Javascript pagination (next project / previous project) with jQuery? - php

I recently came upon a site that has done exactly what I want as far as pagination goes. I have the same basic setup as the site I just found.
I would like to have prev and next links to navigate through my portfolio. Each project would be in a separate file (1.php, 2.php, 3.php, etc.) For example, if I am on the 1.php page and I click "next project" it will take me to 2.php.
The site I am referencing to accomplishes this with javascript. I don't think it's jQuery:
function nextPg(step) {
var str = window.location.href;
if(pNum = str.match(/(\d+)\.php/i)){
pNum = pNum[1] * 1 + step+'';
if ((pNum<1) || (pNum > 20)) { pNum = 1; }
pNum = "".substr(0, 4-pNum.length)+pNum;
window.location = str.replace(/\d+\.php/i, pNum+'.php');
}
}
And then the HTML:
Next Project
I can't really decipher the code above, but I assume the script detects what page you are on and the injects a number into the next page link that is one higher than the current page.
I suppose I could copy this code but it seems like it's not the best solution. Is there a way to do this with php(for people with javascript turned off)? And if not, can this script be converted for use with jQuery?
Also, if it can be done with php, can it be done without dirty URLs?
For example, http://www.example.com/index.php?next=31
I would like to retain link-ability.
I have searched on stackoverflow on this topic. There are many questions about pagination within a page, but none about navigating to another page that I could find.

From your question you know how many pages there are going to be. From this I mean that the content for the pages themselves are hardcoded, and not dynamically loaded from a database.
If this is the approach you're going to take you can take the same course in your javascript: set an array up with the filenames that you will be requesting, and then attach event handlers to your prev/next buttons to cycle through the array. You will also need to keep track of the 'current' page, and check that incrementing/decrementing the current page will not take you out of the bounds of your page array.
My solution below does the loading of the next page via AJAX, and does not change the actual location of the browser. This seems like a better approach to me, but your situation may be different. If so, you can just replace the related AJAX calls with window.location = pages[curPage] statements.
jQuery: (untested)
$(function() {
var pages = [
'1.php',
'2.php',
'3.php'
];
var curPage = 0;
$('.next').bind('click', function() {
curPage++;
if(curPage > pages.length)
curPage = 0;
$.ajax({
url: pages[curPage],
success: function(html) {
$('#pageContentContainer').html(html);
}
});
});
$('.prev').bind('click', function() {
curPage--;
if(curPage < 0)
curPage = (pages.length -1);
$.ajax({
url: pages[curPage],
success: function(html) {
$('#pageContentContainer').html(html);
}
});
});
});
HTML:
<div id = "pageContentContainer">
This is the default content to display upon page load.
</div>
<a class = "prev">Previous</a>
<a class = "next">Next</a>
To migrate this solution to one that does not have the pages themselves hardcoded but instead loaded from an external database, you could simply write a PHP script that outputs a JSON encoded array of the pages, and then call that script via AJAX and parse the JSON to replace the pages array above.
var pages = [];
$.ajax({
url: '/ajax/pages.php',
success: function(json) {
pages = JSON.parse(json);
}
});

You can do this without ever effecting the structure of the URL.
Create a function too control the page flow, with an ajax call
function changePage(page){
$.ajax({
type: 'POST',
url: 'myPaginationFile.php',
data: 'page='+page,
success: function(data){
//work with the returned data.
}
});
}
This function MUST be created as a Global function.
Now we call the function on page load so we always land at the first page initially.
changePage('1');
Then we need to create a Pagination File to handle our requests, and output what we need.
<?php
//include whatever you need here. We'll use MySQL for this example
$page = $_REQUEST['page'];
if($page){
$q = $("SELECT * FROM my_table");
$cur_page = $page; // what page are we on
$per_page = 15; //how many results do we want to show per page?
$results = mysql_query($q) or die("MySQL Error:" .mysql_error()); //query
$num_rows = mysql_num_rows($result); // how many rows are returned
$prev_page = $page-1 // previous page is this page, minus 1 page.
$next_page = $page+1 //next page is this page, plus 1 page.
$page_start = (($per_page * $page)-$per_page); //where does our page index start
if($num_rows<=$per_page){
$num_pages = 1;
//we checked to see if the rows we received were less than 15.
//if true, then we only have 1 page.
}else if(($num_rows % $per_page)==0){
$num_pages = ($num_rows/$per_page);
}else{
$num_pages = ($num_rows/$per_page)+1;
$num_pages = (int)$num_pages;
}
$q. = "order by myColumn ASC LIMIT $page_start, $per_page";
//add our pagination, order by our column, sort it by ascending
$result = mysql_query($q) or die ("MySQL Error: ".mysql_error());
while($row = mysql_fetch_array($result){
echo $row[0].','.$row[1].','.$row[2];
if($prev_page){
echo ' Previous ';
for(i=1;$i<=$num_pages;$i++){
if($1 != $page){
echo "<a href=\"JavaScript:changePage('".$i."');\";> ".$i."</a>";
}else{
echo '<a class="current_page"><b>'.$i.'</a>';
}
}
if($page != $num_pages){
echo "<a class='next_link' href='#' id='next-".$next_page."'> Next </a>';
}
}
}
}
I choose to explicitly define the next and previous functions; so here we go with jQuery!
$(".prev_link").live('click', function(e){
e.preventDefault();//not modifying URL's here.
var page = $(this).attr("id");
var page = page.replace(/prev-/g, '');
changePage(page);
});
$(".next_link").live('click', function(e){
e.preventDefault(); // not modifying URL's here
var page = $(this).attr("id");
var page = page.replace(/next-/g, '');
changePage(page);
});
Then finally, we go back to our changePage function that we built initially and we set a target for our data to go to, preferably a DIV already existing within the DOM.
...
success: function(data){
$("#paginationDiv").html(data);
}
I hope this gives you at least some insight into how I'd perform pagination with ajax and php without modifying the URL bar.
Good luck!

Related

Counting clicks changing link href

I asked this question but did not explain it thoroughly. I have a regular link:
Click Me
I want the change the href after the link is clicked 10 times not by the individual use but clicked 10 total times by all users.My jquery is obviously flawed but here is what i have:
var count = 0;
$(document).ready(function(){
$('a').click(function(){
count++;
if(count > 10){
$('a').attr("href","https://www.yahoo.com");
}
});
});
I am new to jQuery but from what ive read cookies and local storage store individual users information not the total websites information. So how could i use ajax with a database to do this? maybe even php?
You have a huge fundamental misunderstanding of how JavaScript works.
Firstly, when someone clicks that link, they're going to be navigated away from your page unless you do something to prevent that (e.preventDefault or return false in jQuery). Once they're navigated away, your counter is lost because is stored locally, in memory, for the life of the page.
Secondly, even if the counter wasn't cleared, or you stored the counter in a cookie, or localStorage, it will only count for a single user. If you want to count the clicks by all users, you're going to have to do that server side. i.e., in PHP.
So... how do we do that? Well, as I said before, when a user clicks that link, they're going to be sent to Google. Your site will have no knowledge of what has occurred.
We have two options to deal with this. We can intercept the click, and use AJAX (more appropriately "XHR") to send a request back to your server, where you can log the click, before forwarding them off to Google.
Or, you re-write the URL to something like /log_click.php?forward=http://google.com. Now when the user clicks the link, they will actually be sent to your log_click.php script, where you can log the click to your database, and then use $_GET['forward'] in combination with header('location: ...') to forward them off to their destination. This is the easiest solution. Through some JavaScript hackery, you can hide the link so that when they mouse over it, they won't even know they're being sent to your site (Google does this).
Once you've accumulated your 10 clicks, you again use PHP to write out a different HTML link the next time someone views that page.
HTML
<a href='http://www.google.com' data-ref='99'>Click Me</a>
Javascript
$("a").click(function() {
var _this = $(this);
var ref = $(this).data('ref');
$.ajax({
url: '/click_url.php',
type: 'POST',
data: {id:ref}
success: function(href) {
if(href != '')
_this.attr("href",href);
}
});
}
PHP (click_url.php)
if($_POST['id'] > 0){
$id = $_POST['id'];
//count increment
$sql = "UPDATE table SET count = count + 1 WHERE id = '$id'";
mysql_query($sql);
//get row count
$sql = "SELECT * FROM table WHERE id = '$id' LIMIT 1";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
//if count > 10 , return new url
if($row['count'] > 10){
die($row['href']);
}
}
While clicking the link you can call an ajax request and increment the count in the server. So that u should remove link from href and call manually by using javascript window.location.href each time. Hope that helps
var count = 0;
$(document).ready(function(){
$('a').click(function(e){
e.preventDefault();
count++;
if(count > 10){
$('a').attr("href","https://www.yahoo.com");
}
});
});
and use ajax like below
//send set state request
$.ajax({
type: "POST",
contentType: "text/xml; charset=utf-8",
datatype: "xml",// you can set json and etc
url:"your php file url",
data: {test:test1},// your data which you want to get and post
beforeSend: function (XMLHttpRequest) {
// your action
},
success: function (data, textStatus, XmlHttpRequest) {
// your action },
error: function (XMLHttpRequest, textStatus, errorThrown) {
alert(errorThrown);
}
});
for more deatils see Ajax
Mark's answer is more useful, even you want to implement for the sake of some constraints then try below with jQuery 1.9
I have implemented for 3 clicks, AFAIU you need to change the URL on every 3rd successive click
var c=0;
$(document).on('click', 'a#ten', function(e){
c++;
alert('clicked ' + c + ' times');
if(c%3 == 0) {
$('a').attr("href","https://www.yahoo.com");
alert('changed');
c = 0;
}
e.preventDefault();
})
working DEMO
You must save no of times that link has been clicked in the database with php. when you render the link(with php) check the no of times it has been called before and decide what link to render.
Click Me
write this javascript in the page wher you place your link
$(function()
{
$('.mylink').click(function()
{
$.ajax({
type: "POST",
url: "listening/end/point", // enter your counting url here
async: false
);
});
});
And in server on the listening end point write php script to store no of times that link has been called.

Updating PHP session variable using jQuery Ajax

I know this question has been answered multiple times but I haven't been able to find one specifically to solve my problem.
I'm making a website where a user can sell their eBay items, using the eBay API (which is a bit of a pain!). My problem is at the results' pagination: I need a way of updating a $_SESSION page number variable so that the page reloads and displays a different page of results. I'm doing this with AJAX, and it's my first time using it.
The process is the following:
1)User clicks on one of the pagination links on the bottom of the page (like what's at the bottom of your Google results), which I made into a form with a hidden field storing the next page number that updates accordingly when the user clicks.
2)Use AJAX to update said $_SESSION variable on an external page (without refreshing!)
3)Reload the page and display the appropriate page of results.
The problem seems to be between steps #2 and 3. The bits of code I use:
Set $_SESSION variable
<?php
session_start();
if(!isset($_SESSION['pageNumber']))
{
$_SESSION['pageNumber'] = "1";
echo("Session value NOT set, pageNumber = " . $_SESSION['pageNumber']);
}
else
{
echo("Session value SET, pageNumber = " . $_SESSION['pageNumber']);
}
?>
Pagination
<form action="">
<div id="pagination" style="text-align:center; <?php if($totalPages == 1) echo('display:none;');?>">
<?php
global $totalPages;
if(intval($_SESSION['pageNumber']) != 1)
{
print("Previous Page");
}
for($i = 1; $i <= $totalPages; $i++)
{
print("$i");
print(" ");
}
if(intval($_SESSION['pageNumber']) != $totalPages)
{
print("Next Page");
}
?>
</div>
<input type="hidden" name="nextPageNumber" id="nextPageNumber" value="<?php echo($_SESSION['pageNumber']);?>">
</form>
Update Hidden Field and $_SESSION Value
function updatePageNumber(newNumber)
{
//Update hidden field
if(newNumber == -1)
{
var num = document.getElementById('nextPageNumber').value;
num--;
document.getElementById('nextPageNumber').value = num;
}
else if(newNumber == 0)
{
var num = document.getElementById('nextPageNumber').value;
num++;
document.getElementById('nextPageNumber').value = num;
}
else
{
document.getElementById('nextPageNumber').value = newNumber;
}
//Update $_SESSION value with AJAX
var dataString = 'nextPageNumber='+ document.getElementById('nextPageNumber').value;
$.ajax(
{
url: "scripts/updatePageNumber.php",
type: "POST",
data: dataString,
dataType: "text",
success: function(text)
{
alert("Done! Response: " + text);
}
});
And the PHP file
<?php
if (isset($_POST['nextPageNumber']))
{
session_start();
die("Made it this far!");
$nextPageNumber = $_POST['nextPageNumber'];
$_SESSION['pageNumber'] = $nextPageNumber;
echo $nextPageNumber;
}
?>
Note: I don't get to the PHP file's die() method, nor the alert with the AJAX's success (by the way, is that how to properly get the response text?)
I'd greatly appreciate any help at all, I've been stuck at this for quite a long time now!
Your ajax call doesnt have nextPageNumber in its data, so it isn't seen by your PHP script (not in $_POST array) your test for it fails.
(As a general comment, your question involves too many working parts that makes it not a good fit for a site like this, devoted to helping others with similar problems. Next time please isolate the very part of the code that is causing the problem. This is likely why you have no other answers yet - people are sick of getting downvoted when trying to help solve something so comprehensive.)

How do I implement Ajax/JQuery to an existing PHP MYSQL pagination script?

Below is a working pagination script that displays content from a MySQL database. I need to have the pages seamlessly load within the container "#content" rather than have the entire page refreshed. I search extensively for hours but none of the tutorials I encountered helped me implement Ajax/JQuery on this script.
Here is the code I use to display my articles + pagination.
<div id="content">
<?php
include('db.php');
$stmt = $db->query('SELECT * FROM db');
$numrows = $stmt->rowCount();
$rowsperpage=21;
$totalpages=ceil($numrows/$rowsperpage);
if(isset($pageid)&&is_numeric($pageid)){$page=$pageid;}else{$page=1;}
if($page>$totalpages){$page = $totalpages;}
if($page<1){$page=1;}
$offset=($page-1)*$rowsperpage;
$stmt=$db->prepare("SELECT * FROM db ORDER BY ID DESC LIMIT ?,?");
$stmt->bindValue(1, "$offset", PDO::PARAM_STR);
$stmt->bindValue(2, "$rowsperpage", PDO::PARAM_STR);
if($stmt->execute()) {
while ($row = $stmt->fetch()) {
echo '
<article>
article here
</article>
';}}
$range=4;
echo'
<div id="pagination">';
if($page>1){
echo "
<a href='http://www.domain.com/1/'><<</a>";
$prevpage = $page - 1;
echo "
<a href='http://www.domain.com/$prevpage/'><</a>";
}
for ($x = ($page - $range); $x < (($page + $range) + 1); $x++) {
if(($x>0)&&($x<= $totalpages)){
if($x==$page){
echo'
<span class="current">'.$x.'</span>';
}
else{echo"<a href='http://www.domain.com/$x/'>$x</a>";}
}
}
if($page!=$totalpages){
$nextpage=$page+1;
echo"
<a href='http://www.domain.com/$nextpage/'>></a>";
echo "
<a href='http://www.domain.com/$totalpages/'>>></a>";
}
echo '
</div>';
?>
Your setup is a little unclear, but bear with me.
I'm going to assume that on the client side you know when to load the next page (ie the user clicks a button or scrolls to the end of the page etc...) I'm also going to assume that the PHP code you've posted is in its own file and outputs only what you've posted in your question (aka it outputs only the HTML for the articles and nothing else, no wrappers, nothing, if not make it so.
What you're going to want to do is use jQuery (From your question it looks like you already have it on your site so adding another library isn't too taboo) to make an AJAX request to this PHP page. The PHP then echos out what you've posted and the jQuery inserts this on the page inside the #content div.
First a note: I wouldn't recommend having your PHP page output the content div, I would recommend having that stay on the client side and only changing the content of it to what your script returns.
To load new content, you can use this javascript function on the client side:
function makePaginationRequest( pagenum = 1 ) {
// Make ajax request
$.ajax("test2.php", {
// Data to send to the PHP page
data: { "pagenum": pagenum },
// Type of data to receive (html)
dataType: 'html',
// What to do if we encounter a problem fetching it
error: function(xhr, text){
alert("Whoops! The request for new content failed");
},
// What to do when this completes succesfully
success: function(pagination) {
$('#content').html(pagination);
}
})
}
You can place any other parameters you need to pass to the server inside the "data" object (the data: { "pagenum": pagenum }, in key-value form. As you can see from the example, you pass the page number to this function and it passes the "pagenum" request variable to the server.
You'll want to implement a better error handler obviously. As well as change the "test2.htm" filename to that of your PHP script.
A better way of doing this
I feel compelled to mention this:
The way above (what you asked for) is really a messy way of doing this. Whenever you request AJAX data from your server, the server should return content, not markup. You should then insert this content into markup on the client side.
To do this, you would modify your PHP script to first put everything in an array (or an array of array for multiple articles) like this:
while ($row = $stmt->fetch()) {
$output_array[] = array(
"post_title" => $row["title"],
"post_date" => $row["date"],
// etc....
);
}
Then echo it like so:
die(json_encode($output_array));
Then modify your json request:
function makePaginationRequest( pagenum = 1 ) {
$.ajax("test2.htm", {
data: { "pagenum": pagenum },
dataType: 'json',
error: function(xhr, text){
alert("Whoops! The request for new content failed");
},
success: function(pagination) {
// Empty the content area
$('#content').empty();
// Insert each item
for ( var i in pagination ) {
var div = $('<article></article>');
div.append('<span class="title">' + pagination[i].post_title + "</span>");
div.append('<span class="date">' + pagination[i].post_date + "</span>");
$('#content').append(div)
}
}
})
}
jQuery will automagically parse this JSON output into a native javascript object for you.
Taking this approach of having the client make the markup takes alot of load off of your server, and requires less bandwith.
Food for thought, hope that helps.
If you want to do the least amount of rewriting to your original script, the jQuery .load() method might be your best bet. You would basically just need to supply an id to the element that contains all of your articles; something like this should work:
<div id="container">
<div id="articles-container">
<article> ... </article>
</div>
</div>
<div id="pagination">
1 ...
</div>
Then add a script tag and some jQuery code:
<script>
$(function(){
$('#pagination').on('click', 'a', function(e){
e.preventDefault();
var url = $(this).attr('href');
$('#container').load(url + ' #articles-container');
});
});
</script>
.load() will fetch the page, and if you add the optional fragment to the URL, it will filter the result to the element matching the fragment.
EDIT:
Okay, so, to make this work with your current pagination, you need to manually swap the elements. So, assuming your generated markup looks something like this:
<div id="pagination">
1
<span class="current">2</span>
3
4
5
</div>
We want this to happen after the load() completes, so we need to add a callback function to it. I'm also adding a self reference to the clicked element, which we need later:
$(function(){
$('#pagination').on('click', 'a', function(e){
e.preventDefault();
var $this = $(this);
var url = $this.attr('href');
$('#container').load(url + ' #articles-container', function(response, status, jqxhr){
});
});
});
Inside the callback is where we start manipulating #pagination. The first part is easy enough:
var $curr = $('#pagination span.current');
var page = $curr.text();
$curr.replaceWith('' + page + '');
Now we need to replace the link we just clicked:
$this.replaceWith('<span class="current">' + $this.text() + '</span>');
Et viola!, your pagination should be updated. Here's the whole update:
$(function(){
$('#pagination').on('click', 'a', function(e){
e.preventDefault();
var $this = $(this);
var url = $this.attr('href');
$('#container').load(url + ' #articles-container', function(response, status, jqxhr){
var $curr = $('#pagination span.current');
var page = $curr.text();
$curr.replaceWith('' + page + '');
$this.replaceWith('<span class="current">' + $this.text() + '</span>');
});
});
});

pagination using javascript in php and mysql

I am trying to do pagination using javascript but all in vain, please help..
<script language="Javascript">
function nextclicked()
{
document.getElementById("clickednext").value = document.getElementById("clickednext").value + 1;
document.forms["newsmanager"].submit();
}
</script>
<form name = "newsmanager" method="post" action="NewsManager.php">
<input type = "hidden" id="clickednext" name="clickednext" >
if(isset($_POST['clickednext']) && $_POST['clickednext']>=1)
{
$_POST['clickednext'] = $_POST['clickednext'] +9;
$NewsQuery = "SELECT NewsDetails FROM News LIMIT " .$_POST['clickednext']. ",10";
}
else
{
$NewsQuery = "SELECT NewsDetails FROM News LIMIT 0,10";
}
$result = mysqli_query($dbc,$NewsQuery);
}
UPDATE :
<div class=d2 align=left>
<a href="#" onclick=" nextclicked(); submit();" >
Next
</a>
UPDATE ENDS......
The first time when i click the Next hyperlink label, then it works, that is, 10 is assigned $_POST['clickednext'] and the next 10 values appear from the database, but the second time i click the label , then it doesn't?
Your code is completely wrong.
You should scrap it and start all over again.
I will show you how to do so.
I have a rule when it comes to Ajax, and it goes like this.
If you cannot do the functionality without Ajax, there's no way you should attempt to do it with Ajax.
If you know anything about javascript, you'll know that XmlHttpRequest makes working with Ajax hellish. Hence why we have javascript frameworks such as JQuery and Mootools. You might also like a php ajax framework called PHPLiveX. I only use JQuery, so here's how to do the solution in JQuery.
Step 1: Strip your ajax and create the solution in php
This pagination tutorial in php will help.
Step 2a: Create the ajax with PHPLiveX
PHPLiveX is really cool and underated, as it allows you to use php functions without reloading the whole page, in a more convienient way, than if you'd used javascript.
PHPLiveX will help you the best.
It's pretty straightforward. You call a php function to do something, return some values, and choose the target: of where you want the values to go.
I personally would use PHPLiveX for this job, as it's better suited. JQuery is more for postdata.
Step 2b: Create the ajax in JQuery
I'm going to assume that you know how to select elements by id with JQuery and append or replaceWith them. If not you can look the function up.
Below is the code required to submit a POST or GET with JQuery. Adapt this to your code. You'll have to modify the code below to add appending and stuff.
$(".tornfieldcard").click(function() {
var dataString = $("#addfieldForm").serialize();
//lets get the form data and use that
var newValue = $("#newValue").val();
var itemid4 = $(this).attr("itemid4");
var dataString = "itemid=" + itemid + "&newValue=" + newValue;
//or get the attr/valu from elements
$("#loading5").show();
$("#loading5").fadeIn(400).html('<img src="icons/loading.gif">');
$.ajax({
type: "POST",
url: "ajaxcontrols.php",
data: dataString,
cache: false,
success: function(html){
$("#loading5").remove();
$(".fieldcardNEW").fadeOut('slow');
$('.fieldcardNEW').remove();
$("#conveyorbelt_"+itemid4+"").append("<div class=\"fieldcard\"><b>"+attribute+"</b> <br><div itemid=\""+itemid4+"\" attribute=\""+attribute+"\">"+value+"</div></div>");
}
});
Here's a little algorithm I wrote using php to create pagination:
$x=$numStories;
$y=$x%5;
$z=($x-$y)/5;
if($y!=0){
$numPages=$z+1;
}
else{
$numPages=$z;
}
Where 5 is the number of stories per page, and $numStories is the total amount of stories (or in your case, news articles) you wish to use.
Then, just display the amount of pages ($numPages) in any way you'd like, and your good to go.
[EDIT]
I created an archive.php page, that took a page number as a GET parameter (archive.php?page=3). From there, I selected the first five entries in my database after $pageNum (in this case 3) * 10 (or however many posts per page you are wanting to display.
The best thing to do is make as much of your code dynamic and flexible, so that it is self sustaining.
[EDIT 2]
<script>
function nextclicked()
{
document.forms["newsmanager"].submit();
}
</script>
<?php
$currentPage = $_POST['page'];
$numStories = //get the total amount of entries
$x=$numStories;
$y=$x%10;
$z=($x-$y)/10;
if($y!=0){
$numPages=$z+1;
}
else{
$numPages=$z;
}
if(isset($currentPage) && $currentPage>=1)
{
$currentPage = $currentPage +9;
$NewsQuery = "SELECT NewsDetails FROM News LIMIT " .$currentPage. ",10";
}
else
{
$NewsQuery = "SELECT NewsDetails FROM News LIMIT 0,10";
}
$result = mysqli_query($dbc,$NewsQuery);
}
?>
<form>
<input type='hidden' name='page' text='' value='<?php echo "$currentPage"' />
</form>
Next-->
PHP is server-side language. you have to put your php code to
<?php
=====
<script language="Javascript">
function nextclicked()
{
document.getElementById("next").value = document.getElementById("next").value + 1;
document.forms["newsmanager"].submit();
}
</script>
<form name = "newsmanager" method="post" action="NewsManager.php">
<input type = "hidden" id="clickednext" name="clickednext" >
<?php
if(isset($_POST['clickednext']) && $_POST['clickednext']>=1)
{
$_POST['clickednext'] = $_POST['clickednext'] +9;
$NewsQuery = "SELECT NewsDetails FROM News LIMIT " .intval($_POST['clickednext']). ",10";
}
else
{
$NewsQuery = "SELECT NewsDetails FROM News LIMIT 0,10";
}
$result = mysqli_query($dbc,$NewsQuery);
}
?>
additionally, user can't click to hidden form field. you need, for example button and have onclick event ready
<button name="next" value="1" onclick="nextclicked();">Next</button>

How to handle pagination with JQuery and AJAX?

On my site I have the links First, Prev, Next, and Last. These are empty links that are captured and handled by JQuery. However, still being very new to AJAX and JQuery, I'm not sure how to accomplish what I want. I believe I could get this working using post but the only problem is that I want the target page number to go in to the URL in this format:
http://www.mywebsite.com/index.php?page=3
Then on page load I would use the $_GET variable and with the page number I could request the appropriate tables from the database and display them to the user.
Basically what I'm asking is how to make simulate this behavior with JQuery.
You can do something like this:
Javascript:
post:
function pagination(page) {
if (!page)
var page = 1;
$.post("index.php", { page: page }, function(data) {
// data loaded, do something
});
}
or get
function pagination(page) {
if (!page)
var page = 1;
$.get("index.php?page=" + page, function(data) {
// data loaded, do something
});
}
Then, You just have to call the javascript function:
Prev Next
As long as you're requesting this from the same site as the script, you might be able to get away with this.
To load remote content (Google Cross Site Scripting for limitations), jQuery has a simple function to do that:
$('#result').load('ajax/test.html');
This loads test.html into the item with the id of #ajax. Pretty simple.
In order to get the arguments, you can use this script (credit goes to http://jquery-howto.blogspot.com/2009/09/get-url-parameters-values-with-jquery.html):
function getUrlVars()
{
var vars = [], hash;
var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');
for(var i = 0; i < hashes.length; i++)
{
hash = hashes[i].split('=');
vars.push(hash[0]);
vars[hash[0]] = hash[1];
}
return vars;
}
The usage information is avaliable there too.

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