Adding numbered rows/serial numbers to database query result set - php

Hello i'm having problems adding numbered rows/serial numbers to my database query result. I've used $number to collect the actual number of rows.
Then another problem i'm trying to avoid is: Numbering of Column Headers.
Thanks for the help.
<?php
$number = mysql_num_rows($query);
for ($serial = 0; $serial < $number; $serial++)
{
echo "<tr>". $serial ."</tr>";
}
for ($i = 0; $i < $number_cols; $i++)
{
echo "<th>" . mysql_field_name($query, $i) . "</th>\n";
}
while ($row = mysql_fetch_row($query))
{
echo "<tr align=center>\n";
for ($i = 0; $i < $number_cols; $i++)
{
echo "<td>";
if (!isset($row[$i]))
{
echo "NULL";
}
else
{
echo $row[$i];
}
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>";
echo "</span>";
echo "</div>";
?>

trying my best to get something sane out of your terrific code.
<?php
$serial = 1;
while ($row = mysql_fetch_row($query))
{
echo "<tr align=center>\n";
echo "<td>";
echo $serial++;
echo "</td>\n";
foreach ($row as $value)
{
echo "<td>$value</td>\n";
}
echo "</tr>\n";
}

Related

how to make a table row contents to break lline? [duplicate]

I have the following code:
for($i=0; $i<count($gallery);$i++)
{
$temp = array();
$temp = $gallery[$i];
echo "<img src='". $temp->path . "' />";
}
Now this code prints the content in one row. I want to print only 3 per row and then create new row and print another 3 and so on. How can this be done?
appreciate the support :)
EDIT: error
A PHP Error was encountered
Severity: Notice
Message: Undefined offset: 5
Filename: views/profile.php
Line Number: 105
A PHP Error was encountered
Severity: Notice
Message: Trying to get property of non-object
Filename: views/profile.php
Line Number: 106
You can do
$n = 3;
echo "<table><tr>";
for($i=0; $i<count($gallery);$i++){
$temp = array();
$temp = $gallery[$i];
echo "<td><img src='". $temp->path . "' /></td>";
if($i % $n ==0 && $i!=0 ){
echo "</tr><tr>";
}
}
echo '</tr></table>';
Edit:
If you want to do it the "right" way - by building the syntactically correct HTML, you need to do:
$n = 3;
echo "<table><tr>";
$gallery_count = count($gallery);
for($i=0; $i<$gallery_count; $i++){
$temp = array();
$temp = $gallery[$i];
echo "<td><img src='". $temp->path . "' /></td>";
if($i != 0){
if($i % $n == 0 && $i != $gallery_count-1){
echo "</tr><tr>";
}
else{
echo ""; //if it is the last in the loop - do not echo
}
}
}
//example - if the last 2 `td`s are missing:
$padding_tds = $gallery_count % $n;
if($padding_tds != 0 ){
$k = 0;
while($k < $padding_tds){
echo "<td> </td>";
}
}
echo '</tr></table>';
You just need to a modulus that checks how many have been printed - any multiple of 3 will add a break.
$x=0;
for($i=0; $i<count($gallery);$i++)
{
$x++;
$temp = array();
$temp = $gallery[$i];
echo "<img src='". $temp->path . "' />";
if (($x%3)==0) { echo "<br />"; }
}
I just redid it with tables, it's much neater, because each thing will be formatted to look correctly.
It's kind of messy because I just added a little if statement to release the tables.
<table>
<?php
$number_per_row = 3;
for($i=0; $i<count($gallery);$i++)
{
$temp = array();
$temp = $gallery[$i];
if(($i % $number_per_row) == 0) {
echo "<tr>";
}
?>
<td><?php echo "<img src='". $temp->path . "' />"; ?></td>
<?php
if(($i % $number_per_row) == $number_per_row - 1) {
echo "</tr>";
}
}
?>
</table>
$n = 3;
echo "<table>";
echo "<tr>";
for($i=0; $i<count($gallery);$i++){
if(($i % n ==0) && ($i != 0)){
echo "</tr><tr>";
}
$temp = array();
$temp = $gallery[$i];
echo "<td><img src='". $temp->path . "' /></td>";
}
echo "</tr>";
echo '</table>';``

a PHP table map

I want to create a game where I have to create a map with PHP. I want to create 100 tables boxes in the right way but I can't get it work...
$field = 100;
echo "<table border='3px' dir='ltr'>";
for ($row=0; $row < 10 ; $row++) {
echo "<tr>";
for ($column=0; $column < 10; $column++) {
echo "<td>";
echo $field;
$field--;
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
This gives me this table:
But I will need a table like:
If a for loop is not a requirement.
I would use an array, then you have a set to work from rather then calculating things, then you just need reverse the odd row, like so:
$rows = array_reverse(array_chunk(range(1, 100), 10));
echo "<table>\n";
foreach ($rows as $level => $row) {
if (($level-1) % 2) {
$row = array_reverse($row);
}
echo "\t<tr>\n";
foreach ($row as $value) {
echo "\t\t<td>$value</td>\n";
}
echo "\t</tr>\n";
}
echo "<table>\n";
https://3v4l.org/204eh

Dynamic Table Continuous <td> Count

I am stuck in a weird problem, I want to show the continuous number till the last in the row and cols,
instead of that its showing form 1-50 and then again the row starts with 1 up-to 50.
<?php
$rows = 10;
$cols = 50;
$x=1 ;
echo "<table border='1'>";
for($tr=1;$tr<=$rows;$tr++){
echo "<tr>";
for($td=1;$td<=$cols;$td++){
echo "<td>$td</td>";
}
echo "</tr>";
}
echo "</table>";
?>
Thanks
$rows = 10;
$cols = 50;
$x=1 ;
echo "<table border='1'>";
for($tr=1;$tr<=$rows;$tr++){
$style = "green";
if ($tr % 2 == 0) {
$style = "#ccc";
}
echo "<tr style='background-color:".$style."'>";
for($td=1;$td<=$cols;$td++)
{
echo "<td>$x</td>";
$x++;
}
echo "</tr>";
}
echo "</table>";
You are outputting $td which resets at every new tablerow.
Instead, you would like to output an incrementing $x, if I'm not mistaken.
<?php
$rows = 10;
$cols = 50;
$x=1 ;
echo "<table border='1'>";
for($tr=1;$tr<=$rows;$tr++){
echo "<tr>";
for($td=1;$td<=$cols;$td++){
echo "<td>" . $x . "</td>";
$x++;
}
echo "</tr>";
}
echo "</table>";
?>
In response to your comment on another answer: if you would want alternating row colors, you could use $tr and check wether it is even or uneven:
if($tr % 2 == 0)
{
// use color1
}
else
{
// use color2
}

mysqli/PHP - first two rows never show up(table with row data going across columns then moving down)

My website currently ignores the first two images you place into the database and then proceeds to add images going across 5 columns and then moving down to the next row.
Update: Now it shows 3 of the 4 images in the database. Skips one image.
<?php
$i = 1;
echo "<table>";
while ($row = $Recordset2->fetch_object()) {
if ($i == 1) {
echo "<tr>";
}
echo '<td><img src="'.$row_Recordset2['ImgSource'].'" width="100" height="100"></td>';
if ($i == 5) {
$i = 1;
echo "</tr>";
} else {
$i++;
}
}
echo "</table>";
?>
This is what my database looks like
http://i.stack.imgur.com/IFba8.jpg
This is what my website shows
http://i.stack.imgur.com/Wf7E1.jpg
Try this:
<?php
$i = 1;
echo "<table>";
while ($row = $Recordset2->fetch_object()) {
if ($i == 1) {
echo "<tr>";
}
echo '<td><img src="'.$row['ImgSource'].'" width="100" height="100"></td>';
if ($i == 5) {
$i = 1;
echo "</tr>";
} else {
$i++;
}
}
echo "</table>";
?>
Please try this.
<?php
$i = 1;
echo "<table>";
while ( $row = $Recordset2->fetch_object() ) {
if ($i == 1) {
echo "<tr>";
}
echo '<td><img src="'.$row_Recordset2['ImgSource'].'" width="100" height="100"></td>';
if ($i == 5) {
$i = 1;
echo "</tr>";
} else {
$i++;
}
}
echo "</table>";
?>

Show specific fields in array in php?

echo "<table>";
for ($x=0; $x<=count
($arr['chart_data']); $x++) {
echo "<tr>\n";
foreach($arr['chart_data'][$x] as $key=>$val)
{
echo "<td align='center;' style='color:white;'>". $val . "</td>\n";
}
echo "</tr>\n";
}
echo "</table>\n";
I want to show only the first 4 fields in the table. I am decoding a multidimensional array in php. I
Try like
$cnt = 0;
foreach($arr['chart_data'][$x] as $key=>$val) {
if($cnt++ < 4) {
echo "<td align='center;' style='color:white;'>". $val . "</td>\n";
} else {
break;
}
}

Categories