Ajax Form Submission & Javascript Confirm Error - php

I have a form that submits through Ajax, which works perfectly at the moment. I tried to add a confirm option to allow / prevent the Ajax submission through adding the following lines:
var answer = confirm('Submit now?');
return answer // answer is a boolean
if(answer) { ... }
Below is my full function, which, as you can see, fires on clicking the submit button. The error occurs when the user selects okay in the dialog. The entire page is refreshed and any single Ajax warnings are returned at the top of a blank screen. In a normal case, without this confirm code, the error messages appear in the div#result tag at the bottom of the form.
$("#submitbtn").click(function() {
var answer = confirm('Submit now?');
return answer // answer is a boolean
if(answer) {
$('#result').html('<img id="loading" src="images/loading.gif" />').fadeIn();
var input_data = $('#create_po').serialize();
$.ajax({
type: "POST",
url: "<?php echo "http://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI']; ?>",
data: input_data,
success: function(msg){
$('#loading').remove();
$('<div>').html(msg).appendTo('div#result').hide().fadeIn('slow');
}
});
return false;
}
});
How should I implement a confirm dialog that doesn't refresh the screen? Any suggestions would be greatly appreciated. Thanks!

You are doing return answer. Which doesn't make any sense here.
It will stop the JavaScript function, and will return the boolean. Remove this line, and you're set
Also, add this to make your submit not fireing if the confirm box is false ;)
if (answer){
// your ajax call
}
else {
return false;
}

Do not use this:
<input type="submit">
Use this:
<input type="button">
A submit button automatically submits a form. A regular button does nothing. You can use that to listen for clicks and THEN submit your form, or not.

Related

Submitting form with AJAX without button

I'm trying to send a form with AJAX and without submit button. Everything works just fine with submit button, but if I try to submit the form by clicking something else it won't work.
I searched for an answer for quite a while, but didn't find anything useful so far.
function ajaxSubmit(){
var showHideForm = jQuery('#dashboard-hki-subjects-form').serialize();
$.ajax({
type:"POST",
url: "/wp-admin/admin-ajax.php",
data: showHideForm,
success:function(data){
$('#formMessage').html(data);
}
});
return false;
}
$('.show-hide-subject-button').click(function(){
var subject = $(this).attr('subject');
$('#hide-subject').attr('value',subject);
});
$('#dashboard-hki-subjects-form').submit(ajaxSubmit);
I'm using Wordpress, so the AJAX is handeled with admin-ajax.php.
What if you just use an enter key handler...
Try this:
<input type="text" name="txt"/>
$('#txt').keydown(function (e){
if(e.keyCode == 13){
console.log('you pressed enter!'); //prints to the browser console...
ajaxSubmit(); //the function you described in your question...
}
})
You have to bind the ajaxSubmit() to whatever there is you're clicking, otherwise there simply will be nothing on your page to trigger it. E.g., if you want your form to be submitted whenever you click on the .show-hide-subject-button element, you have to call ajaxSubmit() explicitly:
$('.show-hide-subject-button').click(function(){
var subject = $(this).attr('subject');
$('#hide-subject').attr('value',subject);
ajaxSubmit();
});

Submiting a form after clicking the submit button to perform an AJAX query, unexpected results

I have a form, I have a submit button. On click of the submit button, I suspend the form from submitting and peform an AJAX request. This sometimes works and sometimes doesnt. Can you see any flaws in the code below?
$('#ambition_submit').click(function(e){
e.preventDefault();
var output = getTimelineEntryData(data.toJSON());//console.log(output);
$.getJSON('http://www.test.com/x/api/add_subgoals.php',{action:'add.subgoals',ambition_id:ambition_id,subgoals:output}, function (response) {
//var this_url = this.url; console.log(this_url);
if (response.status == 200) {
var result = response.message;//alert(response.message);
$('form[name=testing747]').submit();//console.log('Test ' + $('form[name=testing747]').length);
}
else{
alert(response.message);
}
});
});
Thanks
I previously had some issues with click in the past.
I changed it to live and fixed those issues. Maybe it won't fix yours, but you could give it a try:
$('#ambition_submit').live('click',function(){
});
For the most recent jquery version, it has been replaced by .on though.
Hope that helps!

How would I check the value in form before sending it to server using ajax

I want to check the value enter in the form by user. i have applied validation and its working. The problem is that if user enter any form value incorrectly and then clicks submit, the whole page is refreshed and all input data is lost.
I want that validations is checked before passing it to server. One of my friends told me its possible with AJAX. Can anyone guide a beginner on how to do this?
You can use javascript instead and save the server from transferring some extra KBs and calculations by using Ajax (which technically is javascript but you send the request back to the server)
Jquery has a plugin called validation that will make your life easier though:
http://docs.jquery.com/Plugins/validation
There is a live demo in the link above
For example if you wanted to validate the username you could do this
<script>
$(document).ready(function(){
$("#commentForm").validate();
});
</script>
<form id="commentForm">
<input id="uname" name="name" class="required" />
</form>
yes you can use ajax or otherwise with your current approach you can use sessions to store user data and prevent it from being lost. with ajax you can show response from the server to show to the user.
$.ajax({
url: 'ajax_login.php',
type:'post'.
data:(/*data from form, like,*/ id: $('#username').val())
success: function( data ) {
if(data == 1) {
$('.feedback').html('data has been saved successfully');
//redirect to another page
}
else {
$('.feedback').html('data could not be saved');
$('.errors').html(data);
}
}
});
ajax_login.php would be something like
<?php
if(isset($_POST)) {
//do form validation if it is valid
if(form is valid) {
saveData();
echo 1;
}
else {
echo $errors;
}
}
?>
Do not need ajax.
Just set the onsubmit attribute of your form to "return checkfun();" and define checkfun some way like this:
function checkfun()
{
if ( all things were checked and no problem to submit)
return true;
else
{
alert('ERROR!');
return false;
}
}

jquery ajax post - how to get data back?

I have a profile page that contains a series of images. I want to use jQuery to allow the user to delete an image from the server and have the page update without reloading the entire page. When it's successful, it will remove the image's containing div from the page. My delete function is PHP; fairly simple:
delete.php
<?php
if (isset($_POST['id'])) {
if (unlink($_POST['id'])) {
echo "success";
}
else {
echo "failure";
}
}
?>
(There's already user authentication in place just to get them to the page that calls delete.php.)
Here's the html of one displayed image - there can be up to 5 of these chunks one after another:
<div class="box">
<img src="uploads/t_10DOT_22C_1111_1300370702_3.jpg" />
<h5><a rel="external" href="uploads/10DOT_22C_1111_1300370702_3.jpg">See full version</a></h5>
<a href="#" id="10DOT_22C_1111_1300370702_3.jpg" class="delete" onclick="return ConfirmDelete();" >x</a>
<div class="clear"></div>
</div>
My jQuery so far looks like this:
$(document).ready(function() {
$('#load').hide();
});
$(function() {
$(".delete").click(function() {
$('#load').fadeIn();
var commentContainer = $(this).parent();
var id = $(this).attr("id");
var string = 'id='+ id ;
$.ajax({
type: "POST",
url: "delete.php",
data: string,
cache: false,
success: function(data){
commentContainer.slideUp('slow', function() {$(this).remove();});
$('#load').fadeOut();
}
});
return false;
});
});
The part I'm concerned with is the ajax post. How does the success part actually work? What do I need to do in my php file so that ajax knows whether the delete was a success or failure?
Once an ajax post request has finished executing the file you sent the request to, if there was no error, the code you add in the "success" section is executed, in this case
success: function(data){
/*The code you need*/
});
The previous part if where the code is executed, the "data" variable contains anything you return from your php file, it can be data, it can be a simple "true" or "false", you choose what to send to let your jQuery know if it was successful.
Hope this helps a bit.
Edit Note:
function(applyData){
if ( applyData.toString() == 'invalid' ){
$('#pollError').html('Global styles cannot be modified.');
$('#pollNotice').html('');
}
else{
$('#pollNotice').html('The changes to the style have been applied.');
}
});
The previous example is a live example of what you can do inside the function in the "success" event. There I handle an "invalid" status and otherwise it's successful, after that I refresh a couple DIVs in case of invalid or update a single DIV in case of success.
This is the php that executes:
if ( !$db->isGlobal($id_css)){
$data['id_poll'] = $id_poll;
$data['id_css'] = $id_css;
$data['css'] = $css;
$db->applyCssChanges($data);
}
else{
echo 'invalid';
}
You've two obvious options I can think of:
Your returned text should appear in the data parameter supplied to your success callback function - however you'll probably also need to make sure it's in a format compatible with the MIME Content-Type returned by your PHP, or jQuery might complain that it can't parse it, or:
Send back a 5xx Failure type message from your PHP using the header() function if the delete didn't work. That should then trigger an AJAX error callback, which you'll need to supply.
From delete.php return whether the delete succeeded or not. In the success even check for that data and handle it appropriately.
HTH.

Jquery form only working the first time you submit it, and not the second

I have a form that you can add data to a database. It is all done with jquery and ajax so when you press submit it validates the code and then if everything is correct it submits the post data with out refreshing the page. The problem is the form works the first time, but then when you go to submit another entry with the form it doesn't work. I thought it had something to do with the
$(document).ready(function(){
But I really have no idea. I've pasted some of the code below. It is pretty long, but this should give enough info to know what it's doing.
The entire js file is at http://www.myfirealert.com/callresponse/js/AddUser.js
$(document).ready(function(){
$('#AddCaller').click(function(e){
//stop the form from being submitted
e.preventDefault();
/* declare the variables, var error is the variable that we use on the end
to determine if there was an error or not */
var error = false;
var Firstname = $('#Firstname').val();
...OTHER FORM FIELDS HERE
/* in the next section we do the checking by using VARIABLE.length
where VARIABLE is the variable we are checking (like name, email),
length is a javascript function to get the number of characters.
And as you can see if the num of characters is 0 we set the error
variable to true and show the name_error div with the fadeIn effect.
if it's not 0 then we fadeOut the div( that's if the div is shown and
the error is fixed it fadesOut. */
if(Firstname.length == 0){
var error = true;
$('#Firstname_error').fadeIn(500);
}else{
$('#Firstname_error').fadeOut(500);
}
if(Lastname.length == 0){
var error = true;
$('#Lastname_error').fadeIn(500);
}else{
$('#Lastname_error').fadeOut(500);
}
...MORE CONDITIONAL STATEMENTS HERE
//now when the validation is done we check if the error variable is false (no errors)
if(error == false){
//disable the submit button to avoid spamming
//and change the button text to Sending...
$('#AddCaller').attr({'disabled' : 'true', 'value' : 'Adding...' });
/* using the jquery's post(ajax) function and a lifesaver
function serialize() which gets all the data from the form
we submit it to send_email.php */
$.post("doadd.php", $("#AddCaller_form").serialize(),function(result){
//and after the ajax request ends we check the text returned
if(result == 'added'){
//$('#cf_submit_p').remove();
//and show the success div with fadeIn
$('#Add_success').fadeIn(500);
$('#AddCaller').removeAttr('disabled').attr('value', 'Add A Caller');
document.getElementById('Firstname').value = "";
document.getElementById('Lastname').value = "";
document.getElementById('PhoneNumber').value = "";
document.getElementById('DefaultETA').value = "";
document.getElementById('Apparatus').value = "";
document.getElementById('DefaultLocation').value = "";
setTimeout(" $('#Add_success').fadeOut(500);",5000);
}else if(result == 'alreadythere'){
//checks database to see if the user is already there
$('#Alreadythere').fadeIn(500);
$('#AddCaller').removeAttr('disabled').attr('value', 'Add A Caller');
}
else{
//show the failed div
$('#Add_fail').fadeIn(500);
//reenable the submit button by removing attribute disabled and change the text back to Send The Message
$('#AddCaller').removeAttr('disabled').attr('value', 'Send The Message');
}
});
}
});
});
Right now, the first time you use the form it works great. and the button is reenabled, but then when you try to make another entry and click the button nothing happens.
Thanks for the help!
EDIT: After the form submits the first time the button is still enabled and you can click on it, but when you click on it nothing happens... even if you don't fill in the form. It's like the click event of the form isn't firing the first time.
EDIT2 As requested, I'm going to post the HTML, it's behind a password protected site, so I can't send you the page link.
<form action='addcallers.php' method='post' id='AddCaller_form'>
<h2>Add Callers</h2>
<p>
First Name:
<div id='Firstname_error' class='error'> Please Enter a First Name</div>
<div><input type='text' name='Firstname' id='Firstname'></div>
</p>
<p>
Last Name:
<div id='Lastname_error' class='error'> Please Enter a Last Name</div>
<div><input type='text' name='Lastname' id='Lastname'></div>
</p>
...MORE FORM FIELDS HERE
<div style="display:none;">
<input type='text' name='DefaultLocation' id='DefaultLocation' value= "Sometthing" readonly=readonly >
</div>
</p>
<p>
<div id='Add_success' class='success'> The user has been added</div>
<div id='Alreadythere' class='error'> That user is already in the database</div>
<div id='Add_fail' class='error'> Sorry, don't know what happened. Try later.</div>
<p id='cf_submit_p'>
<input type='submit' id='AddCaller' value='Send The Message'>
</p>
</form>
</div>
EDIT3 There is other ajax on the page too, but it's written in straight javascript. I'm not sure if that would affect the functionality in any way. But if needed I can post that ajax as well.
EDIT4 I got the original tutorial from http://web.enavu.com/tutorials/create-an-amazing-contact-form-with-no-ready-made-plugins/ and modified it
EDIT After putting in some different alerts, I found out that it does not do the conditional statement if(error==false)... Any Idea why?
most likely, it's the #DefaultLocation field, since it's a read only and you are resetting it after the first post:
document.getElementById('DefaultLocation').value = "";
And never changing it's value back to something (or are you?)
so you have to do one of the following:
don't reset it
set it's value with something after posing the form
don't validate it at all since it's a read only and you are using it as a hidden input (which is wrong by the way)!
also, it can be the other "ajax" code you are talking about so please post that too here, also maybe you have other fields (elements) somewhere else on the page with same IDs like the ones in the form..
anyway, here are sometips for you:
1- close the input tags correctly (add / to the end of it):
<input type='text' name='Firstname' id='Firstname' />
2- make sure all DIVs and Ps are closed...as it seems that you have an open P here:
<p>
<div id='Add_success' class='success'> The user has been added</div>
<div id='Alreadythere' class='error'> That user is already in the database</div>
<div id='Add_fail' class='error'> Sorry, don't know what happened. Try later.</div>
</p> <---- missing this one
<p id='cf_submit_p'>
3- you are redeclaring the error variable all the time, you don't need to do that:
if(Firstname.length == 0){
var error = true;
....
just use error = true; without var this applies on all places you are changing its value only use var on initialization:
var error = false;
4- instead of this:
$('#AddCaller').attr({'disabled' : 'true', 'value' : 'Adding...' });
use:
$('#AddCaller').attr({'disabled' : 'disabled', 'value' : 'Adding...' });
5- if you are using DefaultLocation as a hidden field then instead of this:
<div style="display:none;">
<input type='text' name='DefaultLocation' id='DefaultLocation' value= "Sometthing" readonly=readonly />
</div>
use:
<input type="hidden" name="DefaultLocation" id="DefaultLocation" value="Something" />
Try to change from using the click event handler to the form's submit event handler
Change this : $('#AddCaller').click
To this : $('#AddCaller_form').submit
Do not remove the attribute of disabled, set it to false.
This line
$('#AddCaller').removeAttr('disabled').attr(...
should be
$('#AddCaller').attr('disabled', false).attr(...
I assume that by removing and adding attributes, the element is removed and replaced by the new one, but the handler is not re-attached. Try using $('#AddCaller').live('click', function(){ //code }) instead of .click()
This function send queries to php and can return results from the php file using ajax.
I have left comments for guide. the first part with try & catch statements does not need modifications. go to #1 and #2
function ajaxFunction(){
var ajaxRequest;
//Browser compatible. keep it as it is
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
//Browser compatible end
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
//#2 opional: create functions to return data from your php file
$('#resultArea').html(ajaxRequest.responseText);
}
}
//#1 Set the form method, filename & query here here
ajaxRequest.open("GET", "serverTime.php?query=something", true);
ajaxRequest.send(null);
}
example:
<input type='submit' value='ajax-submit' onclick='ajaxFunction()' />
quick jquery plugin for that since you might use this in almost every ajax form on your site:
it will disable all fields that could trigger a submit event and also add a class on the form tag so that you can apply some styling, or showing a load message when the form is submitted:
jQuery.extend(jQuery.fn, {
formToggle: function (enable){
return this.each(function(){
jQuery(this)[(enable ? 'remove' : 'add') + 'Class']('disabled')
.find(':input').attr('disabled', !enable);
},
enable: function(){ return this.formToggle(true); },
disable: function(){ return this.formToggle(false); }
}
then on your jq ajax code:
[...]
var $form = $(your_form).submit(function(){
$.ajax({
type: 'post',
url: "/whatever/",
data: $form.serialize(),
success: function (){ alert ('yay');},
complete: function(){ $form.enable();},
error: function(){ alert('insert coin')}
}
$form.disable();
return false;
});
It should be enough to properly block the submits while the forms is sending/receiving data.
If you are really paranoid you can add a check so that it cannot be sent twice between the moment the user triggers the submit and the fields get disabled with : if ($form.is('.disabled')) return false; as first line of the submit handler, but it shouldn t be necessary really
Set some breakpoints in Firebug and watch if it goes somewhere.
Button can lose its click handler after submit and applying effects. You probably need to assign click handler again after submit and stuff.
Not 100% on this but try setting the code as a separate function then rebinding the click event at the end.
Example:
function addCaller(e) {
// your unchanged code
$('#AddCaller').click(addCaller(e));
}
$(document).ready(function(){
// added an unbind just in case
$('#AddCaller').unbind('click').click(addCaller(e));
});
Try to change this:
$('#AddCaller').attr({'disabled' : 'true', 'value' : 'Adding...' });
into that:
$('#AddCaller').attr({'value' : 'Adding...' });
This should make it work.

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