MySQL syntax error - php

IM GETTING THIS ERROR:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'release (project_id, start_date, end_date, predicted_velocity,
release_title, )' at line 1
MY PHP FILE:
<?php
include("../db_connect/connect.php");
$project_id = $_POST['project_id'];
$release_title = $_POST['release_id'];
$start_date = $_POST['start_date'];
$end_date = $_POST['end_date'];
$predicted_velocity = $_POST['predicted_velocity'];
$query = "INSERT INTO release (project_id, start_date, end_date, predicted_velocity, release_title, ) VALUES ('" . $predicted_velocity . "','" . $release_title . "','" . $start_date . "','" . $end_date . "','" . $project_id . "', NOW())";
mysql_query($query) or die(mysql_error());
header("location: ../view-project.php?project_id=$project_id");
?>
ANY IDEAS WHY? IM NEW TO THIS!

You have a missing column name, resulting in an orphaned comma.
, )
should be
, MyColumn)
I assume MyColumn is meant to be populated by the NOW() function.
Also, your values are not listed in the same order as the columns, which will cause the query to fail.
To summarize the issues here:
Missing column name (column count must match value count)
Hanging comma
Column order does not match variable order
Code is subject to SQL injection attack
No server-side validation is being done on user input

Extra comma:
[..snip..] predicted_velocity, release_title, ) VALUES
^--- here

You have a stray comma after release_title.

#john_allen You said you got the error message "right syntax to use near 'release (project_id," - that is interesting, because MySQL always starts the example where the syntax error occurs.
If the error was just the incorrect comma after release_title, then the error from MySQL would have been "the right syntax to use near ') VALUES...". That is an error, but not the one that the MySQL parser is hitting first.
There's something else wrong here, and I think it is because you don't have a table called 'release', or at least MySQL can't find your table called 'release' using the credentials you've given it. Check your connection string.

Related

On duplicate gives syntax error and does not work

I'm trying to add products to a database from an XML file and when there's a duplicate article number I want to just update the stock level.
I'm still learning PHP and MySQL and I've read numerous post on this forum but I just can't get it to work.
So what I did is this:
$xml = simplexml_load_file("a-link-to-downloaded_products.xml") or die("Error: Cannot create object");
foreach ($xml->children() as $row) {
$article_code = $row->artikelnummer;
$brand = $row->merk;
$name_nl = $row->naam;
$ean = $row->ean;
$stock = $row->voorraad_aanwezig;
$sql = "INSERT INTO `products` (article_code,brand,name_nl,ean,stock) VALUES ('" . $article_code . "','" . $brand . "','" . $name_nl . "','" . $ean . "','" . $stock . "') ON DUPLICATE KEY UPDATE `stock` = VALUES(`$stock`)";
$result = mysqli_query($db, $sql);
..... etc .....
}
Above gives me an error saying
Unknown column '1' in 'field list'
or
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '1)' at line 1
Because of that second error I assume that it has something to do with ON DUPLICATE KEY UPDATE stock = VALUES($stock)" However I tried a lot of different variations but I just can't get it to work! I used backticks, quotes etc. Almost anything I can think of.
Just replace this:
ON DUPLICATE KEY UPDATE `stock` = VALUES(`$stock`)
With:
ON DUPLICATE KEY UPDATE `stock` = VALUES(`stock`)
Explanation: the VALUES() construct in the ON DUPLICATE UPDATE clause is used to reference a column value that is passed in the INSERT clause.
Important note: anyone on SO will tell you that you should really consider using prepared statement and parameterized queries, in order to make your queries safer and more efficient.

Error inserting values to a table in MySql

I am having error inserting values to a database table in mysql.The connection is allright. I have checked it. My code is :
$emails = implode(",", $not_submitted);
$sql_update_query = "INSERT INTO reminders_table(id,group_name,runtimes,emails) VALUES(NULL, '".mysql_real_escape_string($group_name) ."' ,'".mysql_real_escape_string($runtimes) ."' , '".mysql_real_escape_string($emails) ."')";
mysql_query(sql_update_query, $con);
echo $sql_update_query, "<br>";
echo mysql_error(), "<br>";
After seeing the error in my console, it says :
"responseText: "INSERT INTO reminders_table(id,group_name,runtimes,emails) VALUES(NULL, 'BIT' , 'tue,wed-02:45,23:15' , 'c_faw,)<br>You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'sql_update_query' at line 1<br>"Reminders have been sent....! Please close this page."↵"
Any help is appreciated. So far I have tried debugging a lot. I added "mysql_real_escape_string" also, but still it doesn't work.
It a missing a Single quote after email variable.

MySQL throws error but works - PhpMyAdmin without error

I am running this query on my MySQL Database - with mysql_query it throws me an error but the data is still properly inserted into the table. If I enter it in PhpMyAdmin it works without error.
INSERT INTO `kommentare` VALUES(NULL,'1','MyName','MyEmail','MyText','2014-08-05');
PHP :
$name = mysql_escape_string($name);
$email = mysql_escape_string($email);
$kommentar = mysql_escape_string($kommentar);
$datum = mysql_escape_string($datum);
$reiseid = str_replace("/", "", $reiseid);
$query = "INSERT INTO kommentare VALUES(NULL,'" . $reiseid . "','" . $name . "','" . $email . "','" . $kommentar . "','" . $datum . "');";
$result = mysql_query($query) or die(mysql_error());
echo $query;
Error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
How is that possible? I am experienced with MySQL but this wrecks my nerves - it works but says it doesn't?!
UPDATE:
It just happens when I have more than one entry in the table. ANd even if I remove all the ' it gives me the same error, saying I should check near the '
If the first column is a auto-increment primary key, you don't pass it NULL, you pass it DEFAULT:
INSERT INTO kommentare VALUES
(DEFAULT,'$reiseid','$name','$email','$kommentar','$datum');
But really you should instead be naming your columns and skipping those that you don't have a value for:
INSERT INTO kommentare
(reiseid, name, email, kommentar, datum)
VALUES
('$reiseid','$name','$email','$kommentar','$datum');
SOLUTION:
My id has been passed not as 1 but as 1/ for some reason. This caused MySQL to crash although it was not shown to me. I replace the / with "" now and everything works fine!

PHP MySQL command syntax error

This sql query is not working:
$sql = "INSERT INTO top(topic_subject,topic_date, topic_cat, topic_by)
VALUES(" . mysql_real_escape_string($_POST['topic_subject']) . " , NOW()," . mysql_real_escape_string($_POST['topic_cat']) . " , " . isset ($_SESSION['user_id']) . ")";
how can I fix it?. I am getting this error message.
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 2`
It's likely that topic_subject is character data. To include literal strings in SQL text, it should be enclosed in single quotes.
... VALUES ('abc', ...
If you used prepared statements, this wouldn't be an issue, and for the love of all things that are beautiful and good in this world, don't use the deprecated PHP mysql_ interface for new development. It's been superseded by the mysqli_ and PDO interfaces.
You forgot the quotes.
$sql = "INSERT INTO top(topic_subject,topic_date, topic_cat, topic_by)
VALUES('" . mysql_real_escape_string($_POST['topic_subject']) . "' , NOW(),'" . mysql_real_escape_string($_POST['topic_cat']) . "' , '" . isset ($_SESSION['user_id']) . "')";
And be aware that mysql_* is deprecated. Use PDO or mysqli instead.
There are couple problems here.
Quote your strings
Make sure your data is of the correct type
$topic_subject = mysql_real_escape_string($_POST['topic_subject']);
$topic_date = NOW();
$topic_cat = mysql_real_escape_string($_POST['topic_cat']);
$topic_by = isset($_SESSION['user_id']) ? $_SESSION['user_id'] : ""; // always returns a string value.
$sql = "INSERT INTO top(topic_subject,topic_date, topic_cat, topic_by)
VALUES('{$topic_subject}' , {$right_now}, '{$topic_cat}' , '{$topic_by}')";
It may help you to use more variables in your code (shown) so that you can use a debugger to verify that the strings and variables you create have the values you intend them to have.

wrong query inserting value in specific row

I'm trying to execute the following query where I want to add a value in the column firstime in the corresponding row with $netid and mac.
$query="INSERT INTO node WHERE netid='".$netid."' AND mac='" . $_GET['mac'] . "' (firstime) VALUES ('" . $firstcheck . "')";
mysql_query($query, $conn) or die("Error executing query: ".mysql_error($conn));
when I try I get the following error message:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE netid='28' AND mac='24:A4:3C:40:4D:EB' (firstime) VALUES ('2014-01-16 12:0' at line 1
Any Idea??
You cannot use WHERE clause for INSERT query since it makes no sense
Here is a documentation page about its proper syntax: http://dev.mysql.com/doc/refman/5.6/en/insert.html
A scientific guess: what you need is UPDATE
Perhaps you want an update:
update node
set firsttime = '" . $firstcheck . "'
WHERE netid = '".$netid."' AND mac = '" . $_GET['mac'] . "';
insert inserts a new row into the table, not a new value into the row.
update updates a value in a row.
The WHERE conditions must go at after the colums and values declaration.
INSERT INTO node (firstime) VALUES ('" . $firstcheck . "') WHERE netid='".$netid."'
AND mac='" . $_GET['mac'] . "'";
Also use prepared statements and sanitize user submitted data, in order to prevent a SQL INJECTION which is a present and clear threaten.

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