Variable passed to each() is not an array or object - php

Question

I really don't understand why I'm getting this error or how to fix it!
Variable passed to each() is not an array or object on line-
while(list($key,$value) = each($_FILES['images']['name']))
Full code-
$max_no_img=4; // Maximum number of images value to be set here
$imgs_names = array('CV', 'Research Plan', 'Degree Transcript', 'GRE Scores');
echo "<form method=post action='' enctype='multipart/form-data'>";
echo "<table border='0' width='400' cellspacing='0' cellpadding='0' align=left>";
for($i=1; $i<=$max_no_img; $i++){
echo "<tr><td>".$imgs_names[$i-1]."</br</td><td>
<input type=file name='images[]' class='bginput'></td></tr>";
}
echo "<tr><td colspan=2 align=center><input type=submit value='Submit'></td></tr>";
echo "</form> </table>";
while(list($key,$value) = each($_FILES['images']['name']))
{
echo $key;
echo "<br>";
echo $value;
echo "<br>";
if(!empty($value)){ // this will check if any blank field is entered
$filename =rand(1,100000).$value; // filename stores the value
$filename=str_replace(" ","_",$filename);
$add = "upload/$filename"; // upload directory path is set
copy($_FILES['images']['tmp_name'][$key], $add);
echo $add;
Any ideas?

Answer 1

$_FILES['images']['name] is not an array, $_FILES['images'] is.
So
while (list($key, $object) = each($_FILES['images']))
{
//use $object['name'] or $object['tmp_name']
}

Answer 2

$_FILES['images']['name'] is not an array! It is a value inside the array.
If you want to iterate over the files, you should:
while(list($key,$value) = each($_FILES['images']) {
(...)
}