Failure to load resource 500 error ajax POST in PHP - php

Question

I have seen many other posts like this, but I cannot see anything I have done wrong. I also read it could be a problem with the hosting (Heroku) so I have created a ticket, but no answer after 3 days.
Below is the code which sends the info:
(discuss.php)
<script type="text/javascript">
$(function() {
$('#ideasubmit').click(function() {
console.log();
$('#ideacontainer').append('<img src="images/loading.gif" alt="Please Wait" id="idealoading" />');
var ideatitle = $('#ideatitle').val();
var ideafbid = $('#ideafbid').val();
var idea = $('#idea').val();
$.ajax({
url: 'ajaxsqli.php',
type: 'POST',
data: 'ideatitle=' + ideatitle + '&ideafbid=' + ideafbid + '&idea=' + idea,
success: function(result) {
$('#idearesponse').remove();
$('#ideacontainer').append('<p id="idearesponse">' + result + '</p>');
$('#idealoading').fadeOut(500, function() {
$(this).remove();
});
}
});
return false;
});
});
Below here is the code file which gets the error when it sent the info:
(ajaxsqli.php)
$db = new db;
$query = "INSERT into comments(user_fbid, discuss_type, discuss_post_title, discuss_post, date) VALUES (?, ?, ?, ?, )";
$stmt = $db->stmt_init();
if($stmt->prepare($query)) {
$stmt->bind_param('iissi', $_POST['ideafbid'], 1, $_POST['ideatitle'], $_POST['idea'], date('Ymd'));
$stmt->execute();
}
if($stmt) {
echo "Thank you. We'll be in touch with you shortly!";
} else {
echo "There was a problem. Please try again later.";
}
?>
Whats odd is I had it working 3 days ago, and I went to improve some of the code and now I am unable to make it work, even if I restore the back up.
This is the full error message:
Failed to load resource: the server responded with a status of 500 (Internal Server Error) and points to ajaxsqli.php
Using Chrome Inspect Elements I can see the POST is posting the information, but no response information.
Is there anything wrong with this code ?

Answer 1

A 500 error usually refers to a problem in the php. Load ajaxsqli.php in the browser with the paramaters (change $_POST to $_REQUEST and then you can use the querystring. EG
$db = new db;
$query = "INSERT into comments(user_fbid, discuss_type, discuss_post_title, discuss_post, date) VALUES (?, ?, ?, ?, )";
$stmt = $db->stmt_init();
if($stmt->prepare($query)) {
$stmt->bind_param('iissi', $_REQUEST['ideafbid'], 1, $_REQUEST['ideatitle'], $_REQUEST['idea'], date('Ymd'));
$stmt->execute();
}
if($stmt) {
echo "Thank you. We'll be in touch with you shortly!";
} else {
echo "There was a problem. Please try again later.";
}
?>
Then go to http://yourhost/ajaxsqli.php?ideafbid=data&ideatitle=data&idea=data and see what the PHP error is