how do i send a timestamped image name to mysql with PHP - php

Question

Below I have included my code that uploads multiple images to a folder and the path to mysql. I am brand new so please excuse me for such a silly question but I can not figure where to start with sending this timestamp or $fileName value to mysql.
<?php
require_once('storescripts/connect.php');
mysql_select_db($database_phpimage,$phpimage);
$uploadDir = 'upload/';
if(isset($_POST['upload']))
{
foreach ($_FILES as $file)
{
$fileName = $file['name'];
$tmpName = $file['tmp_name'];
$fileSize = $file['size'];
$fileType = $file['type'];
if ($fileName != ""){
$filePath = $uploadDir;
$fileName = str_replace(" ", "_", $fileName);
//Split the name into the base name and extension
$pathInfo = pathinfo($fileName);
$fileName_base = $pathInfo['fileName'];
$fileName_ext = $pathInfo['extension'];
//now we re-assemble the file name, sticking the output of uniqid into it
//and keep doing this in a loop until we generate a name that
//does not already exist (most likely we will get that first try)
do {
$fileName = $fileName_base . uniqid() . '.' . $fileName_ext;
} while (file_exists($filePath.$fileName));
$result = move_uploaded_file($tmpName, $filePath.$fileName);
}
if(!get_magic_quotes_gpc())
{
$fileName = addslashes($fileName);
$filePath = addslashes($filePath);
}
$fileinsert[]=$filePath;
}
$cat=$_POST['cat'];//this is the category the product is stored in
$about=$_POST['about'];//this is some general information about the item
$price=$_POST['price'];//the price of the item
$item=$_POST['item'];//the name of the item
$name1=basename($_FILES['image01'][$fileName]);//the file name of the first actual jpg
$name2=basename($_FILES['image02'][$fileName]);//the file name of the sencond actual jpg
$name3=basename($_FILES['image03'][$fileName]);//the file name of the third actual jpg
$name4=basename($_FILES['image04'][$fileName]);//the file name of the fourth actual jpg
$query = "INSERT INTO image (mid, cid, about, price, item, name1, name2, name3, name4) ".
"VALUES ('','$cat','$about','$price','$item','$name1','$name2','$name3','$name4')";
mysql_query($query) or die('Error, query failed : ' . mysql_error()); }
?>

Answer 1

If I understand your question correctly, you need to change:
$fileinsert[]=$filePath;
to:
$fileinsert = array(); // initialize the variable before the loop
...
$fileinsert[]=$filePath.$fileName; // or just $fileName if you don't need the path in the DB
and then you need to change:
$name1=basename($_FILES['image01'][$fileName]);//the file name of the first actual jpg
$name2=basename($_FILES['image02'][$fileName]);//the file name of the sencond actual jpg
$name3=basename($_FILES['image03'][$fileName]);//the file name of the third actual jpg
$name4=basename($_FILES['image04'][$fileName]);//the file name of the fourth actual jpg
to:
$name1=$fileinsert[0];
$name2=$fileinsert[1];
$name3=$fileinsert[2];
$name4=$fileinsert[3];
Something like that should do it.