Retrieving a specific row depending on a date variable? - php

Question

I have 7 columns that which contain the information of closing times, each for one day. (It goes like VENUE_CLOSE_T_MO, VENUE_CLOSE_T_TU... etc)
How would I, for example choose one of those columns depending on a date variable ($somevariable) which contains a specific date?
For example, if the date variable was Sunday, March 18 22:00, it would choose column VENUE_CLOSE_T_SU.
Thanks for the help everyone!
EDIT (Solution given by TEEZ that solved the issue)
My Date variable is $Start.
And this is the code:
$day_name=strtoupper(date('D',$start));
$day_name=substr($day_name,0,2);
$selectcolumn='VENUE_CLOSE_T_'.$day_name;
So in this case $selectcolumn = VENUE_CLOSE_T_SU
And the echo is then this:
$row[$selectcolumn]
Thanks for all your help again Teez!

Answer 1

first get day name from variable ($somevariable)
$day_name=strtoupper(date('D',$somevariable));
then make query like below for getting column according to day in $somevariable
select concat('VENUE_CLOSE_T_',left($day_name,2)) as datecolumnname from tableame
EDIT:
OR
you don't need to do this in query if you taking all column in query. just add these lines in php code where you printing data in we page under date column
$day_name=strtoupper(date('D',$somevariable));
$day_name=substr($day_name,0,2);
$selectcolumn='venues.VENUE_CLOSE_T_'.$day_name;
echo $row[$selectcolumn];