I'm using Views 3 in Drupal 7 to output a list of fields and using a grouping field to generate separate lists. I need each of the groupings to have a unique ID attribute applied to the < ul > but they don't by default.
As far as I'm aware I would need to edit the views-view-list.tpl.php template but I don't know how to achieve a unique ID per iteration.
Can anyone help please?
easiest way I can think of off the top of my head...
<?php print $wrapper_prefix; ?>
<?php if (!empty($title)) : ?>
<h3><?php print $title; ?></h3>
<?php endif; ?>
<ul id="<?php echo uniqid(); ?>">
<?php foreach ($rows as $id => $row): ?>
<li class="<?php print $classes_array[$id]; ?>"><?php print $row; ?></li>
<?php endforeach; ?>
</ul>
<?php print $wrapper_suffix; ?>
that would go in your views-view-list.tpl.php file.
For future reference:
Put a div around everyting in view-views-list.tpl.php. You can (ab-)use the $title to generate unique (but consistent) id's.
Do it like this:
<?php $id = str_replace('FOR ALL UNWANTED CHARS','',$title); ?>
<div id="<?php print strtolower($id); ?>">
You can use the $view->dom_id variable. It is a unique id for that views instance.
In your .tpl.php file:
<?php print $view->dom_id; ?>
From comments in modules\views\theme\theme.inc:
<?php
// It is true that the DIV wrapper has classes denoting the name of the view
// and its display ID, but this is not enough to unequivocally match a view
// with its HTML, because one view may appear several times on the page. So
// we set up a hash with the current time, $dom_id, to issue a "unique" identifier for
// each view. This identifier is written to both Drupal.settings and the DIV
// wrapper.
?>
Related
Is it possible to only show the code below if there's a category description?
<h2>About <?php $cat = get_the_category(); echo $cat[0]->cat_name; ?></h2>
<?php $catID = get_the_category(); echo category_description ( $catID[0] ); ?>
I have these codes on my single posts in Wordpress but sometimes, I forgot to add descriptions on a new category that I added. So when a user visits the post, they will just see the word About Category and no description at all, making it looks like an incomplete article.
I'm not a developer and I'm also not familiar with PHP. I only added that code on the single.php to show the description. But I want it not to show when there's no description available.
Hope someone can give me the exact code to make it work.
Thanks!
Good practice to assign your values into variables at the top of your script before entering into HTML whenever possible. This will help prevent you making redundant calls and to debug your code better. Once you have your assigned values, you'll want to check if the value is empty. I am assuming the code you presented will always return some kind of value for index 0.
<?php
$cat = get_the_category();
$cat_0 = $cat[0];
$cat_0_name = $cat_0->cat_name;
$cat_0_desc = category_description($cat_0);
?>
<?php if(!empty($cat_0_desc)): ?>
<h2>About <?php echo $cat_0_name; ?></h2>
<?php echo $cat_0_desc; ?>
<?php endif; ?>
I should like to point out that I am choosing to use an alternative syntax for control structures versus the traditional brace control. This will make your code more readable and easily debugged when mixed in with HTML.
If your code is still throwing you errors, I would suggest you check your error logs as something would be happining during the get_the_cateory() call or that it's not returning any values resulting in error with $cat[0].
<?php if ($cat = get_the_category() && count($cat)>0) { ?>
<!-- <?php echo print_r($cat,1); ?> -->
<h2>About <?php echo $cat[0]->cat_name;?></h2>
<?php echo category_description ($cat[0]->cat_id); ?>
<?php } ?>
I am trying to set a condition for php- mysql pagination so that it can change the current page "li" to "li class="active" " to mark the current selected page. I am new to php and searching for such pagination tutorial but no luck.
I have done so far what is working but not able to mark selected page. Here $id is for detecting the current page id. How can I set if condition ( or other) so that I can mark the current page item in the pagination? Thousands thanks for helping me.
<ul class="pagination">
<?php if($id > 1) {?> <li>Previous</li><?php }?>
<?php
for($i=1;$i <= $page;$i++){
?>
<?php
if ($id>1)
{ ?>
<li class="active"><?php echo $i;?></li>
<?php }
?>
<!-- <li><?php echo $i;?></li> -->
<?php
}
?>
<?php if($id!=$page)
//3!=4
{?>
<li>Next</li>
<?php }?>
</ul>
You could change your for loop from
<?php
for($i=1;$i <= $page;$i++){
?>
<?php
if ($id>1)
{ ?>
<li class="active"><?php echo $i;?></li>
<?php }
?>
<!-- <li><?php echo $i;?></li> -->
<?php
}
?>
to:
<?php
for($i=1;$i <= $page;$i++){
$class=($i==$id)? ' class="active"' : '';
echo '<li'.$class.'>'.$i.'</li>';
}
?>
If I've understood your code properly, $page represents total pages and $id represents the current page, this will set the current page number as the active class and leave the other pages without the class
Assuming that $id is the current page number, and that $page is the total number of pages, you need to highlight only one by doing the following in your loop:
if($i==$id) // highlight
else // don’t highlight
Your main errors are that you didn’t test whether $i==$id, and you didn’t have an alternative unhighlighted version.
I really think that you should simplify your code by separating your logic from the HTML. It becomes very unreadable otherwise, and very hard to manage.
I have taken the liberty of doing just that. This way you can see where the logic does the hard work, an you only need to print the results in the HTML.
<?php
$id=3; // test value
$page=20; // test value
$li=array(); // temporary array for convenience
$template='<li%s>%s</li>';
if($id>1) $li[]=sprintf($template,'',$id-1,'Previous');
for($i=1;$i<=$page;$i++) {
if($i==$id) $li[]=sprintf($template,' class="active"',$i,$i); // Current
else $li[]=sprintf($template,'',$i,$i);
}
if($id<$page) $li[]=sprintf($template,'',$id+1,'Next');
$li=implode('',$li); // convert to string for printing
?>
<ul class="pagination">
<?php print $li; ?>
</ul>
You will also see two techniques to make things easier:
I use an array as a temporary container. It is easier to add items this way and then to implode it into a string afterwards
sprintf makes it easier to define a template string, so you can manage the HTML component more easily, and fill in the gaps when the time comes.
I have my data being output to a span currently... this is how it looks:
Now, when i remove the span and place a div there i am given this output:
This is desired, but I want to set a height to my page and have the data show up in as little as 3 columns. How would I do this? I have searched everywhere online but can't seem to find anything that shows a solution.
I did read that some use javascript for the format but i am still clueless on even this option.
My desired output would look like this:
If you know how many items you want in a column then you can seperate them out into individual divs and then float those divs to the left to get them to be next to each other.
<div style='float:left'>
//Items go here
</div>
<div style='float:left'>
//Items go here
</div>
etc.
If you figure out how many items your query returned, say using mysql_num_rows() and divide by 3 you can tell how many to put in each column.
Also be sure to clear the floats afterwards, so like this:
<div style="clear:both"></div>
Sometimes this is necessary as there will be random issues if this is not put there.
What you are describing can be solved with styling only. You have several divs that must be displayed in columns. The easiest way is floating them to the left, and setting the width for 1/3 of the parent. If you want 4 columns, set the with to 1/4 of the parent, and so on.
<div class='sqlResult' style="float:left;width:33%;">
<a href='#'>$key</a>
</div>
Also as other answers mentioned, don't use duplicated ids. Always use classes. If you need to target each div individually, give it a unique id, such as "category_1", "category_2", and so on.
This should work
<table><tr>
<?php $count=0; $total=mysqli_stmt_num_rows($sql)-1; $idxcount=0; $limit=10; while($row = mysqli_fetch_array($sql)): $key = $row['Keyword_Name']; ?>
<?php if($count == 0){ echo '<td>';} ?>
<span>
<?php echo $key; ?>
</span>
<?php if($total == $idxcount): ?>
</td>
<?php elseif($count == $limit): ?>
</td>
<?php $count=0; else: $count++; ?>
<?php endif; $idxcount++; ?>
<?php endwhile; ?>
</tr></table>
How do you when using custom fields in Wordpress echo just the first value using foreach?
Currently the code is:
<?php for(get_field('venue_event') as $post_object): ?>
<?php echo get_the_title($post_object) ?>
<?php endforeach; ?>
This takes the field from the wordpress page (the field is a link to another page), creates a link to that page using get_permalink but when I want to echo the page title it does it, but then it also echos all other values that are not needed.
If you just want the execute the first iteration of the loop, try this:
<?php foreach(get_field('venue_event') as $post_object): ?>
<?php echo get_the_title($post_object) ?>
<?php break; ?>
<?php endforeach; ?>
Wouldn't it then be easier just to use the first element of the returned array? Maybe Wordpress offers other filters that return the the page's title only.
you can just add
$counter = 0;
<?php for(get_field('venue_event') as $post_object): ?>
$counter++;
if($counter == 1)
{
<?php echo get_the_title($post_object) ?>
}
<?php endforeach; ?>
I have an array of user ids and I need to go through the a user: id field within a view, adding a bit of specific HTML for matching and non-matching results.
So I'm guessing something like this needs to go in views-view-field--uid.tpl.php:
<?php if (//Field content matches an array value): ?>
<span class="friend"><?php print $output; ?></span>
<?php endif; ?>
<?php if (//Field content doesn't match an array value): ?>
<span class="not-friend"><?php print $output; ?></span>
<?php endif; ?>
Can someone help me fill in the gaps, please? :)
Assuming $ouput is going to be only an integer representing the uid (and not HTML markup), you could do something like this:
<span class="<?php if(!in_array($output, $your_array)): ?>not-<?php endif; ?>friend">
<?php print $output; ?>
</span>
see php in_array()
However, $output might be HTML. If that's the case you should use $row instead of $output.
To see what $row contains I love doing this in template files:
<!-- <?php echo print_r($row,true); ?> -->
(then view source in browser)
Also, I'd recommend not doing this at all in your template file because it ties logic to the theme... Check out Views Customfield -- it will let you do PHP in a custom field... If you put it under the UID, and exclude UID from display, you can access the UID and execute the same code I've got above in the custom field, using the $data object instead of $row or $output.