Trying to use Zend_Search_Lucene to search a MySql database and display the results. Running the following code and can't figure out why I'm not getting any info into my index. Quite new with PHP, MySql and Zend but I've spent the last week trying to figure this out on my own and have exhausted every resource I could find. Anyway, I echoed what's coming out of my database to make sure my query worked which seems to be OK. It also creates the index files just fine but when I've taken a look at it with the Luke Toolbox I get nothing but a list of the fields created filled with gooseggs. Just to make sure I'm using that correctly I found some code using Zend_Feed and ran that through Lukes and got all kinds of results. Also able to get results from that same code on my result test page but getting 0 when using the code below. Seems I can't get the database info indexed although the count tells me that 5 documents have been indexed (which is the number of rows I have in my database table) and I'm not getting any errors. The library script is just an autoloader script and where I set up my db connection which I've confirmed works as well. Although it's likely I'm missing the obvious or demonstrating what a novice I truly am, any help would be much appreciated.Thanks.
<?php>
require_once('scripts/library.php');
require_once ('Zend/Search/Lucene.php');
$index = Zend_Search_Lucene::create('./docindex');
$sql = ('SELECT * FROM news');
foreach ($db->query($sql) as $row){
echo $row ['author'];
echo $row['headline'];
echo $row ['source'];
}
foreach ($row as $document){
$document = new Zend_Search_Lucene_Document ();
$document->addField(Zend_Search_Lucene_Field::Text ('author', $docAuthor));
$document->addField(Zend_Search_Lucene_Field::Text ('headline', $docHeadline));
$document->addField(Zend_Search_Lucene_Field::Text ('source', $docSource));
$document->addField(Zend_Search_Lucene_Field::Unstored ('contents', $docStory));
$index->addDocument($document);
}
$index->commit();
echo $index->count()." documents have been indexed.\n";
?>
It looks like you had an extra foreach() that wasn't really doing anything and I couldn't see where your data variables were assigned, try this it should be pretty close:
<?php
require_once('scripts/library.php');
require_once ('Zend/Search/Lucene.php');
$index = Zend_Search_Lucene::create('./docindex');
$sql = ('SELECT * FROM news');
foreach ($db->query($sql) as $row) {
echo $row ['author'];
echo $row['headline'];
echo $row ['source'];
$document = new Zend_Search_Lucene_Document ();
//you use an unindexed field for the id because you want the
//id to be included in the search results but not searchable
$document->addField(Zend_Search_Lucene_Field::unIndexed('id', $row['id']));
$document->addField(Zend_Search_Lucene_Field::Text('author', $row ['author']));
$document->addField(Zend_Search_Lucene_Field::Text('headline', $row['headline']));
$document->addField(Zend_Search_Lucene_Field::Text('source', $row ['source']));
$document->addField(Zend_Search_Lucene_Field::Unstored('contents', $row['docStory']));
$index->addDocument($document);
}
$index->commit();
echo $index->count() . " documents have been indexed.\n";
?>
Related
I'm updating some old code that has deprecated MySQL functions. But for some reasons I cannot get all the results from the column. The strange part is that if I run the query directly on the server I get all results fine. So this is an issue with PHP getting the results, not the MySQL server or my query.
Here is the new and old code:
My current updated code:
$sql = "SELECT user, monitor FROM users WHERE `status` = 'y'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
// This works. It shows all results
echo $row["user"];
// This does not work! Only shows one result:
$account= $row["user"];
}
else {
echo 'No results';
}
When I use that query directly on DB server, I get all results. So the SQL query is correct. I actually also get all results as well in PHP if I echo the row directly like:
echo $row["user"];
But for some reason when I try to use it with a PHP with variable it only lists one user result.
In the past I used this but the mysql_fetch_array function is now deprecated
while ($row = mysql_fetch_array($result)) {
array_push($data, $row["user"]);
}
foreach($data as $value) {
$account = $value
}
I cannot use my previous code anymore as those MySQL functions are obsolete today. I need to write the results into a file and my old method worked fine. The new one using mysqli does not.
Any suggestions?
You just need to add one of these [, and one of these ].
$account[] = $row["user"];
// ^^ right here.
$account= $row["user"]; means you're storing the value of $row["user"] in $account each time the loop executes. $account is a string, and it gets a new value each time.
$account[] = $row["user"]; means you're appending each value of $row["user"] to an array instead.
You should not use array_push for this. It's overkill for appending a single value to an array. And if the array isn't defined beforehand, it won't work at all.
Forgive me if my question sounds stupid as I'm a begginer with SQLite, but I'm looking for the simplest SQLite query PHP solution that will give me full text results from at least three separate SQLite databases.
Google seems to give me links to articles without examples and I have to start from somewhere.
I have three databases:
domains.db (url_table, title_table, date_added_table)
extras.db (same tables as the first db)
admin.db (url_table, admin_notes_table)
Now I need a PHP query script that will execute a query and give me results from domains.db but if there are matches also from extras.db and admin.db.
I'm trying to just grasp the basics of it and looking for a starting point where I can at least study and learn the first code.
First, you connect to 'domains.db', query what you need, save however you want, than if there were a result in the first query, you connect to the others and query them.
$db1 = new SQLite3('domains.db');
$results1 = $db1->query('SELECT bar FROM foo');
if ($results1->numColumns() && $results1->columnType(0) != SQLITE3_NULL) {
// have rows
// so, again, $result2 = $db2->query('query');
// ....
} else {
// zero rows
}
// You can work with the data like this
//while ($row = $results1->fetchArray()) {
// var_dump($row);
//}
Source:
http://php.net/manual/en/sqlite3.query.php
http://php.net/manual/en/class.sqlite3result.php
Edit.: A better approach would be to use PDO, you can find a lot of tutorials and help to use it.
$db = new PDO('sqlite:mydatabase.db');
$result = $db->query('SELECT * FROM MyTable');
foreach ($result as $row) {
echo 'Example content: ' . $row['column1'];
}
You can also check the row count:
$row_count = sqlite_num_rows($result);
Source: http://blog.digitalneurosurgeon.com/?p=947
I'm currently pulling the data from MySQL Database with the current code Example 1
function User_Details($uid){
$uid = mysql_real_escape_string($uid);
$query = mysql_query("SELECT uid,password,email,nickname,username,profile_pic,friend_count FROM users WHERE uid='$uid' AND status='1'");
$data = mysql_fetch_array($query);
return $data;
}
I'd like to use this query across multiple PHP pages without having to write a foreach loop for every PHP file.
Currently I have it inside a class called class Wall_Updates { }, and I try to print it with the following code: Example1 : < ?php echo $data['username']; ? >.
The class Wall_Updates is being called on the header which should also include the User_Details, so the only issue is how do I print with just the following PHP example I gave above without the need of a loop.
The class words with single fielded queries such as Example 2 $face = $Wall->Profile_Pic($msg_uid); and if I echo $face it'll show my current Profile_Pic which is a single query.
Example 3 of how I don't want to do as it's very messy.
<?php
if ($uid) {
$updatesarray = $Wall->Updates($uid);
}
if ($updatesarray) {
foreach ($updatesarray as $data) {
$username = $data['username'];
?>
#HTML CODE GOES HERE
<?php } ?>
So I'd like my query to pull multiple fields from users and use it across any page without a foreach.
PS: I'm sorry if it's not making sense, I've been complained a lot for not showing what I've tried and I hope to not get complained about it this time, I appreciate for looking at my question.
you need to issue the "or die" sql command EVERYWHERE otherwise you have no idea why it failed.
http://pastie.org/7897405
you have a column name wrong (look at the last line of the pastie
also, get off of the mysql_ stuff and get into pdo. you should know better chump !
I have a problem. I have an array of values from database, when I try to pass it to a string with commas, it works fine on my localhost, but when I upload it to my online server, the string doesn't show any values. For example: select from table where in (,,) only shows the commas and in my xampp server it works excellent. Any ideas what this can be?
Here's the code:
<?php
$sql = "select id from users where gid = 1";
$result = mysql_query( $sql);
$cat_titles=array();
while( $row=mysql_fetch_assoc($result) )
{
$cat_titles[] = $row['id '];
// do stuff with other column
// data if we want
}
mysql_free_result( $result );
echo "<p>\n";
foreach($cat_titles as $v)
{
$cat_titles[]= $row['id'];
}
echo "</p>\n";
$cat_titles = implode(',',$cat_titles);
$cat_titles = substr($cat_titles,0,-2);
echo $cat_titles;
echo "select * from users where IN (".$cat_titles.")";
?>
A number of potential issues here:
You are not handling error conditions around you database access, so if you are having issue with your queries you would never know.
Your second select query doesn't specify a field in the WHERE clause, so it will never work
This section of code does absolutely nothing and is in fact where you problem likely lies.
foreach($cat_titles as $v)
{
$cat_titles[]= $row['id'];
}
Here $row['id'] won't have a value, so you are basically looping throguh your existing array and appending empty value to new indexes.
In all likelihood you could do this with a single query, it might help if you explain what you are actually trying to do.
You should not be using mysql_* functions. They are deprecated. Use mysqli or PDO instead.
Well i've been searching google, but I still can't find out how to do this.
I'm a beginner in php so i'm really stumped.
Anyways what I need to do is get all the data from a table and display it on my page.
Like
Contents of row 1
Contents of row 2
etc.
Well that's nice, get down voted for asking for help.
This might help you
print_r() displays information about a variable in a way that's readable by humans.
print_r(), var_dump() and var_export() will also show protected and private properties of objects with PHP 5. Static class members will not be shown.
Remember that print_r() will move the array pointer to the end. Use reset() to bring it back to beginning.
http://php.net/manual/en/function.print-r.php
This is pretty much PHP DB access 101
$pdo = new PDO('mysql:host=localhost;dbname=myDbName', 'username', 'password');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare('SELECT * FROM a_table');
$stmt->execute();
$resultSet = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($resultSet as $idx => $row) {
echo '<p>Contents of row ', $idx + 1, '</p><dl>';
foreach ($row as $col => $val) {
printf('<dt>%s</dt><dd>%s</dd>',
htmlspecialchars($col),
htmlspecialchars($val));
}
echo '</dl>';
}
I think google should have given you your answer since this is a rather easy to answer question, but when starting, you don't always know what to search for.
Anyways, hope this helps.
<?php
// connect with you database, returns boolean so you know if you succeeded or not
$con = mysql_connect($database,$username,$password);
if(!$scon){
die('Could not connect to database'); // Stop execution if connection fails
}
//create your query
$query = "Place your database query here";
//get the results
$result = mysql_query($query);
//now you want to go through each row of the result table and echo the contents, or
//use them for whatever reason
while($row = mysql_fetch_array($result)){
echo $row['field_you_want_to_display'];
echo $row['another_field_you_want_to_display']; //You see where this is going
}
//After doing what you want, close the connection to the database
mysql_close($con);
?>
Also, you may want to take a look at the documentation of php for find out what functions you have not seen before do.