The problem goes as follows:
File 1 which has the name of: Lesson 17_Forms - Simple Form.php
and
File 2 which has the name of: Lesson 17_Forms - Process.php
The contents of file 1 are as follows:
<html>
<title>Lesson 17_Forms - Simple Form</title>
<head>
<center><h1>Lesson 17_Forms - Simple Form</h1></center>
</head>
<body>
<form action= "Lesson 17_Forms - Process.php" method="post">
Username: <input type="text" name="username" value="" />
<br />
Password: <input type="password" name="password" value="" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
The contents of file 2:
<html>
<title>Lesson 17_Forms - Process</title>
<head>
<center><h1>Lesson 17_Forms - Process</h1></center>
</head>
<body>
<?php
// Ultra-simple form processing
// Just retrieve the value and return it to the browser
$username = $_POST['username'];
$password = $_POST['password'];
echo "{$username}: {$password}";
?>
</body>
</html>
Both files are in the same directory, when i am trying to process the form by clicking the submit button, i am receiving the following error:
Object not found!
The requested URL was not found on this server. The link on the
referring page seems to be wrong or outdated. Please inform the author
of that page about the error.
If you think this is a server error, please contact the webmaster.
Error 404
localhost Sat 12 May 2012 02:40:39 PM EEST Apache/2.2.21 (Unix) DAV/2
mod_ssl/2.2.21 OpenSSL/1.0.0c PHP/5.3.8 mod_apreq2-20090110/2.7.1
mod_perl/2.0.5 Perl/v5.10.1
Any suggestions are greatly appreciated.
No spaces are allowed in url -> change the names to simple_form.php and process.php.
or if you want to keep spaces in name then replace all spaces by '%20' whenever you use it as a url.
Or the best option is to use urlencode -> it automatically replaces all non-allowed characters by their web acceptable placeholders.
<form action=<?php echo '"'.urlencode("Lesson 17_Forms - Process.php").'"'; ?> method="post">
Make sure you have both files on the same directory. Also, eliminate any spaces in file names, while valid, they will cause massive headaches. So name your files something more like: lesson17_forms_process.php.
Also, after some modifications, this is the code I get:
<?php
//Initialize variables
$fields_set = false;
$username = "";
$password = "";
//Validity check
if (isset($_POST['username']) && isset($_POST['password'])) {
$fields_set = true;
$username = $_POST["username"];
$password = $_POST["password"];
}
?>
<html>
<head>
<title>Lesson 17_Forms - Process</title>
</head>
<body>
<h1 style="text-align: center;">Lesson 17_Forms - Process</h1>
<?php
//Display results if validity passed, or error in case it didn't.
if ($fields_set) {
echo "{$username}: {$password}";
}
else {
echo "Error! username or password not set!";
}
?>
</body>
</html>
Some Points
I process all form data before I start sending HTML. Separate logic and display as much as possible.
I removed the h1 element from the head and placed it in the body (where it belongs). All page content must go in body.
I removed the presentational element <center> and replaced it with CSS.
I validate the input prior to processing.
I display an error in case the form is not valid.
I'll use your existing code, and modify it. With new file names.
I did also correct your HTML.
Create a file named: form.php, insert the code below:
<html>
<head>
<title>Submit form</title>
</head>
<body>
<center><h1>Submit form</h1></center>
<form action="process.php" method="post">
Username:<input type="text" name="username" value="" />
<br />
Password: <input type="password" name="password" value="" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
Create a file named: process.php, insert the code below:
<html>
<head>
<title>Your form</title>
</head>
<body>
<center><h1>Lesson 17_Forms - Process</h1></center>
<?php
// Ultra-simple form processing
// Just retrieve the value and return it to the browser
$username = $_POST['username'];
$password = $_POST['password'];
echo "{$username}: {$password}";
?>
</body>
</html>
That should work perfectly, remember to have both files in the same folder.
Related
I tried to execute the following html code:
<html>
<head>
<title>Listing 9.1 A simple HTML form</title>
</head>
<body>
<form action="listing.php" method="POST">
<p><strong>Name:</strong><br>
<input type="text" name="user"></p>
<p><strong>Address:</strong><br>
<textarea name="address" rows="5" cols="40"></textarea></p>
<p><input type="submit" value="send"></p>
</form>
</body>
</html>
And this is the code of the associated php file (listing.php):
<html>
<head>
<title>Listing Reading input from a form </title>
</head>
<body>
Welcome <?php echo $_POST["user"]; ?><br>
Your email address is: <?php echo $_POST["address"]; ?>
</body>
</html>
I was able to get the form and enter values as shown below:
Form Input
But, when I clicked 'Send Message', it displays only:
Welcome
Your email address is:
Without the values that I entered through the form.
When I tried to run the php file directly from the local host (http://localhost/listing.php), I received these error messages:
Welcome
Notice: Undefined index: user in C:\xampp\htdocs\listing.php on line 7
Your email address is:
Notice: Undefined index: address in C:\xampp\htdocs\listing.php on line 8
I even modified the php code as follows, but still got the same output:
<html>
<head>
<title>Listing Reading input from a form </title>
</head>
<body>
Welcome <?php
if(isset($_POST['submit'];)) {
session_start();
$user = $_POST['user'];
echo "$text";}else {echo 'Could not load text!';}?><br>
Your email address is: <?php echo $_POST["address"]; ?>
</body>
</html>
I would really appreciate it if you could give some advice to make it work.
Thanks
if(isset($_POST['submit'];)) should be changed,so you check if address and user is isset. Furthermore you normally don't want ; in your if statements.
Here i have a optimized version for you. the !empty is added so we also check if the inputs are not empty.
if (isset($_POST["name"] && isset($_POST["address"])) {
if (!empty($_POST["name"] && !empty($_POST["address"]) {
// execute code as u would
}
}
Notice: Undefined index: address in C:\xampp\htdocs\listing.php on line 8
This is caused by the use of the ';' in the if condition.
Remove that and you should be good. for now.
Try this code:
<html>
<head>
<title>Listing Reading input from a form </title>
</head>
<body>
Welcome <?php
if(isset($_POST['submit']))
{
session_start();
$user = $_POST['user'];
echo $user;
echo "<br><br>Your Email Address is: ".$_POST['address'];
}
else
{
echo 'Could not load text!';
}
?>
<br>
<form action="" method="POST">
<p><strong>Name:</strong><br>
<input type="text" name="user"></p>
<p><strong>Address:</strong><br>
<textarea name="address" rows="5" cols="40"></textarea></p>
<p><input type="submit" value="send" name="submit"></p>
</form>
</body>
</html>
In your second code block $text isn't defined anywhere. Do you mean to have $user?
<html>
<head>
<title>Listing Reading input from a form</title>
</head>
<body>
Welcome
<?php
if(isset($_POST['submit'])) {
session_start();
echo isset($_POST['user']) ? $_POST['user'] : "User";
} else {
echo "User";
}
?>
<br>
Your email address is:
<?php
echo isset($_POST["address"]) ? $_POST["address"] : "Address"
?>
</body>
</html>
Try this and let me know:
<?php
session_start();
if(isset($_POST['submit'])) {
$user = $_POST['user'];
echo "Welcome ".$user;
echo "<br>";
echo "Your email address is: ".$_POST["address"];
}else {
// you may get rid of this block if you like
echo 'Could not load text!';
}
?>
<html>
<head>
<title>Listing 9.1 A simple HTML form</title>
</head>
<body>
<form action="" method="POST">
<p><strong>Name:</strong><br>
<input type="text" name="user"></p>
<p><strong>Address:</strong><br>
<textarea name="address" rows="5" cols="40"></textarea></p>
<p><input type="submit" name='submit' value="send"></p>
</form>
</body>
</html>
Hi im trying to upload an image to a database using php but every time i press the submit button i get the error
accept-file.php was not found
i dont see anywhere in my code where it will be directing to that is there something im missing?
<?php
session_start();
$link = mysqli_connect("localhost","root","","pictureupload");
if(isset($_POST['submit'])){
$imagename=$_FILES["iamge"]["name"];
$imagetmp=addslashes (file_get_contents($_FILES['image']['tmp_name']));
$insert_image="INSERT INTO images VALUES('$imagetmp','$imagename')";
mysqli_query($link,$insert_image);
}
?>
<!DOCTYPE html>
<html>
<head>
<Title>HomePage</Title>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<form action="accept-file.php" method="post" enctype="multipart/form-data">
Your Image: <input type="file" name="image" size="25" />
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
change your form tag to
<form action="?"
Your form has "accept-file.php" set as action:
<form action="accept-file.php" method="post" enctype="multipart/form-data">
This is where the form data will be sent to via the set method (POST in this case) and using the given encoding type.
After you click on "submit" your browser will call this script, which in your case does not exist. Therefore your webserver will return the error message instead of handling the upload.
To make it work you need to change the action to the filename of your script, which you have posted above.
First of all this is not my code, I just need it changed a little.
I need to know how to write messages onto the same file where the user posts the message.
Here is one page where the user can post their message:
<html>
<head>
<title>Form to Flat File</title>
</head>
<body>
<form action="sendinfo.php" method="get">
Your Name:<br />
<input type="text" name="name"><br />
Your Message:<br />
<textarea name="message"></textarea><br />
<input type="submit" value="Send Info">
</form>
</body>
</html>
And here is the other that writes the message onto a PHP file:
<html>
<head>
<title>Form to Flat File</title>
</head>
<body>
<?php
include('config.php');
$user = $_GET["name"];
$message = $_GET["message"];
print("<b>Thank You!</b><br />Your information has been added! You can see it by <a href=savedinfo.php>Clicking Here</a>");
$out = fopen("savedinfo.php", "a");
if (!$out) {
print("Could not append to file");
exit;
}
fputs ($out,implode,("\n"));
fwrite($out,"<b>$user</b><br />$message<br /><br />");
fclose($out);
?>
</body>
</html>
Pretty much I just want everything on one page, I got close to doing that but it won't let me write onto the same page. I'm sure it's possible I'm just nowhere near experienced enough. Please help!
What you want is to put content of both files in a single file, but execute the content of the second file only if form has been submitted.
First of all, change the form's method value to POST and replace all references to $_GET with $_POST
Then create a single file containing
<html>
<head>
<title>Form to Flat File</title>
</head>
<body>
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
// here put content of the file that stores form values in a file
// just remove all html code and leave only PHP code
}
?>
// here put content of the file that displays the form
// just remove HTML, HEAD and BODY tags first
</body>
</html>
I am currently learning the most basic PHP ever. I have 5 files.
index.php:
<html>
<head>
<title>Budget Calcule</title>
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<h2>Put in your: - </h2>
<form action="functions.php" method="post">
<h3>Income</h3>
<label>Salary: <input name="salary" type="text" /></label><br />
<h3>Outgoings</h3>
<label>Living: <input name="living" type="text" /></label><br />
<label>Insurance: <input name="insurance" type="text" /></label><br />
<label>Communication: <input name="communication" type="text" /></label><br />
<label>Loan: <input name="loan" type="text" /></label><br />
<label>Food & Drink: <input name="foodAndDrink" type="text" /></label><br />
<label>Entertaintment / Shopping: <input name="entertainmentOrShopping" type="text" /></label><br />
<label>Transport: <input name="transport" type="text" /></label><br />
<label>Other: <input name="other" type="text" /></label><br />
<input type="submit" value="Submit" />
</form>
</body>
</html>
this is my functions.php:
<?php
include('variables.php');
if(!($_POST['Submit'])){
if(isset($_POST['salary'])){
header('Location: output.php');
return $_POST['lon'];
}else{
echo "All fields are required";
}
}
?>
this is my variables.php:
<?php
$salary= $_POST['salary'];
$living= $_POST['living'];
$insurance= $_POST['insurance'];
$communication = $_POST['communication'];
$loan = $_POST['loan'];
$food = $_POST['food'];
$entertaintmentOrShopping = $_POST['entertaintmentOrShopping'];
$transport = $_POST['transport'];
$other= $_POST['other'];
?>
this is my output.php file:
<?php
include('outputFunction.php');
?>
<html>
<head>
<title>Output.php</title>
</head>
<body>
<?php myText(); ?>
</body>
</html>
and last but not least, this is my outputFunction.php file:
<?php
include('variables.php');
function myText(){
echo "Your salary per month is: " . $_POST['salary'];
}
?>
Now you're thinking "why have he split up his code in different files?" Well first of all, I split the variables from functions.php because I wanted outputFunctions.php to get the variables from variables.php so i could echo my `$_POST['salary']; . The function myText(); outputs the text just fine, but it doesnt output the $_POST['salary'];.
I do not know why it doesnt work, I just wonder if you could be my extra eyes and see if I've done some mistake.
PS! Don't down vote my question just because you think it's stupid. I am having problem with this issue and been working on it for hours without advancing anywhere.
A few things:
You don't need to include a variables.php file. The variables you're accessing are global and you're just creating duplicates that aren't being used. They also go away after the page changes since you're re-declaring them each page load.
You are also trying to call a variable that doesn't exist when you reference $_POST['lon'] instead of 'loan'.
And finally to actually answer your question:
Your myText() function is referencing a variable that is not there anymore.
You need to merge functions.php and outputFunction.php and output.php into one file so the variables aren't lost and all the processing is done without opening a new file each time. I can see your original concept for separated files but an output file is going to be the file to process the input data from the form.
Now in your newly merged output.php, you should have something resembling this:
<html>
<head>
<title>Output</title>
</head>
<body>
<?php
if(isset($_POST['Submit'])) {
if(isset($_POST['salary'])) {
echo "Your salary per month is: " . $_POST['salary'];
}
} else {
echo "All fields required.";
}
?>
</body>
</html>
This means only two files - your form page and this page.
A few more tips:
If you want to check if the form was submitted, it has look something like this:
if(isset($_POST['Submit'])){ ... }
Also, you should add a name="" attribute to your submit-Button:
<input type="submit" name="Submit" value="Submit" />
And what is the variables.php for? You don't use any of those variables.
When you redirect the user via header() the data that is stored in the $_POST array gets lost.
You could directly redirect to ouput.php
<form action="output.php" method="post">
And do something like this:
<?php
include('outputFunction.php');
if(isset($_POST['Submit'])) {
if(isset($_POST['salary'])) {
?>
<html>
<head>
<title>Output.php</title>
</head>
<body>
<?php myText(); ?>
</body>
</html>
<?php
} else {
echo "All field required";
}
}
?>
By the way you can always check what your $_POST contains with print_r($_POST);
This can be very useful for debugging.
On one PHP server I have two files. One file (the name is "first.php") contains this code:
<html>
<head>
<title>First Page</title>
</head>
<body>
Please enter your password and age:
<form action="pass.php" method="post">
Name: <input type="text" name="fname" />
Age: <input type="text" name="age" />
<input type="submit" />
</form>
</body>
</html>
The other file ("pass.php") contains this code:
<html>
<head>
<title>Secon Page</title>
</head>
<body>
<?php
if ($fname=="Jack")
echo "You are Jack!";
else
echo "You are not Jack!";
?>
</body>
</html>
As far as I understand, if a user enters "Jack" in the first page, than the second page should be displayed with "You are Jack!" line, but it doesn't happen. Why is it so?
On your second page, instead of checking for $fname, check for $_POST['fname'] instead. I think that is all you are missing.
You probably don't have register_globals set. This is depreciated and will be removed in 6.x. So for good programming you should instead of $fname try $_POST['fname'] on your second page.
pass.php needs to look like this
<html>
<head>
<title>Secon Page</title>
</head>
<body>
<?php
if ($_POST['fname'] =="Jack")
echo "You are Jack!";
else
echo "You are not Jack!";
?>
</body>
</html>
It might help to set the post values as variables and work with that. Something like this:
foreach($_POST as $key => $value)
{
$$key = $value;
}
Then whatever is posted will be available rather than using $_POST['xxxxx'] in your logic.