JSON.parse: unexpected character - php

Question

I'm trying to pass a json from php jquery, after getting into an array of sql query and get the following javascript error.
JSON.parse: unexpected character
The function to return result of sql:
public function selectassocSql($sql){
$i = 0;
$resSelect = array();
mysql_query("SET NAMES 'utf8'");
$result = mysql_query($sql);
while ( $row = mysql_fetch_assoc($result) )
{
$resSelect[$i] = $row;
$i++;
}
mysql_free_result($result);
return $resSelect;
}
After use this function in this way,
$sql = "SELECT id, code, name FROM table WHERE code LIKE '%$codcli%' ";
$v = $data->selectassocSql($sql);
echo json_encode($v, JSON_FORCE_OBJECT);
And the javascript code is this:
$('#formclientes').submit(function(e){
e.preventDefault();
$.ajax({
type: 'POST',
url:$(this).attr('action'),
data:$(this).serialize(),
success:function(data)
{
//console.log("SUCCESS " + data);
var json_cli = $.parseJSON(data);
}
})
})
How I can correct this error and how I can read a json from jquery?

Answer 1

You don't need the $.parseJSON call as jQuery automatically does it because if you don't specify a dataType property jQuery tries to guess it and calls the correct function to parse the response before the data is handled to the success function
$.ajax({
type: 'POST',
url:$(this).attr('action'),
data:$(this).serialize(),
success:function(data)
{
//console.log("SUCCESS " + data);
var json_cli = data;
}
})
check out also this question Why is 'jQuery.parseJSON' not necessary?

Answer 2

I just ran into this in FF10.0.2 with data that looked like:
[ { "firstName": 'Joe', "lastName": 'Smith' } ]
(with multiple objects in the array - shortened for clarity)
It actually parsed OK using eval, though, instead of JSON.parse. (I'm not using jQuery here.)
The problem went away when I changed ' to " for the values:
[ { "firstName": "Joe", "lastName": "Smith" } ]
I thought the " requirement was only for property names, not data values.