How do I get the last part of a string in PHP - php

I have many strings that follow the same convention:
this.is.a.sample
this.is.another.sample.of.it
this.too
What i want to do is isolate the last part. So i want "sample", or "it", or "too".
What is the most efficient way for this to happen. Obviously there are many ways to do this, but which way is best that uses the least resources (CPU and RAM).

$string = "this.is.another.sample.of.it";
$contents = explode('.', $string);
echo end($contents); // displays 'it'

I realise this question is from 2012, but the answers here are all inefficient. There are string functions built into PHP to do this, rather than having to traverse the string and turn it into an array, and then pick the last index, which is a lot of work to do something quite simple.
The following code gets the last occurrence of a string within a string:
strrchr($string, '.'); // Last occurrence of '.' within a string
We can use this in conjunction with substr, which essentially chops a string up based on a position.
$string = 'this.is.a.sample';
$last_section = substr($string, (strrchr($string, '-') + 1));
echo $last_section; // 'sample'
Note the +1 on the strrchr result; this is because strrchr returns the index of the string within the string (starting at position 0), so the true 'position' is always 1 character on.

http://us3.php.net/strpos
$haystack = "this.is.another.sample.of.it";
$needle = "sample";
$string = substr( $haystack, strpos( $haystack, $needle ), strlen( $needle ) );

Just do:
$string = "this.is.another.sample.of.it";
$parts = explode('.', $string);
$last = array_pop(parts);

$new_string = explode(".", "this.is.sparta");
$last_part = $new_string[count($new_string)-1];
echo $last_part; // prints "sparta".

$string = "this.is.another.sample.of.it";
$result = explode('.', $string); // using explode function
print_r($result); // whole Array
Will give you
result[0]=>this;
result[1]=>is;
result[2]=>another;
result[3]=>sample;
result[4]=>of;
result[5]=>it;
Display any one you want (ex. echo result[5];)

Related

Get all numeric before first Alpha in PHP String

I'm trying to get all numeric before space/alpha in PHP string.
Example:
<?php
//string
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
//result I need
firstStr = 12
SecondStr = 412
thirdStr = 100
How do I can get all the number of a string just like example above?
I've an idea to get the position of first Alpha, then get all numeric before that position.
I've successfully get the position using
preg_match('~[a-z]~i', $value, $match, PREG_OFFSET_CAPTURE);
But I'm not done yet to get the numeric before the posisition.
How do I can do that, or anybody know how to fix my idea?
Anyhelp will be appreciated.
You don't need to use regex for strings like the examples you've shown, or any functions at all for that matter. You can just cast them to ints.
$number = (int) $firstStr; // etc.
The PHP rules for string conversion to number will handle it for you.
However, because of those rules, there are some other types of strings that this won't work for. For example, '-12 Car' or '412e2 8all'.
If you do use a regex, be sure to anchor it to the beginning of the string with ^ or it will match digits anywhere in the string as the other regex answers here do.
preg_match('/^\d+/', $string, $match);
$number = $match[0] ?? '';
Here's an extremely hackish approach that will work in most situations:
$s = "1001BigHairyCamels";
$n = intval($s);
$my_number = str_replace($n, '', $s);
$input = '100Pen';
if (preg_match('~(\d+)[ a-zA-Z]~', $input, $m)) {
echo $m[1];
}
This function will do the job!
<?php
function getInt($str){
preg_match_all('!\d+!', $str, $matches);
return $matches[0][0];
}
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
echo 'firstStr = '.getInt($firstStr).'<br>';
echo 'secondStr = '.getInt($secondStr).'<br>';
echo 'thirdStr = '.getInt($thirdStr);
?>

str replace - replace the x-value

Assuming I have a string
$str="0000,1023,1024,1025,1024,1023,1027,1025,1024,1025,0000";
there are three 1024, I want to replace the third with JJJJ, like this :
output :
0000,1023,1024,1025,1024,1023,1027,1025,JJJJ,1025,0000
how to make str_replace can do it
thanks for the help
As your question asks, you want to use str_replace to do this. It's probably not the best option, but here's what you do using that function. Assuming you have no other instances of "JJJJ" throughout the string, you could do this:
$str = "0000,1023,1024,1025,1024,1023,1027,1025,1024,1025,0000";
$str = str_replace('1024','JJJJ',$str,3)
$str = str_replace('JJJJ','1024',$str,2);
Here is what I would do and it should work regardless of values in $str:
function replace_str($str,$search,$replace,$num) {
$pieces = explode(',',$str);
$counter = 0;
foreach($pieces as $key=>$val) {
if($val == $search) {
$counter++;
if($counter == $num) {
$pieces[$key] = $replace;
}
}
}
return implode(',',$pieces);
}
$str="0000,1023,1024,1025,1024,1023,1027,1025,1024,1025,0000";
echo replace_str($str, '1024', 'JJJJ', 3);
I think this is what you are asking in your comment:
function replace_element($str,$search,$replace,$num) {
$num = $num - 1;
$pieces = explode(',',$str);
if($pieces[$num] == $search) {
$pieces[$num] = $replace;
}
return implode(',',$pieces);
}
$str="0000,1023,1024,1025,1024,1023,1027,1025,1024,1025,0000";
echo replace_element($str,'1024','JJJJ',9);
strpos has an offset, detailed here: http://php.net/manual/en/function.strrpos.php
So you want to do the following:
1) strpos with 1024, keep the offset
2) strpos with 1024 starting at offset+1, keep newoffset
3) strpos with 1024 starting at newoffset+1, keep thirdoffset
4) finally, we can use substr to do the replacement - get the string leading up to the third instance of 1024, concatenate it to what you want to replace it with, then get the substr of the rest of the string afterwards and concatenate it to that. http://www.php.net/manual/en/function.substr.php
You can either use strpos() three times to get the position of the third 1024 in your string and then replace it, or you could write a regex to use with preg_replace() that matches the third 1024.
if you want to find the last occurence of your string you can used strrpos
Do it like this:
$newstring = substr_replace($str,'JJJJ', strrpos($str, '1024'), strlen('1024') );
See working demo
Here's a solution with less calls to one and the same function and without having to explode, iterate over the array and implode again.
// replace the first three occurrences
$replaced = str_replace('1024', 'JJJJ', $str, 3);
// now replace the firs two, which you wanted to keep
$final = str_replace('JJJJ', '1024', $replaced, 2);

Removing last part of string divided by a colon

I have a string that looks a little like this, world:region:bash
It divides folder names, so i can create a path for FTP functions.
However, i need at some points to be able to remove the last part of the string, so, for example
I have this world:region:bash
I need to get this world:region
The script wont be able to know what the folder names are, so some how it needs to be able to remove the string after the last colon.
$res=substr($input,0,strrpos($input,':'));
I should probably highlight that strrpos not strpos finds last occurrence of a substring in given string
$tokens = explode(':', $string); // split string on :
array_pop($tokens); // get rid of last element
$newString = implode(':', $tokens); // wrap back
You may want to try something like this:
<?php
$variable = "world:region:bash";
$colpos = strrpos($variable, ":");
$result = substr($variable, 0, $colpos);
echo $result;
?>
Or... if you create a function using this information, you get this:
<?php
function StrRemoveLastPart($string, $delimiter)
{
$lastdelpos = strrpos($string, $delimiter);
$result = substr($string, 0, $lastdelpos);
return $result;
}
$variable = "world:region:bash";
$result = StrRemoveLastPart($variable, ":");
?>
Explode the string, and remove the last element.
If you need the string again, use implode.
$items = array_pop(explode(':', $the_path));
$shotpath = implode(':', $items);
Use regular expression /:[^:]+$/, preg_replace
$s = "world:region:bash";
$p = "/:[^:]+$/";
$r = '';
echo preg_replace($p, $r, $s);
demo
Notice how $ which means string termination, is made use of.
<?php
$string = 'world:region:bash';
$string = implode(':', explode(':', $string, -1));

How to get everything after a certain character?

I've got a string and I'd like to get everything after a certain value. The string always starts off with a set of numbers and then an underscore. I'd like to get the rest of the string after the underscore. So for example if I have the following strings and what I'd like returned:
"123_String" -> "String"
"233718_This_is_a_string" -> "This_is_a_string"
"83_Another Example" -> "Another Example"
How can I go about doing something like this?
The strpos() finds the offset of the underscore, then substr grabs everything from that index plus 1, onwards.
$data = "123_String";
$whatIWant = substr($data, strpos($data, "_") + 1);
echo $whatIWant;
If you also want to check if the underscore character (_) exists in your string before trying to get it, you can use the following:
if (($pos = strpos($data, "_")) !== FALSE) {
$whatIWant = substr($data, $pos+1);
}
strtok is an overlooked function for this sort of thing. It is meant to be quite fast.
$s = '233718_This_is_a_string';
$firstPart = strtok( $s, '_' );
$allTheRest = strtok( '' );
Empty string like this will force the rest of the string to be returned.
NB if there was nothing at all after the '_' you would get a FALSE value for $allTheRest which, as stated in the documentation, must be tested with ===, to distinguish from other falsy values.
Here is the method by using explode:
$text = explode('_', '233718_This_is_a_string', 2)[1]; // Returns This_is_a_string
or:
$text = end((explode('_', '233718_This_is_a_string', 2)));
By specifying 2 for the limit parameter in explode(), it returns array with 2 maximum elements separated by the string delimiter. Returning 2nd element ([1]), will give the rest of string.
Here is another one-liner by using strpos (as suggested by #flu):
$needle = '233718_This_is_a_string';
$text = substr($needle, (strpos($needle, '_') ?: -1) + 1); // Returns This_is_a_string
I use strrchr(). For instance to find the extension of a file I use this function:
$string = 'filename.jpg';
$extension = strrchr( $string, '.'); //returns "jpg"
Another simple way, using strchr() or strstr():
$str = '233718_This_is_a_string';
echo ltrim(strstr($str, '_'), '_'); // This_is_a_string
In your case maybe ltrim() alone will suffice:
echo ltrim($str, '0..9_'); // This_is_a_string
But only if the right part of the string (after _) does not start with numbers, otherwise it will also be trimmed.
if anyone needs to extract the first part of the string then can try,
Query:
$s = "This_is_a_string_233718";
$text = $s."_".substr($s, 0, strrpos($s, "_"));
Output:
This_is_a_string
$string = "233718_This_is_a_string";
$withCharacter = strstr($string, '_'); // "_This_is_a_string"
echo substr($withCharacter, 1); // "This_is_a_string"
In a single statement it would be.
echo substr(strstr("233718_This_is_a_string", '_'), 1); // "This_is_a_string"
If you want to get everything after certain characters and if those characters are located at the beginning of the string, you can use an easier solution like this:
$value = substr( '123_String', strlen( '123_' ) );
echo $value; // String
Use this line to return the string after the symbol or return the original string if the character does not occur:
$newString = substr($string, (strrpos($string, '_') ?: -1) +1);

PHP substring extraction. Get the string before the first '/' or the whole string

I am trying to extract a substring. I need some help with doing it in PHP.
Here are some sample strings I am working with and the results I need:
home/cat1/subcat2 => home
test/cat2 => test
startpage => startpage
I want to get the string till the first /, but if no / is present, get the whole string.
I tried,
substr($mystring, 0, strpos($mystring, '/'))
I think it says - get the position of / and then get the substring from position 0 to that position.
I don't know how to handle the case where there is no /, without making the statement too big.
Is there a way to handle that case also without making the PHP statement too complex?
The most efficient solution is the strtok function:
strtok($mystring, '/')
NOTE: In case of more than one character to split with the results may not meet your expectations e.g. strtok("somethingtosplit", "to") returns s because it is splitting by any single character from the second argument (in this case o is used).
#friek108 thanks for pointing that out in your comment.
For example:
$mystring = 'home/cat1/subcat2/';
$first = strtok($mystring, '/');
echo $first; // home
and
$mystring = 'home';
$first = strtok($mystring, '/');
echo $first; // home
Use explode()
$arr = explode("/", $string, 2);
$first = $arr[0];
In this case, I'm using the limit parameter to explode so that php won't scan the string any more than what's needed.
$first = explode("/", $string)[0];
What about this :
substr($mystring.'/', 0, strpos($mystring, '/'))
Simply add a '/' to the end of mystring so you can be sure there is at least one ;)
Late is better than never. php has a predefined function for that. here is that good way.
strstr
if you want to get the part before match just set before_needle (3rd parameter) to true
http://php.net/manual/en/function.strstr.php
function not_strtok($string, $delimiter)
{
$buffer = strstr($string, $delimiter, true);
if (false === $buffer) {
return $string;
}
return $buffer;
}
var_dump(
not_strtok('st/art/page', '/')
);
One-line version of the accepted answer:
$out=explode("/", $mystring, 2)[0];
Should work in php 5.4+
This is probably the shortest example that came to my mind:
list($first) = explode("/", $mystring);
1) list() will automatically assign string until "/" if delimiter is found
2) if delimiter "/"is not found then the whole string will be assigned
...and if you get really obsessed with performance, you may add extra parameter to explode explode("/", $mystring, 2) which limits maximum of the returned elements.
The function strstr() in PHP 5.3 should do this job.. The third parameter however should be set to true..
But if you're not using 5.3, then the function below should work accurately:
function strbstr( $str, $char, $start=0 ){
if ( isset($str[ $start ]) && $str[$start]!=$char ){
return $str[$start].strbstr( $str, $char, $start+1 );
}
}
I haven't tested it though, but this should work just fine.. And it's pretty fast as well
You can try using a regex like this:
$s = preg_replace('|/.*$|', '', $s);
sometimes, regex are slower though, so if performance is an issue, make sure to benchmark this properly and use an other alternative with substrings if it's more suitable for you.
Using current on explode would ease the process.
$str = current(explode("/", $str, 2));
You could create a helper function to take care of that:
/**
* Return string before needle if it exists.
*
* #param string $str
* #param mixed $needle
* #return string
*/
function str_before($str, $needle)
{
$pos = strpos($str, $needle);
return ($pos !== false) ? substr($str, 0, $pos) : $str;
}
Here's a use case:
$sing = 'My name is Luka. I live on the second floor.';
echo str_before($sing, '.'); // My name is Luka
$arr = explode("/", $string, 2); $first = $arr[0];
This Way is better and more accurate than strtok
because if you wanna get the values before # for example
while the there's no string before # it will give you whats after the sign .
but explode doesnt
$string="kalion/home/public_html";
$newstring=( stristr($string,"/")==FALSE ) ? $string : substr($string,0,stripos($string,"/"));
why not use:
function getwhatiwant($s)
{
$delimiter='/';
$x=strstr($s,$delimiter,true);
return ($x?$x:$s);
}
OR:
function getwhatiwant($s)
{
$delimiter='/';
$t=explode($delimiter, $s);
return ($t[1]?$t[0]:$s);
}

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