PHP Last log in script [closed] - php

Question

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Closed 10 years ago.
I wanted to know a good and efficient way to be able to tell how long ago my users last logged in.
On the users profile I want it for say how long ago their last log in was.
Eg:
User 1
Last login: 2 hours ago
User 2
Last login: 3 minutes ago
User 3
Last login: 2 months ago
I will keep their last login information in a MySQL database but want to know how to do the script.
I just realized that Stackoverflow uses this feature, so that can help you understand what I want.
mysql_query("UPDATE users SET lastactivity = ".time()." WHERE id = ".$userID);
This is how I will update the DB.

Answer 1

Each page request just update their last activity.
<?php
mysql_query("UPDATE users SET lastactivity = ".time()." WHERE id = ".$userID);
to show when they were last online, just select their lastactivity field from database and show it
<?php
$activity = mysql_result(mysql_query("SELECT lastactivity FROM users WHERE id = ".$userID), 0);
echo "Last activity: ".relativeTime($active);
where relativeTime() is function I've been using:
function relativeTime($time, $short = false){
$SECOND = 1;
$MINUTE = 60 * $SECOND;
$HOUR = 60 * $MINUTE;
$DAY = 24 * $HOUR;
$MONTH = 30 * $DAY;
$before = time() - $time;
if ($before < 0)
{
return "not yet";
}
if ($short){
if ($before < 1 * $MINUTE)
{
return ($before <5) ? "just now" : $before . " ago";
}
if ($before < 2 * $MINUTE)
{
return "1m ago";
}
if ($before < 45 * $MINUTE)
{
return floor($before / 60) . "m ago";
}
if ($before < 90 * $MINUTE)
{
return "1h ago";
}
if ($before < 24 * $HOUR)
{
return floor($before / 60 / 60). "h ago";
}
if ($before < 48 * $HOUR)
{
return "1d ago";
}
if ($before < 30 * $DAY)
{
return floor($before / 60 / 60 / 24) . "d ago";
}
if ($before < 12 * $MONTH)
{
$months = floor($before / 60 / 60 / 24 / 30);
return $months <= 1 ? "1mo ago" : $months . "mo ago";
}
else
{
$years = floor ($before / 60 / 60 / 24 / 30 / 12);
return $years <= 1 ? "1y ago" : $years."y ago";
}
}
if ($before < 1 * $MINUTE)
{
return ($before <= 1) ? "just now" : $before . " seconds ago";
}
if ($before < 2 * $MINUTE)
{
return "a minute ago";
}
if ($before < 45 * $MINUTE)
{
return floor($before / 60) . " minutes ago";
}
if ($before < 90 * $MINUTE)
{
return "an hour ago";
}
if ($before < 24 * $HOUR)
{
return (floor($before / 60 / 60) == 1 ? 'about an hour' : floor($before / 60 / 60).' hours'). " ago";
}
if ($before < 48 * $HOUR)
{
return "yesterday";
}
if ($before < 30 * $DAY)
{
return floor($before / 60 / 60 / 24) . " days ago";
}
if ($before < 12 * $MONTH)
{
$months = floor($before / 60 / 60 / 24 / 30);
return $months <= 1 ? "one month ago" : $months . " months ago";
}
else
{
$years = floor ($before / 60 / 60 / 24 / 30 / 12);
return $years <= 1 ? "one year ago" : $years." years ago";
}
return "$time";
}

Answer 2

In addition to what #Martin. said, you can get the current timestamp using time(), and then retrieve the last login timestamp from the database, and subtract it from the current timestamp.
<?php
$date = strtotime("2012-03-08 16:02:35");
$now = time();
$diff = $now - $date;
?>
...then $diff is the time difference in seconds. Then you can calculate whatever you want.