_array().
For more help click here

Answer 4

mysql_fetch_assoc returns one row from your result set so it will only return the first value. You need to loop through your result set ($result3 in your code) and get all the rows.
btw, the mysql_ family of functions is quite old and most people would suggest using the mysqli_ family, or even better, PDO
EDIT:
A very basic PDO example:
$ddh = new PDO( /* connection details */ );
$sth = $dbh->prepare('SELECT name FROM table WHERE id= ? ');
$sth->execute(array(1));
$names = $sth->fetchAll();

Answer 5

Try this
$result3 = mysql_query("SELECT name FROM table WHERE id='1'", $link);
while($row=mysql_fetch_array($result3))
{
echo $row['name'];
}