php mysql select with array in to array [duplicate] - php

Question

This question already has answers here:
How can I bind an array of strings with a mysqli prepared statement?
(7 answers)
Closed 6 months ago.
I need to select ids from database with arrays.
my english not good. I think the best way to show my codes
the form result print_r($malayalam); like this Array ( [0] => helo [1] => hi[2] => how)
I need to select its ids from table. my code is not correct. any way let me show you here
$results=mysql_query("SELECT ml_id FROM ml_table WHERE word = '$malayalam'");
$numrows=mysql_num_rows($results);
if($numrows!=0){
$ml_row = mysql_fetch_array($results);
$ml_id = $ml_row['ml_id'] ;
echo "Malayalam ID " . $ml_id . "<br />";
}
I need to add all my result in to another array.
is that possible ?
if u have any idea could you answer to me please

Answer 1

If I understood properly, the following is what you need
$results=mysql_query("SELECT * FROM ml_table WHERE word = '$malayalam'");
if(mysql_num_rows($results)>0){
$newArray = array(); //Create a new array
while($ml_row = mysql_fetch_array($results)) {
$ml_id = $ml_row['ml_id'] ;
$newArray[$ml_id] = $ml_row;
echo "Malayalam ID " . $ml_id . "<br />";
}
//$newArray is your new array accesible from id
}

Answer 2

You should write something like this:
$ids = array();
$in = '"' . implode('","', array_map('mysql_real_escape_string', $malayalam)) . '"';
$result = mysql_query('SELECT id FROM ml_table WHERE word IN(' . $in . ')');
while($row = mysql_fetch_assoc($result)) {
$ids[] = $row['id'];
}
$anotherArray = array_merge($ids, $anotherArray);
OR
$anotherArray += $ids;

Answer 3

$i=0;
foreach($malayalam as $key=>$value)
{
$results=mysql_query("SELECT * FROM ml_table WHERE word = '$value'");
$numrows=mysql_num_rows($results);
if($numrows!=0)
{
$ml_row = mysql_fetch_array($results);
$ml_id = $ml_row['ml_id'] ;
$ml_ad[$i]=$ml_id;
echo "Malayalam ID " . $ml_id . "<br />";
$i++;
}
}
Now when you printr($ml_ad); it will show all your id's in an array.

Answer 4

finally fainally found solution with the help of answers
$rArray = mysql_query("SELECT ml_id FROM ml_table WHERE word IN ('".implode("', '", $malayalam)."')");
if(mysql_num_rows($rArray)>0){
$temp_rows = array();
while(($row = mysql_fetch_array($rArray))) {
$temp_rows[] = $row['ml_id'];
}
}
the result of print_r($temp_rows) coming like this Array ( [0] => 123 [1] => 234 [2] => 312)
thank to all