Is this better then?
<form id="form1" name="form1" method="post" action="cart.php">
<input name="size" type="radio" value="Small">Small<br>
<input name="size" type="radio" value="Large">Large<br>
<input name="size" type="radio" value="XXL">XXL<br>
<input type="hidden" name="sizes" id="sizes" value=""/>
<input type="hidden" name="pid" id="pid" value="85" />
<input type="submit" name="button" value="Add To Cart"/></form>
Just a quick note that for retreiving the result I am using this code here:
if(isset($_POST['sizes'])){
$myvar = $_POST['sizes'];
echo "Your Size:", $myvar ;
}
You seem to be calling the radio buttons 'form1' but you have the same name for the first hidden field.
I would suggest that the form is submitting this field and ignoring the radio buttons for this reason.
Looking at your revised code, surely you need:
$myvar = $_POST['size'];
if ($myvar) {
echo "Size is $myvar";
}
'sizes' is never getting set to a 'true' value.
Note: the if ($myvar) works, in this instance, as effectively as the 'isset' statement but is simpler to code and read.
With JavaScript & jQuery:
$("#form1 input[name='size']").click(function(){
var size = $('input:radio[name=size]:checked').val();
$("#form1 input[name='sizes']").val(size);
});
That should do the trick.
Related
html:
<form method="GET">
<input type="text" name="k" id="header-search" value="<?=$_GET["k"];?>"/>
<input type="submit" id="header-submit" value="" />
</form>
When current url is:
https://example.com/search/cats?b=5
After click on submit button it remove b query and show like this:
https://example.com/search/cats?k=sometext
But i want this result:
https://example.com/search/cats?b=5&k=sometext
I have other query like b, d and also c maybe add more in future, so this is not a static, maybe url have b maybe d or maybe c or maybe all together or maybe no one.
I tried this but looks like no changes:
action="<?=$_SERVER['REQUEST_URI'];?>"
You can add the variables inside hidden inputs:
<form method="GET">
<?php if(isset($_GET['b']){ ?>
<input type="hidden" name="b" value="<?=$_GET["b"];?>"/>
<?php } ?>
<input type="text" name="k" id="header-search" value="<?php echo isset($_GET["k"]) ? $_GET["k"] : '';?>"/>
<input type="submit" id="header-submit" value="" />
</form>
However this solution will not work very well if you have many different types of variables that may or may not exist all the time. If you add all the variables as hidden, they will all be visible when you submit the form. To prevent this, you will need to check if the variables are isset() and only print them if they are.
Here is a solution that uses hidden fields and handles any amount of get parameters:
<form method="GET">
<?php
foreach($_GET as $key => $value){
// do not make a hidden input for k, there is already a text input for k
if($key != 'k'){
echo '<input type="hidden" name="'.$key.'" value="'.$value.'"/>';
}
}
?>
<input type="text" name="k" id="header-search" value="<?php echo isset($_GET["k"]) ? $_GET["k"] : '';?>"/>
<input type="submit" id="header-submit" value="" />
</form>
I'm trying to get a value from a form, then display it on posting of the form. I can get the value to appear in the second text field, once I have chosen an option using the Ajax Auto-Select, but how do I get that value shown stored into a variable for display on posting? This is what I have been trying -
if ($_POST['action'] == 'getentity') {
$value= $entity;
$content .= '<div>'.$value.' hello</div>';
}
<form method="post" action="?">
<input type="text" name="TownID_display" size="50" onkeyup="javascript:ajax_showOptions(this,\'getEntitiesByLetters\',event)">
<input type="text" name="TownID" id="TownID_display_hidden" value="'.$entity.'" />
<input type="hidden" name="action" value="getentity" />
<input type="submit" name="submit" value="Find"/>
Many thanks for any help.
Try
<input type="text" name="TownID" id="TownID_display_hidden" value="<?php $value = $entity; echo $entity; ?>" />
and its better to use like this
if ($_POST['action'] == 'getentity') {
$value= $_POST['TownID'];
$content .= '<div>'.$value.' hello</div>';
}
it should work.
I have a problem with my form. I need it to redirect user to different pages basing on which radio button was selected. User has to choose one of two options and click next, and according to his choice, page should redirect him to other page.
Here is the code as it looks for now
<fieldset>
<legend>Select option</legend>
<center>
<form method="post" action="">
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio2" value="Firma"/>Company
</br>
<input type = "submit", class = "buttonStyle2", value=""/>
</form>
</center>
</fieldset>
and then php code
if(isset($_POST['Company'])
header("Location: http://myaddress.com/company.php");
Big thanks in advance for your help
Here is one way to achieve this.
Sidenote: Make sure you're not outputting before header. Consult this page on Stack about possible Headers already sent..., should this occur and making sure error reporting is set/on.
Otherwise, PHP will fail silently.
if(isset($_POST['radio1']) && ($_POST['radio1']) == "Osoba fizyczna"){
header("Location: http://www.example.com/non_company.php");
}
elseif(isset($_POST['radio1']) && ($_POST['radio1']) == "Firma"){
header("Location: http://www.example.com/company.php");
}
else{
header("Location: http://www.example.com/redirect_to_home.php");
}
Nota: The else would be if the person did not make a choice and simply clicked on submit without making a selection.
while using radio buttons of the same group name in your form:
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio1" value="Firma"/>Company
Note about
<input type = "submit", class = "buttonStyle2", value=""/>
remove the commas
<input type = "submit" class = "buttonStyle2" value=""/>
Since HTML source in FF will reveal No space between attributes in red/as an error.
<fieldset>
<legend>Select option</legend>
<center>
<form method="post" action="">
<input type="radio" name="radio1" value="Osoba fizyczna"/>Non-company
</br>
<input type="radio" name="radio1" value="Firma"/>Company
</br>
<input type = "submit" class = "buttonStyle2" value=""/>
</form>
</center>
</fieldset>
and
if ( isset($_POST['radio1']) ) {
$filename = $_POST['radio1'] . "php";
header("Location: http://myaddress.com/".$filename);
}
Might be even better to set up an array with allowed values and check if radio1 is in that array.
I have this:
<form method="post" id="kl" action="step2.php">
<input type="radio" name="rubrik" value="bussines"></input>
<input type="radio" name"rubrik" value="private"></input>
<input type="image" value="submit" src="/images/submit.png" alt="Submit" />
</form>
What i bassicaly want is: When the second radio button is checked, to submit the form to step2a.php, a different file. How can i do this? Jquery, Javascript, php?
You could do this with JavaScript (bind a submit listener that checks the value of the radio button and then sets the action property of the form), but it would be simpler and more reliable to do something (server side) along the lines of:
<form ... action="step-selector.php">
and
<?php
if (isset($_POST['rubrik']) && $_POST['rubrik'] == 'bussines') {
include('step2.php');
} elseif (isset($_POST['rubrik']) && $_POST['rubrik'] == 'private') {
include('step2a.php');
} else {
include('error-state.php');
}
?>
you can do this by modifying the Form into:
<form method="post" id="kl" action="step2.php">
<input type="radio" class="radio" rel="step2.php" name="rubrik" value="bussines"></input>
<input type="radio" class="radio" rel="step2a.php" name"rubrik" value="private"></input>
<input type="image" value="submit" src="/images/submit.png" alt="Submit" />
</form>
I added rel attribute to radio buttons. each has a value of the url. I also added a class to get the element with jQuery.
Now, you will need some Javascript, i will use jQuery code:
$('.radio').click(function (){
rad = $(this);
radRel = rad.attr('rel');
$('form#kl').attr('action', radRel);
});
There are multiple ways of doing it, depending on what you want exactly.
Check this one out, it might help you get there; Radio Button to open pages
You can use form.submit() as onclick-handler (not onchange) and change the action, too.
<input type="radio" name"rubrik" value="private" onclick="this.parentNode.action='yourOtherFile.php'; this.parentNode.submit()"></input>
I have a simple registration form.
I want to pass value entered in one page to other in a text field.
how to pass and access it from next page in php.
this is my first php page.
Thanks in advance.
You can add hidden fields within HTML and access them in PHP:
<input type="hidden" name="myFieldName" value="someValue"/>
Then in PHP:
$val = $_POST['myFieldName'];
If you're going to ouput this again you should use htmlspecialchars or something similar to prevent injection attacks.
<input type="hidden" name="myFieldName" value="<?=htmlspecialchars($_POST['myFieldName']);?>"/>
Suppose this the form input in page A
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="">
<input type=submit>
</form>
In page B
In the page you want to get values put this code
<?PHP
foreach ($_REQUEST as $key => $value ) {
$$key=(stripslashes($value));
}
?>
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="<?PHP echo $myvalue" ?>">
<input type=submit>
</form>
So yo can use or attach variable value to another form do what else you want to do
use following code, that should help you.
<form action ="formhandler.php" method ="POST" >
<input name = "inputfield" />
<input type="submit" />
</form>
on formhandler.php file yo need to enter following code to get the value of inputfiled.
$inputfield = isset($_POST['inputfield'])?$_POST['inputfield']:"";
// now you can do what ever you want with $inputfield value
echo($inputfield);