Here is my js code.
....
var arrayData = {"projectId": projectId, "stateId":stateId};
$.ajax({
type: "GET",
contentType: "application/json; charset=utf-8",
url: "/bidboldly/projects/editproject/",
data: arrayData,
success : function(response) {
alert(response);
},
error: function(){
alert("error");
}
})
Server side.
$city = $this->City->find('list',array('conditions' =>array('City.status'=>1, 'City.state_id'=>$this->params['url']['stateId']),'fields'=>array('City.id','City.city'),'order'=>array('City.city ASC')));
echo json_encode($city);
After that in client side I've recieved city list + html. Something like this.
..."Young America" [20292]=> string(10) "Zanesville" } <html><head>......
Why is HTML transfered ?
This article http://book.cakephp.org/1.1/view/316/Helpers says you should use the ajax render layout:
$this->layout = "ajax";
Another page full of helpful articles on ajax and cake php is this one:
http://ahsanity.wordpress.com/2007/02/23/get-started-with-ajax-in-cakephp/
Related
First, let me say that I've looked through other similar questions on this site and the jQuery documentation. So far, I haven't found something that fixes my issue.
I am trying to get HTML data from ajax request but every time in response i got current page html.
Here is my Ajax function.
jQuery.ajax({
url:"url to function call",
type: "POST",
datatype : "html",
headers: {
'Content-Type': 'application/x-www-form-urlencoded'
},
data: {
qtext: filter_search
},
success:function(data) {
console.log(data);
jQuery("#appendHtml").html(data);
},
error : function(data) {}
});
and here is my Joomla PHP function where I have return HTML
public function getHtmlAjax()
{
$token = $this->createToken();
$listData = $this->getKapsulelist($token);
$html = $this->buildLayout($listData);
echo $html;
jexit();
}
I had this issue because I was using:
echo admin_url(); to get the ajaxurl,
after changing to
echo admin_url('admin-ajax.php');
it worked!
I am extremely bad at AJAX (actually, I just started to learn it).
So, I write whois service on PHP and I want to make it to output the result via AJAX-request.
All I have at the moment is:
my PHP code:
$domain = $_POST['domain'];
$whois = new Whois();
header("content-type:application/json");
$res = $whois->getWhois($domain); // Calls the Whois-query function;
echo json_encode($res);
my JS code:
$('#submit').on('click', function() {
e.preventDefault();
var domain = $('#value').val();
});
$.ajax({
url: 'ajax/whois.php',
type: "post",
data: {'domain': domain, 'action': 'whois'},
dataType: "json",
success: function(json) {
$('#whoisResult').html('<h2>Whois Query result for ' + domain + '</h2>');
$('#whoisContent').html(json.html);
},
error: function(xhr, status) {
$('#whoisResult').html('<h2>Sorry, an error occured. Try again later, please!</h2>')
}
});
As HTML I have an input: <input type="text" id="value"> and the submit button.
I searched for the script examples and tried to make something similar, but it does not work at all...
P.S. Guess you won't hit this question a negative rating :)
P.P.S: As requested, this is my response from PHP:
{"domain":"exp.cm","whois":"[Domain]\nDomain: exp.cm\nStatus: active\nChanged: 2014-02-25T12:22:00.957819+02:00\n\n[Holder]\nType: Legal person\nName: Name, Surname\nEmail: email#example.com\nPhone: Phone here\nAddress: Address goes here\nSome other info\n\nUpdated: 2014-03-18T18:12:35.717462+00:00\n"}
In this case you don't need the JSON datatype, just return html.
Additionally, you'll want the ajax request to be inside the click event. In your click event, you also forgot to pass the e parameter.
$domain = $_POST['domain'];
$whois = new Whois();
header("content-type:text/html");
$res = $whois->getWhois($domain); // Calls the Whois-query function;
echo $res;
js:
$('#submit').on('click', function(e) {
e.preventDefault();
var domain = $('#value').val();
$.ajax({
url: 'ajax/whois.php',
type: "post",
data: {'domain': domain, 'action': 'whois'},
//dataType: "json",
success: function(html) {
$('#whoisResult').html('<h2>Whois Query result for ' + domain + '</h2>');
$('#whoisContent').html(html);
},
error: function(xhr, status) {
$('#whoisResult').html('<h2>Sorry, an error occured. Try again later, please!</h2>')
}
});
});
The code I want to work:
$.ajax({
type: "POST",
url: "_Source/ajap/ajap.nlSrch.php",
data: { sndJson : jsonData },
dataType: "json",
processData: false,
success: function(html) {
$("#srchFrm").append(html);}
});
The code that works:
$.ajax({
type: "POST",
url: "_Source/ajap/ajap.nlSrch.php",
data: { sndJson : jsonData },
success: function(html) {
$("#srchFrm").append(html);}
});
Unfortunately when I send the first one my post data looks like this "Array ()" and when I use the later I get this "Array ( [sndJson] => [\"8\",\"3\",\"6\",\"7\"] )".
I know that there has to be a simple explanation but I haven't been able to figure it out.
Help please!
Try sending your data in a query string...
$.ajax({
type:"POST",
url:"_Source/ajap/ajap.nlSrch.php?json="+jsonData,
dataType:"json",
success: function(data) {
$("#srchFrm").append(data);}
error: function(xhr, ajaxOptions, thrownError)
{alert("Error!");}
});
You can use shorthand $.post instead of using low level ajax class --- because you don't need to advanced handling. So, this one will be great enough.
$(document.ready(function(){
$("#submit_button").click(function(){
$.post('php_script.php', {
// here's what you want to send
// important -- double quotes, 'cause It's evals as valid JSON
"var1" : "val1"
"var2" : "val2"
}, function (respond){
try {
var respond = JSON.parse(respond);
} catch(e){
//error - respond wasn't JSON
}
});
});
});
PHP code:
<?php
/**
* Here you can handle variable or array you got from JavaScript
* and send back if need.
*/
print_r($_POST); // var1 = val1, var2 = val2
?>
Back to your question,
Why my .ajax request doesn't work?
This is because JavaScript throws fatal error and stops further code execution.
You can catch and determine the error occasion, simply by adding
try {} catch(){} block to the statement you think may occur any error
When you specify dataType: json, jQuery will automatically evaluate the response and return a Javascript object, in this case an array. You're taking the result and adding it as html to #srchForm, so it does not make sense to convert it to a javascript object. Use dataType: html, or none at all.
http://api.jquery.com/jQuery.ajax/
The following examples above are not reusable. I am a huge fan of reuseable code. here is my solution.
Software design 101:
DRY Don't repeat your self. You should wrap your code into an object. This way you can call it from anywhere.
var Request = {
version: 1.0, //not needed but i like versioning things
xproxy: function(type, url, data, callback, timeout, headers, contentType)
{
if (!timeout || timeout <= 0) { timeout = 15000; }
$.ajax(
{
url: url,
type: type,
data: data,
timeout: timeout,
contentType: contentType,
success:function(data)
{
if (callback != undefined) { callback(data); }
},
error:function(data)
{
if (callback != undefined) { callback(data); }
},
beforeSend: function(xhr)
{
//headers is a list with two items
if(headers)
{
xhr.setRequestHeader('secret-key', headers[0]);
xhr.setRequestHeader('api-key', headers[1]);
}
}
});
}
};
Usage:
<script type="text/javascript">
var contentType = "applicaiton/json";
var url = "http://api.lastfm.com/get/data/";
var timeout = 1000*5; //five seconds
var requestType = "POST"; //GET, POST, DELETE, PUT
var header = [];
header.push("unique-guid");
header.push("23903820983");
var data = "{\"username\":\"james\"}"; //you should really deserialize this w/ a function
function callback(data)
{
//do logic here
}
Request.xproxy(requestType, url, data, callback, timeout, header, contentType);
</script>
Everything was going great in my previous help request thread. I was on the correct track to get around a CSRF, but needed to be pointed in the right direction. I received great help and even an alternate script used to log into Google's Android Market. Both my script and the one I altered to match my form is get hung up at the same point. Apparently cURL cannot process JS, is there any way to work around the form being submitted with submitForm() without changing the form?
Here is the code for the SubmitForm function
function submitForm(formObj, formMode) {
if (!formObj)
return false;
if (formObj.tagName != "FORM") {
if (!formObj.form)
return false;
formObj = formObj.form;
}
if (formObj.mode)
formObj.mode.value = formMode;
formObj.submit();
}
Here is the code for the submit button -
<a class="VertMenuItems" href="javascript: document.authform.submit();">Submit</a>
Here is a link to my last question in case more background information is needed.
PHP service...
<?php
// PHP service file
// Get all data coming in via GET or POST
$vars = $_GET + $_POST;
// Do something with the data coming in
?>
Javascript elsewhere...
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
function sendData(data)
{
var response;
$.ajax({
url: 'phpservice.php',
data: data,
type: 'POST',
dataType: 'json',
async: false,
success: function(response_from_service)
{
response = response_from_service;
},
error: function()
{
}
});
return response;
};
function getData(data)
{
var response;
$.ajax({
url: 'phpservice.php',
data: data,
type: 'GET',
dataType: 'json',
async: false,
success: function(response_from_service)
{
response = response_from_service;
},
error: function()
{
}
});
return response;
};
});
</script>
I'm using zend framework, i would like to get POST data using Jquery ajax post on a to save without refreshing the page.
//submit.js
$(function() {
$('#buttonSaveDetails').click(function (){
var details = $('textarea#details').val();
var id = $('#task_id').val();
$.ajax({
type: 'POST',
url: 'http://localhost/myproject/public/module/save',
async: false,
data: 'id=' + id + '&details=' + details,
success: function(responseText) {
//alert(responseText)
console.log(responseText);
}
});
});
});
On my controller, I just don't know how to retrieve the POST data from ajax.
public function saveAction()
{
$data = $this->_request->getPost();
echo $id = $data['id'];
echo $details = $data['details'];
//this wont work;
}
Thanks in advance.
Set $.ajax's dataType option to 'json', and modify the success callback to read from the received JSON:
$('#buttonSaveDetails').click(function (){
var details = $('textarea#details').val();
var id = $('#task_id').val();
$.ajax({
type: 'POST',
dataType: 'json',
url: 'http://localhost/myproject/public/module/save',
async: false,
// you can use an object here
data: { id: id, details: details },
success: function(json) {
console.log(json.id + ' ' + json.details);
}
});
// you might need to do this, to prevent anchors from following
// or form controls from submitting
return false;
});
And from your controller, send the data like this:
$data = $this->_request->getPost();
echo Zend_Json::encode(array('id' => $data['id'], 'details' => $data['details']));
As a closing point, make sure that automatic view rendering has been disabled, so the only output going back to the client is the JSON object.
Simplest way for getting this is:
$details=$this->getRequest()->getPost('details');
$id= $this->getRequest()->getPost('id');
Hope this will work for you.