I am using the data module in drupal 7 and i created a view which shows my table.
But I have a blob in my table and this is filling my page with content.Is there any way that I can get the blob to display as a link and the file must be downloaded when clicked.
Also is it possible for the data module to access tables in a different database than the default drupal database mentioned in settings.php.I added another database in the settings.php which has the required table but I am not able to adopt tables from there.(They do not show up in the orphaned tables list).Is there a place where I can change so that the data module only sees the new database and not the default database
Fixed the first problem by doing this in the theme.inc
if($vars['fields'][$field] == 'content')
{
$field_output = "<form action=\"download.php\"
method=\"POST\">
<input type=\"submit\" name=\"download\" value=\"Download\">
<input type=\"hidden\" name=\"did\" value=\"$num+1\">
</form>";
}
and download.php needs to have something like this
<?php
if(isset($_POST['id']))
{
$table = 'tablename';
$download_id = $_POST['id'];
$q="SELECT * FROM {$table} where id = $download_id";
$link = mysqli_connect(...);
$res = mysqli_query($link,$q);
if($res)
{
$row = mysqli_fetch_assoc($res);
$id = $row['id'];
$name = $row['name'];
$status = $row['status'];
$content = $row['content'];
header("Content-type: required type");
header("Content-Disposition: attachment; filename=$name");
echo $content;
exit;
}
else{
echo "Cannot download";}
}
?>
I am still unable to fix the second problem.
Related
When im displaying the image of restaurant but the image is broken.can anyone help me to solve or find out the problem?i tried to googling or looking tutorial yet i found there are several way to store image which is either storing the file path to database or storing the image to database,in my case is storing the file path to database.
this is the data in my database.the image is type is blob.
this is my html code for displaying
<?php
$sql = "SELECT * FROM restaurant";
$result = $conn->query($sql) or die($conn->error);
while ($row = $result->fetch_assoc()){
<tr>
<td>{$row['ID']}</td>
<td>";echo "<img src='".$row['Logo']."' />";echo "</td>
<td>{$row['Name']}</td>
<td>{$row['ContactNumber']}</td>
<td>{$row['Address']}</td>
<td>{$row['CuisineType']}</td>
<td>{$row['SupportArea']}</td>
</tr>\n";
}
?>
this is php code for adding restaurant
<?php
include 'db.php';
//define other variables with submitted values from $_POST
$name = $_POST['restaurant_name'];
$contactnum = $_POST['restaurant_contactnum'];
$address = $_POST['restaurant_address'];
$cuisinetype = $_POST['cuisinetype'];
$checkbox1 = $_POST['area'];
$allowedExts = array("png","jpg","jpeg"); /* ACCEPTED FILE FORMAT */
$extension = pathinfo($filename, PATHINFO_EXTENSION); /* GET THE FILE EXTENSION */
$extension = strtolower($extension); /* LOWER THE STRINGS OF THE EXTENSION */
$chk="";
foreach($checkbox1 as $chk1)
{
$chk.= $chk1.",";
}
if(in_array($extension,$allowedExts)){ /* IF FILE IS INDEED AN IMAGE */
$photo="restaurantlogo/" . $_FILES["restaurant_logo"]["name"];
}
//insert user data into database
$sql = "INSERT INTO restaurant (Logo, Name, Password, ContactNumber, Address, CuisineType, SupportArea ) VALUES ('$photo', '$name', '$password', '$contactnum', '$address', '$cuisinetype','$chk')";
$insert = mysqli_query($conn, $sql) or die(mysqli_error($conn));
//check if mysql query is successful
if ($sql){
//redirect the user to welcome.php
header("Location: ../restaurant-add.php");
}
The problem is in your PHP output. You were missing echo at multiple places and I exchanged the " for ' so the HTML <img>'s src tag is wrapped in " ".
Here is the corrected code:
<?php
$sql = "SELECT * FROM restaurant";
$result = $conn->query($sql) or die($conn->error);
while ($row = $result->fetch_assoc())
{
echo '<tr>
<td>'.$row['ID'].'</td>
<td><img src="'.$row['Logo'].'" /></td>
<td>'.$row['Name'].'</td>
<td>'.$row['ContactNumber'].'</td>
<td>'.$row['Address'].'</td>
<td>'.$row['CuisineType'].'</td>
<td>'.$row['SupportArea'].'</td>
</tr>";
}
?>
Click F12 to open inspect element, check if you are getting valid src path for image.
If it is valid, try to open in in new tab and see if it appears there. Clearly you will find your error there
I am trying to add image in MAMP server table & fetch it in PHP, and create json. But I am not getting how to add image in table and again it in file. I am new in PHP scripting. Please someone provide me right direction. I have added my PHP code & also MAMP table screenshot.
PHP Code file
<?php
$conn = mysql_connect("localhost:8888","asmita","asmita123") or die(mysql_error());
if($conn)
{
mysql_select_db("EmployeeInfo");
//echo "connected";
//echo $_SERVER['DOCUMENT_ROOT'];
}
else
{
echo "not connected";
mysql_error();
}
$selectQuery="select * from Emp";
$row=mysql_query($selectQuery);
while($result=mysql_fetch_array($row))
{
//echo $_SERVER['http://localhost:8888/images/index.jpg'];
//output need in JSON format for webservice ...
$empname= $result['Name'];
$empadd= $result['Address'];
$emppho= $result['Phone'];
$emppost= $result['Post'];
$empphoto=$result['Photo'];
$jsonArray[]=array("name"=>"$empname","address"=>"$empadd","phone"=>"$emppho","post"=>"$emppost","photo"=>"$empphoto");
}
echo json_encode($jsonArray);
?>
MAMP table data
Here I added image path. Is this correct? Thanks.
HTML Code
<input type="file" name="img_file" id="imageUpload">
PHP Code
$filename = $_FILES['img_file']['name'];
$src = $_FILES['img_file']['tmp_name'];
$folder = "/images/" ;
$move= move_uploaded_file($src,"$folder/".$image);
if($move!=false)
{
$pic = "http://localhost:8888/directoryName/images" .$filename; //This variable insert into Photo column
$query="Insert or Update Query for your table";
$rslt = mysql_query($query);
}
$data=array();
$selectQuery="select * from Emp";
$row=mysql_query($selectQuery);
while($result=mysql_fetch_array($row))
{
$data[] = $result;
}
echo json_encode($data);
I have a download button and when i click on it, instead of saving to disk it opens it in the browser. I tried a bunch of attempts to make it open in the browser but it doesnt seem to do anything
<?php
// make a connection to the database
require_once("connection/connection.php");
//retrieve the ID from the url to fetch the specific details
if ($_GET['id'] != ""){
$item_id = $_GET['id'];
$bad_id = FALSE;
}
else{
$item_id = "";
$bad_id = TRUE;
}
//select the specific item from the database
// run if statement to ensure valid id was passed
if (is_numeric ($_GET['id'])){
$query = "SELECT name FROM repository WHERE item_id = '$item_id'";
$result = mysql_query($query) or die(mysql_error());
// assign the values to an array
$row = mysql_fetch_assoc($result);
//assign the values from the array to variables
$name = $row['name'];
}
// define path to the xml file
$file = "xml/".$hud_name . "_cfg.xml";
// check to make sure the file exists
if(!file_exists($file)){
die('Error: File not found.');
} else{
// Set headers
header("Content-Type: application/xml");
header("Content-Disposition:attachment; filename=".basename($file)."");
readfile($file);
}
?>
That is download.php and it obviously finds the file because it doesnt give the error about it not existing. It also echos back the correct file path
Then on another page i have:
<img src="images/download.png" alt=""/>
Any ideas whats wrong?
Well the solution turned out to be simple in the end but i didnt see any documentation saying the header must be the very first line. If i placed:
header("Content-Type: application/xml");
as the first line and then the coding below it and the other header info at the end it works. Im not sure if that's the solution or a workaround but it fixed it for me
I have a file in which a user can view its stored files. I want that only the logged in user and it can only be viewed by that member who has stored that file. It works fine when I view other files like .html, .txt etc. But when I view any image, it doesn't work.
This is my script :
require ('config.php');
$id = intval($_GET['id']);
$dn2 = mysql_query('select authorid from files where uploadid="'.$id.'"');
while($dnn2 = mysql_fetch_array($dn2))
{
if(isset($_SESSION['username']) and ($_SESSION['userid']==$dnn2['authorid'] or $_SESSION['username']==$admin)){
$query = "SELECT data, filetype FROM files where uploadid=$id"; //Find the file, pull the filecontents and the filetype
$result = MYSQL_QUERY($query); // run the query
if($row=mysql_fetch_row($result)) // pull the first row of the result into an array(there will only be one)
{
$data = $row[0]; // First bit is the data
$type = $row[1]; // second is the filename
Header( "Content-type: $type"); // Send the header of the approptiate file type, if it's' a image you want it to show as one :)
print $data; // Send the data.
}
else // the id was invalid
{
echo "invalid id";
}
}
}
How can I view the image?
I have read every tutorial I can find on this topic, but none of them helped fix my issue. I don't know why, but my code is just giving me an html file whenever I click on the download button, instead of downloading an image file.
HTML:
Download Now
PHP:
<?php
$id= $_GET['id'];
$con= mysqli_connect("localhost","root","","dbname");
if (mysqli_connect_errno($con))
{
echo "<script type=\"text/javascript\">alert('Failed To connect to MySQL: "+"mysqli_connect_error();"+"');</script>";
}
else
{
$sql = "SELECT * FROM users_files WHERE file_id = ".$id;
$result = mysql_query($sql);
$row_cnt = mysqli_num_rows($result);
echo "<script type=\"text/javascript\">alert('".$row_cnt."');</script>";
if(!$result || !mysql_num_rows($result)){
echo "<script type=\"text/javascript\">alert('Invalid file chosen.');</script>";
//echo '<script language="javascript" type="text/javascript" >';
//echo ' window.location.assign("ViewMyFiles.php");';
//echo '</script>';
mysqli_close($con);
}
$curr_file = mysql_fetch_assoc($result);
$size = $curr_file['file_size'];
$type = $curr_file['file_type'];
$name = $curr_file['file_name'];
$content = $curr_file['file_content'];
header("Content-length: ".$size."");
header("Content-type: ".$type."");
header('Content-Disposition: attachment; filename="'.$name.'"');
readfile($content);
$_SESSION['email']=$nemail;
mysqli_close($con);
}
?>
I named the above PHP file getfile.php and I'm getting on download result as getfile.htm.
Debug!
Comment out the headers and see, what really gets to the client. Then comment them in and check in browser dev console (header + response).
You're also vulnerable to SQL injections.