JavaScript variable value to PHP variable - php

I have a JavaScript function that creates a <div>. It uses Ajax to access the database so and creates a different <div> if the dates match. But now I want to take the 'date' variable from the JavaScript <div> that matches the database and send it through another PHP function that gets all entries with that date and echoes them out to a JQuery pop-up. What am I’m doing wrong and is there an easier way than the code below?
First AJAX call:
beforeMonth:function(date)
{
$.ajax({
type: "GET",
url: "getCalendarEvents.php",
dataType: "json",
data: "date="+date,
async: false, //stop rendering the calender until eventdates is changed.
success: function(json){
$.fn.ical.changeEventDates(json); //this function changes the eventdates
}
})
}
getCalendarEvents.php
include ("Includes/dbConnect.php");
$_GET['date'];
$query2 = "SELECT * FROM events";
$checkevent = mysqli_query($cxn,$query2) or die("Couldn't execute query!");
$dates = array();
while ($row2 = mysqli_fetch_array($checkevent))
{
$eventDate = $row2['eventDate'];
$eventName = $row2['eventName'];
$eventHost = $row2['host'];
$dates[$eventDate] = array('title' => $eventName, 'desc' => $eventHost);
}
echo json_encode(array("dates" => $dates));
exit;
JavaScript in a separate file (just the function that creates the <div>):
if(!datejson)
{
options.beforeDay(formatdate);
$("table tr:last, obj").append("<td id = '"+formatdate+"'>"+i+"</td"); //add day
}
else
{
options.beforeDay(formatdate);
$("table tr:last, obj").append("<td class='date_has_event' id = '"+formatdate+"' name='"+formatdate+"'>"+i+"<div class='title'><a href='#' class='popup'><img src='images/facebook.png' class='popup'/></a></div>"+"<div class='events'><ul><li><span class='desc'>"+datejson.desc+"</span></li></ul></div></td"); //add day
}
PHP in the HTML:
<div id="popupContact">
Close X
<div id="popupHeader">Events occurring on</div>
<?php
include ("Includes/dbConnect.php");
$calendarDate=$_GET['formatdate']
$query = "SELECT * FROM events WHERE eventDate='$calendarDate'";
$check = mysqli_query($cxn,$query) or die("Couldn't execute query!");
while($row = mysqli_fetch_array($check))
{
$id = $row['eventID'];
echo "<div class='submit_event_list'><a href='individual_event_page_main.php?id=$id'>";
echo $row['eventName'];
echo " | " . $row['venue'];
echo " | " . $row['eventDate'];
echo "</a></div>";
echo "<br />";
}
mysqli_close($cxn);
?>
</div>

Related

How do we pass data in ajax? [duplicate]

This question already has answers here:
How can I get the data-id attribute?
(16 answers)
Closed 5 years ago.
I am new to Ajax and I am confused as to how we pass data in Ajax. I have an index.php file which displays some data, it has a link to delete the record, now the problem is, I am not able to figure out how to transfer the id value from index.php of the selected record to ajax file. Also, how should I go about once I have fetched the value in delete.php page where lies the code to delete records.
I have coded as below.
index.php
<div id="delMsg"></div>
<?php
$con=mysqli_connect("localhost","root","","ajaxtest");
$data=mysqli_query($con,"select * from member");
$col=mysqli_num_fields($data);
echo "<table>";
while($row=mysqli_fetch_array($data))
{
echo "<tr>";
for($i=0;$i<$col;$i++)
{
echo "<td>".$row[$i]."</td>";
}
echo "<td><a class='del' href='delete.php' data-ID=$row[0]>Delete</a></td>";
echo"</tr>";
}
echo "</table>";
?>
ajax-file.js
$(document).ready(function(){
$(".del").click(function(event){
event.preventDefault();
$.ajax({
url:"delete.php",
method:"get",
data:{id:'ID'},
dataType:"html",
success:function(str){
$('#delMsg').html(str);
}
})
})
})
delete.php
<?php
$id=$_GET['id'];
$con=mysqli_connect("localhost","root","","ajaxtest");
$data=mysqli_query($con,"delete from member where id='$id'");
if($data)
{
echo "success";
}
else
{
echo "error";
}
?>
Hopefully this conveys the idea of how an AJAX call works.
The first thing we want to do is setup our trigger, which in your case is a button with an onclick event.
<script
src="http://code.jquery.com/jquery-3.3.1.min.js"
integrity="sha256-FgpCb/KJQlLNfOu91ta32o/NMZxltwRo8QtmkMRdAu8="
crossorigin="anonymous"></script>
<!-- <button id="delete">Delete Something</button> -->
<button id="delete" onclick="onClickHandler(5)">Delete Something</button>
<p id="message">AJAX</p>
<script>
/* Notice I removed the document ready */
function onClickHandler(id)
{
event.preventDefault();
$.ajax(
{
url:"delete.php",
method:"POST", /* In the real world you want to use a delete here */
data: { /* plugin your data */
id: id,
name: "Bob",
age: 25
},
dataType:"html",
success: function(success) {
// Handle the success message here!
if (success) {
$('#message').text("Your message was received!");
}
},
error: function(error) {
// Handle your errors here
$('#message').text("Something went wrong!");
}
});
};
</script>
Notice how my data is prepared in the data object. I leave it up to you to figure out how to grab data and set it in the right field. You could: $('#someId').value(); or pass it through a function. If this is a source of confusion I can clarify.
data: { /* plugin your data */
id: 1,
name: "Bob",
age: 25
},
Next, we need to setup our script.
delete.php
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
// Obviously validate the data.
// But this is how you access it.
// $_POST is a global array, so you can access it like so:
$id = $_POST['id'];
$name = $_POST['name'];
$age = $_POST['age'];
// Do your server side stuff...
$sql = "DELETE FROM member
WHERE id = '{$id}' AND name = '{$name}' AND age = '{$age}'";
// Do your SQL (delete) here
// $con = mysqli_connect("localhost","root","","ajaxtest");
// Use prepared statements http://bobby-tables.com/php
// $data = mysqli_query($con,"delete from member where id='$id'");
// if ($data) { // Your condition
// This is where you would check if the query passed
// and send back the appropriate message.
if ($id) {
echo json_encode($id);
}
else {
echo http_response_code(500);
}
}
else {
echo "You don't belong here!";
}
you should use what is called JSON ( Javascript Object Notation, I think). This will let you order your data better to do that you have to use, json_encode.
Now I am not exactly sure what you mean by this id value from index.php
But taking your index.php file, I would change it like this
//make sure the is no space here
<?php
//start output buffering
ob_start();
$html = ['<div id="delMsg"></div>'];
$con=mysqli_connect("localhost","root","","ajaxtest");
$data=mysqli_query($con,"select * from member");
$col=mysqli_num_fields($data);
$html[] = "<table>";
while($row=mysqli_fetch_array($data))
{
$html[] = "<tr>";
for($i=0;$i<$col;$i++)
{
$html[] = "<td>".$row[$i]."</td>";
}
$html[] = "<td><a class='del' href='delete.php' data-ID=$row[0]>Delete</a></td>";
$html[] = "</tr>";
}
$html[] = "</table>";
$result = [
'html' => implode("\n", $html),
'debug' => ob_get_clean()
];
header("Content-type:application/json");
echo json_encode($result);
//?> ending tags are undesirable
Your JavaScript part will change too
$(document).ready(function(){
$(".del").click(function(event){
event.preventDefault();
$.ajax({
url:"delete.php",
method:"get",
data:{id:'ID'},
dataType:"html",
success:function(data){
$('#delMsg').html(data.html);
}
})
})
})
You can see now that instead of just returning HTML, We will be returning it like this data in the Javascript and $result in php
{
html : '<div id=" ...',
debug : ""
}
I added ob_start and ob_get_clean this can be helpful because you cannot just echo content when outputting JSON, so this will catch any echo or print_r type content and put that into the debug item in the return.
Just replace
echo "<td><a class='del' href='delete.php' data-ID=$row[0]>Delete</a></td>";
To
echo "<td><a onclick="deleteRow($row[0])">Delete</a></td>";
Javascript
function deleteRow(recordID)
{
event.preventDefault();
$.ajax({
type: "GET",
url: "delete.php",
data:{id: recordID}
}).done(function( result ) {
alert(result);
});
}
In your PHP I recommend you to use PDO which is more easy and protected from SQL injection attacks.
PHP:
$db = new PDO('mysql:host=localhost;dbname=yourDB','root','');
$query = $db->prepare("Delete From yourTableName Where ID=:ID");
$id=$_GET['id'];
$query->bindParam('ID', $id);
$query->execute();
if ($query->rowCount()) {
echo "success";
}
else
{
echo "fails";
}

Update Text Value in PHP form display using jQuery & MySQL database

I have a table display and I want to enable users to edit the values of the table in a live way using jQuery. The table is simple, it just has 1 column with a list of names. I have it all built out but at the moment the table doesn't update the value. All the code is below, I am still learning everything so it's probably not written very well/correctly! Thanks in advance.
Form Display:
<?php
echo "<div class=\"table-responsive\"><table class=\"table table-striped\">";
echo "<thead><tr><th>Employee Name</th><th></th></tr></thead><tbody>";
require_once 'connectionsettings.php'; // Gets connection settings
$sql = "SELECT id, employees FROM Employees ORDER BY employees ASC";
$result = $mysqli->query($sql);
if ($result->num_rows > 0) {
// what it's saying is that if there's rows do something
while($row = $result->fetch_assoc()) {
// now it's saying get the data and put it in rows
echo "<tr><td data-id='{$row['id']}' contenteditable=\"true\">" . $row["employees"] . "</td><td><span data-id='{$row['id']}' name='remove_{$row['id']}' class='employee glyphicon glyphicon-remove' aria-hidden='true'></span></td></tr>";
}
}else{
echo "No Employees! Let's add some.";
}
$mysqli->close();
echo "</tbody></table></div>";
?>
Jquery Info:
$(function(s){
$("td[contenteditable=true]").blur(function(){
var id = $(this).attr("id") ;
var name = $(this).text() ;
var formURL = "updateemployeename.php";
$.ajax({
url : formURL,
type: "POST",
data : {name: name, id: id},
success:function(data, textStatus, jqXHR)
{
$('#successmessage2').slideDown('fast').delay(1500).slideUp('fast');
$('div#employeedisplay').hide();
$('div#updatedemployeedisplay').load('employeedisplay.php').fadeIn(3000);
},
error: function(jqXHR, textStatus, errorThrown)
{
//if fails
}
});
});
s.preventDefault(); //STOP default action
});
SQL Info:
<?php
require_once 'connectionsettings.php'; // Gets connection settings
$name = htmlspecialchars(trim($_POST['name']));
$id = htmlspecialchars(trim($_POST['id']));
$sql = "UPDATE Employees SET employees='$name' WHERE id='$id'";
if($mysqli->query($sql) === TRUE) {
echo "status updated successfully";
}else{
echo "Error updating status" . $mysqli->error;
}
$mysqli->close();
?>

How to assign ajax response to Variables

I have drop down Select box as follows
<?php
$sql = "SELECT scheduleName FROM schedule";
$result = mysqli_query($link,$sql);
echo "<select name='schedule' id='schedule'>";
echo "<option value=''>-- Select Schedule --</option>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['scheduleName'] . "'>" . $row['scheduleName'] . "</option>";
}
echo "</select>";
?>
And I have a file called processClg.php as follows
<?php
include "config.php";
if ($_POST['type']=='POST')
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE 'Row id of drop down selection'";
$res = mysqli_query($link,$qry);
}
?>
How can I call processClg.php file on $("#schedule").change(function ());by assigning Row id of drop down selection as where condition.
Update
Am getting Response from processClg.Php as follows
[{"id":"2","scheduleName":"shanth","subject":"Patho","university":"Dali","facultyName":"Dr","scheduleStartDate":"2015-06-05","scheduleEndDate":"2015-06-09"}]
How to assign response values from ajax call to the following Php variables
<?php
$scheduleStartDate = '';
$scheduleEndDate = '';
?>
Any help my greatly appreciated.
$("#schedule").change(function() {
var value = $('#schedule option:selected').text();
var ajaxCheck = $.ajax({
url: 'processClg.php',
type: 'POST', // had mention post bcoz u mention in processClg.php
dataType: 'json', // processClg.php will return string means change to text
data: { id: value },
success: function(data){
console.log('success');
itrToRead(data);
}
});
});
function itrToRead(data) {
$(data).each(function(key, value){
console.log('key is: '+key+' and value is: '+value);
});
}
processClg.php
<?php
include "config.php";
if ($_POST['type']=='POST') {
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_POST['id']."'";
$res = mysqli_query($link,$qry);
echo $res;
}
?>
You can call ajax as follows:
var RowId;
$.ajax({
type: "POST",
async: false,
url: url,
data: postdata,
//dataType: "json",
success: function (data) {
RowId = data;
}
});
The fact is that to assign response to variable is pass the parameter async: false,
Then its work.
I guess you have your dropdown in your rendered page and you want to send the selected value to the php page:
$("#schedule").change(function(){
var val2pass = $(this).find(':selected').val(); // get the value
$.ajax({
url: 'processClg.php',
type:'post', // <-----you need to use post as you are using $_POST[]
data: { rowid : val2pass }, //<---pass the value
success: function(data){
itrToRead(data);
}
});
});
So now on the php side you need to do this:
<?php
include "config.php";
if ($_POST['type']=='POST')
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_POST['rowid']."'";
$res = mysqli_query($link,$qry);
}
?>
Your procellClg.php will be
<?php
include "config.php";
if (isset($_REQUEST['qid']))
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_REQUEST['qid']."'";
$result = mysqli_query($link,$qry);
echo "<select name='schedule' id='schedule'>";
echo "<option value=''>-- Select Schedule --</option>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['scheduleName'] . "'>" . $row['scheduleName'] . "</option>";
}
echo "</select>";
}
?>
and then make Ajax function call
$("#schedule").change(function() {
val = $(this).val();
$.ajax({
type: "POST",
async: false,
url: 'processClg.php',
data: {qid:val},
success: function(data){
$(this).html(data);
}
});
});

Is it possible to return a table with some constraint in another .php page in ajax and show it in div

when i click the today button, it goes to updatetoday.php page where i select a query and display it in call back of an ajax and display the table in .php file to div with id #test. but it display's error as Uncaught TypeError: Illegal invocation
$(document).ready(function(){
$('#today').click(function()
{
alert("hi");
$.ajax({
url:'updatetoday.php',
data:{update:today}, // pass data
success:function(result)
{$( "#test" ).html(result);}
});
});
});
updatetoday.php
<?php
$conn = mysql_connect('localhost', 'root', 'root') or die("error connecting1...");
mysql_select_db("cubitoindemo",$conn) or die("error connecting database...");
if($_GET['update']==today) //taking
{
echo "<table align='center' border='1' cellspacing='2'><tr><th>Book_id</th><th>Name</th><th>Phone Number</th><th>Email Address</th><th>Start Date</th><th>Source</th><th>Destination</th><th>Morning Time</th><th>Evening Time</th><th>Duration</th><th>Days Off</th><th>Date Off</th><th>Current Status</th><th>Call Counter</th><th>Option</th><th>Calender</th><th>Save</th></tr><br><br><br>
<?php
$query_book = 'Select * from `booking` where validity = 1 limit 5';
$result_book = mysql_query($query_book);
while($row = mysql_fetch_assoc($result_book))
{
$user_id = $row['user_id'];
// query for customer table
$query_cus = 'Select * from `customer` where user_id = $user_id limit 5';
$result_cus = mysql_query($query_cus);
$row_cus = mysql_fetch_assoc($result_cus);
$name = $row_cus['user_id'];
$email = $row_cus['email_id'];
$mobile_number = $row_cus['mobile_number'];
$current_status = $row['valid'];
$startdate = $row['start_date_timestamp'];
if($current_status == '1')
{
$status = '<p style='color:green;font-weight:600;font-size:19px'>Reg</p>';
}
else if($current_status == '2')
{
$status = '<p style='color:green;font-weight:600;font-size:19px'>New</p>';
}
else if ($current_status == '3.1' )
{
$status = '<p style='color:red;font-weight:600;font-size:19px'>R</p>';
}
?>
<tr align='center'><td class='bookid'><?=$row['book_id']?></td><td ><?=$row_cus['name']?></td><td ><?=$row_cus['mobile_number']?></td><td ><?=$row_cus['email_id']?></td><td><?=$row['start_date_timestamp']?></td><td ><?=$row['source']?></td><td ><?=$row['destination']?></td><td ><?=$row['mor_timestamp']?></td>
<td><?=$row['eve_timestamp']?></td><td><?=$row['duration']?></td><td ><?=$row['days_off']?></td><td ><?=$row['date_off']?></td>
<td><?=$row['current_status']?></td ><td ><?=$row['call_counter']?></td>
<td><select class='sel' name='select_option'><option value='NULL'>Select An Option</option><option value='taking'>Taking</option><option value='later-def'>Later Defined</option><option value='later-undef'>Later Undefined</option><option value='outofrange'>Out Of Range</option><option value='rejected'>Rejected</option><option value='norespond'>No Respond</option></select></td><td><input type='text' class='cal' size='6' disabled='disabled' value='<?=$startdate?>'/></td><td><button id='<?php echo $row['book_id'];?>' class='save'>Save</button></td></tr>
<?php
}//booking table while ends
echo '</table>';
?>
</div>";
}
?>
To fix your problem you must change the line :
data:{update:today}, // pass data
to :
data:{update:'today'}, // pass data
in your code today is a string not a varible
Change the line :
success:function(data)
to :
success:function(result)
You are assigning the result from the php to a variable called data and in
{$( "#test" ).html(result);}
trying to display inside the #test div a variable called result.

Table doesn't respond to second jQuery request

My PHP script generates a table with rows which can optionally be edited or deleted. There is also a possibility to create a new Row. The PHP is activated through jQuery Events.
Now all works well, I can edit delete and create an Item. After each action which makes use of the PHP script the HTML table gets updated.
But when I try after an Event to do an action again the HTML Table doesn't get updated though in the background the PHP script makes an entry into the database.
Does someone of you know why my HTML Table doesn't update itself when I trigger a second event?
Here is the Script:
PHP
<?php
require_once "../../includes/constants.php";
// Connect to the database as necessary
$dbh = mysql_connect(DB_SERVER,DB_USER,DB_PASSWORD)
or die ("Unaable to connnect to MySQL");
$selected = mysql_select_db(DB_NAME,$dbh)
or die("Could not select printerweb");
$action = $_POST['action'];
$name = $_POST['name'];
$id = $_POST['id'];
if($action == "new")
{
mysql_query("INSERT INTO `place` (`id`, `name`) VALUES (NULL, '$name')");
}
elseif($action == "edit")
{
mysql_query("UPDATE `place` SET `name` = '$name' WHERE `id` = '$id'");
}
elseif($action == "delete")
{
mysql_query("DELETE FROM place WHERE id = '$id'");
}
echo "<table><tbody>";
$result = mysql_query("SELECT * FROM place");
while ($row = mysql_fetch_array($result)) {
echo "<tr><td id=".$row["id"]." class=inputfield_td><input class=inputfield_place type=text value=".$row["name"]." /></td><td class=place_name>".$row["name"]."</td><td class=edit>edit</td><td class=cancel>cancel</td><td class=delete>delete</td><td class=save>SAVE</td></tr> \n";
}
echo "</tbody>";
echo "</table>";
echo "<input type=text class=inputfield_visible />";
echo "<button class=new>Neu</button>";
?>
JS
$(function() {
$.ajax({
url: "place/place_list.php",
cache: false,
success: function (html){
$("#place_container").append(html);
}
});
$(".edit").live("click", function() {
$(this).css("display","none").prevAll(".place_name").css("display","none").prevAll(".inputfield_td").css("display","block").nextAll(".cancel").css("display","block").nextAll(".save").css("display","block").prevAll(".inputfield_td").css("display","block");
});
$(".cancel").live("click", function() {
myvariable5 = $(this).prevAll(".place_name").html();
$(this).css("display","none").prevAll(".edit").css("display","block").prevAll(".place_name").css("display","block").prevAll(".inputfield_td").css("display","none").nextAll(".save").css("display","none").siblings().find("input[type=text]").val(myvariable5);
});
$(".save").live("click", function() {
var myvariable1 = $(this).siblings().find("input[type=text]").val();
var myvariable2 = $(this).prevAll("td:last").attr("id");
$(this).css("display","none").prevAll(".cancel").css("display","none").prevAll(".edit").css("display","block").prevAll(".place_name").css("display","block").prevAll(".inputfield_td").css("display","none");
$.post("place/place_list.php", {action: "edit", name: ""+myvariable1+"", id: ""+myvariable2+""}, function (html){$("#place_container").replaceWith(html);});
});
$(".delete").live("click", function() {
var myvariable3 = $(this).prevAll("td:last").attr("id");
$.post("place/place_list.php", {action: "delete", id: ""+myvariable3+""}, function (html){$("#place_container").replaceWith(html);});
});
$(".new").live("click", function() {
var myvariable4 = $(this).prevAll("input[type=text]").val();
$.post("place/place_list.php", {action: "new", name: ""+myvariable4+""}, function (html){$("#place_container").replaceWith(html);});
});
});
I think I know. You do replaceWith instead of append, so your DIV with ID #place_container disappears after the first operation (you are left with only a table in your page), and of course jQuery does not find it and is unable to refresh it with new content from the second operation.
Just use append or, better yet, html methods.
Shouldnt you replace the complete table ?
$("#place_container").html(html);

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