My code doesn't insert any records to mysql. What is wrong? I am really confused.
I have designed a form and I want to read data from text box and send to the database.
<?php
if(isset($_post["tfname"]))
{
$id=$_post["tfid"];
$name=$_post["tfname"];
$family=$_post["tffamily"];
$mark=$_post["tfmark"];
$tel=$_post["tftell"];
$link=mysql_connect("localhost","root","");
if (!$link)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("university",$link);
$insert="insert into student (sid,sname,sfamily,smark,stel) values ($id,'$name','$family',$mark,$tel)";
mysql_query($insert,$link);
}
mysql_close($link);
?>
You'd better to put quotation mark for id, mark and tel after values in your query. Also as #Another Code said, you must use $_POST instead of $_post in your code. Try this and tell me the result:
<?php
if(isset($_POST["tfname"])) {
$id=$_POST["tfid"];
$name=$_POST["tfname"];
$family=$_POST["tffamily"];
$mark=$_POST["tfmark"];
$tel=$_POST["tftell"];
$link=mysql_connect("localhost","root","");
if (!$link) {
die('Could not connect: ' . mysql_error());
} else {
mysql_select_db("university",$link);
$insert="insert into student
(sid,sname,sfamily,smark,stel) values
('$id','$name','$family','$mark','$tel')";
mysql_query($insert,$link) or die (mysql_error());
mysql_close($link);
}
} else {
die('tfname did not send');
}
?>
Use mysql_query($insert,$link) or die (mysql_error()); to fetch the error message.
With the code you've provided it could almost be anything - to do some tests... have you echo'd something to confirm you are even getting the tfname in POST? Does it select the database fine? Do the fields $id, $mark, and $tel need single quotes around them as well? We need to know more about where the code is not working to provide more help but that snippet appears as though it should be running, in the interim, please use some echo's to narrow down your problem!
Try to run the generated sql query in the sql query browser. Get the query by "echo $insert" statement.
change the $insert to:
$insert="insert into student (sid,sname,sfamily,smark,stel) values ($id,'".$name."','".$family."','".$mark."','".$tel."')";
further set ini_set('display_errors',1) so that php displays the error messages as required.
Lastly, whenever doing a mysql query, try to use or die(mysql_error()) in the query so that if somethings wrong with mysql or syntax, we are aware.
$q = mysql_query($query) or die(mysql_error());
Related
I was uploading data from my android application to a PHP file then inserting it to Mysql database, the problem i am having that i buy a new hosting plan and when i configured everything in the new hosting, i try to upload data from the application it shows only blank fields in the table, i am sure that there's no problem in the PHP or the android code, cause it was working fine and great with the old hosting.. i tried to change the encoding but same issue.
Here's the PHP file:
<?php
$con = mysql_connect("HOST","USER","PASS");
if (!$con)
{
die('Could not Connect:'. mysql_error());
}
mysql_select_db("TABLE",$con);
mysql_query ("INSERT INTO table (rep_desc,dateT) VALUES ('".$_REQUEST['report_Desc']."','".$_REQUEST['Date_Time']."')");
mysql_close($con);
?>
Thanks in advance
If there is any auto_increment column in table. Better check if its auto_increment flag not got uncheck.
Please also check length of database fields and data that you actually trying to insert.
Name of all request variables, columns, tables should be in proper case if it is a UNIX system.
get all the tables by something like this query ...
$sql = "SHOW TABLES FROM $dbname";
$result = mysql_query($sql);
if (!$result) {
echo "DB Error, could not list tables\n";
echo 'MySQL Error: ' . mysql_error();
exit;
}
while ($row = mysql_fetch_row($result)) {
echo "Table: {$row[0]}\n";
}
I use this code , to log $_SERVER['REMOTE_ADDR']; to my small db
my issue is value never saved to db , cant figure what i missed in the code
Any tips ?
<?php
mysql_connect("localhost", "usr", "passwd");
mysql_select_db("db") or die ( 'Can not select database' );
function initCounter() {
$ip = $_SERVER['REMOTE_ADDR'];
$sql = "INSERT INTO logs(REMOTE_ADDR,) VALUES ('$ip')";
}
echo $_SERVER['REMOTE_ADDR'];
?>
This should work. In addition to the other comments here, you had a comma (,) too much in your query.
<?php
mysql_connect("localhost", "usr", "passwd");
mysql_select_db("db") or die ( 'Can not select database' );
function initCounter() {
$ip = $_SERVER['REMOTE_ADDR'];
$sql = "INSERT INTO logs (REMOTE_ADDR) VALUES ('$ip')";
mysql_query($sql);
}
initCounter();
?>
You aren't actually executing the query. You create the SQL but don't use mysql_query($sql)
You have a comma at this point in the SQL REMOTE_ADDR, <-- remove that
When you execute the query, use mysql_error() to test for an error message (and check the result of mysql_query() for a boolean false.
Finally I would suggest switching to MySQLi or PDO.
If that's you're full code... there is one thing missing you actually need to EXECUTE the query...
mysql_query($sql);
EDIT:
I have just noticed, you're connecting to the DB OUTSIDE of the function trying to run the Query... obviously it will fail as inside the function, it has no awareness of the DB connection.
I'm having a problem trying to truncate the 'requestID' field from my requests table.
This is my code.
<?php
include 'mysql_connect.php';
USE fypmysqldb;
TRUNCATE TABLE requestID;
echo "Request ID table has been truncated";
?>
I'm using server side scripting so no idea what error is coming back.
Anyone got an idea?
You aren't executing queries, you're just putting SQL code inside PHP which is invalid. This assumes you are using the mysql_*() api (which I kind of suspect after viewing one of your earlier questions), but can be adjusted if you are using MySQLi or PDO.
// Assuming a successful connection was made in this inclusion:
include 'mysql_connect.php';
// Select the database
mysql_select_db('fypmysqldb');
// Execute the query.
$result = mysql_query('TRUNCATE TABLE requestID');
if ($result) {
echo "Request ID table has been truncated";
}
else echo "Something went wrong: " . mysql_error();
Take a look at the function mysql_query which performs the query execution. The code to execute a query should look something like this.
$link = mysql_connect('host', 'username', 'password') or die(mysql_error());
mysql_select_db("fypmysqldb", $link) or die(mysql_error());
mysql_query("TRUNCATE TABLE requestID", $link) or die(mysql_error());
mysql_close($link);
I did wrote piece of php code to show 'product' name from a database.But nothing shows up after executing,Database is ok,i double checked database,table name,other fieldsI couldn't figure out the error so please help.
code
<?php
mysql_connect('localhost','root');
mysql_select_db('cybersoft');
$no=1;
$res=mysql_query("select product from test where 'serial'=$no ");
while($rowa=mysql_fetch_array($res))
{
echo $rowa[1];
}
?>
First of all, mysql_connect() takes three parameters.
mysql_connect('localhost', 'root', 'mypassword');
and to see an error you can use mysql_error() function
mysql_query('some query') or die(mysql_error());
Change single quote (') to ` or just remove. Quotes are used for string types.
select product from test where `serial`= $no
Remove your quotes around serial, they are not needed. This should work:
$res=mysql_query("select product from test where serial=$no");
If result is still empty, double check that there is a row with serial = 1.
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Error: ' . mysql_error());
}
mysql_select_db('cybersoft');
$res=mysql_query("select product from test where serial=" . $no);
Remove the single quotes around "serial", or make them backticks instead.
Also, you likely aren't seeing anything when you run the script because you don't have error reporting turned on. Do that in php.ini or programatically:
error_reporting(E_ALL);
Try this
mysql_connect('localhost','root');
mysql_select_db('cybersoft');
$no=1;
$res=mysql_query("select product from test where serial='$no' ");
while($rowa=mysql_fetch_array($res))
{
echo $rowa[1];
}
?>
Try this
$res=mysql_query("select product from test where serial=$no");
I run this function and the value of the post form doesn't insert into the DB. I'm not getting any error messages but I checked and saw that $this->user_id is populating. Am I missing something else?
function senddata () {
$con = mysql_connect("localhost","root","XXXXX");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("user", $con);
$sql="INSERT INTO profile (collegemajor) VALUE('$_POST[major]') WHERE userid=$this->user_id";
mysql_close($con);
}
INSERT statement don't have WHERE clausule,
you need to send query!!!
First of all, I don't see the mysql_query() - the function to execute the query.
It seems like the problem is here:
$sql="INSERT INTO profile (collegemajor) VALUE('$_POST[major]') WHERE userid=$this->user_id";
Use $sql="INSERT INTO profile (collegemajor) VALUE('$_POST[major]'); instead.
The code:
function senddata () {
$con = mysql_connect("localhost","root","XXXXX");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("user", $con);
$sql="INSERT INTO profile (collegemajor) VALUE('$_POST[major]');";
mysql_query( $sql , $con );
mysql_close($con);
}
This should be an update function, it seems, rather than an insert function (if you're trying to update a row that already exists, which is seems you are based on the "Where" clause).
And, as others have mentioned, you never ran mysql_query() or similar function.